Addition Rule Applications

  • 9th Grade
Reviewed by Cierra Henderson
Cierra Henderson, MBA |
K-12 Expert
Review Board Member
Cierra is an educational consultant and curriculum developer who has worked with students in K-12 for a variety of subjects including English and Math as well as test prep. She specializes in one-on-one support for students especially those with learning differences. She holds an MBA from the University of Massachusetts Amherst and a certificate in educational consulting from UC Irvine.
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Quizzes Created: 8156 | Total Attempts: 9,588,805
| Attempts: 11 | Questions: 10 | Updated: Jan 21, 2026
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Question 1 / 11
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1) P(A) = 0.4, P(B) = 0.5, P(A∩B) = 0.2. Find P(A∪B).

Explanation

P(A ∪ B) = 0.4 + 0.5 − 0.2 = 0.7.

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Addition Rule Applications - Quiz

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2) P(A) = 0.2, P(B) = 0.2, P(A∩B) = 0.1. Find P(A∪B).

Explanation

P(A ∪ B) = 0.2 + 0.2 − 0.1 = 0.3.

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3) P(A) = 0.65, P(B) = 0.25, P(A∩B) = 0.15. Find P(A∪B).

Explanation

P(A ∪ B) = 0.65 + 0.25 − 0.15 = 0.75.

Submit

4) P(A) = 0.45, P(B) = 0.55, P(A∩B) = 0.25. Find P(A∪B).

Explanation

P(A ∪ B) = 0.45 + 0.55 − 0.25 = 0.75.

Submit

5) P(A) = 0.25, P(B) = 0.45, P(A∩B) = 0.15. Find P(A∪B).

Explanation

P(A ∪ B) = 0.25 + 0.45 − 0.15 = 0.55.

Submit

6) P(A) = 0.6, P(B) = 0.5, P(A∩B) = 0.3. Find P(A∪B).

Explanation

P(A ∪ B) = 0.6 + 0.5 − 0.3 = 0.8.

Submit

7) P(A) = 0.1, P(B) = 0.7, P(A∩B) = 0.05. Find P(A∪B).

Explanation

P(A ∪ B) = 0.1 + 0.7 − 0.05 = 0.75.

Submit

8) P(A) = 0.35, P(B) = 0.65, P(A∩B) = 0.20. Find P(A∪B).

Explanation

P(A ∪ B) = 0.35 + 0.65 − 0.20 = 0.8.

Submit

9) P(A) = 0.5, P(B) = 0.5, P(A∩B) = 0.5. Find P(A∪B).

Explanation

P(A ∪ B) = 0.5 + 0.5 − 0.5 = 0.5.

Submit

10) P(A) = 0.9, P(B) = 0.4, P(A∩B) = 0.3. Find P(A∪B).

Explanation

P(A ∪ B) = 0.9 + 0.4 − 0.3 = 1.0.

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Cierra Henderson |MBA |
K-12 Expert
Cierra is an educational consultant and curriculum developer who has worked with students in K-12 for a variety of subjects including English and Math as well as test prep. She specializes in one-on-one support for students especially those with learning differences. She holds an MBA from the University of Massachusetts Amherst and a certificate in educational consulting from UC Irvine.
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P(A) = 0.4, P(B) = 0.5, P(A∩B) = 0.2. Find P(A∪B).
P(A) = 0.2, P(B) = 0.2, P(A∩B) = 0.1. Find P(A∪B).
P(A) = 0.65, P(B) = 0.25, P(A∩B) = 0.15. Find P(A∪B).
P(A) = 0.45, P(B) = 0.55, P(A∩B) = 0.25. Find P(A∪B).
P(A) = 0.25, P(B) = 0.45, P(A∩B) = 0.15. Find P(A∪B).
P(A) = 0.6, P(B) = 0.5, P(A∩B) = 0.3. Find P(A∪B).
P(A) = 0.1, P(B) = 0.7, P(A∩B) = 0.05. Find P(A∪B).
P(A) = 0.35, P(B) = 0.65, P(A∩B) = 0.20. Find P(A∪B).
P(A) = 0.5, P(B) = 0.5, P(A∩B) = 0.5. Find P(A∪B).
P(A) = 0.9, P(B) = 0.4, P(A∩B) = 0.3. Find P(A∪B).
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