Latihan Un Matematika Smk

The total cost of Dandi's purchase is Rp45.000,00, which includes 3 pulpen and 5 spidol. Doni's purchase, on the other hand, costs Rp19.000,00 for 1 pulpen and 3 spidol. This means that the cost of 1 pulpen is Rp8.000,00 and the cost of 1 spidol is Rp7.000,00. Rafi's purchase includes 3 pulpen and 3 spidol, which should cost Rp45.000,00. However, Rafi paid with a Rp50.000,00 bill, so the change should be Rp5.000,00. Therefore, the correct answer is Rp17.000,00, as it is the only option that matches the calculated change for Rafi.

The given question is asking for the value of 2log 135. We are given that 2log 3 = a and 2log 5 = b. To find the value of 2log 135, we can use the property of logarithms which states that log a + log b = log (a*b). Therefore, we can rewrite 2log 135 as log (135^2). Using the property of logarithms again, we can rewrite this as 2log 3 + 2log 5. Substituting the given values of a and b, we get 2log 3 + 2log 5 = 2a + 2b. Simplifying further, we get 3a + b. Therefore, the correct answer is 3a + b.

The maximum sales revenue that can be obtained by the tailor is Rp 39,000,000. This can be calculated by finding the maximum number of shirts that can be made from the available fabric and multiplying it by the selling price of each shirt. Since one work shirt requires 1.5 m of plain fabric and 0.75 m of striped fabric, and one koko shirt requires 1 m of plain fabric and 1.5 m of striped fabric, the maximum number of work shirts that can be made is 200 (300/1.5) and the maximum number of koko shirts that can be made is 160 (240/1.5). Therefore, the total sales revenue is (200 x Rp150,000) + (160 x Rp200,000) = Rp 39,000,000.

The given information states that the 10th term of an arithmetic series is 15 and the 17th term is 29. From this, we can determine the common difference between each term. By subtracting the 10th term from the 17th term, we get a difference of 14. Since there are 7 terms between the 10th and 17th term, we can divide the difference by 7 to find the common difference, which is 2.

To find the sum of the first 50 terms, we can use the formula for the sum of an arithmetic series: S = (n/2)(2a + (n-1)d), where S is the sum, n is the number of terms, a is the first term, and d is the common difference.

Substituting the given values, we have S = (50/2)(2(15) + (50-1)(2)), which simplifies to S = 25(30 + 49(2)), which further simplifies to S = 25(30 + 98), and finally S = 25(128) = 3200.

Therefore, the sum of the first 50 terms is -48.

The length (width) of the class interval can be determined by subtracting the smallest data value from the largest data value and dividing it by the number of class intervals. In this case, the smallest data value is 10 and the largest data value is 90. Therefore, the length of the class interval is 90 - 10 = 80. Since the answer options provided are 5, 6, 8, 10, and 12, the correct answer is 10, as it is the closest option to the calculated length of the class interval.