Binding Energy Per Nucleon Quiz: Explore Nuclear Energy Trends

  • Grade 11th
Reviewed by Ekaterina Yukhnovich
Ekaterina Yukhnovich, PhD |
Science Expert
Review Board Member
Ekaterina V. is a physicist and mathematics expert with a PhD in Physics and Mathematics and extensive experience working with advanced secondary and undergraduate-level content. She specializes in combinatorics, applied mathematics, and scientific writing, with a strong focus on accuracy and academic rigor.
, PhD
By Thames
T
Thames
Community Contributor
Quizzes Created: 11119 | Total Attempts: 9,762,531
| Questions: 20 | Updated: Mar 9, 2026
Please wait...
Question 1 / 21
🏆 Rank #--
0 %
0/100
Score 0/100

1. Coulomb repulsion increases as the number of ______ increases.

Explanation

Concept: repulsion depends on charge. More protons → more repulsion. Increasing the number of positively charged particles increases the electric repulsive effect.

Submit
Please wait...
About This Quiz
Binding Energy Per Nucleon Quiz: Explore Nuclear Energy Trends - Quiz

This quiz features 20 questions on binding energy per nucleon, focusing on key concepts in nuclear energy trends. You will explore topics such as nuclear stability, fission, and fusion, which are vital for understanding how energy is released in nuclear reactions. Students in Grade 11 will find this quiz helpful... see morefor grasping the importance of binding energy in the context of real-world applications and scientific principles. By completing it, you will sharpen your knowledge and enhance your confidence in discussing nuclear energy topics.
see less

2.

What first name or nickname would you like us to use?

You may optionally provide this to label your report, leaderboard, or certificate.

2. Grade 11 takeaway: be/a is a handy number because it summarizes:

Explanation

Concept: summary meaning. It's a compact stability indicator. By condensing binding information into one average number, it helps predict stability and energy trends.

Submit

3. You can use be/a to compare stability without knowing every detail of nuclear structure.

Explanation

Concept: be/a as a broad metric. It's a broad, useful metric. While it doesn't replace detailed models, it provides a quick way to compare overall stability trends.

Submit

4. Be/a is best described as:

Explanation

Concept: definition. It's an average binding measure. be/a tells how strongly each nucleon is bound on average within the nucleus.

Submit

5. A nucleus with low be/a is more likely to:

Explanation

Concept: low be/a and stability. Lower average binding suggests less stability. Such nuclei can be more likely to undergo decay or reactions if conditions allow.

Submit

6. If be stays the same but A increases, be/a decreases.

Explanation

Concept: average behavior. Same total divided by bigger number gives smaller average. Increasing A without increasing be spreads the same binding energy over more nucleons.

Submit

7. Which statements are correct?

Explanation

Concept: be/a meaning and units. A, B, D are correct; C is incorrect. Higher be/a means nucleons are more tightly bound, so separation is harder, not easier.

Submit

8. "Energy released" in a reaction usually appears as:

Explanation

Concept: forms of nuclear energy release. Nuclear energy becomes motion and radiation. Reaction products often carry kinetic energy, and radiation like gamma rays can also carry away energy.

Submit

9. Be/a is always highest for the heaviest nuclei.

Explanation

Concept: be/a trend. It peaks at medium nuclei and decreases for very heavy ones. Very heavy nuclei have increased coulomb repulsion, which lowers average binding.

Submit

10. If be = 560 MeV and A = 70, be/a is closest to:

Explanation

Concept: simple be/a computation. 560/70 = 8 MeV per nucleon. This is a straightforward division to find the average binding per particle.

Submit

11. Binding energy per nucleon is given by:

Explanation

Concept: be/a definition. Divide total binding energy (be) by nucleon count (a). This gives the average binding energy per nucleon, which is useful for comparing different nuclei.

Submit

12. For very heavy nuclei, be/a tends to decrease mainly because:

Explanation

Concept: why be/a falls for very heavy nuclei. Proton repulsion matters more at large Z. As nuclei get heavier, the coulomb repulsion becomes a larger 'penalty,' reducing the average binding per nucleon.

Submit

13. The strong force is attractive at the typical distances between nucleons.

Explanation

Concept: strong-force attraction. It binds nucleons together. At nuclear distances, the strong force provides the attractive interaction that creates binding energy.

Submit

14. A nucleus with be/a of 8.5 MeV is generally more tightly bound than one with:

Explanation

Concept: comparing be/a values. Higher be/a means tighter binding. Since 7.2 MeV is lower than 8.5 MeV, that nucleus is less tightly bound on average.

Submit

15. If be per nucleon increases after a nuclear change, the change is likely to:

Explanation

Concept: energy direction from be/a. More tightly bound products correspond to lower energy. If the final nucleus (or nuclei) is more tightly bound per nucleon, the difference often appears as released energy.

Submit

16. Binding energy per nucleon allows comparison across different sizes of nuclei.

Explanation

Concept: normalization. It normalizes by nucleon count. That makes it a fair 'per-particle' measure rather than a total that naturally grows with size.

Submit

17. If two nuclei have the same A but one has higher be, the one with higher be is usually:

Explanation

Concept: comparing equal-size nuclei. More binding (same size) usually means more stability. With the same nucleon count, the nucleus with higher total binding energy is held together more strongly.

Submit

18. If total binding energy is be and nucleon number is a, then be per nucleon = ______.

Explanation

Concept: formula recall. That is the definition. It is the standard way to 'normalize' binding energy so nuclei of different sizes can be compared.

Submit

19. If a nucleus has total binding energy 160 MeV and A = 20, the binding energy per nucleon is:

Explanation

Concept: simple be/a computation. 160/20 = 8 MeV per nucleon. You divide the total binding energy by the number of nucleons to get the average.

Submit

20. In nuclear physics, binding energy is often expressed in MeV (mega-electronvolts).

Explanation

Concept: units in nuclear physics. MeV is a common nuclear energy unit. Nuclear energies are much larger than chemical energies, so MeV is a convenient scale.

Submit
×
Saved
Thank you for your feedback!
View My Results
Ekaterina Yukhnovich |PhD |
Science Expert
Ekaterina V. is a physicist and mathematics expert with a PhD in Physics and Mathematics and extensive experience working with advanced secondary and undergraduate-level content. She specializes in combinatorics, applied mathematics, and scientific writing, with a strong focus on accuracy and academic rigor.
Cancel
  • All
    All (20)
  • Unanswered
    Unanswered ()
  • Answered
    Answered ()
Coulomb repulsion increases as the number of ______ increases.
Grade 11 takeaway: be/a is a handy number because it summarizes:
You can use be/a to compare stability without knowing every detail of...
Be/a is best described as:
A nucleus with low be/a is more likely to:
If be stays the same but A increases, be/a decreases.
Which statements are correct?
"Energy released" in a reaction usually appears as:
Be/a is always highest for the heaviest nuclei.
If be = 560 MeV and A = 70, be/a is closest to:
Binding energy per nucleon is given by:
For very heavy nuclei, be/a tends to decrease mainly because:
The strong force is attractive at the typical distances between...
A nucleus with be/a of 8.5 MeV is generally more tightly bound than...
If be per nucleon increases after a nuclear change, the change is...
Binding energy per nucleon allows comparison across different sizes of...
If two nuclei have the same A but one has higher be, the one with...
If total binding energy is be and nucleon number is a, then be per...
If a nucleus has total binding energy 160 MeV and A = 20, the binding...
In nuclear physics, binding energy is often expressed in MeV...
play-Mute sad happy unanswered_answer up-hover down-hover success oval cancel Check box square blue
Alert!