Gibilisco:Chapter 4 - Basic DC Circuits

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Gibilisco:Chapter 4 - Basic DC Circuits

This is the MCQs for Gibilisco: CHAPTER 4 - BASIC DC CIRCUITS


Questions and Answers
  • 1. 
    Suppose you double the voltage in a simple dc circuit, and cut the resistance in half. The current will become: 
    • A. 

      Four times as great

    • B. 

      Twice as great

    • C. 

      The same as it was before

    • D. 

      Half as great

  • 2. 
    A wiring diagram would most likely be found in: 
    • A. 

      An engineer’s general circuit idea notebook

    • B. 

      An advertisement for an electrical device

    • C. 

      The service/repair manual for a radio receiver

    • D. 

      A procedural flowchart

  • 3. 
    Given a dc voltage source delivering 24 V and a circuit resistance of 3.3 KΩ, what is the current? 
    • A. 

      0.73 A

    • B. 

      138 A

    • C. 

      138 mA

    • D. 

      7.3 mA

  • 4. 
    Suppose that a circuit has 472 Ω of resistance and the current is 875 mA. Then the source voltage is: 
    • A. 

      413 V

    • B. 

      0.539 V

    • C. 

      1.85 V

    • D. 

      None of the above

  • 5. 
    The dc voltage in a circuit is 550 mV and the current is 7.2 mA. Then the resistance is: 
    • A. 

      0.76 Ω

    • B. 

      76 Ω

    • C. 

      0.0040 Ω

    • D. 

      None of the above

  • 6. 
    Given a dc voltage source of 3.5 kV and a circuit resistance of 220 Ω, what is the current? 
    • A. 

      16 mA

    • B. 

      6.3 mA

    • C. 

      6.3 A

    • D. 

      None of the above

  • 7. 
    A source delivers 12 V and the current is 777 mA. Then the best expression for the resistance is: 
    • A. 

      15 Ω

    • B. 

      15.4 Ω

    • C. 

      9.3 Ω

    • D. 

      9.32 Ω

  • 8. 
    A circuit has a total resistance of 473,332 Ω and draws 4.4 mA. The best expression for the voltage of the source is: 
    • A. 

      2082 V

    • B. 

      110 kV

    • C. 

      2.1 kV

    • D. 

      2.08266 kV

  • 9. 
    The voltage is 250 V and the current is 8.0 mA. The power dissipated by the potentiometer is: 
    • A. 

      31 mW

    • B. 

      31 W

    • C. 

      2.0 W

    • D. 

      2.0 mW

  • 10. 
    The voltage from the source is 12 V and the potentiometer is set for 470 Ω. The power is about: 
    • A. 

      310 mW

    • B. 

      25.5 mW

    • C. 

      39.2 W

    • D. 

      3.26 W

  • 11. 
    The current through the potentiometer is 17 mA and its value is 1.22KΩ. The power is: 
    • A. 

      0.24 μW

    • B. 

      20.7 W

    • C. 

      20.7 mW

    • D. 

      350 mW

  • 12. 
    Suppose six resistors are hooked up in series, and each of them has a value of 540 Ω. Then the total resistance is: 
    • A. 

      90 Ω

    • B. 

      3.24 KΩ

    • C. 

      540 Ω

    • D. 

      None of the above

  • 13. 
    Four resistors are connected in series, each with a value of 4.0 KΩ. The total resistance is: 
    • A. 

      1 KΩ

    • B. 

      4 KΩ

    • C. 

      8 KΩ

    • D. 

      16 KΩ

  • 14. 
    Suppose you have three resistors in parallel, each with a value of 68,000 Ω. Then the total resistance is: 
    • A. 

      23 Ω

    • B. 

      23 KΩ

    • C. 

      204 Ω

    • D. 

      0.2 MΩ

  • 15. 
    There are three resistors in parallel, with values of 22 Ω, 27Ω, and 33 Ω. A 12-V battery is connected across this combination, as shown in Fig. 4-11. What is the current drawn from the battery by this resistance combination? 
    • A. 

      1.3 A

    • B. 

      15 mA

    • C. 

      150 mA

    • D. 

      1.5 A

  • 16. 
    Three resistors, with values of 47 Ω, 68 Ω, and 82 Ω, are connected in series with a 50-V dc generator, as shown in Fig. 4-12. The total power consumed by this network of resistors is: 
    • A. 

      250 mW

    • B. 

      13 mW

    • C. 

      13 W

    • D. 

      Not determinable from the data given

  • 17. 
    You have an unlimited supply of 1-W, 100-Ω resistors. You need to get a 100- Ω, 10-W resistor. This can be done most cheaply by means of a series-parallel matrix of 
    • A. 

      3 X 3 resistors

    • B. 

      4 X 3 resistors

    • C. 

      4 X 4 resistors

    • D. 

      2 X 5 resistors

  • 18. 
    • A. 

      Four sets of two 1000-Ω resistors in series, and connecting these four sets in parallel

    • B. 

      Four sets of two 1000-Ω resistors in parallel, and connecting these four sets in series

    • C. 

      A 3 X 3 series-parallel matrix of 1000-Ω resistors

    • D. 

      Something other than any of the above

  • 19. 
    You have an unlimited supply of 1-W, 1000-Ω resistors, and you need to get a 3000-Ω, 5-W resistance. The best way is to: 
    • A. 

      Make a 2 X 2 series-parallel matrix

    • B. 

      Connect three of the resistors in parallel

    • C. 

      Make a 3 X 3 series-parallel matrix

    • D. 

      Do something other than any of the above

  • 20. 
    Good engineering practice usually requires that a series-parallel resistive network be made: 
    • A. 

      From resistors that are all very rugged

    • B. 

      From resistors that are all the same

    • C. 

      From a series combination of resistors in parallel

    • D. 

      From a parallel combination of resistors in series