Taylor Polynomials: Local Linear & Quadratic Approximations

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| Questions: 9 | Updated: Dec 15, 2025
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1) The Taylor series for a function f centered at x = a is a power series of the form ∑ [f⁽ⁿ⁾(a)/n!] (x - a)ⁿ from n=0 to infinity. What is the coefficient of the term with (x - a)³?

Explanation

The general term in a Taylor series centered at x = a is [f⁽ⁿ⁾(a)/n!] (x - a)ⁿ where n! means n factorial. For the term containing (x - a)³, the exponent n = 3, so the coefficient is f^(3)(a)/3!. Since 3! = 6, this is the same as f'''(a)/6, but the standard form uses 3! in the denominator.

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About This Quiz
Taylor Polynomials: Local Linear & Quadratic Approximations - Quiz

Taylor series allow us to express functions as infinite polynomials built from their derivatives, offering a powerful window into how functions behave near a chosen point. In this quiz, you’ll explore how individual coefficients arise from successive derivatives, how to construct Taylor polynomials of various degrees, and how these polynomials... see moreapproximate functions like exe^xex, ln⁡xln xlnx, and sin⁡xsin xsinx. You’ll practice identifying correct Taylor expansions, computing centered polynomials, and understanding why higher-degree terms greatly improve accuracy. You’ll also deepen your intuition about how Taylor polynomials relate to the full Taylor series and why approximations are most reliable near the center point. Whether you’re evaluating functions, estimating values, or analyzing error behavior, this quiz will strengthen your command of Taylor expansions from the ground up. see less

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2) What is the Taylor series for eˣ centered at x = 0?

Explanation

For eˣ, all derivatives are eˣ, and at x = 0 they equal 1. The coefficient of xⁿ is f⁽ⁿ⁾(0)/n! = 1/n!, so the series is 1 + x + x²/2! + x³/3! + ... which is written as ∑ xⁿ / n! from n=0 to ∞.

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3) What is the third-degree Taylor polynomial for f(x) = ln(x) centered at x = 1?

Explanation

For ln(x) centered at a=1: f(1)=0, f'(x)=1/x so f'(1)=1, f''(x)=-1/x² so f''(1)=-1, f'''(x)=2/x³ so f'''(1)=2, f^(4)(x)=-6/x⁴ so f^(4)(1)=-6. Coefficients: f(1)/0! = 0, f'(1)/1! = 1, f''(1)/2! = -1/2, f'''(1)/3! = 2/6 = 1/3. So T3(x) = (x-1) - (x-1)²/2 + (x-1)³/3.

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4) What is the Taylor polynomial of degree 2 for f(x) = sin(x) centered at x = π/4?

Explanation

T2(x) = f(a) + f'(a)(x-a) + f''(a)/2!(x-a)². Here a = π/4, f(π/4) = √2/2, f'(x) = cos(x) so f'(π/4) = √2/2, f''(x) = -sin(x) so f''(π/4) = -√2/2. Thus T2(x) = √2/2 + (√2/2)(x - π/4) + (-√2/2)/2 (x - π/4)² = √2/2 + (√2/2)(x - π/4) - (√2/4)(x - π/4)².

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5) What is the first term (n=0) in any Taylor series centered at x = a?

Explanation

The n=0 term is f^(0)(a)/0! (x-a)⁰= f(a)/1 * 1 = f(a). This is true for any function and any center a.

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6) Why do higher-degree Taylor polynomials generally give better approximations near the center point?

Explanation

A degree-n Taylor polynomial matches the function and its first n derivatives at the center point x = a. The more derivatives that match, the closer the graph of the polynomial stays to the graph of the original function near that point.

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7) What is the relationship between a Taylor polynomial and a Taylor series?

Explanation

A Taylor series is an infinite series representation of a function. A Taylor polynomial is obtained by truncating this infinite series after a finite number of terms. If we take the first n+1 terms of a Taylor series, we get the nth degree Taylor polynomial. In other words, a Taylor polynomial is exactly a partial sum of the infinite Taylor series. Option B reverses the relationship. Option C is false as they are directly related. Option D is incorrect because the limit of partial sums gives the infinite series itself, not just a polynomial.

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8) Using T3(x) (third-degree Taylor polynomial) for eˣ centered at 0 to approximate e^1, what do we get?

Explanation

T3(x) = 1 + x + x²/2 + x³/6. At x=1: 1 + 1 + 1/2 + 1/6 = 1 + 1 + 0.5 + 0.1667 ≈ 2.6667.

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9) When using a Taylor polynomial to approximate a function value, the error is usually smallest:

Explanation

Taylor polynomials are designed to match the function and its derivatives at the center. The farther you move away from the center, the more the higher derivatives cause the curves to diverge, so the approximation is best close to the center.

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The Taylor series for a function f centered at x = a is a power series...
What is the Taylor series for eˣ centered at x = 0?
What is the third-degree Taylor polynomial for f(x) = ln(x) centered...
What is the Taylor polynomial of degree 2 for f(x) = sin(x) centered...
What is the first term (n=0) in any Taylor series centered at x = a?
Why do higher-degree Taylor polynomials generally give better...
What is the relationship between a Taylor polynomial and a Taylor...
Using T3(x) (third-degree Taylor polynomial) for eˣ centered at 0 to...
When using a Taylor polynomial to approximate a function value, the...
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