# Principles Of Factoring Quadratic Equations

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| By Olson1da
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Olson1da
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Quizzes Created: 1 | Total Attempts: 524
Questions: 5 | Attempts: 532  Settings  The following quiz is based on all the previous information given about the process of factoring quadratic equations. Please read each question carefully and select what you think is the best answer. (Remember to check your answer by using the foil method. )

• 1.

### What is the factorization of the quadratic equation x2+5x+6=0?

• A.

(x+2)(x+3)=0

• B.

(x+1)(x+3)=0

• C.

(x+3)(x+1)=0

• D.

(x-2)(x-8)=0

• E.

(x+2)(x+1)=0

A. (x+2)(x+3)=0
Explanation
The given quadratic equation is x^2 + 5x + 6 = 0. To find the factorization, we need to determine two binomials that, when multiplied together, will give us the quadratic equation. By looking at the options, we can see that (x+2)(x+3) is the correct factorization. When we expand this expression, we get x^2 + 5x + 6, which matches the original equation. Therefore, the factorization of the quadratic equation x^2 + 5x + 6 = 0 is (x+2)(x+3)=0.

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• 2.

### Before factoring a quadratic equation, the equation must equal (_______).

0
o
zip
nothing
zero
Explanation
Before factoring a quadratic equation, the equation must equal zero. This is because factoring involves finding the values of x that make the equation equal to zero, which are called the roots or solutions of the equation. By setting the equation equal to zero, we can then factor it into two binomial expressions or use other methods to solve for x.

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• 3.

### Factor the following equation: x2+2x=3. What is the factorization?

• A.

(x+3)(x+2)=0

• B.

(x+3)(x-1)=0

• C.

(x+5)(x-3)=0

• D.

X(x-2)=3

• E.

2(x-1)=3

B. (x+3)(x-1)=0
Explanation
The given equation is x^2 + 2x = 3. To factorize this equation, we need to find two binomials that multiply together to give us the original equation. In this case, the correct factorization is (x+3)(x-1)=0. By expanding this factorization, we get x^2 + 2x - 3, which is equal to the original equation. To find the solutions, we set each factor equal to zero, so x+3=0 or x-1=0, giving us x=-3 or x=1.

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• 4.

### For the quadratic equation x2-2x+1=0, what is the value of x?

• A.

(x-2)(x-1)=0

• B.

(x-1)(x-2)=0

• C.

X=0

• D.

X=2

• E.

X=1

E. X=1
Explanation
The given quadratic equation can be factored as (x-1)(x-1)=0. This means that either (x-1) or (x-1) must equal zero in order for the equation to be true. Therefore, the value of x that satisfies the equation is x=1.

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• 5.

### For the equation 3x(x+4)=0, what are the two values of x? (Hint: The equation does NOT need to be solved.)

• A.

X=2, x=4

• B.

X=1, x=-2

• C.

X=0, x=0

• D.

X=0, x=-4

• E.

X=-3, x=2

D. X=0, x=-4
Explanation
The equation 3x(x+4)=0 can be factored as 3x(x+4)=0. By applying the zero product property, we know that either 3x=0 or (x+4)=0. Therefore, the two possible values for x are x=0 and x=-4.

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