Advanced One-Sided Limits with Rational, Trig, and Log Functions

Reviewed by Editorial Team
The ProProfs editorial team is comprised of experienced subject matter experts. They've collectively created over 10,000 quizzes and lessons, serving over 100 million users. Our team includes in-house content moderators and subject matter experts, as well as a global network of rigorously trained contributors. All adhere to our comprehensive editorial guidelines, ensuring the delivery of high-quality content.
Learn about Our Editorial Process
| By Thames
T
Thames
Community Contributor
Quizzes Created: 7682 | Total Attempts: 9,547,133
| Questions: 15 | Updated: Dec 17, 2025
Please wait...
Question 1 / 15
0 %
0/100
Score 0/100
1) Evaluate the one-sided limit: limx→2+ (x - 2)/|x - 2|.

Explanation

For x approaching 2 from the right, we have x > 2. So x - 2 is positive. Thus, |x - 2| =x - 2. Substitute: (x - 2)/|x - 2| = (x - 2)/(x - 2) = 1 for all x > 2. As x approaches 2 from the right the expression stays 1, so the right-hand limit equals 1.

Submit
Please wait...
About This Quiz
Advanced One-sided Limits With Rational, Trig, And Log Functions - Quiz

Can you handle one-sided limits when functions get more advanced? This quiz takes you into rational expressions, trigonometric limits, and logarithms near key points. You’ll simplify expressions like (x² − 9)/(x − 3), analyze sin(x)/x as x → 0, and study ln(x) as x approaches 0 from the right. You’ll... see morealso interpret infinite limits and piecewise-defined functions using one-sided limits. It’s a solid step toward the limit techniques you’ll rely on in a first calculus course.
see less

2)
You may optionally provide this to label your report, leaderboard, or certificate.
2) Evaluate limx→0⁺ 1/x.

Explanation

For x approaching 0 from the right, x is positive and very small. The reciprocal 1/x becomes a very large positive number. There is no finite limit; the expression grows without bound toward positive infinity. Therefore the right-hand limit is +∞.

Submit
3) Evaluate lim as x→3⁺ of (x² - 9)/(x - 3).

Explanation

For x ≠ 3, factor numerator: x² - 9 = (x - 3)(x + 3). For x near 3 but greater than 3, cancel (x - 3) to get x + 3. The expression equals x + 3 for x ≠ 3. Taking the right-hand limit as x→3⁺ gives 3 + 3 = 6. So the one-sided limit from the right is 6.

Submit
4) Determine limx→0- sin(x)/x.

Explanation

The function f(x) = sin(x)/x is an even function, meaning f(-x) = f(x). Since the standard limit as x→0 is 1, the limit as x approaches 0 from the left is also 1. Alternatively, using the small angle approximation for x near 0, sin(x) ≈ x, so the ratio approaches 1.

Submit
5) Evaluate lim as x→1^- of (|x - 1|)/(x - 1).

Explanation

For x

Submit
6) Consider f(x) = (x - 4)/(x² - 16). Evaluate limx→4⁺ f(x).

Explanation

Factor the denominator: x² - 16 = (x - 4)(x + 4). The expression becomes (x - 4)/[(x - 4)(x + 4)]. For x ≠ 4, we can cancel the (x - 4) terms, simplifying the function to 1/(x + 4). As x approaches 4 from the right, the denominator approaches 4 + 4 = 8. Thus, the limit is 1/8.

Submit
7) Evaluate lim as x→0⁺ of ln(x).

Explanation

For x positive and approaching 0, ln(x) becomes large in magnitude and negative because the logarithm of a number less than 1 is negative and tends to negative infinity as the argument approaches 0+. Therefore the right-hand limit is -∞.

Submit
8) Given the graph of a function that has y = 2 for x < 0, a hole at (0, 2), and y = -1 for x > 0, determine limx→0- f(x) and limx→0⁺ f(x). Choose the correct pair.

Explanation

The graph shows constant value y = 2 for x values less than 0, so approaching 0 from the left the function values approach 2. For x > 0 the graph shows y = -1, so approaching 0 from the right the values approach -1. Therefore the left-hand limit is 2 and the right-hand limit is -1.

Submit
9) Evaluate lim as x→2^- of (x² - 4)/(x - 2).

Explanation

Factor numerator: x² - 4 = (x - 2)(x + 2). For x ≠ 2, the expression simplifies to x + 2. Approaching 2 from the left gives 2 + 2 = 4. The one-sided approach does not change the simplified value, so the left-hand limit equals 4.

Submit
10) Evaluate lim as x→1⁺ of (x - 1)/(x - 1)².

Explanation

Simplify the expression: (x - 1)/(x - 1)² = 1/(x - 1) for x ≠ 1. For x approaching 1 from the right, x - 1 is a small positive number, so 1/(x - 1) is a large positive number. Therefore the right-hand limit is +∞.

Submit
11) Evaluate lim as x→0^- of (x)/(√(x²)).

Explanation

For x ≠ 0, √(x²) = |x|. So the expression equals x/|x|. For x

Submit
12) Evaluate lim as x→2^- of (x² - 5x + 6)/(x - 2).

Explanation

Factor numerator: x² - 5x + 6 = (x - 2)(x - 3). For x ≠ 2, the expression simplifies to x - 3. Substituting x = 2 into the simplified expression gives 2 - 3 = -1. Therefore, the limit is -1.

Submit
13) Evaluate lim as x→2⁺ of (x² - 4)/(x - 2).

Explanation

Factor the numerator: x² - 4 = (x - 2)(x + 2). For x ≠ 2, the expression simplifies to x + 2. Substituting x = 2 into the simplified expression gives 2 + 2 = 4. Therefore, the limit is 4.

Submit
14) Evaluate lim as x→0^- of (1/(1 + x)).

Explanation

As x approaches 0 from the left, 1 + x approaches 1. The reciprocal 1/(1 + x) therefore approaches 1. So the left-hand limit equals 1..

Submit
15) If the overall limit lim_{x→c} f(x) exists, then the left-hand limit lim_{x→c⁻} f(x) must equal the right-hand limit lim_{x→c⁺} f(x).

Explanation

The definition of a limit existing at a point x = c requires that the limit approaching from the left and the limit approaching from the right both exist and are equal to the same value.

Submit
×
Saved
Thank you for your feedback!
View My Results
Cancel
  • All
    All (15)
  • Unanswered
    Unanswered ()
  • Answered
    Answered ()
Evaluate the one-sided limit: limx→2+ (x - 2)/|x - 2|.
Evaluate limx→0⁺ 1/x.
Evaluate lim as x→3⁺ of (x² - 9)/(x - 3).
Determine limx→0- sin(x)/x.
Evaluate lim as x→1^- of (|x - 1|)/(x - 1).
Consider f(x) = (x - 4)/(x² - 16). Evaluate limx→4⁺ f(x).
Evaluate lim as x→0⁺ of ln(x).
Given the graph of a function that has y = 2 for x < 0, a hole at...
Evaluate lim as x→2^- of (x² - 4)/(x - 2).
Evaluate lim as x→1⁺ of (x - 1)/(x - 1)².
Evaluate lim as x→0^- of (x)/(√(x²)).
Evaluate lim as x→2^- of (x² - 5x + 6)/(x - 2).
Evaluate lim as x→2⁺ of (x² - 4)/(x - 2).
Evaluate lim as x→0^- of (1/(1 + x)).
If the overall limit lim_{x→c} f(x) exists, then the left-hand limit...
Alert!

Advertisement