Asam Basa Kuis

Moon is round because of formed and collapsed under the force of their own gravity.

Moon is round because of formed and collapsed under the force of their own gravity.

Moon is round because of formed and collapsed under the force of their own gravity.

Moon is round because of formed and collapsed under the force of their own gravity.

The given answer is correct because when copper metal reacts with dilute hydrochloric acid, it does not produce any gas. The reaction between copper metal and dilute hydrochloric acid only produces copper chloride, which is a salt, and water. Therefore, this reaction does not result in the formation of any gas.

When AgNO3(aq) and NaCl(aq) are mixed, a precipitation reaction occurs. This is because AgNO3(aq) contains Ag+ ions and NaCl(aq) contains Cl- ions. When these ions combine, they form AgCl(s), which is insoluble in water and therefore precipitates out of the solution.

The given question asks for the value of "a" in a solution with a pH of 12. The pH scale measures the acidity or alkalinity of a solution, with values below 7 being acidic, 7 being neutral, and values above 7 being alkaline. A pH of 12 indicates a highly alkaline solution. To calculate the value of "a," we need to consider the concentration of hydroxide ions (OH-) in the solution. Since NaOH is a strong base, it fully dissociates in water to form Na+ and OH- ions. The concentration of OH- ions can be calculated using the formula: concentration (mol/L) = moles/volume (L). Given that the volume of the solution is 500 mL (or 0.5 L) and the molar mass of NaOH is 40 g/mol, we can calculate the moles of NaOH using the formula: moles = mass/molar mass. Assuming the mass of NaOH is "a" grams, the moles of NaOH are "a/40." Therefore, the concentration of OH- ions is (a/40)/0.5 = a/20 mol/L. To find the value of "a" that corresponds to a pH of 12, we can use the formula: pH = -log[H+], where [H+] is the concentration of hydrogen ions. Since pH = 12, we can rearrange the formula to find [H+]: [H+] = 10^(-pH). Plugging in the value of pH, we get [H+] = 10^(-12). Since water is neutral and has a pH of 7, the concentration of OH- ions is equal to the concentration of H+ ions in a neutral solution. Therefore, the concentration of OH- ions in our solution is 10^(-12) mol/L. Since the concentration of OH- ions is a/20 mol/L, we can equate the two expressions to find the value of "a": 10^(-12) = a/20. Solving for "a," we find a = 0.2.

The correct answer is H₂SO₄. The question is asking for the conjugate acid of HSO₄⁻. In chemistry, a conjugate acid is formed when a base gains a proton. HSO₄⁻ is a base because it can accept a proton, and when it does, it becomes the conjugate acid, which is H₂SO₄.

The pH of a solution is a measure of its acidity or alkalinity. It is defined as the negative logarithm of the concentration of hydrogen ions (H⁺) in the solution. In this case, we are given that the pH of a weak base with a valency of 1 is 11. Since a basic solution has a higher concentration of hydroxide ions (OH⁻), we can use the equation pOH + pH = 14 to find the pOH of the solution. pOH is the negative logarithm of the concentration of hydroxide ions. By subtracting the pH from 14, we get a pOH of 3. Therefore, the concentration of hydroxide ions in the solution is 1 x 10⁻³.