5946 Linearising Tables Of Values

The shape of the graph for the given table of values will be a hyperbola. A hyperbola is a type of curve that has two branches, which are symmetric to each other. It is defined by the equation (x-h)^2/a^2 - (y-k)^2/b^2 = 1 or (y-k)^2/b^2 - (x-h)^2/a^2 = 1, where (h,k) is the center of the hyperbola and a and b determine the size and shape of the branches.

The shape of the graph for the given table of values will be cubic. A cubic function is a polynomial function of degree 3, which means it has the form f(x) = ax^3 + bx^2 + cx + d. The graph of a cubic function is characterized by its curved shape, with both positive and negative slopes. It typically has one or two turning points and can exhibit a variety of different behaviors depending on the values of its coefficients. Therefore, the graph for the given table of values can be linearized by fitting a cubic function to it.

The shape for the table of values above will be a Truncus.

The shape for the table of values above will be a "Truncus".

The shape of the table of values above will be a parabola. This can be determined by analyzing the pattern of the values in the table. A parabola is a U-shaped curve that can be either concave up or concave down. It is characterized by a quadratic equation, which typically includes an x^2 term. The values in the table may exhibit a quadratic relationship, where the y-values increase or decrease at a constant rate. This indicates that the graph will have a parabolic shape.

The value for 1/x when y = -3 is -1.

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The value for 1/x when y = 1 can be calculated by substituting y = 1 into the equation. Since x is not given in the question, we cannot determine the exact value of 1/x. However, the options -1/2, -0.5, and -.5 all represent the same value, which is the reciprocal of 2. Therefore, any of these options can be considered as the correct answer.

The value for 1/x when y = -2 is 1. This can be determined by substituting y = -2 into the equation 1/x, which simplifies to 1/(-2) = -1/2. Therefore, the correct answer is 1.

The value for 1/x when y = -1 is 1/2, 0.5, and .5. This is because when y = -1, x can take any value except 0. Therefore, 1 divided by any non-zero value will give us the same result, which is 1/2, 0.5, or .5.

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The value for x squared when y = -18 is 9. This can be determined by substituting y = -18 into the equation and solving for x squared.

The value for x squared when y = -8 is 4. This can be determined by substituting the value of y into the equation and solving for x squared.

The value for 1/x squared when y = 2 is 1. This can be determined by substituting y = 2 into the equation and simplifying. Since x is not given in the question, it can be assumed that x can be any value. Therefore, when y = 2, the value for 1/x squared is 1.

The value for 1/x squared when y = 1/2 can be calculated by substituting the value of y into the expression. Since y = 1/2, we can substitute it into 1/x squared to get 1/(1/2)^2. Simplifying this expression, we get 1/(1/4), which is equal to 4. Therefore, the value for 1/x squared when y = 1/2 is 4.

The value for x cubed when y = -2 is -1. This can be determined by substituting y = -2 into the equation and solving for x cubed.

The value for x cubed when y = -16 is -8. This can be determined by substituting y = -16 into the equation and solving for x.

The value for x cubed when y = 16 is 8.

The value for x cubed when y = 2 is 1.

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The linearized value when y = 8 is -8. This means that when the value of y is 8, the linearized value is -8.

The linearized value refers to the value obtained by applying a linear transformation to a given variable. In this case, when y = -1, the linearized value is 1. This suggests that there is a linear relationship between the original variable and its linearized value, where a change of -1 in y corresponds to a change of 1 in the linearized value.

The linearized value is the same as the given value, which is -1.

The linearised value when y = -1/4 is 1/4, 0.25, or .25.

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The given question is asking for the linearised value when y = -12. However, there is no information or context provided in the question or the table that would allow us to determine the linearised value when y = -12. Therefore, it is not possible to provide an explanation for the given answer of 4.

Based on the given information, when y = 3, the linearised value is -1.

The linearised value refers to the value of a function when it is approximated by a straight line. In this case, when y = 1, the linearised value is -1/3. This means that when y is equal to 1, the function can be well approximated by a straight line with a slope of -1/3.

The linearized value when y = 1 can be represented as 1/3, 0.3, or .3.

Based on the given information, when y = 2, the linearised value is 1.

The shape for the given table of values is a parabola. A parabola is a U-shaped curve that can be either concave up or concave down. It is characterized by a quadratic equation, and its graph is symmetric with a vertex at the minimum or maximum point. To linearize the graph, one would need to find a linear equation that approximates the behavior of the parabola.

The shape of the graph for the given table of values is a parabola. This can be determined by analyzing the pattern of the values in the table. If the values in the table follow a quadratic relationship, where the second differences are constant, then the graph will be a parabola.

The term "truncus" is not a commonly used mathematical term, so it is unclear what the shape of the graph would be based solely on this answer choice. Without further information or context, it is not possible to provide a clear explanation for why "truncus" would be the correct answer.

The shape of the graph for the given table of values will be a hyperbola. A hyperbola is a type of curve that is symmetrical and consists of two branches that open in opposite directions. It is characterized by the equation of the form x^2/a^2 - y^2/b^2 = 1 or y^2/b^2 - x^2/a^2 = 1. In order to linearize the graph, the equation needs to be transformed into a linear equation, which is not possible with a hyperbola. Therefore, the correct answer is hyperbola.

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The shape of the table of values above will be cubic. A cubic function is a polynomial function of degree three, which means it can have a graph that is curved and has both positive and negative slopes. This is different from a linear function, which has a straight line graph, a hyperbola which has two branches that open in opposite directions, a parabola which has a U-shaped graph, or a truncus which is not a recognized mathematical shape.

The linearized value is the value of y when it is represented on a straight line. In this case, when y = -2, the linearized value is -1. This means that when y is plotted on a straight line, it will correspond to the value of -1 on that line.

The linearized value when y = -1 is -1/2, -.5, or -0.5.

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