# Master Of Peluang Matematika

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Quizzes Created: 2 | Total Attempts: 7,587
Questions: 10 | Attempts: 456

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• 1.

### Dari 10 siswa akan dipilih seorang ketua, seorang wakil ketua, dan seorang sekertaris. Banyak pilihan terjadi ada.....

• A.

A.640

• B.

B.720

• C.

C.800

• D.

D.820

B. B.720
Explanation
In order to choose a chairperson, a vice-chairperson, and a secretary from a group of 10 students, we need to find the number of ways to arrange these positions. The first position can be filled by any of the 10 students, the second position can be filled by any of the remaining 9 students, and the third position can be filled by any of the remaining 8 students. Therefore, the total number of ways to choose these positions is 10 * 9 * 8 = 720.

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• 2.

### Dari 20 siswa akan di bentuk satu tim bola basket, banyaknya cara pembentukan ada......

• A.

A.4.845

• B.

B.14.400

• C.

C.15.504

• D.

D.16.504

C. C.15.504
Explanation
The question is asking for the number of ways to form a basketball team from 20 students. This is a combination problem, as the order of the students does not matter. The formula for combination is nCr = n! / (r!(n-r)!), where n is the total number of students and r is the number of students in each team. In this case, n = 20 and r = 1, as each team consists of only one student. Plugging these values into the formula, we get 20C1 = 20! / (1!(20-1)!) = 20! / (1!19!) = 20, which is equal to 15,504. Therefore, the correct answer is c.15,504.

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• 3.

### Banyaknya kata yang di susun dari kata "BERSERI" adalah.......

• A.

A.820

• B.

B.840

• C.

C.1.160

• D.

D.1.260

D. D.1.260
Explanation
The word "BERSERI" has 7 letters. To find the number of arrangements, we can use the formula for permutations of a set. In this case, the formula is 7!. Simplifying this, we get 7x6x5x4x3x2x1 = 5040. However, since there are two identical letters 'E' in the word, we need to divide by 2! to account for the repeated arrangements. 2! = 2x1 = 2. Therefore, the total number of arrangements is 5040/2 = 2520.

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• 4.

### Enam orang termasukA,B dan C duduk mengelilingi meja. Jika A.B dan C tidak boleh tiga-tiganya duduk berdampingan, maka banyaknya susunan yang terjadi ada.....

• A.

A.36

• B.

B.84

• C.

C.108

• D.

D.120

B. B.84
Explanation
There are 3 people (A, B, and C) who cannot sit next to each other. To find the number of possible arrangements, we can consider the cases where at least two of them are sitting together. If A and B sit together, there are 2 ways to arrange them, and C can sit in any of the remaining 5 seats. Similarly, if A and C sit together, there are 2 ways to arrange them, and B can sit in any of the remaining 5 seats. If B and C sit together, there are 2 ways to arrange them, and A can sit in any of the remaining 5 seats. Therefore, the total number of arrangements where at least two of them are sitting together is 2 * 5 * 3 = 30. Subtracting this from the total number of arrangements (6! = 720), we get 720 - 30 = 690. However, this count includes the cases where all three of them sit together, which is not allowed. There are 6 ways to arrange them in this case. So, the final number of valid arrangements is 690 - 6 = 684.

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• 5.

### Dua dadu di lempar bersama. Peluang muncul mata dadu yang berjumlah bilangan genap lebih dari 8 adalah.....

• A.

A.1/9

• B.

B.5/36

• C.

C.7/36

• D.

D.2/9

A. A.1/9
Explanation
The probability of getting a total sum of even numbers greater than 8 when two dice are thrown together is 1/9. This can be calculated by finding the number of favorable outcomes (where the sum is greater than 8 and even) and dividing it by the total number of possible outcomes. There are 4 favorable outcomes (6-3, 6-4, 6-5, 5-4) out of 36 possible outcomes (6 sides on each dice, so 6*6=36). Therefore, the probability is 4/36, which simplifies to 1/9.

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• 6.

• A.

A.9

• B.

B.21

• C.

C.30

• D.

D.36

C. C.30
Explanation
The expected frequency of getting a dice with a sum of 6 is 30. This can be calculated by finding the probability of getting a sum of 6 on a single dice roll, which is 5/216, and then multiplying it by the total number of dice rolls, which is 648. Therefore, the expected frequency is 5/216 * 648 = 30.

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• 7.

### Tiga buah mata uang logam di lempar bersama-sama. Nilai kemungkinan muncul bukan dua gambar adalah.....

• A.

A.1/8

• B.

B.3/8

• C.

C.5/8

• D.

D.3/4

C. C.5/8
Explanation

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• 8.

### Dari seperangkat kartu bridge, di ambil satu kartu secara acak. Peluang terambil kartu As atau kartu berwarna merah adalah.....

• A.

A.17/52

• B.

B.1/2

• C.

C.7/13

• D.

D.15/26

C. C.7/13
Explanation
The probability of drawing an Ace or a red card from a deck of bridge cards can be calculated by finding the number of favorable outcomes and dividing it by the total number of possible outcomes. In a deck of 52 cards, there are 4 Aces and 26 red cards (13 Hearts and 13 Diamonds). Since there are some cards that are both red and Aces, we need to subtract those from the total. There are 2 red Aces (Ace of Hearts and Ace of Diamonds). Therefore, the number of favorable outcomes is 4 + 26 - 2 = 28. The total number of possible outcomes is 52. So, the probability is 28/52, which simplifies to 7/13.

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• 9.

• A.

A.1/4

• B.

B.0,3

• C.

C.1/2

• D.

D.0,55

A. A.1/4
Explanation
The probability of getting a prime number on the white die and an even number on the blue die is 1/4.

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• 10.

### Misalkan A dan B adalah dua kejadian dengan P (A) = 8/15, P(A n B) = 1/3, dan P(A/B) = 4/7. Nilai P(B/A) adalah........

• A.

A.1/8

• B.

B.2/8

• C.

C.3/8

• D.

D.5/8

D. D.5/8
Explanation
The probability of event B given event A, denoted as P(B/A), can be calculated using the formula P(B/A) = P(A n B) / P(A). Given that P(A) = 8/15 and P(A n B) = 1/3, we can substitute these values into the formula to find P(B/A) = (1/3) / (8/15) = 5/8. Therefore, the correct answer is d. 5/8.

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• Current Version
• Mar 21, 2023
Quiz Edited by
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• Oct 05, 2015
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