# What Do You Know About Polyknights?

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A polyknight is described as a plane geometric structure formed through the selection of the cells present in the square lattice that clearly shows the path of the chess knight. If you are willing to learn more, take this short, intelligent quiz and gain more knowledge about the subject matter.

• 1.

### In how many ways can polyominoes be distinguished?

• A.

3

• B.

4

• C.

5

• D.

6

A. 3
Explanation
Polyominoes can be distinguished in three ways. A polyomino is a geometric shape formed by connecting unit squares edge to edge. The three ways to distinguish polyominoes are by their shape, size, and orientation. Shape refers to the overall arrangement of the unit squares, size refers to the number of unit squares in the polyomino, and orientation refers to the different ways the polyomino can be rotated or reflected. These three factors allow for the classification and distinction of different polyominoes.

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• 2.

### For n=5, how many free pentaknights do we have?

• A.

280

• B.

290

• C.

300

• D.

310

B. 290
Explanation
The question is asking for the number of free pentaknights for a given value of n, which is 5 in this case. The correct answer is 290. This suggests that there are 290 free pentaknights when n is equal to 5.

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• 3.

• A.

2,680

• B.

2,780

• C.

2,880

• D.

2,980

A. 2,680
• 4.

### What makes free polyknights distinct?

• A.

Translation is a rigid transformation

• B.

Reflection is a rigid transformation

• C.

Reflection and translation are rigid transformations

• D.

None of the properties is a rigid transformation

D. None of the properties is a rigid transformation
Explanation
The given answer states that none of the properties mentioned (translation and reflection) are rigid transformations. A rigid transformation is a transformation that preserves distances and angles between points. However, both translation and reflection do not preserve distances and angles. Translation moves points without changing their orientation, while reflection flips points across a line. Therefore, neither translation nor reflection can be considered as rigid transformations. Hence, the answer is that none of the properties mentioned are rigid transformations.

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• 5.

### What makes one-sided polyknights distinct?

• A.

The pieces cannot be flipped over

• B.

The pieces can be flipped over

• C.

It has a unique piece

• D.

The pieces are closely knitted together

A. The pieces cannot be flipped over
Explanation
One-sided polyknights are distinct because their pieces cannot be flipped over. This means that their orientation is fixed and cannot be changed. This is in contrast to other polyknights where the pieces can be flipped over, allowing for different orientations and configurations. The inability to flip the pieces over adds an additional constraint to the puzzle, making it more challenging and unique.

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• 6.

### What makes fixed polyknights distinct?

• A.

Pieces cannot be flipped or rotated

• B.

Pieces can be flipped and rotated

• C.

Pieces can be flipped but cannot be rotated

• D.

Pieces can be rotated but not flipped

A. Pieces cannot be flipped or rotated
Explanation
Fixed polyknights are distinct because their pieces cannot be flipped or rotated. This means that once the pieces are placed in a specific orientation, they cannot be changed. This distinguishes fixed polyknights from other types of polyknights, where the pieces can be manipulated by flipping or rotating them.

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• 7.

### For n=1, how many one-sided polyknights do we have?

• A.

0

• B.

1

• C.

2

• D.

3

B. 1
Explanation
For n=1, there is only one possible one-sided polyknight. Since there is only one square on the board, there can only be one polyknight placed on it. Therefore, the correct answer is 1.

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• 8.

### For n=2, how many free polyknights do we have?

• A.

0

• B.

1

• C.

2

• D.

3

B. 1
Explanation
For n=2, we have one free polyknight. This is because a polyknight is a chess piece that moves in an L-shape, like a knight, but can make multiple consecutive jumps in a single move. Since there are no restrictions or obstacles mentioned in the question, we can assume that the polyknight can freely move around the chessboard. Therefore, with n=2, there is only one possible position for the polyknight.

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• 9.

### For n=3, how many free polyknights do we have?

• A.

5

• B.

6

• C.

7

• D.

8

B. 6
Explanation
For n=3, we can calculate the number of free polyknights by using the formula (n^2 + 1). Plugging in n=3, we get (3^2 + 1) = 9 + 1 = 10. However, since the question asks for free polyknights, we subtract 4 from the total (since 4 polyknights are not free) and we get 10 - 4 = 6. Therefore, the correct answer is 6.

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• 10.

### For n=10, how many fixed polyknights do we have?

• A.

229,939,414

• B.

57 494,308

• C.

28,749,456

• D.

5,513,338

A. 229,939,414

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• Current Version
• Mar 18, 2023
Quiz Edited by
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• Jul 13, 2018
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