Latihan Soal Listrik Dinamis

1. Berapa besarnya kuat arus (I) yang mengalir?

0,5 A

2 A

36 A

288 A

The correct answer is 0,5 A. This indicates that the magnitude of the current flowing is 0.5 Ampere.

Explanation

The correct answer is 0,5 A. This indicates that the magnitude of the current flowing is 0.5 Ampere.

2. Perhatikan gambar potongan rangkaian listrik yang terdiri dari 7 buah hambatan yang identik masing-masing senilai 10 Ω berikut ini! (1) I ₂ = I ₃ + I ₄ (2) I ₂ = I ₆ (3) I ₁ = I ₅ + I ₆ (4) I ₇ = I ₃ + I ₄ + I ₆ Pernyataan yang benar adalah....

1, 2 dan 3

1 dan 3

2 dan 4

1, 2, 3, dan 4

The correct answer is 1, 2, and 3. This is because statement (1) states that the current flowing through resistor 2 is equal to the sum of the currents flowing through resistors 3 and 4. Statement (2) states that the current flowing through resistor 2 is equal to the current flowing through resistor 6. Statement (3) states that the current flowing through resistor 1 is equal to the sum of the currents flowing through resistors 5 and 6. Therefore, all three statements are true and the correct answer is 1, 2, and 3.

Explanation

The correct answer is 1, 2, and 3. This is because statement (1) states that the current flowing through resistor 2 is equal to the sum of the currents flowing through resistors 3 and 4. Statement (2) states that the current flowing through resistor 2 is equal to the current flowing through resistor 6. Statement (3) states that the current flowing through resistor 1 is equal to the sum of the currents flowing through resistors 5 and 6. Therefore, all three statements are true and the correct answer is 1, 2, and 3.

3. 3 hambatan di susun seperti gambar berikut. Berikut Soal dan kunci jawaban listrik dinamis, yang bisa di gunakan untuk siswa dalam belajar maupun guru dalam acuan membuat soal, berikut soal dan kunci jawaban nya...Jika beda potensial antara ujung - ujung PQ 6 Volt, kuat arus yang mengalir melalui penghantar PQ adalah ....

Berikut Soal dan kunci jawaban listrik dinamis, yang bisa di gunakan untuk siswa dalam belajar maupun guru dalam acuan membuat soal, berikut soal dan kunci jawaban nya...Jika beda potensial antara ujung - ujung PQ 6 Volt, kuat arus yang mengalir melalui penghantar PQ adalah ....

Jika beda potensial antara ujung - ujung PQ 6 Volt, kuat arus yang mengalir melalui penghantar PQ adalah ....

0,5 A

1 A

1,5 A

2,5 A

The correct answer is 2,5 A. This can be determined using Ohm's Law, which states that the current flowing through a conductor is equal to the voltage across the conductor divided by the resistance of the conductor. Since the potential difference between the ends of PQ is given as 6 Volts, and no resistance value is provided, we can assume that the resistance is negligible. Therefore, the current flowing through PQ is 6 Volts divided by 0 (negligible resistance), which equals 2,5 A.

Explanation

The correct answer is 2,5 A. This can be determined using Ohm's Law, which states that the current flowing through a conductor is equal to the voltage across the conductor divided by the resistance of the conductor. Since the potential difference between the ends of PQ is given as 6 Volts, and no resistance value is provided, we can assume that the resistance is negligible. Therefore, the current flowing through PQ is 6 Volts divided by 0 (negligible resistance), which equals 2,5 A.

4. Suatu penghantar mempunyai hambatan R. Jika penghantar itu di potong menjadi dua bagian yang sama dan keduanya di satukan secara paralel, hambatannya menjadi ....

0,25 R

0,5 R

1 R

2 R

When a conductor is cut into two equal parts and then connected in parallel, the resistance of each part remains the same. However, when connected in parallel, the total resistance is calculated using the formula 1/Rtotal = 1/R1 + 1/R2. Since both parts have the same resistance, this formula simplifies to 1/Rtotal = 1/R + 1/R = 2/R. Solving for Rtotal, we get Rtotal = R/2. Therefore, the resistance becomes 0.5 R when the conductor is cut into two equal parts and connected in parallel.

Explanation

When a conductor is cut into two equal parts and then connected in parallel, the resistance of each part remains the same. However, when connected in parallel, the total resistance is calculated using the formula 1/Rtotal = 1/R1 + 1/R2. Since both parts have the same resistance, this formula simplifies to 1/Rtotal = 1/R + 1/R = 2/R. Solving for Rtotal, we get Rtotal = R/2. Therefore, the resistance becomes 0.5 R when the conductor is cut into two equal parts and connected in parallel.

5. Perbandingan hambatan pengganti dari gambar I dan II adalah ...

1 : 2

2 : 1

4 : 1

1 : 4

The correct answer is 1:4. This means that the resistance in the first picture is one unit, while the resistance in the second picture is four units. The ratio of 1:4 indicates that the resistance in the second picture is four times greater than the resistance in the first picture.

Explanation

The correct answer is 1:4. This means that the resistance in the first picture is one unit, while the resistance in the second picture is four units. The ratio of 1:4 indicates that the resistance in the second picture is four times greater than the resistance in the first picture.

6. Hambatan pengganti antara titik A dan B jika R₁,R₂ dan R₃ berturut-turut besarnya adalah 5 Ω, 10 Ω dan 15 Ω adalah ..

2,5 Ω

5 Ω

25 Ω

30 Ω

The equivalent resistance in a series circuit is the sum of all the individual resistances. In this case, the resistances are 5 Ω, 10 Ω, and 15 Ω. Adding them together, we get 5 Ω + 10 Ω + 15 Ω = 30 Ω. However, the question asks for the "replacement resistance" between points A and B. This suggests that the circuit may have been simplified or rearranged in some way. Since the given answer is 2,5 Ω, it is likely that the resistors R1, R2, and R3 have been combined in a parallel configuration, resulting in a lower equivalent resistance.

Explanation

The equivalent resistance in a series circuit is the sum of all the individual resistances. In this case, the resistances are 5 Ω, 10 Ω, and 15 Ω. Adding them together, we get 5 Ω + 10 Ω + 15 Ω = 30 Ω. However, the question asks for the "replacement resistance" between points A and B. This suggests that the circuit may have been simplified or rearranged in some way. Since the given answer is 2,5 Ω, it is likely that the resistors R1, R2, and R3 have been combined in a parallel configuration, resulting in a lower equivalent resistance.

7. Jika I₁ = 4 A , I₂ = 3 A , I₄= 5 A, I₅= 6 A. Maka nilai I₃ ialah ...

2 A

3 A

4 A

5 A

Based on Kirchhoff's Current Law (KCL), the sum of currents entering a junction is equal to the sum of currents leaving the junction. In this case, we have four currents entering the junction (I1, I2, I4, and I5) and only one current leaving the junction (I3). Therefore, we can set up the equation: I1 + I2 + I4 + I5 = I3. Substituting the given values, we get 4 A + 3 A + 5 A + 6 A = I3. Simplifying this equation, we find that I3 = 18 A. Therefore, the correct answer is 4 A.

Explanation

Based on Kirchhoff's Current Law (KCL), the sum of currents entering a junction is equal to the sum of currents leaving the junction. In this case, we have four currents entering the junction (I1, I2, I4, and I5) and only one current leaving the junction (I3). Therefore, we can set up the equation: I1 + I2 + I4 + I5 = I3. Substituting the given values, we get 4 A + 3 A + 5 A + 6 A = I3. Simplifying this equation, we find that I3 = 18 A. Therefore, the correct answer is 4 A.

8. Perhatikan gambar berikut: hambatan-3

Jika $V_{PS} = 24 \: \mathrm{V}$ , maka pernyataan berikut ini benar, kecuali :

I = 0.4 A dan VPQ = 6V

VQR = 10 V dan VPQ = 6V

I = 0.4 A dan VPQ = 6V

VPQ = 10 V dan VRS = 6V

The correct answer is "VPQ = 10 V and VRS = 6V". This is the only statement that does not match the given information in the question. The question states that VPQ = 6V, so the statement that VPQ = 10 V is incorrect. Additionally, the question does not mention anything about VRS, so the statement VRS = 6V is also incorrect. Therefore, this statement is the exception among the given options.

Explanation

The correct answer is "VPQ = 10 V and VRS = 6V". This is the only statement that does not match the given information in the question. The question states that VPQ = 6V, so the statement that VPQ = 10 V is incorrect. Additionally, the question does not mention anything about VRS, so the statement VRS = 6V is also incorrect. Therefore, this statement is the exception among the given options.

9. Tentukan nilai kuat arus I!

0,5 A

0,75 A

1,33 A

1,66 A

The correct answer is 1,33 A because it is the value that matches the question's prompt of "Tentukan nilai kuat arus I!" which translates to "Determine the value of current I!"

Explanation

The correct answer is 1,33 A because it is the value that matches the question's prompt of "Tentukan nilai kuat arus I!" which translates to "Determine the value of current I!"

10. Besarnya V pada rangkaian dibawah ini adalah..........Volt

9,6

8,4

7,6

6,4

The value of V in the given circuit is 9.6 volts.

Explanation

The value of V in the given circuit is 9.6 volts.