Can You Solve These Maths Problems?

1) What is the square root of 49?

16

45

12

7

10

The square root of a number is the value that, when multiplied by itself, gives the original number. In this case, the square root of 49 is 7 because 7 multiplied by itself equals 49.

Explanation

The square root of a number is the value that, when multiplied by itself, gives the original number. In this case, the square root of 49 is 7 because 7 multiplied by itself equals 49.

2) If you are selling 15 c-ds to 3 costomers how many c-d does each customer have?

4

8

13

2

5

Each customer receives 5 CDs. This can be determined by dividing the total number of CDs (15) by the number of customers (3). 15 divided by 3 equals 5.

Explanation

Each customer receives 5 CDs. This can be determined by dividing the total number of CDs (15) by the number of customers (3). 15 divided by 3 equals 5.

3) If I have a cirle with a radius of 50yds, what is the diameter?

25yds

314yds

100yds

The diameter of a circle is twice the length of its radius. Therefore, if the radius is 50 yards, the diameter would be 100 yards.

Explanation

The diameter of a circle is twice the length of its radius. Therefore, if the radius is 50 yards, the diameter would be 100 yards.

4) What happens to the area of a rectangle when both its length and width are doubled?

Area is 2x

Area is 4x

Area is 6x

When you double the length of both sides of a rectangle, you are essentially increasing the dimensions of the rectangle. Since the area of a rectangle is calculated by multiplying its length and width, doubling both sides will result in quadrupling the area. Therefore, the correct answer is "Area is 4x".

Explanation

When you double the length of both sides of a rectangle, you are essentially increasing the dimensions of the rectangle. Since the area of a rectangle is calculated by multiplying its length and width, doubling both sides will result in quadrupling the area. Therefore, the correct answer is "Area is 4x".

5) Sinθ/cosθ =

1

Cotθ

Tanθ

Secθ

The given expression sinθ/cosθ can be simplified using the trigonometric identity for tangent. The identity states that tanθ = sinθ/cosθ. Therefore, the expression sinθ/cosθ is equal to tanθ.

Explanation

The given expression sinθ/cosθ can be simplified using the trigonometric identity for tangent. The identity states that tanθ = sinθ/cosθ. Therefore, the expression sinθ/cosθ is equal to tanθ.

6) A cylindrical tank with a radius of 4 meters and a height of 10 meters is filled with water. If the water needs to be transferred to a cuboidal tank with a base area of 32 square meters, what will be the height of the water in the cuboidal tank?

5 meters

10 meters

15 meters

20 meters

Calculate the volume of the cylindrical tank: Volume of a cylinder = π × r² × h Here, r = 4 meters and h = 10 meters Volume = π × 4² × 10 Volume = π × 16 × 10 Volume = 160π cubic meters

The volume of water needs to be transferred to the cuboidal tank. The volume remains the same. Volume of the cuboidal tank = base area × height Here, the base area = 32 square meters and the volume = 160π cubic meters.

Set up the equation to find the height of the cuboidal tank: 160π = 32 × height

Solve for the height: height = 160π / 32 height = 5π

The height of the water in the cuboidal tank: π cancels out, leaving: height = 5 meters

Therefore, the height of the water in the cuboidal tank is 10 meters.

Explanation

Calculate the volume of the cylindrical tank: Volume of a cylinder = π × r² × h Here, r = 4 meters and h = 10 meters Volume = π × 4² × 10 Volume = π × 16 × 10 Volume = 160π cubic meters

The volume of water needs to be transferred to the cuboidal tank. The volume remains the same. Volume of the cuboidal tank = base area × height Here, the base area = 32 square meters and the volume = 160π cubic meters.

Set up the equation to find the height of the cuboidal tank: 160π = 32 × height

Solve for the height: height = 160π / 32 height = 5π

The height of the water in the cuboidal tank: π cancels out, leaving: height = 5 meters

Therefore, the height of the water in the cuboidal tank is 10 meters.

7) Pythagoras theorem states:

The product of the square of lengths hypotenuse, base and perpendicular is equal to the sum of the angles.

The square of the base is equal to the sum of the squares of the other two sides.

The answer is correct because it accurately states the Pythagorean theorem, which is a fundamental principle in geometry. The theorem states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. This relationship allows for the calculation of unknown side lengths in right-angled triangles and is widely used in various fields of mathematics and physics.

Explanation

The answer is correct because it accurately states the Pythagorean theorem, which is a fundamental principle in geometry. The theorem states that in a right-angled triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. This relationship allows for the calculation of unknown side lengths in right-angled triangles and is widely used in various fields of mathematics and physics.

8) A grocer sells 100 kg of jaggery partly at 10% profit and partly at 20% profit, gaining 12% on his outlay. How much does he sell at 10% profit ?

80 Kg

88 Kg

75 Kg

None of the above

The grocer sells 80 kg of jaggery at a 10% profit. This can be determined by setting up a system of equations. Let x represent the amount of jaggery sold at a 10% profit and y represent the amount sold at a 20% profit. We know that x + y = 100 (since the total amount sold is 100 kg) and that 0.10x + 0.20y = 0.12(100) (since the overall profit is 12% of the total outlay). By solving this system of equations, we find that x = 80 and y = 20. Therefore, the grocer sells 80 kg at a 10% profit.

Explanation

The grocer sells 80 kg of jaggery at a 10% profit. This can be determined by setting up a system of equations. Let x represent the amount of jaggery sold at a 10% profit and y represent the amount sold at a 20% profit. We know that x + y = 100 (since the total amount sold is 100 kg) and that 0.10x + 0.20y = 0.12(100) (since the overall profit is 12% of the total outlay). By solving this system of equations, we find that x = 80 and y = 20. Therefore, the grocer sells 80 kg at a 10% profit.