Build Wave Models: From Specs to Sine/Cosine (and Back)

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Cierra Henderson, MBA |
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Cierra is an educational consultant and curriculum developer who has worked with students in K-12 for a variety of subjects including English and Math as well as test prep. She specializes in one-on-one support for students especially those with learning differences. She holds an MBA from the University of Massachusetts Amherst and a certificate in educational consulting from UC Irvine.
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| Questions: 20 | Updated: Jan 22, 2026
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1) I(t) = 12 + 3 cos(4πt). Maximum intensity?

Explanation

Max = midline + amplitude = 12 + 3 = 15. Hence, 15.

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About This Quiz
Build Wave Models: From Specs To Sine/Cosine (And Back) - Quiz

Practice writing and adjusting equations for sound and light waves. You will work with amplitude, frequency, and phase to model waves that match given conditions. This quiz focuses on translating real-world descriptions into mathematical models, comparing phase shifts, and understanding how changing one part of an equation affects the wave’s... see moremotion, speed, and appearance.
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2) Period 0.008 s, amplitude 0.5. Which equation?

Explanation

T=0.008 ⇒ f=125 ⇒ ω=2πf=250π. Hence, B.

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3) Y = 4 sin(6x − 18t + π/3). Wavelength?

Explanation

k=6 ⇒ λ=2π/k = π/3. Hence, π/3.

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4) Right shift by 0.2 s. New phase φ′?

Explanation

Right shift Δt ⇒ use (ωt − ωΔt + φ) ⇒ φ′ = φ − ωΔt. Hence, φ − 0.2ω.

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5) Original s(t) = 0.2 sin(440π t). New: amplitude ×3, pitch 220→330 Hz.

Explanation

New A=0.6. New ω=2π·330=660π. Hence, A.

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6) Y = 2 cos(8πt − 4πx). Wave speed magnitude?

Explanation

ω=8π, k=4π ⇒ v=ω/k=2. Hence, 2.

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7) Wavelength 5 mm, midline 20, amplitude 6, peak at x=0. Which fits?

Explanation

Peak at x=0 ⇒ cosine; use 2πx/λ. Hence, B.

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8) S(t) = 1.5 sin(2π·440 t − π/6). Phase shift in time?

Explanation

Right shift = φ/ω = (π/6)/(2π·440) = 1/5280 s. Hence, C.

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9) Y = 0.1 sin(10πx − 40πt). Which is true?

Explanation

k=10π ⇒ λ=2π/k=0.2 m. (Also f=20 Hz, v=4 m/s.) Hence, λ=0.2 m.

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10) Need amplitude 2, frequency 3 Hz, left shift 0.1 s.

Explanation

f=3 ⇒ ω=6π. Left shift Δt ⇒ +ωΔt = +0.6π. Hence, C.

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11) Y = A sin(2πx/0.8 − 2πt/0.2). Speed?

Explanation

λ=0.8, T=0.2 ⇒ v=λ/T=4.0 m/s. Hence, 4.0.

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12) Peaks at t = 1.2, 1.7, 2.2… Max = 5, midline = 1. Correct equation?

Explanation

Amplitude = 5−1=4; T=0.5 s ⇒ ω=4π. Phase shift to match peaks. Hence, B.

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13) Light in glass v = 2.0×10^8 m/s, λ = 400 nm. Frequency?

Explanation

f = v/λ = 2e8 / 4e−7 = 5e14. Hence, 5.0×10^14 Hz.

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14) Delay y(t) = sin(12π t) by 15 ms. Which works?

Explanation

Right shift Δt=0.015 s ⇒ subtract phase ωΔt = 12π·0.015 = 0.18π. Hence, A.

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15) S(t) = 0.4 sin(8π t − π/3). Frequency?

Explanation

2π f = 8π ⇒ f = 4. Hence, 4 Hz.

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16) λ = 600 nm, c = 3.0×10^8 m/s. Frequency?

Explanation

f = c/λ = 3e8 / 6e−7 = 5e14. Hence, 5.0×10^14 Hz.

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17) Y = 3 cos(5x − 20t). Wave speed?

Explanation

v = ω/k = 20/5 = 4. Hence, 4.

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18) Amplitude 6, period 3 s, midline −2.

Explanation

T=3 ⇒ ω=2π/3 ⇒ y=6 sin((2π/3)t)−2. Hence, D.

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19) S1 = 2 sin(10t), s2 = 2 sin(10t + π/2). Which is true?

Explanation

Phase lead +π/2 ⇒ Δt = (π/2)/ω = T/4. Hence, s2 leads by T/4.

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20) Y = A sin(kx − ωt), f = 50 Hz, v = 20 m/s. What is k?

Explanation

λ = v/f = 0.4 ⇒ k = 2π/λ = 5π rad/m. Hence, 5π.

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Cierra Henderson |MBA |
K-12 Expert
Cierra is an educational consultant and curriculum developer who has worked with students in K-12 for a variety of subjects including English and Math as well as test prep. She specializes in one-on-one support for students especially those with learning differences. She holds an MBA from the University of Massachusetts Amherst and a certificate in educational consulting from UC Irvine.
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I(t) = 12 + 3 cos(4πt). Maximum intensity?
Period 0.008 s, amplitude 0.5. Which equation?
Y = 4 sin(6x − 18t + π/3). Wavelength?
Right shift by 0.2 s. New phase φ′?
Original s(t) = 0.2 sin(440π t). New: amplitude ×3, pitch 220→330...
Y = 2 cos(8πt − 4πx). Wave speed magnitude?
Wavelength 5 mm, midline 20, amplitude 6, peak at x=0. Which fits?
S(t) = 1.5 sin(2π·440 t − π/6). Phase shift in time?
Y = 0.1 sin(10πx − 40πt). Which is true?
Need amplitude 2, frequency 3 Hz, left shift 0.1 s.
Y = A sin(2πx/0.8 − 2πt/0.2). Speed?
Peaks at t = 1.2, 1.7, 2.2… Max = 5, midline = 1. Correct equation?
Light in glass v = 2.0×10^8 m/s, λ = 400 nm. Frequency?
Delay y(t) = sin(12π t) by 15 ms. Which works?
S(t) = 0.4 sin(8π t − π/3). Frequency?
λ = 600 nm, c = 3.0×10^8 m/s. Frequency?
Y = 3 cos(5x − 20t). Wave speed?
Amplitude 6, period 3 s, midline −2.
S1 = 2 sin(10t), s2 = 2 sin(10t + π/2). Which is true?
Y = A sin(kx − ωt), f = 50 Hz, v = 20 m/s. What is k?
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