# Could You Pass Ecat Exam?

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| By Zlatan Aleksic
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Zlatan Aleksic
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Quizzes Created: 193 | Total Attempts: 1,048,552
Questions: 10 | Attempts: 165

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Engineering College Admission Test (ECAT) is conducted in Pakistan each year for Pre-Engineering students and is conducted by University of Engineering and Technologyin Punjab. Give it a go and try out this small test!

• 1.

### An incompressible fluid flows steadily through a cylindrical pipe, which has radius '2r' at point 'A' and radius 'r' at 'B' along the direction of the flow. If the velocity at point 'A' is 'v', its velocity at point 'B' is?

• A.

4V

• B.

2V

• C.

V

• D.

V/2

A. 4V
Explanation
The velocity of the fluid at point B is 4V. This can be explained by the principle of continuity, which states that the mass flow rate of an incompressible fluid remains constant along a flow path. Since the fluid is incompressible, the mass flow rate at point A is equal to the mass flow rate at point B. The mass flow rate is given by the product of the cross-sectional area and velocity of the fluid. As the radius at point B is half of the radius at point A, the cross-sectional area at point B is one-fourth of the cross-sectional area at point A. Therefore, to maintain a constant mass flow rate, the velocity at point B must be four times the velocity at point A, which is 4V.

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• 2.

### A hydraulic automobile lift is designed to lift cars with a maximum mass of 3000 kg. The area of cross-section of the piston carrying the load is 425 cm2. What maximum pressure would the smaller piston have to bear? (Given, g = 9.8 ms-2).

• A.

69.2 Nm-2

• B.

6.92 x 105 Nm-2

• C.

3.46 x 105 Nm-2

• D.

6.92 x 106 Nm-2

A. 69.2 Nm-2
Explanation
The maximum pressure that the smaller piston would have to bear can be calculated using the formula P = F/A, where P is the pressure, F is the force, and A is the area. In this case, the force is equal to the weight of the car, which can be calculated as mass multiplied by acceleration due to gravity (F = mg). The area is given as 425 cm2, which needs to be converted to m2 by dividing by 10000. Plugging in the values, we get P = (3000 kg)(9.8 m/s2) / (425 cm2 / 10000) = 69.2 N/m2.

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• 3.

### For a sphere moving in a viscuous medium, if the speed is increased by 10 times the drag force?

• A.

Increases by 5 times

• B.

Increases by 10 times

• C.

• D.

Remains same

C. Cannot answer with given information
• 4.

### Which of the following is the most accurate definition of a solution?

• A.

A homogeneous mixture of two or more kinds of same substances

• B.

A mixture of two or more kinds of different substances

• C.

A heterogeneous mixture of two or more kinds of different substances

• D.

A homogeneous mixture of two or more kinds of different substances

D. A homogeneous mixture of two or more kinds of different substances
Explanation
A solution is a homogeneous mixture, meaning that it is uniform throughout and has the same composition in all its parts. It is made up of two or more kinds of different substances that are evenly distributed at a molecular level. This means that the particles of the substances are mixed together on a microscopic level and cannot be easily separated.

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• 5.

### Concentration in terms of percentage weight/weight is given by?

• A.

Weight of the solute dissolved per one kg of the solution

• B.

Weight of the solute dissolved per 100 g of the solution

• C.

Weight of the solute dissolved per 1000 parts by weight of the solution

• D.

Weight of the solute dissolved per 100 parts by weight of the solution

D. Weight of the solute dissolved per 100 parts by weight of the solution
Explanation
Concentration in terms of percentage weight/weight is given by the weight of the solute dissolved per 100 parts by weight of the solution. This means that the concentration is expressed as a percentage of the weight of the solute relative to the weight of the entire solution. It is a common method to express concentration in chemistry and is useful for comparing the relative amounts of solute in different solutions.

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• 6.

### The vapour pressure of a dilute solution of a solute is not influenced by?

• A.

Melting point of the solute

• B.

Degree of dissociation of the solute

• C.

Mole fraction of the solute

• D.

Temperature of the solution

A. Melting point of the solute
Explanation
The vapour pressure of a dilute solution is determined by the concentration of the solute in the solution, temperature, and the nature of the solvent. The melting point of the solute does not affect the vapour pressure of the solution because the vapour pressure is related to the concentration of the solute particles in the solution, not their physical state. The melting point only indicates the temperature at which the solute transitions from a solid to a liquid state, but it does not directly influence the vapour pressure.

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• 7.

### Set of natural numbers is closed with respect to? Addition Multiplication Subtraction

• A.

I, II and III

• B.

II only

• C.

I and II only

• D.

I only

C. I and II only
Explanation
The set of natural numbers is closed with respect to addition because when you add two natural numbers, the result is always a natural number. Similarly, the set of natural numbers is closed with respect to multiplication because when you multiply two natural numbers, the result is always a natural number. However, the set of natural numbers is not closed with respect to subtraction because when you subtract two natural numbers, the result may not always be a natural number.

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• 8.

### X + 2 is a factor of?

• A.

X4 + 2

• B.

X4 – X2 + 12

• C.

X4 – 2X3 – X + 2

• D.

X4 + 2X3 – X – 2

D. X4 + 2X3 – X – 2
Explanation
The expression X + 2 is a factor of X4 + 2X3 – X – 2 because when X + 2 is divided into X4 + 2X3 – X – 2, the remainder is zero. This means that X + 2 evenly divides into X4 + 2X3 – X – 2 without leaving any remainder.

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• 9.

### A 4 g sugar cube (Sucrose: C12H22O11) is dissolved in 0.5 kg of water. What is the molality of the sugar solution?

• A.

0.023 mol/kg

• B.

0.117 mol/kg

• C.

0.21 mol/kg

• D.

1.2 mol/kg

A. 0.023 mol/kg
Explanation
The molality of a solution is calculated by dividing the moles of solute by the mass of the solvent in kilograms. In this case, we need to find the moles of sugar (sucrose) and the mass of water. The molar mass of sucrose (C12H22O11) is 342.3 g/mol. The moles of sugar can be calculated by dividing the mass of the sugar cube (4 g) by the molar mass of sucrose. The mass of water is given as 0.5 kg. Dividing the moles of sugar by the mass of water gives us the molality of the sugar solution, which is 0.023 mol/kg.

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• 10.

### Which of the following is a definition of Rault's law?

• A.

Increase of vapour pressure is directly proportional to the mole fraction of solvent

• B.

Lowering of vapour pressure is directly proportional to the mole fraction of solute

• C.

Increase of vapour pressure is directly proportional to the mole fraction of solute

• D.

Lowering of vapour pressure is directly proportional to the mole fraction of solvent

A. Increase of vapour pressure is directly proportional to the mole fraction of solvent
Explanation
Rault's law states that the vapor pressure of a solvent above a solution is directly proportional to the mole fraction of the solvent in the solution. This means that as the mole fraction of the solvent increases, the vapor pressure of the solution also increases.

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• Current Version
• Mar 21, 2023
Quiz Edited by
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• Jan 18, 2018
Quiz Created by
Zlatan Aleksic

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