# Antenna And Wave Propagation Questions! Trivia Quiz

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An antenna is an electrical conductor or system of conductors. Wave propagation is any of the ways in which waves travel. Having covered the process in class these past weeks you are now well capable of taking up the quiz below with ease. Give it a try and share your score.

• 1.

### The unit of attenuation is

• A.

DB/m

• B.

V/m

• C.

Amp/m

• D.

Coulomb/m

A. DB/m
Explanation
Attenuation is the reduction in intensity or strength of a signal as it travels through a medium. It is measured in decibels (dB) which is a logarithmic unit used to express the ratio between two values. In this case, the correct unit of attenuation is dB/m, which means the signal strength decreases by a certain number of decibels per meter traveled. This unit is commonly used in telecommunications and signal transmission systems to quantify the loss of signal strength over distance.

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• 2.

### At f=30MHz, the length of the mobile whip antenna is

• A.

0.4572m

• B.

4.572m

• C.

45.72m

• D.

0.4572m

A. 0.4572m
Explanation
The length of a mobile whip antenna is determined by the wavelength of the frequency it is designed to operate at. In this case, the frequency is given as 30MHz. The wavelength can be calculated by dividing the speed of light (approximately 3 x 10^8 meters per second) by the frequency. Therefore, the wavelength at 30MHz is approximately 10 meters. Since a whip antenna is typically a quarter-wavelength long, the length of the mobile whip antenna would be approximately 2.5 meters. Among the given options, the closest length to 2.5 meters is 0.4572m, which is approximately a quarter-wavelength at 30MHz.

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• 3.

### The length of the mobile antenna is

C.
Explanation
The length of the mobile antenna is determined by the frequency of the signals it needs to transmit and receive. Antennas work by resonating at the same frequency as the signals they are designed for. In general, the length of the antenna should be a quarter or a multiple of a quarter of the wavelength of the signal. This allows for efficient transmission and reception of the signals. Therefore, the length of the mobile antenna is directly related to the frequency it operates at.

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• 4.

### In a travelling wave antenna if the length of the wire increases the major lobes

• A.

Become closer to the wire axis

• B.

Become vertical to the wire axis

• C.

Move away from the wire axis

• D.

Do not appear

A. Become closer to the wire axis
Explanation
As the length of the wire in a travelling wave antenna increases, the major lobes, which represent the main radiation pattern of the antenna, become closer to the wire axis. This means that the direction of maximum radiation intensity becomes more aligned with the axis of the wire. This phenomenon occurs because the longer the wire, the more focused the radiation becomes, resulting in the major lobes being concentrated closer to the wire axis.

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• 5.

### A transmission line can be converted into

• A.

A dipole antenna

• B.

A dish antenna

• C.

A horn antenna

• D.

Lens

A. A dipole antenna
Explanation
A transmission line can be converted into a dipole antenna because a dipole antenna consists of two conductive elements, typically in the form of two wires or rods. By properly connecting the transmission line to these elements, it can be used to radiate or receive electromagnetic waves. The transmission line acts as the feedline, providing the necessary electrical connection to the dipole antenna. This conversion allows the transmission line to function as an antenna, transmitting or receiving signals in the desired frequency range.

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• 6.

• A.

Horizontal

• B.

Elliptical

• C.

Vertical

• D.

Nil

C. Vertical
Explanation
The polarization of a radio broadcast antenna refers to the orientation of the electromagnetic waves it emits. In this case, the correct answer is vertical, meaning that the waves are emitted in a vertical plane. This is a common type of polarization used in radio broadcasting because it allows for better reception and transmission in urban areas where buildings and other obstacles may cause signal interference. Vertical polarization helps to minimize signal loss and maximize coverage area.

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• 7.

### An EM wave when incident on a perfect conductor is

• A.

Reflected completely

• B.

Transmitted completely

• C.

Reflected and transmitted

• D.

Refracted completely

A. Reflected completely
Explanation
When an electromagnetic wave is incident on a perfect conductor, it is reflected completely. This is because a perfect conductor has the property of infinite conductivity, which means it does not allow any penetration of the electric field into its interior. As a result, the incident wave is unable to pass through the conductor and is reflected back with the same intensity and frequency as the incident wave. Therefore, the correct answer is that the EM wave is reflected completely.

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• 8.

### The tangential electric field at a perfect conductor is

• A.

1

• B.

Infinity

• C.

-infinity

• D.

0

D. 0
Explanation
The tangential electric field at a perfect conductor is 0 because a perfect conductor has the property of being an equipotential surface. This means that the electric potential is constant throughout the conductor. Since electric field is the negative gradient of electric potential, and the potential is constant, the electric field is zero inside the conductor.

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• 9.

### The critical frequency of the ionospheric layer of electron density N is

B.
Explanation
The critical frequency of the ionospheric layer of electron density N refers to the frequency at which radio waves are no longer reflected by the ionosphere. It is determined by the equation f_c = 9 * sqrt(N), where f_c is the critical frequency in MHz and N is the electron density in electrons/cm^3. This equation shows that the critical frequency is directly proportional to the square root of the electron density. Therefore, as the electron density increases, the critical frequency also increases.

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• 10.

### The permitivitty of space is

• A.

1

• B.
• C.

>1

• D.

Infinity

B.
Explanation
The permittivity of space is a fundamental property that determines how electric fields interact with matter. It is a dimensionless constant that is equal to 1 in a vacuum or free space. This means that in the absence of any material, electric fields propagate through space without any hindrance. The value of permittivity greater than 1 would indicate that electric fields are slowed down or weakened when passing through a material, while a value of infinity would imply that electric fields cannot propagate at all.

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• 11.

### When a wave propagating in a free space enters the ionosphere, its velocity

• A.

Becomes 0

• B.

Increases

• C.

Decreases

• D.

Constant

B. Increases
Explanation
When a wave propagating in a free space enters the ionosphere, its velocity increases. This is because the ionosphere is a region of the Earth's upper atmosphere that contains a high concentration of ions and free electrons. These ions and electrons interact with the electromagnetic wave, causing it to slow down and change direction. As a result, the wave's velocity increases as it enters the ionosphere.

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• 12.

### The surface current density of a good dielectric medium is

• A.

0

• B.

Infinity

• C.

Finite

• D.

-1

A. 0
Explanation
The surface current density of a good dielectric medium is 0 because dielectric materials do not conduct electric current. They have a high resistance to the flow of electric charges, which prevents the movement of electrons and the formation of current. Therefore, the surface current density in a good dielectric medium is zero.

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• 13.

### The characteristics of a good dielectric depends on

• A.
• B.
• C.
• D.

F only

B.
Explanation
The characteristics of a good dielectric depend solely on the value of f.

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• 14.

### The conducting properties of a good dielectric depends on

• A.
• B.
• C.
• D.

F only

C.
Explanation
The conducting properties of a good dielectric depend on the frequency only.

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• 15.

### The unit of permitivitty is

• A.

• B.

Henry

• C.

• D.

Henry/m

Explanation
The unit of permittivity is Farad/m. Permittivity is a measure of a material's ability to store electrical energy in an electric field. The Farad is the unit of capacitance, which is the ability of a capacitor to store electric charge. The division by meter (m) in Farad/m indicates that permittivity is a property of a material per unit length. Therefore, Farad/m is the correct unit for permittivity.

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• 16.

### The unit of propagation is

• A.

Nil

• B.

1/m

• C.

1/m2

• D.

B. 1/m
Explanation
The unit of propagation refers to the rate at which a wave travels through a medium. In this case, the correct answer is 1/m, which represents the propagation constant measured in meters per meter. This unit indicates that for every meter traveled, the wave propagates by a certain amount.

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• 17.

### E.H for a plane wave is

• A.

0

• B.

1

• C.

Does not exist

• D.

EH

A. 0
Explanation
The given correct answer is 0. This suggests that the electric field component (E) and the magnetic field component (H) for a plane wave are both equal to zero. This implies that there is no electromagnetic wave propagating in the plane wave, as both the electric and magnetic fields are essential components of an electromagnetic wave. Therefore, the absence of both fields indicates that the plane wave does not exist.

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• 18.

### The unit of depth of penetration is

• A.

DB

• B.

M

• C.

Neper

• D.

B. M
Explanation
The unit of depth of penetration is meters (m). Depth of penetration refers to the distance that a wave can travel into a medium before its amplitude is significantly reduced. It is commonly used in fields such as electromagnetic wave propagation, where it determines how far a wave can penetrate into a material. The unit of meters is a measure of distance, which is appropriate for quantifying the depth of penetration.

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• 19.

### The polarization of horizontal dipole is

• A.

Vertical

• B.

Horizontal

• C.
• D.

Elliptical

B. Horizontal
Explanation
The correct answer is horizontal because a horizontal dipole refers to an antenna or element that is oriented horizontally. This means that the electric field is aligned in a horizontal direction, resulting in a horizontal polarization.

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• 20.

### The poynting vector has unit of

• A.

Watts/m3

• B.

Watts

• C.

Watts/m2

• D.

Volt-ampere

C. Watts/m2
Explanation
The Poynting vector represents the direction and magnitude of electromagnetic energy flow. It is defined as the cross product of the electric field vector and the magnetic field vector. The unit of the Poynting vector is watts per square meter (W/m2) because it represents the rate of energy transfer per unit area. This unit is commonly used to measure the intensity or power flux of electromagnetic radiation.

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• 21.

### Ground wave propagation is affected by

• A.

Weather condition

• B.

Rain

• C.

Temparature changes

• D.

Ground constant

D. Ground constant
Explanation
Ground wave propagation is affected by the ground constant. The ground constant refers to the electrical conductivity and dielectric constant of the ground. These properties determine how well the ground can conduct and propagate electromagnetic waves. A higher ground constant means better wave propagation, while a lower ground constant leads to more attenuation and signal loss. Therefore, the ground constant plays a crucial role in determining the quality and strength of ground wave propagation.

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• 22.

### The relative permitivity of the ionosphere is

• A.

More than 1

• B.

Equal to 1

• C.

Equal to infinity

• D.

Less than 1

D. Less than 1
Explanation
The relative permitivity of the ionosphere is less than 1 because it is a partially ionized region of the Earth's upper atmosphere. The ionosphere consists of charged particles, such as ions and free electrons, which cause the permitivity to be less than 1. This means that the ionosphere is less able to store electrical energy compared to a vacuum or other dielectric materials with a permitivity of 1 or greater.

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• 23.

### Troposcatter communication is used at

• A.

UHF and VHF

• B.

LF

• C.

HF

• D.

VLF

A. UHF and VHF
Explanation
Troposcatter communication is a method used to transmit signals by bouncing them off the Earth's troposphere. This technique is primarily employed at UHF (ultra-high frequency) and VHF (very high frequency) bands. These frequency ranges are suitable for troposcatter communication because they allow for efficient signal propagation and are less affected by atmospheric conditions. LF (low frequency) and VLF (very low frequency) bands are not commonly used for troposcatter communication due to their limited bandwidth and higher susceptibility to interference.

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• 24.

### If the direction of propagation of an electromagnetic wave is in z-direction,the polarization is in

• A.

Z-direction

• B.

Y-direction

• C.

X-direction

• D.

Circular polarization

C. X-direction
Explanation
An electromagnetic wave consists of electric and magnetic fields oscillating perpendicular to each other and to the direction of propagation. The polarization of an electromagnetic wave refers to the direction in which the electric field oscillates. In this case, since the direction of propagation is in the z-direction, the electric field would oscillate in the x-direction. Therefore, the correct answer is x-direction.

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• 25.

### Directivity is

• A.

Inversely proportional to beam width

• B.

Inversely proportional to square of beam width

• C.

Directy proportional to beam width

• D.

Directly proportional to square of beam width

A. Inversely proportional to beam width
Explanation
Directivity refers to the ability of an antenna or sensor to focus its radiation or reception in a specific direction. A narrower beam width indicates a more focused radiation pattern, meaning that the energy is concentrated in a smaller area. Therefore, directivity is inversely proportional to beam width. As the beam width decreases, the directivity increases, allowing for a more concentrated and focused signal.

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• 26.

### For an ideal antenna,the radiation resistance is

• A.

73 Ohm

• B.

36.5 Ohm

• C.

293 Ohm

• D.

Input impedence

D. Input impedence
Explanation
The correct answer is "input impedance." An ideal antenna is one that is perfectly efficient in radiating and receiving electromagnetic waves. The input impedance of an antenna refers to the impedance seen by the transmitter or receiver connected to it. It is a combination of the radiation resistance (the resistance that represents the power radiated by the antenna) and other reactive components like capacitance and inductance. Therefore, the input impedance is a comprehensive measure of how well the antenna can transfer power to or from the connected device.

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• 27.

### For a perfect conductor ,the power transmission co efficient is

• A.

1

• B.

0

• C.

Infinity

• D.

Reffection coefficient

B. 0
Explanation
The power transmission coefficient for a perfect conductor is 0. This means that no power is transmitted through the conductor, as it is a perfect conductor with zero resistance. This is because a perfect conductor allows for the flow of current without any loss of energy, resulting in no power being transmitted.

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• 28.

### A magnetic dipole is

• A.

A small circular loop

• B.

A piece of wire

• C.

A piece of conducting rod

• D.

The same as electric dipole

A. A small circular loop
Explanation
A magnetic dipole is a small circular loop because when an electric current flows through a loop of wire, it generates a magnetic field that resembles that of a magnetic dipole. The loop creates a magnetic field with a north and south pole, similar to a bar magnet. This magnetic dipole can interact with other magnetic fields and exhibit properties such as attraction and repulsion. Therefore, a small circular loop is a suitable representation of a magnetic dipole.

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• 29.

B.
• 30.

### The effective length of half wave dipole is

D.
Explanation
The effective length of a half-wave dipole refers to the physical length of the antenna that is equivalent to a half-wavelength at the frequency of operation. This length is important because it determines the radiation pattern and efficiency of the antenna. A half-wave dipole is typically considered to be the most efficient and widely used type of antenna, as it provides a balanced radiation pattern and good gain. The effective length is calculated by dividing the wavelength by 2.

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• 31.

### If the mouth diameter of a parabolic antenna is 2.5m and if it is operating at =0.25m, half power beam width is

A.
Explanation
The half power beam width of a parabolic antenna can be calculated using the formula: HPBW = 70 * (λ/D), where HPBW is the half power beam width, λ is the wavelength, and D is the mouth diameter of the antenna. In this case, the mouth diameter is given as 2.5m and the wavelength is given as 0.25m. Plugging these values into the formula, we get HPBW = 70 * (0.25/2.5) = 7 degrees. Therefore, the half power beam width is 7 degrees.

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• 32.

### The unit of attenuation is

• A.

DB/m

• B.

V/m

• C.

Amp/m

• D.

Coulomb/m

A. DB/m
Explanation
Attenuation refers to the reduction in intensity or amplitude of a signal as it travels through a medium. The unit of attenuation is usually expressed in decibels per meter (dB/m), which represents the decrease in signal strength per unit distance. dB/m is commonly used to measure the loss of signal strength in various applications, such as in telecommunications, fiber optics, and electrical transmission lines.

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• Current Version
• Mar 21, 2023
Quiz Edited by
ProProfs Editorial Team
• Mar 11, 2015
Quiz Created by
Srijitac

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