Ilp C++ Final Quiz
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What is the output of the following code class base{ public : virtual void func1()=0; void func2() { cout<<"\n In base, function2"; } }; //end of class class derived : public base{ public : void fun3() { cout<<"\n In derived , function3"; } };//end of class int main(){ derived d; d.fun3(); return 0; }
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In derived, function1
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In derived , function3
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Compilation error
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In base, function2
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The ILP C++ Final Quiz assesses advanced understanding of C++ programming concepts including virtual functions, exception handling, operator overloading, and memory management. This quiz is designed to challenge learners on key aspects of C++ and object-oriented programming.
Quiz Preview
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A special library function which is called automatically when no handler at any level catches the exception
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Exit()
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Terminate()
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Quit()
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Ellipse
Correct Answer
A. Terminate()Explanation
The terminate() function is a special library function that is called automatically when no exception handler at any level catches the exception. It is responsible for terminating the program and cleaning up any resources that were allocated.Rate this question:
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- 3.
What is the output of the following code int main() { char s1[20]="Hello"; char s2[20]="Hai"; s2=s1; cout<<"String1 : "<<s1; cout<<" String2 : "<<s2; return 0; }
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String1 : Hello String2 : Hai
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String1 : Hello String2 : Hello
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Error : forbidden assignment of arrays
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Error: incompatible types in assignment
Correct Answer
A. Error : forbidden assignment of arraysExplanation
The given code tries to assign one array to another, which is not allowed in C++. This results in a compilation error stating "forbidden assignment of arrays". Arrays cannot be assigned directly to each other in C++, instead, you need to use functions like strcpy or strncpy to copy the contents of one array to another.Rate this question:
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- 4.
class Test{ public: ~Test() { cout<<" Destructor"; } }; //end of class int main() { Test t; t.~Test(); return 0; }
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Run time error
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Destructor Destructor
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Compilation error
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Destructor
Correct Answer
A. Destructor DestructorExplanation
The given code snippet creates an object of the Test class named "t" in the main function. Then, the destructor of the Test class is explicitly called using the syntax "t.~Test();". This results in the destructor being called twice, leading to the output "Destructor Destructor". Therefore, the correct answer is "Destructor Destructor".Rate this question:
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- 5.
class VirtualClass { int x,y; public: VirtualClass() { x=1,y=2; } virtual void operator<<(ostream&); }; // end of class void VirtualClass::operator<<(ostream &os) { os<<this->x<<"\t"<<this->y; } int main() { VirtualClass vcObj; vcObj<<cout; return 0; }
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1 2
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Compilation error
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Run time error
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None of the above
Correct Answer
A. 1 2Explanation
The code defines a class called VirtualClass with two integer variables x and y. The constructor initializes x to 1 and y to 2. The class also overloads theRate this question:
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- 6.
int main() { int a=2,b=3; if ((a==2) || (b++==4)) cout<<"success"; return 0; } What will be the values of a and b ?
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2,3
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2,4
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2,5
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None of the above
Correct Answer
A. 2,3Explanation
The values of a and b will be 2 and 3 respectively. In the if statement, the first condition (a==2) is true, so the second condition (b++==4) is not evaluated. Therefore, the value of b remains unchanged. Since the if statement is true, the statement "success" is printed.Rate this question:
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- 7.
What is the output of the below code int main(){ int i=0; for(i=0;i<20;i++) switch(i) { case 0:i+=5; case 1:i+=2; case 5:i+=5; default: i+=4; } cout<<i; return 0; }
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84
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5
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22
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16
Correct Answer
A. 22Explanation
The code starts with initializing the variable i to 0. Then, it enters a for loop with the condition iRate this question:
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- 8.
What is the output of the following code class base{ public : virtual void display() { cout<<" \n I am in base-display ";} void virtual show() { cout<<" \n I am in base-show "; } virtual void show1(){cout<<"In base show1 ";} }; class derived : public base {}; int main(){ derived d; cout<<sizeof(d)<<"\n";}
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4
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8
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10
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16
Correct Answer
A. 8Explanation
The output of the code is 8. This is because the sizeof operator is used to determine the size of an object or data type in bytes. In this case, the object "d" is of type "derived", which is derived from the base class. Since the derived class does not have any additional member variables or functions, its size is the same as the base class, which is 8 bytes.Rate this question:
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- 9.
What is the output of the following code int main(){ int i=4,j; j=i<<2; cout<<j; return 0;}
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4
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8
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12
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16
Correct Answer
A. 16Explanation
The code assigns the value 4 to the variable i. Then, it performs a left shift operation on i by 2 bits, resulting in 16. Finally, it prints the value of j, which is 16.Rate this question:
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- 10.
#define SQR(x) (x*x) main() { int a,b=3; a=SQR(b+2); cout<<a; return 0; }
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11
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25
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Error
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17
Correct Answer
A. 11Explanation
The correct answer is 11.
In the given code, the macro SQR(x) is defined as (x*x).
In the main function, the value of b is 3.
The expression a=SQR(b+2) is evaluated as a=(b+2)*(b+2), which becomes a=3+2*3+2, which simplifies to a=11.
Therefore, the value of a is 11, which is outputted by the cout statement.Rate this question:
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Current Version
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Feb 17, 2023Quiz Edited by
ProProfs Editorial Team -
Sep 12, 2012Quiz Created by
Srikanth_kanthet
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