Linear Equations In Two Variables Quiz Questions And Answers

Since (2, 0) is a solution to the equation 2x + 3y = k, we can substitute the values of x and y into the equation. Plugging in x = 2 and y = 0, we get 2(2) + 3(0) = k, which simplifies to 4 = k. Therefore, the value of k is 4.

The positive solutions of the equation ax + by + c = 0 always lie in the first quadrant because in the first quadrant, both x and y values are positive. Since the equation is linear, the values of x and y can only be positive in order to satisfy the equation. Therefore, the positive solutions will always be in the first quadrant.

The given equation is x + 2y = 17. To check if x = 9 and y = 4 is a solution, we substitute these values into the equation.

9 + 2(4) = 17
9 + 8 = 17
17 = 17

Since the equation is true when x = 9 and y = 4, the answer x + 2y = 17 is correct.

Any point on the line y = x has the same x and y coordinates, which means that the x-coordinate and y-coordinate are equal. Therefore, the correct answer is (a, a).

The graph of x = 9 is a straight line parallel to the y-axis because the equation x = 9 means that the value of x is always 9 regardless of the value of y. This means that all points on the graph will have an x-coordinate of 9 and can have any y-coordinate. Therefore, the graph will be a vertical line parallel to the y-axis.

The correct answer is "Parallel to the y-axis at a distance 5 units from the origin." This is because the equation x = 5 represents a vertical line that is parallel to the y-axis. The line intersects the y-axis at the point (5,0) and is located 5 units to the right of the origin.

The correct answer is (x, 0) because any point on the x-axis has a y-coordinate of 0. The x-coordinate can be any real number, but the y-coordinate will always be 0. Therefore, the correct form for any point on the x-axis is (x, 0).

To find the form of the linear equation given the solutions (-3, 3), (0, 0), and (3, -3), we can use the point-slope form of a linear equation, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line and m is the slope of the line.

From the given solutions:

(-3, 3): x1 = -3, y1 = 3

(0, 0): x1 = 0, y1 = 0

(3, -3): x1 = 3, y1 = -3

First, let's find the slope using the points (-3, 3) and (0, 0): m = (y2 - y1) / (x2 - x1) m = (0 - 3) / (0 - (-3)) m = -3 / 3 m = -1

Now that we have the slope, we can plug it into the point-slope form for each point to determine the correct equation:

For point (-3, 3): y - 3 = -1(x - (-3)) y - 3 = -1(x + 3) y - 3 = -x - 3 y = -x

For point (0, 0): y - 0 = -1(x - 0) y = -x

For point (3, -3): y - (-3) = -1(x - 3) y + 3 = -x + 3 y = -x

Thus, the equation in the form that fits all the given points is: y = -x

Therefore, the correct option is: x + y = 0

The given linear equation has infinitely many solutions because it represents a straight line with a slope of 4/10 and a y-intercept of -14/10. This means that for every value of x, there will be a corresponding value of y that satisfies the equation. In other words, there are an infinite number of points that lie on the line and satisfy the equation.

The equation of a line parallel to the x-axis means that the line will have a constant y-value regardless of the x-value. Since the line is six units above the origin, the y-value will be 6. Therefore, the equation of the line parallel to the x-axis and six units above the origin is y = 6.

The graph of a linear equation is a straight line. To find the point where the line intersects the x-axis, we need to find the x-coordinate of that point. We can do this by setting y=0 in the equation and solving for x. In this case, when y=0, the equation becomes 5x + 3(0) = 10, which simplifies to 5x = 10. Dividing both sides by 5 gives x = 2. Therefore, the point where the line meets the x-axis is (2, 0).

The equation y = 5 represents a linear equation in two variables, x and y. In this equation, the coefficient of x is 0, which means that x does not affect the value of y. On the other hand, the coefficient of y is 1, indicating that y is equal to 5. Therefore, the equation 0 . x + 1 . y = 5 correctly represents the given equation y = 5.

The equation 2x – 3y = 5 has a unique solution if x and y are natural numbers. This means that x and y must be positive integers. If x and y were any other type of number, such as positive real numbers, real numbers, or rational numbers, there would be an infinite number of solutions to the equation. Therefore, the only way for the equation to have a unique solution is if x and y are natural numbers.

The linear equation 2x + 3y = 6 can be rewritten as 3y = -2x + 6. To find the point where the graph cuts the y-axis, we set x = 0 and solve for y. Plugging in x = 0 into the equation, we get 3y = 6, which gives y = 2. Therefore, the graph cuts the y-axis at the point (0, 2).