Build Wave Models: From Specs to Sine/Cosine (and Back)

  • Grade 11th
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Cierra Henderson, MBA |
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Cierra is an educational consultant and curriculum developer who has worked with students in K-12 for a variety of subjects including English and Math as well as test prep. She specializes in one-on-one support for students especially those with learning differences. She holds an MBA from the University of Massachusetts Amherst and a certificate in educational consulting from UC Irvine.
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| Questions: 20 | Updated: Jan 22, 2026
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1) Original s(t) = 0.2 sin(440π t). New: amplitude ×3, pitch 220→330 Hz.

Explanation

New A=0.6. New ω=2π·330=660π. Hence, A.

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About This Quiz
Build Wave Models: From Specs To Sine/Cosine (And Back) - Quiz

Practice writing and adjusting equations for sound and light waves. You will work with amplitude, frequency, and phase to model waves that match given conditions. This quiz focuses on translating real-world descriptions into mathematical models, comparing phase shifts, and understanding how changing one part of an equation affects the wave’s... see moremotion, speed, and appearance.
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2) Delay y(t) = sin(12π t) by 15 ms. Which works?

Explanation

Right shift Δt=0.015 s ⇒ subtract phase ωΔt = 12π·0.015 = 0.18π. Hence, A.

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3) Light in glass v = 2.0×10^8 m/s, λ = 400 nm. Frequency?

Explanation

f = v/λ = 2e8 / 4e−7 = 5e14. Hence, 5.0×10^14 Hz.

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4) Peaks at t = 1.2, 1.7, 2.2… Max = 5, midline = 1. Correct equation?

Explanation

Amplitude = 5−1=4; T=0.5 s ⇒ ω=4π. Phase shift to match peaks. Hence, B.

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5) Y = A sin(2πx/0.8 − 2πt/0.2). Speed?

Explanation

λ=0.8, T=0.2 ⇒ v=λ/T=4.0 m/s. Hence, 4.0.

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6) Need amplitude 2, frequency 3 Hz, left shift 0.1 s.

Explanation

f=3 ⇒ ω=6π. Left shift Δt ⇒ +ωΔt = +0.6π. Hence, C.

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7) Y = 0.1 sin(10πx − 40πt). Which is true?

Explanation

k=10π ⇒ λ=2π/k=0.2 m. (Also f=20 Hz, v=4 m/s.) Hence, λ=0.2 m.

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8) S(t) = 1.5 sin(2π·440 t − π/6). Phase shift in time?

Explanation

Right shift = φ/ω = (π/6)/(2π·440) = 1/5280 s. Hence, C.

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9) Wavelength 5 mm, midline 20, amplitude 6, peak at x=0. Which fits?

Explanation

Peak at x=0 ⇒ cosine; use 2πx/λ. Hence, B.

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10) Y = 2 cos(8πt − 4πx). Wave speed magnitude?

Explanation

ω=8π, k=4π ⇒ v=ω/k=2. Hence, 2.

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11) S(t) = 0.4 sin(8π t − π/3). Frequency?

Explanation

2π f = 8π ⇒ f = 4. Hence, 4 Hz.

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12) Right shift by 0.2 s. New phase φ′?

Explanation

Right shift Δt ⇒ use (ωt − ωΔt + φ) ⇒ φ′ = φ − ωΔt. Hence, φ − 0.2ω.

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13) Y = 4 sin(6x − 18t + π/3). Wavelength?

Explanation

k=6 ⇒ λ=2π/k = π/3. Hence, π/3.

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14) Period 0.008 s, amplitude 0.5. Which equation?

Explanation

T=0.008 ⇒ f=125 ⇒ ω=2πf=250π. Hence, B.

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15) I(t) = 12 + 3 cos(4πt). Maximum intensity?

Explanation

Max = midline + amplitude = 12 + 3 = 15. Hence, 15.

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16) Y = A sin(kx − ωt), f = 50 Hz, v = 20 m/s. What is k?

Explanation

λ = v/f = 0.4 ⇒ k = 2π/λ = 5π rad/m. Hence, 5π.

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17) S1 = 2 sin(10t), s2 = 2 sin(10t + π/2). Which is true?

Explanation

Phase lead +π/2 ⇒ Δt = (π/2)/ω = T/4. Hence, s2 leads by T/4.

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18) Amplitude 6, period 3 s, midline −2.

Explanation

T=3 ⇒ ω=2π/3 ⇒ y=6 sin((2π/3)t)−2. Hence, D.

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19) Y = 3 cos(5x − 20t). Wave speed?

Explanation

v = ω/k = 20/5 = 4. Hence, 4.

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20) λ = 600 nm, c = 3.0×10^8 m/s. Frequency?

Explanation

f = c/λ = 3e8 / 6e−7 = 5e14. Hence, 5.0×10^14 Hz.

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Cierra Henderson |MBA |
K-12 Expert
Cierra is an educational consultant and curriculum developer who has worked with students in K-12 for a variety of subjects including English and Math as well as test prep. She specializes in one-on-one support for students especially those with learning differences. She holds an MBA from the University of Massachusetts Amherst and a certificate in educational consulting from UC Irvine.
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Original s(t) = 0.2 sin(440π t). New: amplitude ×3, pitch 220→330...
Delay y(t) = sin(12π t) by 15 ms. Which works?
Light in glass v = 2.0×10^8 m/s, λ = 400 nm. Frequency?
Peaks at t = 1.2, 1.7, 2.2… Max = 5, midline = 1. Correct equation?
Y = A sin(2πx/0.8 − 2πt/0.2). Speed?
Need amplitude 2, frequency 3 Hz, left shift 0.1 s.
Y = 0.1 sin(10πx − 40πt). Which is true?
S(t) = 1.5 sin(2π·440 t − π/6). Phase shift in time?
Wavelength 5 mm, midline 20, amplitude 6, peak at x=0. Which fits?
Y = 2 cos(8πt − 4πx). Wave speed magnitude?
S(t) = 0.4 sin(8π t − π/3). Frequency?
Right shift by 0.2 s. New phase φ′?
Y = 4 sin(6x − 18t + π/3). Wavelength?
Period 0.008 s, amplitude 0.5. Which equation?
I(t) = 12 + 3 cos(4πt). Maximum intensity?
Y = A sin(kx − ωt), f = 50 Hz, v = 20 m/s. What is k?
S1 = 2 sin(10t), s2 = 2 sin(10t + π/2). Which is true?
Amplitude 6, period 3 s, midline −2.
Y = 3 cos(5x − 20t). Wave speed?
λ = 600 nm, c = 3.0×10^8 m/s. Frequency?
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