In a parallel plate capacitor, the capacitance is given by the formula C = (ε₀ * εᵣ * A) / d, where ε₀ is the vacuum permittivity, εᵣ is the relative permittivity, A is the area of the plates, and d is the distance between the plates. In this question, the relative permittivity is given as 6 and the distance between the plates is d. When the plates are separated by d, the electric field between them is 0.3 N. If the plates are separated by the same distance, the electric field between them would be (0.3 * 6) N, which is equal to 1.8 N. Therefore, the correct answer is 1.8 N.