Radial Distance Variation Quiz: Modeling Radial Distance Variations

  • Grade 11th
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| Questions: 20 | Updated: May 15, 2026
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1) For r(t) = 9000 + 30×sin(0.05t), what is the period?

Explanation

T = 2π/ω = 2π/0.05 = 40π seconds ≈ 125.66 seconds. Option A gives π/0.05 = 20π which incorrectly uses π instead of 2π in the numerator. Option B gives 20π corresponding to ω = 0.1. Option C gives 10π corresponding to ω = 0.2. Only 40π correctly applies T = 2π/0.05.

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About This Quiz
Radial Distance Variation Quiz: Modeling Radial Distance Variations - Quiz

How does radial distance change when an object moves along a curved path? In this quiz, you’ll explore functions that describe how the distance from a center point varies over time or angle. You’ll practice interpreting graphs, analyzing increasing and decreasing intervals, and connecting each pattern to orbital or rotational... see morebehavior. By examining how radius changes dynamically, you’ll gain insight into real-world systems—like satellites or spinning objects—where motion depends on shifting distances.
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2) If A = 0 in r(t) = R0 + A×cos(ωt), the radial distance is constant and equals R0.

Explanation

The answer is True. With A = 0 the sinusoidal term vanishes and r(t) = R0 for all t. The radial distance no longer varies with time and the orbit becomes a perfect circle of constant radius R0. This represents the special case where there is no wobble and the satellite maintains a fixed distance from the central body at all times.

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3) Select all modifications that leave the period unchanged in r(t) = R0 + A×cos(ωt + φ).

Explanation

T = 2π/ω depends only on ω. Increasing R0 shifts the central radius without touching ω, so T is unchanged, confirming A. Changing phase φ only shifts the oscillation horizontally in time without affecting ω or T, confirming C. Doubling A increases wobble size but leaves ω and therefore T completely unchanged, confirming D. Option B directly reduces ω which increases T = 2π/ω, so the period is not preserved.

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4) For r(t) = 8000 + 20×cos(0.4t), compute r(5).

Explanation

Angle = 0.4×5 = 2 radians. cos(2) ≈ -0.41615. r = 8000 + 20×(-0.41615) = 8000 - 8.323 ≈ 7991.677. Option B gives 7980 = 8000 - 20, requiring cos(2) = -1. Option C gives 8020 = 8000 + 20, requiring cos(2) = 1. Option D gives 8008.32, requiring cos(2) ≈ +0.416, the wrong sign.

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5) For r(t) = R0 + A×cos(ωt + φ), what is the radial distance at t = 0?

Explanation

Substituting t = 0 gives r(0) = R0 + A×cos(φ). Option B replaces cos(φ) with ω, mixing angular frequency into the amplitude term incorrectly. Option C replaces A with ω, using the wrong coefficient. Option D negates the cosine term without justification. Only option A correctly evaluates the function at t = 0.

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6) For r(t) = 7500 + 40×cos(0.2t - π/3), what is the phase φ?

Explanation

In r(t) = R0 + A×cos(ωt + φ), the phase φ is the constant added to ωt inside the cosine. Here the argument is 0.2t - π/3, so φ = -π/3. Option B gives +π/3, the wrong sign. Option C gives ω = 0.2, the angular frequency. Option D gives A = 40, the amplitude.

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7) Replacing cos(ωt) by cos(ωt + φ) changes the average radius over time.

Explanation

The answer is False. Adding a phase φ shifts the oscillation horizontally in time but does not change its mean value. Cosine still oscillates symmetrically between -1 and +1 regardless of phase, so its average over a full period remains 0. The average of r(t) therefore stays at R0 whether or not a phase term is present.

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8) Select all true statements for near-circular motion r(t) = R0 + A×cos(ωt + φ) with A much less than R0.

Explanation

Maximum occurs when cosine = 1 giving R0 + A, confirming A. Minimum occurs when cosine = -1 giving R0 - A, confirming B. T = 2π/ω depends only on ω and is completely independent of R0 and A, confirming C. Option D is false — percent wobble = 100×A/R0, meaning amplitude divided by central radius. Option D inverts this ratio giving 100×R0/A which produces a very large number, not a small percentage.

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9) For r(t) = R0 + A×cos(ωt), what does the average of r over one full period equal?

Explanation

Over one full period the integral of cos(ωt) averages to 0. Therefore the average of r(t) = R0 + A×cos(ωt) equals R0 + A×0 = R0. Option A gives just the amplitude. Option B gives the maximum value, not the average. Option C gives 0, ignoring R0 entirely. Only R0 correctly represents the time-averaged central radius.

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10) For r(t) = 7000 + 50×cos(0.1t), when does the first minimum occur for t > 0?

Explanation

Minimum occurs when cos(0.1t) = -1, meaning 0.1t = π, giving t = π/0.1 = 10π seconds. Option B gives 5π, where 0.1×5π = π/2, giving cos(π/2) = 0, not the minimum. Option C gives π, where 0.1×π = π/10, also not the minimum. Option D gives 20π, the full period, which is the second minimum occurrence.

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11) For r(t) = 7000 + 50mcos(0.1t), what is the average central orbit radius?

Explanation

In r(t) = R0 + A×cos(ωt + φ), the average over a full cycle equals R0 because the mean of cosine over any whole number of periods is 0. Here R0 = 7000. Option B gives the amplitude A = 50. Option C gives the angular frequency ω = 0.1. Option D gives half the central radius, which has no geometric meaning here.

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12) For r(t) = 9000 + 30×sin(0.05t), what is the wobble amplitude?

Explanation

The amplitude equals the coefficient of the sinusoidal term regardless of whether sine or cosine is used. Here A = 30. Option B gives R0 = 9000, the central radius. Option C gives ω = 0.05, the angular frequency. Option D gives R0 + A = 9030, the maximum distance, not the amplitude.

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13) Select all changes that alter the average central radius in r(t) = R0 + A×cos(ωt + φ).

Explanation

The cycle average of r(t) equals R0 because the mean of cosine over a full period is 0. Directly increasing R0 raises the average, confirming A. Adding a constant +c shifts the average to R0 + c, confirming D. Changing A only affects wobble size. Changing ω only affects period. Changing φ only shifts the oscillation horizontally. None of B or C affect the average.

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14) In r(t) = R0 + A×cos(ωt + φ), the amplitude A measures the wobble size around the average radius.

Explanation

The answer is True. The sinusoidal term A×cos(ωt + φ) oscillates between -A and +A. Adding R0 shifts this range to between R0 - A and R0 + A. The radial distance therefore varies by exactly ±A from the central value R0. A larger amplitude means greater wobble while A = 0 produces a perfectly circular orbit with constant radius R0.

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15) For r(t) = 7000 + 50×cos(0.2t + π), what is the first t ≥ 0 when r(t) is maximum?

Explanation

Maximum occurs when cos(0.2t + π) = 1, meaning 0.2t + π = 2πk. The smallest nonneg solution uses k = 1: 0.2t = π, so t = 5π. Option B gives 10π corresponding to k = 2. At option C t = π the argument = 0.2π + π = 1.2π and cos(1.2π) ≠ 1. Option D gives 2.5π which does not satisfy the equation.

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16) For r(t) = 7000 + 50×cos(0.1t), what is the minimum radial distance?

Explanation

Minimum occurs when cos(0.1t) = -1, giving r_min = R0 - A = 7000 - 50 = 6950. Option B gives R0 = 7000, the average radius. Option C gives R0 + A = 7050, the maximum distance. Option D gives R0 - 2A = 6900, subtracting the amplitude twice incorrectly.

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17) For r(t) = 7000 + 50×cos(0.1t), what is the maximum radial distance?

Explanation

Maximum occurs when cos(0.1t) = 1, giving r_max = R0 + A = 7000 + 50 = 7050. Option A gives R0, the average radius. Option B gives R0 - A = 6950, the minimum distance. Option D gives R0 + 2A = 7100, adding the amplitude twice incorrectly.

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18) For r(t) = 7000 + 50×cos(0.1t), what is the period T?

Explanation

T = 2π/ω = 2π/0.1 = 20π seconds ≈ 62.83 seconds. Option B gives 2π which requires ω = 1, not 0.1. Option C gives 10π which requires ω = 0.2. Option D gives π which requires ω = 2. Only 20π correctly applies the period formula with ω = 0.1.

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19) For r(t) = 7000 + 50×cos(0.1t), what is the angular frequency ω in rad/s?

Explanation

The angular frequency ω is the coefficient of t inside the cosine. Here the argument is 0.1t, so ω = 0.1 rad/s. Option B inverts the value giving 1/ω = 10. Option C gives 2π, which is the factor used in the period formula but is not ω here. Option D gives ω squared = 0.01.

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20) For r(t) = 7000 + 50×cos(0.1t), what is the wobble amplitude?

Explanation

The amplitude is the coefficient of the sinusoidal term, A = 50. It sets the maximum deviation from the average radius R0. Option A gives R0 = 7000, the central radius. Option B gives ω = 0.1, the angular frequency. Option D gives R0 + A = 7050, the maximum radial distance, not the amplitude itself.

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For r(t) = 9000 + 30×sin(0.05t), what is the period?
If A = 0 in r(t) = R0 + A×cos(ωt), the radial distance is constant...
Select all modifications that leave the period unchanged in r(t) = R0...
For r(t) = 8000 + 20×cos(0.4t), compute r(5).
For r(t) = R0 + A×cos(ωt + φ), what is the radial distance at t =...
For r(t) = 7500 + 40×cos(0.2t - π/3), what is the phase φ?
Replacing cos(ωt) by cos(ωt + φ) changes the average radius over...
Select all true statements for near-circular motion r(t) = R0 +...
For r(t) = R0 + A×cos(ωt), what does the average of r over one full...
For r(t) = 7000 + 50×cos(0.1t), when does the first minimum occur for...
For r(t) = 7000 + 50mcos(0.1t), what is the average central orbit...
For r(t) = 9000 + 30×sin(0.05t), what is the wobble amplitude?
Select all changes that alter the average central radius in r(t) = R0...
In r(t) = R0 + A×cos(ωt + φ), the amplitude A measures the wobble...
For r(t) = 7000 + 50×cos(0.2t + π), what is the first t ≥ 0 when...
For r(t) = 7000 + 50×cos(0.1t), what is the minimum radial distance?
For r(t) = 7000 + 50×cos(0.1t), what is the maximum radial distance?
For r(t) = 7000 + 50×cos(0.1t), what is the period T?
For r(t) = 7000 + 50×cos(0.1t), what is the angular frequency ω in...
For r(t) = 7000 + 50×cos(0.1t), what is the wobble amplitude?
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