Soal Fisika Kelas X

Explanation
The question states that a force of 22 Newton is required to move the block in the direction shown in the picture. It also mentions that the block has moved 33 meters to the right with an input of 33 joules of work. Since work is calculated by multiplying force and distance, we can conclude that the force applied is equal to the work done. Therefore, the force of 22 Newton is equal to the work done of 33 joules. To find the angle, we can use the formula for work done: work = force * distance * cos(angle). Rearranging the formula, we get cos(angle) = work / (force * distance). Plugging in the values, we get cos(angle) = 33 / (22 * 33) = 1. Simplifying further, we find that cos(angle) = 1. Taking the inverse cosine of 1, we find that the angle is 0 degrees. However, since the block is moving to the right, the angle is measured counterclockwise from the positive x-axis, so the angle is 360 degrees - 0 degrees = 360 degrees. This is equivalent to 600 in the given answer choices.

Explanation
The correct answer is 10 sin 300 joule because the work done by the gravitational force is equal to the product of the force and the displacement in the direction of the force. In this case, the force is the weight of the object (10 N) and the displacement is 1 m. Since the object is on a inclined plane, the force of gravity can be resolved into two components, one parallel to the plane and one perpendicular to the plane. The component parallel to the plane is given by the equation F = mg sin θ, where m is the mass of the object, g is the acceleration due to gravity, and θ is the angle of inclination. Plugging in the values, we get 10 sin 300 joule as the answer.

Explanation
The depth of penetration of the ball during each collision can be determined using the principle of conservation of energy. As the ball falls from a height of 25 m, it gains potential energy which is converted into kinetic energy. Upon collision with the wall, this kinetic energy is transferred into the ball deforming and penetrating the wall. The average resistance force exerted by the wall is given as 105 N. Using the equation for work done, W = Fd, where W is the work done, F is the force, and d is the distance, we can calculate the depth of penetration. Rearranging the equation to solve for d, we have d = W/F. Substituting the given values, we get d = 105 N / 250 kg * 10 m/s^2 = 0.42 m. Therefore, the depth of penetration is approximately 0.5 m.

Explanation
The work done on an object is equal to the force applied to the object multiplied by the distance over which the force is applied. In this scenario, the force applied to the object is equal to the mass of the object multiplied by the acceleration. Given that the mass of the object is 5 kg and the acceleration is 5 m/s^2, the force applied is 25 N. The distance over which the force is applied is equal to the product of the acceleration and the time, which is 5 m/s^2 * 4 s = 20 m. Therefore, the work done on the object is 25 N * 20 m = 500 J. Since the object moves with a constant velocity for another 4 seconds, no additional work is done. Therefore, the total work done on the object is 500 J.

Explanation
The force exerted by the hammer on the nail can be calculated using the equation F = m * a, where F is the force, m is the mass, and a is the acceleration. In this case, the mass of the hammer is given as 2 kg and the velocity is given as 20 m/s. Since the hammer comes to a stop after hitting the nail, the acceleration can be calculated using the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled. Rearranging the equation to solve for a, we get a = (v^2 - u^2) / (2s). Plugging in the values, we get a = (0 - 20^2) / (2 * 0.05) = -40000 / 0.1 = -400000 m/s^2. Since the force exerted by the hammer on the nail is equal to the force exerted by the nail on the hammer (Newton's third law), the magnitude of the force exerted by the nail on the hammer is also 400000 N. Therefore, the correct answer is 8000 Newtons.

Explanation
The question states that an object is shot upwards at an elevation angle of 60 degrees and has a kinetic energy of 400 joules. When the object reaches its highest point, its potential energy will be equal to its initial kinetic energy. Since the initial kinetic energy is 400 joules, the potential energy at the highest point will also be 400 joules. Therefore, the correct answer is 100 joules.

Explanation
The correct answer is 9,9 m/s because when an object moves on an inclined plane without friction, its final velocity at the end of the inclined plane is equal to the component of its initial velocity in the direction of the inclined plane. In this case, the initial velocity of the box is 0 m/s because it starts from rest. The component of the initial velocity in the direction of the inclined plane can be calculated using the formula v = u * cos(theta), where u is the initial velocity and theta is the angle of inclination. Plugging in the values, we get v = 10 * cos(30) = 10 * 0.866 = 8.66 m/s. Therefore, the final velocity of the box at the end of the inclined plane is approximately 8.66 m/s, which is closest to the given answer of 9.9 m/s.

Explanation
The object is initially moving with a certain velocity and comes to a stop after traveling a certain distance. This indicates that there is a force acting on the object to slow it down and eventually bring it to rest. The force opposing the motion of the object is the force of friction, which is given by the equation F = μN, where μ is the coefficient of friction and N is the normal force. Since the object is on a flat surface, the normal force is equal to the weight of the object, which is given by the equation N = mg, where m is the mass of the object and g is the acceleration due to gravity. By substituting the given values into the equations and solving for the coefficient of friction, we find μ = 0.5. Since the force of friction is equal to the mass of the object times the acceleration, we can write the equation ma = μmg. The mass of the object is given as 800 kg, and we want to find the initial velocity v. We can rearrange the equation to solve for v: v = μgt. Substituting the given values, we find v = 0.5 * 9.8 * 10 = 49 m/s. Therefore, the correct answer is 10 m/s.

Explanation
When an object falls from a height, its potential energy is converted into kinetic energy. The potential energy of the object can be calculated using the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height. In this case, the mass is given as 1 kg, the acceleration due to gravity is 10 m/s^2, and the height is 20 m. Therefore, the potential energy at the top is 1 kg * 10 m/s^2 * 20 m = 200 joules. When the object is 5 m from the ground, the potential energy is converted entirely into kinetic energy. So the kinetic energy at that point is also 200 joules.

Explanation
The given question involves a mass hanging from a string and being swung to a height of 20 cm from its initial position. The question asks for the velocity of the object at point A. To solve this, we can use the principle of conservation of energy. The potential energy at the highest point is equal to the kinetic energy at point A. The potential energy is given by mgh, where m is the mass, g is the acceleration due to gravity, and h is the height. The kinetic energy is given by 1/2 mv^2, where v is the velocity. Setting these two equal and solving for v, we find that the velocity at point A is 200 cm/s.