Latihan Unbk Biologi 2017 Paket 2

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Latihan Unbk Biologi 2017 Paket 2 - Quiz


Questions and Answers
  • 1. 

    Perhatikan gambar tumbuhan berikut.Berdasarkan gambar tumbuhan diatas, keanekaragaman yang terdapat pada tumbuhan  tersebut termasuk dalam keanekaragaman tingkat….

    • A.

      Gen

    • B.

      Genus

    • C.

      Komunitas

    • D.

      Spesies

    • E.

      Ekosistem

    Correct Answer
    D. Spesies
    Explanation
    Based on the given plant image, the diversity present in the plants can be classified as species diversity. This is because species diversity refers to the variety of different species within a particular area or ecosystem. In the image, there are multiple different plants, each belonging to a different species, indicating species diversity.

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  • 2. 

    Perhatikan gambar bermacam-macam jamur berikut.Yang termasuk ke dalam jenis jamur beracun adalah yang bernomor ….

    Correct Answer
    B.
  • 3. 

    Perhatikan interaksi berikut !
    1. Kucing dan tikus berada dalam satu ruangan
    2. Benalu yang menempel pada pohon mangga
    3. Tanaman Anggrek dan pohon yang ditumpanginya
    4. Ayam dan kambing yang berada pada tanah lapang
    5. Gangngan hijau biru dengan jamur Basidiomycotina
    Jenis interaksi yang hanya menguntungkan salah satu organisme terdapat pada nomor....

    • A.

      1), 2), dan 3)

    • B.

      1), 2, dan 4)

    • C.

      1), 3), dan 5)

    • D.

      2), 3).dan 4)

    • E.

      E. 3), 4), dan 5)

    Correct Answer
    A. 1), 2), dan 3)
    Explanation
    The correct answer is 1), 2), dan 3). This means that the types of interactions that only benefit one organism are present in options 1, 2, and 3. However, without the complete question, it is not possible to determine the specific types of interactions being referred to.

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  • 4. 

    Perhatikan gambar jenis Protozoa berikut ini!Jenis Protozoa tersebut masuk dalam kelompok ….

    • A.

      Rhizopoda

    • B.

      Flagellata

    • C.

      Ciliata

    • D.

      Mastigopora

    • E.

      Sporozoa

    Correct Answer
    C. Ciliata
    Explanation
    The correct answer is Ciliata because the image shown represents a type of protozoa that belongs to the Ciliata group. Ciliates are characterized by the presence of cilia, which are hair-like structures used for movement and feeding. They are typically found in aquatic environments and exhibit complex cellular structures.

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  • 5. 

    Perhatikan Aliran Energi pada jaring-jaring makanan di bawah ini !Dari gambar di atas organisme yang memiliki energi paling tinggi adalah....

    • A.

      Elang

    • B.

      Rubah

    • C.

      Laba-laba

    • D.

      Kelinci

    • E.

      Tumbuhan

    Correct Answer
    E. Tumbuhan
    Explanation
    The correct answer is Tumbuhan. In a food chain, energy flows from producers (plants) to consumers (animals). Plants are able to capture sunlight and convert it into chemical energy through photosynthesis. As a result, they have the highest energy level in the food chain. Elang, Rubah, Laba-laba, and Kelinci are all consumers and obtain their energy by consuming other organisms.

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  • 6. 

    Pada suatu ekosistem padang rumput terdapat jaring-jaring makanan sebagai berikut :Bila populasi ular dimusnahkan akan berakibat….

    • A.

      Populasi kijang meningkat, populasi belalang menurun

    • B.

      Populasi kelinci meningkat, populasi belalang meningkat

    • C.

      Populasi belalang meningkat, populasi padi meningkat

    • D.

      Populasi burung meningkat, populasi padi menurun

    • E.

      Populasi kelinci meningkat, populasi rumput menurun

    Correct Answer
    E. Populasi kelinci meningkat, populasi rumput menurun
    Explanation
    If the population of rabbits increases, it will result in a decrease in the population of grass. This is because rabbits are herbivores and rely on grass as their primary food source. As the rabbit population grows, they will consume more grass, leading to a decline in the available grass for other organisms in the ecosystem. This decrease in grass availability can have a cascading effect on other populations, such as insects that rely on grass for food or birds that rely on insects for food.

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  • 7. 

    Meningkatnya volume kendaraan di kota besar mengakibatkan peningkatan polusi udara. Cara yang dapat dilakukan untuk menanggulangi polusi tersebut adalah ...

    • A.

      Melakukan penghijauan hutan

    • B.

      Membuat monorel di kota besar

    • C.

      Menanam pohon di tiap ruas jalan

    • D.

      Lebih sering mengadakan car free day

    • E.

      Membuat undang-undang tentang polusi

    Correct Answer
    C. Menanam pohon di tiap ruas jalan
    Explanation
    The correct answer suggests that planting trees along every road can help mitigate air pollution caused by the increasing volume of vehicles in big cities. Trees are known to absorb carbon dioxide and release oxygen, which can help improve air quality. By planting trees along the roads, they can act as a natural filter, reducing the amount of pollutants in the air. This solution is practical and can be implemented in urban areas to combat air pollution effectively.

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  • 8. 

    Perhatikan gambar sel di bawah ini!Fungsi organel yang berlabel X adalah  ....

    • A.

      Pelindung bagian dalam sel

    • B.

      Tempat sintesis protein

    • C.

      Penghasil pigmen

    • D.

      Mengatur semua kegiatan sel

    • E.

      Tempat respirasi sel

    Correct Answer
    E. Tempat respirasi sel
    Explanation
    The organelle labeled X in the given image is the mitochondria, which is responsible for cellular respiration. Cellular respiration is the process by which cells convert glucose and oxygen into energy in the form of ATP. The mitochondria have an inner membrane that contains enzymes involved in the production of ATP through aerobic respiration. Therefore, the correct answer is "tempat respirasi sel" (the place of cellular respiration).

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  • 9. 

    Mekanisme trasport sel yang terjadi pada gambar di bawah ini adalah….

    • A.

      Difusi

    • B.

      Osmosis

    • C.

      Transport aktif

    • D.

      Endositosis

    • E.

      Eksositosis

    Correct Answer
    B. Osmosis
    Explanation
    The correct answer is osmosis. Osmosis is the movement of water molecules across a selectively permeable membrane from an area of lower solute concentration to an area of higher solute concentration. In the given image, it is likely that there is a difference in solute concentration on either side of the membrane, causing water molecules to move from one side to the other through osmosis.

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  • 10. 

    Perhatikan gambar penampang melintang batang dikotil di bawah ini !Nama bagian bernomor 2 dan fungsinya adalah ....

    • A.

      Kambium, membentuk jari-jari empulur

    • B.

      Floem, mengangkut hasil fotosintesis

    • C.

      Epidermis, melindungi bagian dalam batang

    • D.

      Xilem, mengangkut air dan garam dari tanah ke daun

    • E.

      Sistem pengangkuatan mengatur pengangkutan air dan hasil fotosintesis

    Correct Answer
    D. Xilem, mengangkut air dan garam dari tanah ke daun
    Explanation
    The correct answer is Xilem, mengangkut air dan garam dari tanah ke daun. Xylem is a tissue in plants that is responsible for transporting water and minerals from the roots to the leaves. It forms a network of tubes that allow for the upward movement of water and nutrients. This process is essential for the plant's survival as it provides the necessary resources for photosynthesis and other metabolic processes.

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  • 11. 

    Perhatikan gambar jaringan hewan dan perannya berikut ini !Hubungan yang benar antara jenis jaringan dengan fungsinya adalah ....

    • A.

      A

    • B.

      B

    • C.

      C

    • D.

      D

    • E.

      E

    Correct Answer
    B. B
    Explanation
    The correct answer is B. Unfortunately, without the provided options or additional information about the network of animal tissues and their functions, it is not possible to generate an explanation.

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  • 12. 

    Pehatikan gambar persendian berikut ini !Persendian pada gambar A dan B secara berurutan dapat melakukan gerakan ....

    • A.

      Fleksi dan ekstensi

    • B.

      Abduksi dan adduksi

    • C.

      Supinasi dan pronasi

    • D.

      Fleksi dan adduksi

    • E.

      Supinasi dan elevasi

    Correct Answer
    A. Fleksi dan ekstensi
    Explanation
    The correct answer is "Fleksi dan ekstensi" (Flexion and extension). This is because flexion refers to the movement that decreases the angle between two body parts, while extension refers to the movement that increases the angle between two body parts. In the given image, both joint A and B are capable of performing these movements.

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  • 13. 

    Perhatikan gambar mekanisme pembekuan darah berikut ini !Nama dan fungsi dari  bagian yang bernomor 1 adalah….

    • A.

      Trombokinase, mengubah protombin menjadi thrombin

    • B.

      Protombin, mengubah thrombin menjadi fibrinogen

    • C.

      Thrombin, mengubah fibrinogen menjadi fibrin

    • D.

      Trombokinase, mengubah thrombin menjadi fibrinogen

    • E.

      Trombokinase, mengubah fibrinogen menjadi fibrin

    Correct Answer
    A. Trombokinase, mengubah protombin menjadi thrombin
    Explanation
    The correct answer is "Trombokinase, mengubah protombin menjadi thrombin." In the process of blood clotting, thrombokinase is an enzyme that converts prothrombin into thrombin. Thrombin is then responsible for converting fibrinogen into fibrin, which forms a mesh-like structure to create a blood clot. Therefore, option 1 is the correct answer as it accurately identifies the name and function of the numbered part in the given mechanism of blood clotting.

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  • 14. 

    Perhatikan gambar sistem pencernaan manusia berikut !Fungsi dari organ yang berlabel X dan Y berturut turut adalah….

    • A.

      Tempat dimulainya pencernaan makanan, mencerna makanan secara mekanik.

    • B.

      Mencerna makanan secara mekanik, merupakan kelenjar penghasil ludah

    • C.

      Tempat dimulainya pencernaan makanan, untuk memotong dan mengoyak makanan yang masuk ke mulut

    • D.

      Mencerna makanan secara mekanik dan kimiawi, tempat pembusukkan makanan

    • E.

      Mencerna makanan secara mekanik, tempat pembusukkan makanan

    Correct Answer
    D. Mencerna makanan secara mekanik dan kimiawi, tempat pembusukkan makanan
    Explanation
    Organ X is responsible for digesting food mechanically, which means breaking down food into smaller pieces through physical movements such as chewing and grinding. Organ Y is responsible for digesting food both mechanically and chemically, indicating that it not only breaks down food physically but also releases enzymes to chemically break down food components. Additionally, organ Y is also involved in the process of food decomposition. Therefore, the correct answer is "Mencerna makanan secara mekanik dan kimiawi, tempat pembusukkan makanan."

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  • 15. 

    Perhatikan tabel hasil uji sampel urin berikut ini !Berdasarkan data hasil pengamatan di atas dapat disimpulkan bahwa Haslinda menderita penyakit….

    • A.

      Diabetes insipidus

    • B.

      Diabetes mellitus

    • C.

      Hematuria

    • D.

      Anuria

    • E.

      Albuminuria

    Correct Answer
    B. Diabetes mellitus
    Explanation
    Based on the given table of urine sample test results, it can be concluded that Haslinda is suffering from diabetes mellitus.

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  • 16. 

    Berikut ini gambar oogenesis yang terjadi dalam ovarium:Proses yang terjadi pada tahap bernomor 1 adalah ....

    • A.

      Oosit primer bermitosis menjadi oosit sekunder dan badan kutub satu dengan kromosom haploid

    • B.

      Oosit primer bermeiosis 1 membentuk oosit sekunder dan badan polar primer dengan kromosom haploid

    • C.

      Ootid bermeiosis menjadi ovum primer dan ovum sekunder dengan kromosom diploid

    • D.

      Oosit sekunder bermitosis menjadi 2 ootid dengan kromosom haploid

    • E.

      Oosit primer bermeiosis kemudian bermitosis membentuk oosit sekunder dan polosit satu yang haploid

    Correct Answer
    B. Oosit primer bermeiosis 1 membentuk oosit sekunder dan badan polar primer dengan kromosom haploid
    Explanation
    The correct answer states that during stage 1 of oogenesis, the primary oocyte undergoes meiosis 1 to form a secondary oocyte and a polar body, both with haploid chromosomes. This is the correct explanation as it accurately describes the process of oogenesis, where the primary oocyte goes through meiosis 1 to produce a secondary oocyte and a polar body, which contains half the number of chromosomes.

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  • 17. 

    Seorang siswa melakukan percobaan tentang pengaruh kadar giberellin terhadap pertumbuhan tanaman jagung. Setelah satu minggu diperoleh data seperti pada tabel berikut:Berdasarkan tabel hasil pengamatan di atas, yang merupakan variabel bebas dan variabel terikatnya adalah ....

    • A.

      Pengaruh kadar giberellin terhadap pertumbuhan tanaman jagung

    • B.

      Bagaimanakah pengaruh kadar giberellin terhadap pertumbuhan tanaman jagung

    • C.

      Variabel bebas kadar giberelin, variabel terikat tinggi tanaman

    • D.

      Variabel bebas tinggi tanaman, variabel terikat kadar giberelin

    • E.

      Tanaman dapat tumbuh optimal jika diberi kadar giberellin 500 ppm

    Correct Answer
    C. Variabel bebas kadar giberelin, variabel terikat tinggi tanaman
    Explanation
    Based on the given table, the independent variable is the "kadar giberelin" (level of gibberellin) and the dependent variable is the "tinggi tanaman" (plant height). The independent variable is the one that is manipulated or changed by the researcher, which in this case is the level of gibberellin. The dependent variable is the one that is measured or observed as a result of the changes in the independent variable, which in this case is the plant height. Therefore, the correct answer is "variabel bebas kadar giberelin, variabel terikat tinggi tanaman" (independent variable is the level of gibberellin, dependent variable is plant height).

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  • 18. 

    Dalam percobaan pertumbuhan, kelompok Ani memilih rumusan masalah: “Apakah kelembaban berpengaruh terhadap pertumbuhan kacang hijau?” Kelompok tanaman I di kardus atasnya ditutup kain kasa (Ø 2 cm = lubang  kasa), ditempatkan  di  teras,  tiap pagi kardus disemprot 1 botol air. Kelompok tanaman II, di kardus atasnya ditutup kain kasa Ø 2 cm, ditempatkan di teras yang sama, tiap pagi kardus disemprot 3 botol air.Berdasarkan perlakuan di atas, alasan penyemprotan air dengan jumlah yang berbeda bertujuan untuk ….

    • A.

      Memberi intensitas sinar yang berbeda

    • B.

      Memberi kelembaban yang berbeda

    • C.

      Mengatur penyerapan air oleh tanaman

    • D.

      Menjaga kandungan air dalam tanah

    • E.

      Menjaga kelembaban karena penutupan kasa

    Correct Answer
    B. Memberi kelembaban yang berbeda
    Explanation
    The reason for spraying different amounts of water is to provide different levels of humidity. By spraying 1 bottle of water on the first group of plants and 3 bottles on the second group, the experimenters are manipulating the humidity levels around the plants. This allows them to observe how different levels of humidity affect the growth of green beans. By comparing the growth of the two groups, they can determine whether humidity has an influence on the growth of the plants.

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  • 19. 

    Perhatikan grafik hubungan pH dengan rata-rata kecepatan reaksi untuk enzim pepsin dan amylase.Berdasarkan diagram di atas dapat disimpulkan bahwa….

    • A.

      Kecepatan reaksi untuk enzim pepsin dan amilase, tidak dipengaruhi oleh PH

    • B.

      Kecepatan reaksi untuk enzim pepsin dan amilase, pada PH asam

    • C.

      Kecepatan reaksi untuk enzim pepsin dan amilase, pada PH basa

    • D.

      Enzim pepsin bekerja optimum pada PH asam, sedangkan enzim amylase bekerja optimum pada PH netral

    • E.

      Enzim pepsin bekerja optimum pada PH basa, sedangkan enzim amylase bekerja optimum pada PH asam

    Correct Answer
    D. Enzim pepsin bekerja optimum pada PH asam, sedangkan enzim amylase bekerja optimum pada PH netral
    Explanation
    Based on the given graph, it can be concluded that the enzyme pepsin works best at acidic pH, while the enzyme amylase works best at neutral pH. This is because the graph shows that the average reaction rate for pepsin is highest at acidic pH levels, while the average reaction rate for amylase is highest at neutral pH levels. This indicates that the activity of these enzymes is influenced by the pH of the environment they are in.

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  • 20. 

    DNA tersusun atas senyawa:1 = basa nitrogen2 = gula deoksiribosa3 = asam fosfatDiagram struktur potongan DNA yang benar adalah....

    Correct Answer
    C.
  • 21. 

    Perhatikan  Siklus Calvin Bensen pada bagan berikut ini !Secara berurutan 1, 2 dan 3 adalah …

    • A.

      RDP, CO2 dan PGA

    • B.

      Klorofil, cahaya matahari dan amilum

    • C.

      Klorofil, O2 dan H2O

    • D.

      H2O, RDP, O2

    • E.

      CO2, RDP dan PGA

    Correct Answer
    A. RDP, CO2 dan PGA
  • 22. 

    Tahapan-tahapan sintesa protein :
    1. RNA d meninggalkan inti menuju ribosom
    2. RNA t mengikat asam amino yang sesuai
    3. RNA d dibentuk di dalam inti oleh DNA
    4. asam amino berderet sesuai dengan urutan kode genetik
    5. pembentukan protein yang diperintahkanUrutan yang sesuai dengan sintesa protein adalah ....

    • A.

      3, 2, 1, 4, dan 5

    • B.

      1, 2, 3, 4, dan 5

    • C.

      3, 1, 2, 4, dan 5

    • D.

      5, 4, 3, 2, dan 1

    • E.

      2, 3, 4, 1, dan 5

    Correct Answer
    C. 3, 1, 2, 4, dan 5
    Explanation
    The correct sequence of the steps in protein synthesis is 3, 1, 2, 4, and 5. First, RNA leaves the nucleus and goes to the ribosome. Then, RNA binds to the corresponding amino acids. Next, RNA is formed inside the nucleus by DNA. After that, the amino acids are arranged according to the genetic code. Finally, the protein is formed as instructed.

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  • 23. 

    Rangkaian percobaan uji fermentasi alkohol.Tabung A diisi glukosa + air + ragi.Tabung B diisi air kapur dan ditetesi fenolftalein, setelah 30 menit terjadi perubahan warna pada tabung B dari merah muda menjadi jernih.Perubahan warna terjadi karena ....

    • A.

      Peningkatan suhu yang terjadi di tabung A

    • B.

      Terbentuk etanol dari proses fermentasi di tabung A

    • C.

      Terbentuk energi dalam bentuk ATP

    • D.

      Penurunan suhu yang terjadi di tabung B

    • E.

      Adanya CO2 sebagai hasil fermentasi masuk ke tabung B

    Correct Answer
    E. Adanya CO2 sebagai hasil fermentasi masuk ke tabung B
    Explanation
    The correct answer is "adanya CO2 sebagai hasil fermentasi masuk ke tabung B." This is because the change in color from pink to clear in tube B indicates the presence of carbon dioxide (CO2), which is a byproduct of alcohol fermentation. The reaction between CO2 and water in tube B forms carbonic acid, causing the phenolphthalein indicator to change from pink (alkaline) to clear (acidic). This confirms that fermentation has occurred in tube A, producing CO2 that has entered tube B.

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  • 24. 

    Gambar fase pemblahan selBerdasarkan gambar  fase tersebut adalah .....

    • A.

      Interfase

    • B.

      Profase

    • C.

      Anafase

    • D.

      Metafase

    • E.

      Telofase

    Correct Answer
    D. Metafase
    Explanation
    Based on the given information, the correct answer is "metafase". The explanation for this is that the image shows the phase of cell division where the chromosomes are aligned at the center of the cell. This phase is known as metaphase.

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  • 25. 

    Seorang ibu membeli buah mangga di pasar, ternyata buah mangga yang dibelinya rasanya    manis tetapi berdaging tipis. Kemungkinan genotip kedua induknya adalah ....

    • A.

      MMtt >< Mmtt

    • B.

      MMTT >< Mmtt

    • C.

      MMTT >< MMtt

    • D.

      MmTT >< Mmtt

    • E.

      MmTT >< MmTT

    Correct Answer
    A. MMtt >< Mmtt
    Explanation
    The correct answer is MMtt >< Mmtt. This is because the mother purchased mangoes that were sweet but had thin flesh. This indicates that the mother mango (MMtt) had a genotype for sweet taste (MM) but a genotype for thin flesh (tt). The father mango (Mmtt) must have had a genotype for both sweet taste (Mm) and thin flesh (tt). When these genotypes are crossed, they can produce offspring with a genotype of MMtt, which would explain the characteristics of the mangoes the mother bought.

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  • 26. 

    Tanaman   berbatang   tinggi   (TT)   dominan terhadap  pendek (tt), bunga di  ujung  (UU) dominan terhadap bunga di pangkal (uu). Apabila tanaman  bergenotip  TtUU  disilangkan dengan tanaman heterozigot (TtUu) menghasilkan 480 biji tanaman.  Kemungkinan biji tanaman akan menghasilkan tumbuhan berbatang pendek dan berbunga di ujung adalah sejumlah ….

    • A.

      30

    • B.

      90

    • C.

      120

    • D.

      240

    • E.

      360

    Correct Answer
    C. 120
    Explanation
    When the genotype of the first plant is TtUU and it is crossed with a heterozygous plant TtUu, the possible genotypes of the offspring are TtUU, TtUu, TtuU, and Ttuu. The question asks for the number of offspring that will have the phenotype of short stem and flowers at the top. The only genotype that will produce this phenotype is Ttuu. Since the genotype Ttuu is only possible in one out of the four possible genotypes, the number of offspring that will have this phenotype is 1 out of 4, which is equal to 120 out of 480. Therefore, the correct answer is 120.

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  • 27. 

    Dari persilangan gandum berkulit hitam (HHkk) dengan gandum berkulit kuning (hhKK) diperoleh semua keturunannya berkulit hitam. Apabila gandum berkulit hitam (HhKk) disilangkan dengan gandum berkulit kuning (hhKk), maka kemungkinan rasio penotif keturunannya yang berkulit hitam : kuning : putih adalah ....

    • A.

      12 : 3 : 1

    • B.

      12 : 1 : 3

    • C.

      4 : 3 : 1

    • D.

      3 : 3 : 2

    • E.

      1 : 2 : 1

    Correct Answer
    C. 4 : 3 : 1
    Explanation
    The given question involves a cross between wheat plants with black husk (HHkk) and wheat plants with yellow husk (hhKK). All the offspring from this cross have black husk, indicating that the black husk trait is dominant over the yellow husk trait. When wheat plants with black husk (HhKk) are crossed with wheat plants with yellow husk (hhKk), the possible ratio of their offspring with black : yellow : white husk is 4 : 3 : 1. This is because the black husk trait is dominant over the yellow husk trait, but both traits are dominant over the white husk trait. Therefore, the correct answer is 4 : 3 : 1.

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  • 28. 

    Disilangkan ayam berpial rose (Rrpp) dengan ayam berpial walnut (RrPp). Hasil  persilangan  tersebut  memunculkan  4 macam varian ayam dengan pial yang berbeda-beda.  Persentase  fenotip  walnut  dan  rose secara berturut-turut adalah ….

    • A.

      12,5% dan 25%

    • B.

      25% dan 25%

    • C.

      25% dan 37,5%

    • D.

      37,5% dan 37,5%

    • E.

      37,5% dan 50%

    Correct Answer
    D. 37,5% dan 37,5%
    Explanation
    The given question describes a cross between two types of chickens, one with rose comb (Rrpp) and the other with walnut comb (RrPp). The cross results in four different variants of chickens with different comb types. The percentage of walnut comb phenotype and rose comb phenotype is 37.5% each. This means that out of the four possible combinations of alleles, two of them will result in the walnut comb phenotype and the other two will result in the rose comb phenotype.

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  • 29. 

    Diketahui gen ekspresi bunga Linaria marocana :A = Pigmen antosianin                    a = tidak ada pigmenB = Suasana Basa                            b = suasana asamJika tanaman Linaria marocana bunga merah (Aabb) disilangkan dengan yang berbunga ungu (AaBb) menghasilkan keturunan sebayak 160 tanaman, maka rasio fenotip yang diperoleh adalah ....

    • A.

      40 ungu ; 60 merah ;60 putih

    • B.

      40 merah ; 90 putih ; 30 ungu

    • C.

      90 ungu ; 30 merah ; 20 putih

    • D.

      60 ungu ; 60 putih ; 40 merah

    • E.

      60 ungu ; 60 merah ; 40 putih

    Correct Answer
    D. 60 ungu ; 60 putih ; 40 merah
    Explanation
    The given answer suggests that the phenotypic ratio obtained from the cross between the red-flowered Linaria marocana (Aabb) and the purple-flowered Linaria marocana (AaBb) is 60 ungu (purple), 60 putih (white), and 40 merah (red). This ratio is derived from the combination of alleles in the parent plants and follows Mendelian inheritance patterns.

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  • 30. 

    Diketahui pada lalat buah warna tubuh abu-abu dominan (A) terhadap warna hitam (a) dan sayap panjang (P) dominan terhadap sayap pendek (p).  Persilangan lalat buah jantan abu-abu sayap panjang dengan lalat buah betina hitam sayap pendek diperoleh F1 lalat buah Abu-abu sayap panjang 100%. Jika F1 Jantan Abu-abu sayap panjang mengalami pindah silang ditescroskan maka diperoleh keturunan dengan genotipe sebagai berikut, Kecuali....

    • A.

      AAPP

    • B.

      AaPp

    • C.

      Aapp

    • D.

      AaPp

    • E.

      Aapp

    Correct Answer
    A. AAPP
    Explanation
    The given question describes a cross between a gray, long-winged male fruit fly and a black, short-winged female fruit fly. The F1 generation consists of all gray, long-winged fruit flies. If the F1 generation undergoes a test cross, the expected offspring genotypes would be AaPp, Aapp, aaPp, and aapp. However, the genotype AAPP is not expected in the offspring. Therefore, the correct answer is AAPP.

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  • 31. 

    Seorang pria normal menikah dengan wanita normal yang ayahnya penderita buta warna. Dari hasil perkawian tersebut diperoleh 2 orang anak laki-laki dan 2 orang anak perempuan. Kemungkinan fenotipe anak-anaknya adalah ....

    • A.

      100% normal

    • B.

      50% normal dan 50% Buta warna

    • C.

      75% normal dan 25% buta warna

    • D.

      100% anak laki-laki normal dan 50% buta warna

    • E.

      25% anak laki-laki normal dan 75% buta warna

    Correct Answer
    C. 75% normal dan 25% buta warna
    Explanation
    From the given information, we know that the man is normal and his wife is also normal, but her father is color blind. Color blindness is a recessive trait that is carried on the X chromosome. Since the woman's father is color blind, it means that she carries one copy of the color blindness gene. The man does not carry the color blindness gene. When they have children, there is a 50% chance that the woman will pass on her copy of the color blindness gene to each of her children. Therefore, there is a 25% chance that each child will be color blind (25% buta warna) and a 75% chance that each child will be normal (75% normal).

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  • 32. 

    Perhatikan diagram perkawinan berikut ini !Genotip yang bernomor 2,3 dan 4 secara berurutan adalah ….

    • A.

      XBY, XBXb, XbY

    • B.

      XbY, XBXB, XbY

    • C.

      XbY, XBXb, XbY

    • D.

      XbY, XbXb, XbY

    • E.

      XbY, XBXb, XBY

    Correct Answer
    C. XbY, XBXb, XbY
    Explanation
    The correct answer is XbY, XBXb, XbY. This is because in the given genotype, the first individual has a sex chromosome combination of XbY, the second individual has a sex chromosome combination of XBXb, and the third individual has a sex chromosome combination of XbY.

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  • 33. 

    Perhatikan gambar mutasi berikut !Jenis mutasi tersebut adalah ....

    • A.

      Translokasi

    • B.

      Insersi

    • C.

      Delesi

    • D.

      Duplikasi

    • E.

      Transversi

    Correct Answer
    B. Insersi
    Explanation
    Based on the given image of the mutation, it appears that there is an additional segment of genetic material inserted into the original sequence. This type of mutation is known as "insertion."

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  • 34. 

    Marmot hitam disilangkan dengan marmot albino menghasilkan 12 keturunan hitam. Apabila marmot hitam yang salah satu induknya albino disilangkan dengan marmot hitam generasi kedua, diperoleh 9 hitam dan 3 albino. Penjelasan yang tepat untuk keadaan tersebut adalah ....

    • A.

      Hitam bersifat resesif

    • B.

      Albino bersifat dominan

    • C.

      Generasi kedua heterozigot

    • D.

      Hitam dan albino alela ganda

    • E.

      Hitam dan albino saling mendominasi

    Correct Answer
    C. Generasi kedua heterozigot
    Explanation
    The correct answer suggests that the second generation of black marmots is heterozygous. This means that they carry both the dominant and recessive alleles for black and albino traits. This is supported by the fact that when a black marmot with an albino parent is crossed with a black marmot, 9 black and 3 albino offspring are produced. This indicates that the black marmot parent carries both the dominant allele for black and the recessive allele for albino, resulting in a mixture of black and albino offspring in the second generation.

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  • 35. 

    Perhatikan pernyataan-pernyataan berikut ini.
    1. Di muka bumi ini tidak ada individu yang sama
    2. Setiap populasi berkecenderungan untuk bertambah banyak
    3. Pada saat berkembang biak, makhluk hidup memerlukan makanan dan ruang yang cukup
    4. Variasi yang diwariskan induk kepada keturunannya diatur oleh factor genetic bukan faktor lingkungan
    5. Makhluk hidup akan menyesuaikan diri baik secara fisiologis maupun morfologis
    Setelah melakukan observasi di kepulauan Galapagos, Darwin membuat beberapa poin penting tentang teori evolusi makhluk hidup. Beberapa hal pokok dalam teori evolusi Darwin terdapat pada nomor….

    • A.

      (1), (2), dan (3)

    • B.

      (1), (2), dan (5)

    • C.

      (2), (3), dan (4)

    • D.

      (2), (4), dan (5)

    • E.

      (3), (4), dan (5)

    Correct Answer
    A. (1), (2), dan (3)
    Explanation
    The correct answer is (1), (2), and (3). This is because in the given statements, Darwin's main points about the theory of evolution are mentioned. Statement (1) states that there are no identical individuals on Earth, which supports the idea of variation within a population. Statement (2) suggests that populations tend to increase in size, which is a fundamental concept in Darwin's theory. Statement (3) highlights the need for food and space during reproduction, which relates to the struggle for existence and natural selection. Therefore, all three statements align with Darwin's theory of evolution.

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  • 36. 

    Perhatikan gambar perangkat percobaan Francesco Redi berikut ini !Setelah dibiarkan beberapa hari diperoleh hasil sebagai berikut :
    • Ditutup rapat, tidak ada larva
    • Terbuka, ada banyak larva
    • Ditutup kain kasa, ada sedikit larva
    Berdasarkan percobaan Francesco Redi, maka dapat disimpulkan bahwa….

    • A.

      Kehidupan berasal dari tempat yang bersih

    • B.

      Kehidupan berasal dari tempat terbuka

    • C.

      Makhluk hidup berasal dari makhluk hidup

    • D.

      Tempat terbuka sumber makhluk hidup

    • E.

      Tempat tertutup menghambat makhluk hidup

    Correct Answer
    C. Makhluk hidup berasal dari makhluk hidup
    Explanation
    Based on Francesco Redi's experiment, it can be concluded that living organisms come from other living organisms. This is because in the experiment, when the jar was tightly closed, no larvae were found, indicating that the presence of living organisms was prevented. However, when the jar was left open, many larvae were found, suggesting that living organisms were able to enter and reproduce. Additionally, when the jar was covered with gauze, only a few larvae were found, indicating that the gauze acted as a barrier, limiting the entry and reproduction of living organisms. Therefore, the correct answer is "Makhluk hidup berasal dari makhluk hidup" (Living organisms come from other living organisms).

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  • 37. 

    Pernyataan di bawah ini menyebabkan perubahan leher jerapah.(1) Jerapah berleher panjang berasal dari induk jerapah berleher pendek(2) Pada masa lampau terdapat jerapah berleher panjang maupun berleher pendek.(3) Memanjangnya leher jerapah karena pengaruh lingkungan.(4) Jerapah berleher pendek mati, sedangkan berleher panjang tetap lestari/hidup.Teori Darwin yang ada hubungannya dengan evolusi jerapah ditunjukkan oleh ....

    • A.

      (1) dan (2)

    • B.

      (1) dan (4)

    • C.

      (2) dan (3)

    • D.

      (2) dan (4)

    • E.

      (3) dan (4)

    Correct Answer
    B. (1) dan (4)
    Explanation
    The correct answer is (1) dan (4). The statement (1) suggests that giraffes with long necks originated from giraffes with short necks, indicating a change in the neck length over time. The statement (4) implies that giraffes with short necks died out while those with long necks survived, further supporting the idea of evolution and natural selection. Both statements align with Darwin's theory of evolution, making (1) dan (4) the correct answer.

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  • 38. 

    Perhatikan gambar  anggota gerak depan pada hewan berikut !Berdasarkan gambar tersebut, anggota gerak depan pada hewan 1 dan 2 berturut- turut merupakan contoh organ….

    • A.

      Homologi dan analogi

    • B.

      Analogi dan homologi

    • C.

      Keduanya homologi

    • D.

      Keduanya analogi

    • E.

      Keduanya bukan organ homologi ataupun analogi

    Correct Answer
    A. Homologi dan analogi
    Explanation
    Based on the given image, it can be observed that the front limbs of animals 1 and 2 have similar structures but serve different functions. This indicates that they are examples of both homology and analogy. Homology refers to the similarity in structure due to common ancestry, while analogy refers to the similarity in function due to similar environmental pressures. Therefore, the correct answer is "Homologi dan analogi."

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  • 39. 

    Pada suatu daerah dengan 10.000 penduduk, terdapat 4% warga yang albino. Maka perbandingan jumlah orang yang berkulit normal homozigot dan heterozigot secara berurutan adalah ....

    • A.

      6.400 dan 1.600

    • B.

      6.400 dan 3.200

    • C.

      3.200 dan 1.600

    • D.

      3.200 dan 400

    • E.

      1.600 dan 400

    Correct Answer
    B. 6.400 dan 3.200
    Explanation
    The correct answer is 6.400 dan 3.200. The question states that in a population of 10,000 people, 4% are albino. This means that 4% of the population are homozygous for the albino trait. Since homozygous individuals have two copies of the same allele, the number of homozygous individuals would be 4% of 10,000, which is 400. The remaining 3,200 individuals would be heterozygous, meaning they have one copy of the albino allele and one copy of the normal allele. Therefore, the ratio of homozygous to heterozygous individuals is 400:3,200, which simplifies to 1:8 or 6,400:3,200.

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  • 40. 

    1. Perhatikan beberapa produk bioteknologi berikut.
    1. Antibiotik
    2. Antibodi monoklonal
    3. Biogas
    4. Domba hasil kloning
    5. Anggur minuman
    6. Organism transgenik
    Produk bioteknologi merupakan hasil dari bioteknologi konvensional adalah nomor….

    • A.

      1, 2, 3

    • B.

      1, 3, 6

    • C.

      1, 3, 5

    • D.

      1, 2, 5

    • E.

      1, 2, 6

    Correct Answer
    C. 1, 3, 5
    Explanation
    Antibiotik (antibiotics) and Biogas are products of conventional biotechnology. Antibodi monoklonal (monoclonal antibodies), Domba hasil kloning (cloned sheep), and Organisme transgenik (transgenic organisms) are products of modern biotechnology. Therefore, the correct answer is 1, 3, 5.

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  • Current Version
  • Mar 22, 2023
    Quiz Edited by
    ProProfs Editorial Team
  • Apr 01, 2017
    Quiz Created by
    Fannisa
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