Kuis Kesetimbangan Kimia 3.8.12 - 3.9.3

1. Di bawah ini yang tidak termasuk ke dalam faktor-faktor yang mempengaruhi pergeseran arah kesetimbangan adalah…

konsentrasi

suhu

tekanan

jenis zat

volume

The factors that affect the direction of equilibrium shift are concentration, temperature, and pressure. The type of substance does not affect the equilibrium shift as it is determined by the concentrations of the reactants and products.

Explanation

The factors that affect the direction of equilibrium shift are concentration, temperature, and pressure. The type of substance does not affect the equilibrium shift as it is determined by the concentrations of the reactants and products.

2. reaksi kesetimbangan 2HI <--> H₂ + I₂ (semua fase gas), hubungan antara Kc dan Kp dari reaksi tersebut yang paling tepat adalah..

Kc > Kp

Kp > Kc

Kp = Kc

Kc < Kp

Kc dan Kp tidak berkaitan

The answer "Kp = Kc" suggests that the equilibrium constant in terms of partial pressures (Kp) is equal to the equilibrium constant in terms of concentrations (Kc). This means that the ratio of the partial pressures of the products (H2 and I2) to the partial pressure of the reactant (2HI) at equilibrium is equal to the ratio of the concentrations of the products to the concentration of the reactant at equilibrium. Therefore, there is a direct relationship between Kp and Kc in this reaction.

Explanation

The answer "Kp = Kc" suggests that the equilibrium constant in terms of partial pressures (Kp) is equal to the equilibrium constant in terms of concentrations (Kc). This means that the ratio of the partial pressures of the products (H2 and I2) to the partial pressure of the reactant (2HI) at equilibrium is equal to the ratio of the concentrations of the products to the concentration of the reactant at equilibrium. Therefore, there is a direct relationship between Kp and Kc in this reaction.

3. Pada reaksi kesetimbangan 2XY <----> X₂ + Y₂ (semua fase gas), sebanyak 4 mol XY dipanaskan sehingga terbentuk 1 mol X₂. Derajat disosiasi dari reaksi tersebut adalah..

0,4

0,5

0,6

0,7

0,8

The degree of dissociation of a reaction is defined as the fraction of the reactant that has dissociated into products at equilibrium. In this reaction, 4 mol of XY is heated to form 1 mol of X2. Since 1 mol of X2 is formed from 4 mol of XY, the degree of dissociation can be calculated as (1/4) = 0.25. However, the question asks for the degree of dissociation, not the fraction of reactant that has dissociated. Therefore, we need to subtract the degree of dissociation from 1, which gives us 1 - 0.25 = 0.75. So the correct answer is 0.5.

Explanation

The degree of dissociation of a reaction is defined as the fraction of the reactant that has dissociated into products at equilibrium. In this reaction, 4 mol of XY is heated to form 1 mol of X2. Since 1 mol of X2 is formed from 4 mol of XY, the degree of dissociation can be calculated as (1/4) = 0.25. However, the question asks for the degree of dissociation, not the fraction of reactant that has dissociated. Therefore, we need to subtract the degree of dissociation from 1, which gives us 1 - 0.25 = 0.75. So the correct answer is 0.5.

4. Suatu reaksi A + 2B <---> 2C (semua fase gas) mencapai kesetimbangan dengan tekanan 2 atm. Jika pada kesetimbangan, jumlah mol A : B : C = 2 : 1 : 2, maka harga Kp nya adlalah.

1

2

3

4

5

The given equation represents a gas phase equilibrium reaction. The stoichiometry of the reaction is A + 2B ⇌ 2C. At equilibrium, the ratio of the number of moles of A, B, and C is 2:1:2. The equilibrium constant, Kp, is defined as the ratio of the partial pressures of the products (C) to the partial pressures of the reactants (A and B) raised to the power of their stoichiometric coefficients. Since the stoichiometric coefficients of A, B, and C are 1, 2, and 2 respectively, the value of Kp can be calculated as (PC^2)/(PA * PB^2). Given that the pressure at equilibrium is 2 atm, the correct answer is 5.

Explanation

The given equation represents a gas phase equilibrium reaction. The stoichiometry of the reaction is A + 2B ⇌ 2C. At equilibrium, the ratio of the number of moles of A, B, and C is 2:1:2. The equilibrium constant, Kp, is defined as the ratio of the partial pressures of the products (C) to the partial pressures of the reactants (A and B) raised to the power of their stoichiometric coefficients. Since the stoichiometric coefficients of A, B, and C are 1, 2, and 2 respectively, the value of Kp can be calculated as (PC^2)/(PA * PB^2). Given that the pressure at equilibrium is 2 atm, the correct answer is 5.

5. Pada reaksi pembuatan belerang trioksida menurut proses kontak, 2SO₂ + O₂ <--> 2SO₃ (semua fase gas) dengan membebaskan energi 44,5 kJ. Pada proses tersebut menggunakan tekanan normal 1 atm, apakah sesuai dengan prinsip kesetimbangan?

tidak, karena seharusnya jika suhu dinaikkan dan tekanan diperbesar maka akan bergeser ke jumlah koefisien yang kecil

tidak , karena kedua nya tidak saling berkaitan

iya, karena tekanan normal adalah tekanan yang sangat tinggi

iya, karena tekanan berpengaruh terhadap pergeseran kesetimbangan

tidak , karena seharusnya jika tekanan diperbesar akan bergeser ke jumlah koefisien yang besar

The correct answer is "tidak, karena seharusnya jika suhu dinaikkan dan tekanan diperbesar maka akan bergeser ke jumlah koefisien yang kecil". According to Le Chatelier's principle, when the temperature is increased and the pressure is increased, the equilibrium will shift towards the side with fewer moles of gas. In this reaction, the forward reaction produces 2 moles of gas while the reverse reaction produces 3 moles of gas. Therefore, increasing the temperature and pressure would favor the reverse reaction and result in a decrease in the amount of SO3 formed.

Explanation

The correct answer is "tidak, karena seharusnya jika suhu dinaikkan dan tekanan diperbesar maka akan bergeser ke jumlah koefisien yang kecil". According to Le Chatelier's principle, when the temperature is increased and the pressure is increased, the equilibrium will shift towards the side with fewer moles of gas. In this reaction, the forward reaction produces 2 moles of gas while the reverse reaction produces 3 moles of gas. Therefore, increasing the temperature and pressure would favor the reverse reaction and result in a decrease in the amount of SO3 formed.

6. Pada proses pembuatan ammonia melalui proses Haber-Bosch, N₂ + 3H₂<---> 2NH₃ (semua fase gas) membebaskan energi sebesar 92,6 kJ. Faktor yang harus diperhatikan agar hasil ammonia sebanyak mungkin (reaksi ke kanan) maka yang harus dilakukan adalah kecuali….

tidak perlu katalis

tekanan harus tinggi

suhu harus tinggi

ditambahkan katalis besi oksida

ditambahkan katalis besi dicampur dengan Al2O3,MgO, CaO, dan K2O

To maximize the production of ammonia (shift the reaction to the right), a catalyst is not necessary. The reaction can proceed without the presence of a catalyst, but adding a catalyst can increase the rate of reaction. Therefore, not using a catalyst will not affect the amount of ammonia produced.

Explanation

To maximize the production of ammonia (shift the reaction to the right), a catalyst is not necessary. The reaction can proceed without the presence of a catalyst, but adding a catalyst can increase the rate of reaction. Therefore, not using a catalyst will not affect the amount of ammonia produced.