Probability Histogram Quiz: Test!

1.

What is the experimental probability that that the spinner lands on red?

4%

20%

25%

40%

The experimental probability of an event is determined by conducting an experiment and observing the outcomes. In this case, if the spinner is spun multiple times and it lands on red 20% of the time, then the experimental probability of the spinner landing on red is 20%.

Explanation

The experimental probability of an event is determined by conducting an experiment and observing the outcomes. In this case, if the spinner is spun multiple times and it lands on red 20% of the time, then the experimental probability of the spinner landing on red is 20%.

2.

The entertainment sector is too small relative to the groceries sector

The rent sector is too large relative to the entertainment sector.

The sample size is too small.

The sectors do not add to 100%.

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Explanation

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3.

2001-2002

2002-2003

2003-2004

2004-2005

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Explanation

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4.

Bar graph

Circle graph

Histogram

Line graph

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Explanation

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5.

Find the mean, median, and mode. (Round answers to the nearest tenth.)

Mean: 54.6 Median: 55 Mode: 51

Mean: 54.6 Median: 62 Mode: 51

Mean: 55 Median: 54.6 no mode

Mean: 55 Median: 55 no mode

The mean is calculated by finding the average of all the numbers, which in this case is 54.6. The median is the middle value when the numbers are arranged in ascending order, and in this case, it is 55. The mode is the number that appears most frequently, and in this case, it is 51.

Explanation

The mean is calculated by finding the average of all the numbers, which in this case is 54.6. The median is the middle value when the numbers are arranged in ascending order, and in this case, it is 55. The mode is the number that appears most frequently, and in this case, it is 51.

6.

{0, 1, 2, 4, 5, 6, 7, 7, 9, 9}

{1, 11, 23, 41, 53, 61, 71, 72, 90, 90}

{9, 9, 10, 11, 14, 16, 17, 27, 32, 35}

{27, 99, 325, 101,467}

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Explanation

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7.

The bar for 40–44 is too short and the bar for 45–49 is too tall.

The bar for 50–54 is too tall.

The bar for 50–54 is too short and the bar for 55–59 is too tall.

The bar for 55–59 is too short.

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Explanation

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8.

If Angie spins the spinner 250 times, predict the number of times it will land on green.

10

25

50

125

If Angie spins the spinner 250 times, and the spinner has an equal chance of landing on each color, then we can assume that each color will appear the same number of times on average. Since there are 4 colors on the spinner, including green, we can divide 250 by 4 to get the average number of times each color will appear. 250 divided by 4 is 62.5, so each color should appear approximately 62.5 times. However, since we can't have a fraction of a spin, we round up to the nearest whole number, which is 63. Therefore, we can predict that the spinner will land on green approximately 63 times.

Explanation

If Angie spins the spinner 250 times, and the spinner has an equal chance of landing on each color, then we can assume that each color will appear the same number of times on average. Since there are 4 colors on the spinner, including green, we can divide 250 by 4 to get the average number of times each color will appear. 250 divided by 4 is 62.5, so each color should appear approximately 62.5 times. However, since we can't have a fraction of a spin, we round up to the nearest whole number, which is 63. Therefore, we can predict that the spinner will land on green approximately 63 times.

9. Find the theoretical probability of randomly choosing a vowel from the letters in EXPERIMENT

The theoretical probability of randomly choosing a vowel from the letters in EXPERIMENT can be found by dividing the number of vowels (4) by the total number of letters (10). This is because there are 4 vowels (E, E, I, and E) out of 10 letters in total. Therefore, the theoretical probability is 4/10, which can be simplified to 2/5 or 0.4.

Explanation

The theoretical probability of randomly choosing a vowel from the letters in EXPERIMENT can be found by dividing the number of vowels (4) by the total number of letters (10). This is because there are 4 vowels (E, E, I, and E) out of 10 letters in total. Therefore, the theoretical probability is 4/10, which can be simplified to 2/5 or 0.4.

10.

F

G

H

J

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Explanation

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11.

The value of Q1 is incorrect

The value of the median is incorrect.

The value of Q3 is incorrect.

The boxplot is correct

If the boxplot accurately represents the data distribution with the correct values for Q1, median, and Q3, and the whiskers extend to the minimum and maximum values within 1.5 times the interquartile range (IQR) from the quartiles, then the box-and-whisker plot is correct. Therefore, if there are no errors in the construction or placement of the components, the boxplot itself is accurate.

Explanation

If the boxplot accurately represents the data distribution with the correct values for Q1, median, and Q3, and the whiskers extend to the minimum and maximum values within 1.5 times the interquartile range (IQR) from the quartiles, then the box-and-whisker plot is correct. Therefore, if there are no errors in the construction or placement of the components, the boxplot itself is accurate.

12. The probability of picking a red marble from a bag is

. What are the odds against picking a red marble?

2:5

5:2

5:7

7:5

The odds against picking a red marble can be calculated by taking the ratio of the number of outcomes that are not picking a red marble to the number of outcomes that are picking a red marble. In this case, the ratio is 5:2, which means that for every 5 outcomes of not picking a red marble, there are 2 outcomes of picking a red marble.

Explanation

The odds against picking a red marble can be calculated by taking the ratio of the number of outcomes that are not picking a red marble to the number of outcomes that are picking a red marble. In this case, the ratio is 5:2, which means that for every 5 outcomes of not picking a red marble, there are 2 outcomes of picking a red marble.

13. A game board has 8 cards, and 2 say WIN. Mayela picks 2 cards without replacing the first. What is the probability that neither say WIN?

The probability that the first card does not say WIN is 6/8, since there are 6 cards out of 8 that do not say WIN. After picking the first card, there are 7 cards left, and 5 of them do not say WIN. Therefore, the probability that the second card does not say WIN is 5/7. To find the probability that neither card says WIN, we multiply the probabilities together: (6/8) * (5/7) = 30/56 = 15/28.

Explanation

The probability that the first card does not say WIN is 6/8, since there are 6 cards out of 8 that do not say WIN. After picking the first card, there are 7 cards left, and 5 of them do not say WIN. Therefore, the probability that the second card does not say WIN is 5/7. To find the probability that neither card says WIN, we multiply the probabilities together: (6/8) * (5/7) = 30/56 = 15/28.

14. A number cube is rolled 2 times in a row. What is the probability of rolling a multiple of 3 both times?

The probability of rolling a multiple of 3 on a number cube is 1/3, since there are 3 multiples of 3 (3, 6, and 9) out of the 6 possible outcomes (1, 2, 3, 4, 5, and 6). Since the number cube is rolled 2 times, the probability of rolling a multiple of 3 both times is (1/3) * (1/3) = 1/9.

Explanation

The probability of rolling a multiple of 3 on a number cube is 1/3, since there are 3 multiples of 3 (3, 6, and 9) out of the 6 possible outcomes (1, 2, 3, 4, 5, and 6). Since the number cube is rolled 2 times, the probability of rolling a multiple of 3 both times is (1/3) * (1/3) = 1/9.

15. From 5 players, 2 are chosen to play the bonus round. How many different teams of two are possible? Does the situation involve permutations or combinations?

10; combinations

20; combinations

20; permutations

60; permutations

There are 5 players and 2 need to be chosen for the team. Since the order in which the players are chosen does not matter, it involves combinations. The number of different teams of two that can be formed is 10.

Explanation

There are 5 players and 2 need to be chosen for the team. Since the order in which the players are chosen does not matter, it involves combinations. The number of different teams of two that can be formed is 10.