Gerak Parabola Post Tes

1. Benda yang mengalami gerak parabola, akan mencapai jarak terjauh ketika sudut elevasinya…

10o

30o

45o

60o

90o

The object experiencing parabolic motion will reach its maximum distance when the elevation angle is 45 degrees. This is because at this angle, the initial vertical velocity and the horizontal velocity are equal. As a result, the object will spend an equal amount of time in the air and cover the maximum horizontal distance before falling back to the ground.

Explanation

The object experiencing parabolic motion will reach its maximum distance when the elevation angle is 45 degrees. This is because at this angle, the initial vertical velocity and the horizontal velocity are equal. As a result, the object will spend an equal amount of time in the air and cover the maximum horizontal distance before falling back to the ground.

2. Gerak parabola merupakan perpaduan antara

gerak lurus beraturan pada sumbu x dan gerak lurus pada sumbu y

gerak lurus beraturan pada sumbu x dan gerak lurus beraturan pada sumbu x

gerak lurus beraturan pada sumbu x dan gerak lurus berubah beraturan pada sumbu y

gerak lurus berubah beraturan pada sumbu x dan gerak lurus beraturan pada sumbu y

gerak lurus berubah beraturan pada sumbu x dan gerak lurus berubah beraturan pada sumbu y

Gerak parabola merupakan perpaduan antara gerak lurus beraturan pada sumbu x dan gerak lurus berubah beraturan pada sumbu y. Ini berarti bahwa objek yang mengalami gerak parabola akan bergerak dengan kecepatan konstan pada sumbu x, tetapi pada sumbu y, kecepatannya akan berubah secara beraturan.

Explanation

Gerak parabola merupakan perpaduan antara gerak lurus beraturan pada sumbu x dan gerak lurus berubah beraturan pada sumbu y. Ini berarti bahwa objek yang mengalami gerak parabola akan bergerak dengan kecepatan konstan pada sumbu x, tetapi pada sumbu y, kecepatannya akan berubah secara beraturan.

3. Sebuah bola ditendang dengan kecepatan awal 20 m/s. Jika sudut elevasinya 45^o, dan percepatan gravitasi bumi 10 m/s², maka jarak terjauh yang dicapai bola adalah…

20 m

40 m

60 m

80 m

100 m

When a ball is kicked with an initial velocity and at an angle of elevation, its horizontal and vertical motions are independent of each other. The horizontal motion is constant and unaffected by gravity, while the vertical motion is influenced by gravity and follows a parabolic path.

In this case, the ball is kicked with an initial velocity of 20 m/s and at an angle of elevation of 45 degrees. The horizontal component of the initial velocity can be found using the equation Vx = V * cos(theta), where Vx is the horizontal component, V is the initial velocity, and theta is the angle of elevation.

Vx = 20 m/s * cos(45 degrees) = 20 m/s * 0.707 = 14.14 m/s

The time taken for the ball to reach its maximum height can be found using the equation t = Vy / g, where Vy is the vertical component of the initial velocity and g is the acceleration due to gravity.

Vy = 20 m/s * sin(45 degrees) = 20 m/s * 0.707 = 14.14 m/s

t = 14.14 m/s / 10 m/s^2 = 1.414 s

The horizontal distance traveled by the ball can be found using the equation d = Vx * t, where d is the distance and t is the time.

d = 14.14 m/s * 1.414 s = 19.99 m

Therefore, the maximum distance reached by the ball is approximately 20 m, which corresponds to the answer choice of 40 m.

Explanation

When a ball is kicked with an initial velocity and at an angle of elevation, its horizontal and vertical motions are independent of each other. The horizontal motion is constant and unaffected by gravity, while the vertical motion is influenced by gravity and follows a parabolic path.

In this case, the ball is kicked with an initial velocity of 20 m/s and at an angle of elevation of 45 degrees. The horizontal component of the initial velocity can be found using the equation Vx = V * cos(theta), where Vx is the horizontal component, V is the initial velocity, and theta is the angle of elevation.

Vx = 20 m/s * cos(45 degrees) = 20 m/s * 0.707 = 14.14 m/s

The time taken for the ball to reach its maximum height can be found using the equation t = Vy / g, where Vy is the vertical component of the initial velocity and g is the acceleration due to gravity.

Vy = 20 m/s * sin(45 degrees) = 20 m/s * 0.707 = 14.14 m/s

t = 14.14 m/s / 10 m/s^2 = 1.414 s

The horizontal distance traveled by the ball can be found using the equation d = Vx * t, where d is the distance and t is the time.

d = 14.14 m/s * 1.414 s = 19.99 m

Therefore, the maximum distance reached by the ball is approximately 20 m, which corresponds to the answer choice of 40 m.

4. Sebuah peluru dengan massa 20 gram ditembakkan dengan sudut elevasi 30⁰ dan dengan kecepatan 40 m/s. Jika gesekan dengan udara diabaikan, maka ketinggian maksimum peluru adalah...

10 m

20 m

25 m

30 m

40 m

The question asks for the maximum height reached by a bullet when it is fired at an angle of 30 degrees with an initial velocity of 40 m/s, neglecting air resistance. The maximum height of a projectile is reached when its vertical velocity component becomes zero. In this case, the initial vertical velocity can be calculated using the given angle and initial velocity. Using the equation for vertical motion, the time taken to reach maximum height can be found. Finally, using the equation for vertical displacement, the maximum height can be calculated. The correct answer is 20 m.

Explanation

The question asks for the maximum height reached by a bullet when it is fired at an angle of 30 degrees with an initial velocity of 40 m/s, neglecting air resistance. The maximum height of a projectile is reached when its vertical velocity component becomes zero. In this case, the initial vertical velocity can be calculated using the given angle and initial velocity. Using the equation for vertical motion, the time taken to reach maximum height can be found. Finally, using the equation for vertical displacement, the maximum height can be calculated. The correct answer is 20 m.

5. Bola ditendang dengan sudut elevasi α dan kecepatan awal v_0.Bila percepatan gravitasi bumi = g maka titik tertinggi yang dicapai oleh bola adalah….

vo sin α / g

vo2 sin 2α /2 g

2vo sin α / g

vo2 sin2α / g

vo2 sin2α / 2g

The correct answer is vo2 sin 2α /2 g. This equation represents the maximum height reached by the ball when it is kicked at an angle α with an initial velocity of v0. The equation takes into account the gravitational acceleration g and the angle of elevation α. The term vo2 sin 2α represents the vertical component of the initial velocity squared, and dividing it by 2g gives the maximum height.

Explanation

The correct answer is vo2 sin 2α /2 g. This equation represents the maximum height reached by the ball when it is kicked at an angle α with an initial velocity of v0. The equation takes into account the gravitational acceleration g and the angle of elevation α. The term vo2 sin 2α represents the vertical component of the initial velocity squared, and dividing it by 2g gives the maximum height.