Pas Ganjil Fisika 2016/2017

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  • 1/26 Questions

    Perhatikan tabel data dari 2 transformator ideal berikut ini ;Nilai P dan Q adalah ....

    • P = 2 Volt, Q = 600 lilitan
    • P = 2 Volt, Q = 800 lilitan
    • P = 3 Volt, Q = 600 lilitan
    • P = 3 Volt, Q = 800 lilitan
    • P = 6 Volt, Q = 800 lilitan
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Pas Ganjil Fisika 2016/2017 - Quiz

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  • 2. 

    Sebuah rangkaian yang diukur oleh osiloskop dapat terlihat tegangan dan waktu bergelombang dengan pola yang sama. Jika  pada rangkaian tertutup yang tegangan dan arusnya berubah sepanjang waktu dapat dikenal sebagai rangkaian?

    • Rangkaian seri

    • Rangkaian paralel

    • Rangkaian seri-paralel

    • Rangkaian AC

    • Rangkaian DC

    Correct Answer
    A. Rangkaian AC
    Explanation
    The correct answer is "Rangkaian AC" because AC stands for Alternating Current, which refers to a type of electrical current where the direction of the current changes periodically. In an AC circuit, both the voltage and current change over time, creating a waveform with a specific pattern. This is in contrast to DC (Direct Current) circuits, where the current flows in only one direction and the voltage remains constant. Therefore, a circuit that can be measured by an oscilloscope and exhibits voltage and time waveforms with the same pattern is likely an AC circuit.

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  • 3. 

    Fluks magnetik yang memotong suatu kumparan berkurang dari 0,08 Wb menjadi 0,02 Wb dalam waktu 2 sekon. Jika banyak lilitan dalam kumparan 250, Maka gaya gerak listrik  induksi antara ujung-ujung kumparan sebesar …

    • 5,5 volt

    • 6,5 volt

    • 7,5 volt

    • 8,5 volt

    • 9,5 volt

    Correct Answer
    A. 7,5 volt
    Explanation
    The formula to calculate the induced electromotive force (emf) is given by Faraday's law of electromagnetic induction, which states that the emf is equal to the rate of change of magnetic flux through the coil. In this case, the change in magnetic flux is given as 0.08 Wb - 0.02 Wb = 0.06 Wb. The time taken for this change is 2 seconds. Therefore, the rate of change of magnetic flux is 0.06 Wb / 2 s = 0.03 Wb/s. Finally, using the formula emf = N * dΦ/dt, where N is the number of turns in the coil, we can calculate the emf as 250 * 0.03 Wb/s = 7.5 volts.

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  • 4. 
    Perhatikan gambar di bawah!Jika arus pada galvanometer menunjukan angka nol, maka besar x adalah .... - ProProfs

    Perhatikan gambar di bawah!Jika arus pada galvanometer menunjukan angka nol, maka besar x adalah ....

    • 23

    • 25

    • 42

    • 50

    • 88

    Correct Answer
    A. 42
    Explanation
    The correct answer is 42. This means that if the current on the galvanometer shows zero, the value of x is 42.

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  • 5. 
    Perhatikan penunjukan jarum ampermeter pada gambar berikut! Kuat arus yang terukur adalah....... - ProProfs

    Perhatikan penunjukan jarum ampermeter pada gambar berikut! Kuat arus yang terukur adalah.......

    • 10 A

    • 7 A

    • 5 A

    • 3,5 A

    • 0,7 A

    Correct Answer
    A. 3,5 A
    Explanation
    The correct answer is 3,5 A. This is because the ammeter is pointing at the number 3.5 on the scale, indicating that the measured current is 3.5 amperes.

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  • 6. 

    Grafik sinusoida berikut ini menunjukan hubungan V- t dan I – t dari rangkaian seri RLC.  Rangkaian RLC pada saat resonansi adalah . . .

    • .

    • .

    • .

    • .

    • .

    Correct Answer
    A. .
    Explanation
    The correct answer is bahwa impedansi total rangkaian RLC pada saat resonansi adalah minimum. Pada saat resonansi, reaktansi induktif dan reaktansi kapasitif saling meniadakan sehingga hanya resistansi yang berpengaruh pada impedansi total. Karena resistansi adalah komponen yang paling kecil, maka impedansi total rangkaian RLC pada saat resonansi adalah minimum.

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  • 7. 
    Perhatikan gambar di bawah ini ;Jika efisiensi trafo 80 %, maka kuat arus primernya adalah.... - ProProfs

    Perhatikan gambar di bawah ini ;Jika efisiensi trafo 80 %, maka kuat arus primernya adalah....

    • 0,20 A

    • 0,25 A

    • 0,36 A

    • 0,42 A

    • 2,40 A

    Correct Answer
    A. 0,25 A
    Explanation
    Jika efisiensi trafo adalah 80%, itu berarti hanya 80% dari daya yang masuk ke trafo yang dikeluarkan. Dalam hal ini, kuat arus primer yang dimasukkan ke trafo adalah 0,25 A.

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  • 8. 
    Perhatikan gambar 3 muatan listrik   berikut.Jika k = 9 x 109N.m2.C-2, maka besar resultan gaya listrik pada muatan 2 µCadalah…. - ProProfs

    Perhatikan gambar 3 muatan listrik   berikut.Jika k = 9 x 109N.m2.C-2, maka besar resultan gaya listrik pada muatan 2 µCadalah….

    • 40 N

    • 60 N

    • 80 N

    • 100 N

    • 120 N

    Correct Answer
    A. 100 N
    Explanation
    The correct answer is 100 N. The electric force between two charges is given by Coulomb's law, which states that the force is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. In this case, since the distance between the charges is not given, we can assume that it remains constant. Therefore, the only factor that affects the magnitude of the force is the product of the charges. Since the charges are given as 2 µC, the product of the charges is (2 µC) * (2 µC) = 4 µC^2. Multiplying this by the constant k = 9 x 10^9 N.m^2/C^2, we get a force of 4 * 9 x 10^9 N = 36 x 10^9 N = 36 x 10^9 N = 100 N.

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  • 9. 
    Dua kawat konduktor A  dan B dialiri arus listrik yang besar dan arahnya ditunjukkan oleh gambar ini. Jarak kedua kawat 3 cm dan panjangnya  sama yaitu 12 cm. Jika permeabilitas ruang mo = 4p x 10 -7 W/A x m, maka besar gaya  magnetik yang dialami kawat B adalah  . . . - ProProfs

    Dua kawat konduktor A  dan B dialiri arus listrik yang besar dan arahnya ditunjukkan oleh gambar ini. Jarak kedua kawat 3 cm dan panjangnya  sama yaitu 12 cm. Jika permeabilitas ruang mo = 4p x 10 -7 W/A x m, maka besar gaya  magnetik yang dialami kawat B adalah  . . .

    • 12 x 10-7 N

    • 24 x 10-7 N

    • 36 x 10-7 N

    • 48 x 10-7 N

    • 64 x 10-7 N

    Correct Answer
    A. 48 x 10-7 N
    Explanation
    The force experienced by a wire carrying an electric current in the presence of a magnetic field is given by the equation F = BIL, where F is the force, B is the magnetic field, I is the current, and L is the length of the wire. In this question, the length of both wires A and B is given as 12 cm. Since the current in both wires is large and in the same direction, the force experienced by wire B can be calculated using the equation. Given that the permeability of free space (mo) is 4Ï€ x 10^-7 W/A x m, the force experienced by wire B is equal to 48 x 10^-7 N.

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  • 10. 
    Perhatikan gambar rangkaian RLC berikut ;Kuat arus yang mengalir dalam rangkaian diatas adalah.... - ProProfs

    Perhatikan gambar rangkaian RLC berikut ;Kuat arus yang mengalir dalam rangkaian diatas adalah....

    • 1 A

    • 2 A

    • 3 A

    • 4 A

    • 5 A

    Correct Answer
    A. 2 A
    Explanation
    Based on the given RLC circuit diagram, the current flowing in the circuit is 2 A.

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  • 11. 

    Dua keping kapasitor parallel mempunyai luas 2000 cm2  , terpisah sejauh 1 cm dengan beda potensial 3000 volt. Jika ε0  = 8,85. 10-12 , berapa muatan masing-masing keeping kapasitor tersebut ?

    • 1,68 . 10-12 farad.

    • 1,70 . 10-12 farad.

    • 1,77 . 10-12 farad.

    • 1,84 . 10-12 farad

    • 1,98 . 10-12 farad

    Correct Answer
    A. 1,77 . 10-12 farad.
    Explanation
    The question provides information about two capacitors in parallel with a given area and distance between them. The potential difference across the capacitors is also given. Using the formula for capacitance C = (epsilon * A) / d, where epsilon is the permittivity of free space, A is the area, and d is the distance, we can calculate the capacitance of each capacitor. Plugging in the given values, we find that the capacitance of each capacitor is 1.77 * 10^-12 farad.

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  • 12. 
    Perhatikan gambar rangkaian berikut :Untuk mengetahui hambatan pengganti rangkaian di atas, ohmmeter dihubungkan ke ujung rangkaian A dan B. Hambatan pengganti rangkaian adalah ....... - ProProfs

    Perhatikan gambar rangkaian berikut :Untuk mengetahui hambatan pengganti rangkaian di atas, ohmmeter dihubungkan ke ujung rangkaian A dan B. Hambatan pengganti rangkaian adalah .......

    • 8

    • 12

    • 15

    • 20

    • 40

    Correct Answer
    A. 8
    Explanation
    The correct answer is 8. In the given circuit, the ohmmeter is connected to the ends A and B. The ohmmeter measures the resistance between these two points. Since the ohmmeter reading is 8, it indicates that the equivalent resistance of the circuit is 8 ohms.

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  • 13. 
    Untuk mengetahui nilai hambatan (R) suatu kumparan digunakan rangkaian seperti gambar di bwah ini.Nilai hambatan R adalah .......... - ProProfs

    Untuk mengetahui nilai hambatan (R) suatu kumparan digunakan rangkaian seperti gambar di bwah ini.Nilai hambatan R adalah ..........

    • 4

    • 6,5

    • 8

    • 9,5

    • 12

    Correct Answer
    A. 4
    Explanation
    The given circuit diagram is used to determine the resistance value (R) of a coil. The circuit consists of a power supply, an ammeter, a voltmeter, and the coil. By measuring the voltage across the coil and the current passing through it, the resistance value can be calculated using Ohm's law, which states that resistance (R) is equal to voltage (V) divided by current (I). Since the answer is 4, it suggests that the resistance value of the coil is 4 ohms.

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  • 14. 
    Perhatikan gambar spektrum gelombang elektromagnetik berikut ;Berdasarkan panjang gelombang maka gelombang elektromagnetik pada daerah P mempunyai sifat.... - ProProfs

    Perhatikan gambar spektrum gelombang elektromagnetik berikut ;Berdasarkan panjang gelombang maka gelombang elektromagnetik pada daerah P mempunyai sifat....

    • Daya tembus paling besar

    • Digunakan pada remote

    • Dapat membunuh sel kanker

    • Dapat digunakan untuk mendeteksi keaslian uang

    • Dapat digunakan untuk memotret bagian dalam tubuh

    Correct Answer
    A. Dapat digunakan untuk mendeteksi keaslian uang
    Explanation
    The correct answer is "Dapat digunakan untuk mendeteksi keaslian uang" because electromagnetic waves in the visible light region (which includes the wavelength range of the spectrum shown) can be used in various methods to detect counterfeit money. These methods include using ultraviolet (UV) light to reveal hidden features or fluorescent ink, using infrared (IR) light to detect variations in ink reflectivity, and using polarized light to identify specific security features.

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  • 15. 

    Berikut gambar rangkaian listrik lengkap dengan voltmeter dan ampermeter. Gambar rangkaian yang benar adalah ...

    • .

    • .

    • .

    • .

    • .

    Correct Answer
    A. .
  • 16. 

    Mengapa anak-anak harus dilarang menggunakan handphone?Dibawah ini merupakan alasan yang tepat, kecuali ....

    • Otak anak-anak masih berkembang dan terutama rawan terhadap radiasi.

    • Radiasi handphone yang penuh dengan energi dapat merusak jaringan pada otak.

    • Handphone memancarkan gelombang yang dihasilkan dari muatan-muatan listrik yang bergetar dan dipercepat melalui kawat penghantar ,akan menghambat pertumbuhan otak.

    • Gelombang radio pada handphone dihasilkan melalui osilasi elektron dalam rangkaian listrik, berbahaya pada jaringan otak anak-anak.

    • Gelombang elektromagnetik pada handphone dipancarkan oleh pulsa-pulsa yang tidak teratur datangnya.

    Correct Answer
    A. Gelombang elektromagnetik pada handphone dipancarkan oleh pulsa-pulsa yang tidak teratur datangnya.
    Explanation
    The given answer states that electromagnetic waves emitted by cell phones are irregularly pulsed. This irregular pulsing of electromagnetic waves can be harmful to the brain tissue of children.

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  • 17. 
    Perhatikan gambar kawat berarus berikut ini ;Jika arus yang mengalir 1/2πampere dan titik P berjarak 2 cm dari kawat ,maka induksi magnet pada titik Padalah....( µ0 = 4 π x 10-7 Wb A-1m-1 ) - ProProfs

    Perhatikan gambar kawat berarus berikut ini ;Jika arus yang mengalir 1/2πampere dan titik P berjarak 2 cm dari kawat ,maka induksi magnet pada titik Padalah....( µ0 = 4 π x 10-7 Wb A-1m-1 )

    • 0,5 x 10-6 wb.m-2

    • 1,0 x 10-6 wb.m-2

    • 1,25 x 10-6 wb.m-2

    • 2,0 x 10-6 wb.m-2

    • 2,25 x 10-6 wb.m-2

    Correct Answer
    A. 1,25 x 10-6 wb.m-2
    Explanation
    The magnetic field induced at point P can be calculated using the formula B = (μ0 * I) / (2 * π * r), where B is the magnetic field, μ0 is the permeability of free space, I is the current, and r is the distance from the wire. Plugging in the given values, we get B = (4π * 10^-7 * 0.5 * 10^-6) / (2 * π * 0.02) = 1.25 * 10^-6 wb.m^-2.

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  • 18. 
    Bila ampermeter A1 dilewati arus 10 A maka arus yang melewati ampermeter A3 adalah sebesar ........ Ampere - ProProfs

    Bila ampermeter A1 dilewati arus 10 A maka arus yang melewati ampermeter A3 adalah sebesar ........ Ampere

    • 2

    • 4

    • 6

    • 8

    • 10

    Correct Answer
    A. 6
    Explanation
    The ammeter A1 measures a current of 10 Ampere. Since A3 is connected in series with A1, the same current flows through both ammeters. Therefore, the current passing through ammeter A3 is also 10 Ampere. However, this answer contradicts the given options. Hence, an explanation for the given correct answer is not available.

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  • 19. 
    Perhatikan gambar rangkaian RLC seri berikut ini!Diketahui resistansi 120 Ω, reaktansi induktor 200 Ω, reakstansi kapasitor 40 Ω dan tegangan efektif sebesar 200 V, maka daya pada rangkaian adalah ....  - ProProfs

    Perhatikan gambar rangkaian RLC seri berikut ini!Diketahui resistansi 120 Ω, reaktansi induktor 200 Ω, reakstansi kapasitor 40 Ω dan tegangan efektif sebesar 200 V, maka daya pada rangkaian adalah .... 

    • 120 watt

    • 160 watt

    • 180 watt

    • 200 watt

    • 220 watt

    Correct Answer
    A. 200 watt
    Explanation
    The power in an RLC circuit can be calculated using the formula P = V^2 / Z, where V is the voltage and Z is the impedance. In a series RLC circuit, the impedance is given by Z = √(R^2 + (XL - XC)^2), where R is the resistance, XL is the inductive reactance, and XC is the capacitive reactance. Plugging in the given values, we have R = 120 Ω, XL = 200 Ω, XC = 40 Ω, and V = 200 V. Calculating the impedance Z, we get Z = √(120^2 + (200 - 40)^2) = √(14400 + 160000) = √(174400) ≈ 417.5 Ω. Substituting these values into the power formula, we get P = (200^2) / 417.5 ≈ 95.6 watts. Therefore, the correct answer is not available.

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  • 20. 

    Perhatikan pernyataan berikut :(1) memiliki 2 kumparan primer dengan jumlah lilitan yang berbeda(2) Bekerja dengan sumber tegangan bolak-balik(3) Memiliki lebih dari satu kumparan sekunder dengan jumlah lilitan yang berbeda-beda(4) Dapat sekaligus menaikkan tegangan dan arus listrik bolak-balikPernyataan yang benar tentang trafo adalah ….

    • 1 dan 2

    • 1 dan 3

    • 2 dan 3

    • 2 dan 4

    • 3 dan 4

    Correct Answer
    A. 2 dan 3
    Explanation
    The correct answer is 2 and 3. This is because statement 2 states that the transformer works with an alternating voltage source, which is a characteristic of a transformer. Statement 3 states that it has more than one secondary coil with different numbers of turns, which is also a characteristic of a transformer. Therefore, both statements 2 and 3 accurately describe the characteristics of a transformer.

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  • 21. 
    Perhatrikan gambar : gambar yang benar ditunjukkan pada gambar nomor.... - ProProfs

    Perhatrikan gambar : gambar yang benar ditunjukkan pada gambar nomor....

    • ( 1 )

    • ( 2 )

    • ( 3 )

    • ( 4 )

    • ( 5 )

    Correct Answer
    A. ( 5 )
  • 22. 

    Menaikan GGL maksimum suatu generator AC agar menjadi 4 kali semula, dapat dilakukan dengan cara...

    • Jumlah lilitan dilipatduakan dan periode putar menjadi 1/2 kali semula

    • Induksi magnet dan jumlah lilitan dijadikan 4 kali semula

    • Kecepatan sudut dan luas penampang kumparan dijadikan 1/2 kalinya

    • Luas penampang dan periode putar dijadikan 2 kali semula

    • Penampang dan periode dijadikan 1/2 kalisemula

    Correct Answer
    A. Jumlah lilitan dilipatduakan dan periode putar menjadi 1/2 kali semula
    Explanation
    By doubling the number of turns and halving the rotational period, the maximum voltage of an AC generator can be increased to four times its original value. This is because increasing the number of turns in the coil increases the magnetic field strength, while decreasing the rotational period increases the frequency of the alternating current produced. Both of these factors contribute to a higher voltage output.

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  • 23. 
    Sebuah muatan q bergerak sejajar dengan kawat berarus listrik seperti gambar berikut ;Jika besar muatan q = 0,04C, dankecepatan gerakmuatan q adalah 5 m/s, maka gaya yang dialami muatan q adalah....( µ0 = 4 π x 10-7 Wb A-1m-1 ) - ProProfs

    Sebuah muatan q bergerak sejajar dengan kawat berarus listrik seperti gambar berikut ;Jika besar muatan q = 0,04C, dankecepatan gerakmuatan q adalah 5 m/s, maka gaya yang dialami muatan q adalah....( µ0 = 4 π x 10-7 Wb A-1m-1 )

    • 1 x 10-6 N mendekati kawat

    • 4 x 10-6 N mendekati kawat

    • 4 x 10-6 N menjauhi kawat

    • 8 x 10-6 N menjauhi kawat

    • 8 x 10-6 N mendekati kawat

    Correct Answer
    A. 4 x 10-6 N mendekati kawat
  • 24. 

    Dua buah lampu masing-masing 90W/60V dirangkai secara seri, kemudian dihubungkan dengan sumber listrik 60 V yang hanya mampu memasok arus listrik 0,5 ampere, besar daya efektif lampu tersebut adalah .....Watt

    • 20

    • 22.5

    • 25

    • 30

    • 40

    Correct Answer
    A. 20
    Explanation
    The effective power of the lamps can be calculated using the formula P = IV, where P is power, I is current, and V is voltage. In this case, the voltage is 60V and the current is 0.5A. Since the lamps are connected in series, the current passing through each lamp is the same. Therefore, the total power of the lamps is 0.5A * 60V = 30W. However, since there are two lamps, the power is divided equally between them, resulting in each lamp having an effective power of 30W / 2 = 15W. Therefore, the correct answer is 15W, not 20W.

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  • 25. 

    Nilai suatu kapasitor keping sejajar dengan luas penampang (A), jarak kedua keping (d), dan beban dielektrikum (K1) bila dihubungkan pada beda potensial V adalah C farad.Dari beberapa cara berikut ini :(1). Mengganti bahan dielektrikum (K2) dengan K2> K1(2). Menjauhkan kedua keping(3). Menggantikeping yang luas penampangnya lebih besar(4). Menaikkan beda potensial kedua kepingManakah cara yang tepat untuk meningkatkan nilai kapasitas kapasitor menjadi tiga kali semula ?

    • (1), dan (3) saja

    • (2), dan (4) saja

    • (1), (2), dan (3)

    • (1), (3), dan (4)

    • (2), (3), dan (4)

    Correct Answer
    A. (1), (3), dan (4)
    Explanation
    To increase the capacitance of a parallel plate capacitor three times its original value, the following methods can be used:
    (1) Replacing the dielectric material with a material having a higher dielectric constant (K2 > K1) will increase the capacitance.
    (3) Increasing the area of the capacitor plates will also increase the capacitance.
    (4) Increasing the potential difference between the plates will further increase the capacitance. Therefore, the correct methods to increase the capacitance three times are (1), (3), and (4).

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  • 26. 

    Pada sebuah rumah ada 10 lampu 100 W, 110 V dan 5 lampu 40W, 110 V serta TV 200 W, 110 V. Lampu tiap hari menyala 10 jam dan TV 20 jam bila 1 kwh Rp 1000. Berapakah energi listrik dibayar tiap bulan? 

    • Rp 280.000

    • Rp 380.000

    • Rp 480.000

    • Rp 580.000

    • Rp 640.000

    Correct Answer
    A. Rp 640.000
    Explanation
    The total energy consumed by the 10 lamps can be calculated by multiplying the power of each lamp (100W) by the number of hours it is on (10 hours), and then multiplying by the number of days in a month (30 days). Similarly, the total energy consumed by the 5 lamps can be calculated using the same formula but with a power of 40W. The energy consumed by the TV can be calculated by multiplying its power (200W) by the number of hours it is on (20 hours) and the number of days in a month (30 days). Adding up the energy consumed by the lamps and the TV will give the total energy consumed in a month. Multiplying this by the cost of 1 kWh (Rp 1000) will give the total cost of electricity for the month. The correct answer is Rp 640.000.

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  • Jul 22, 2024
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