Real Number (Class X )
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For some integer ‘m’ every odd integer is of form:
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M + 1
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2 m
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M
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2 m + 1
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This Class X quiz on Real Numbers tests understanding of integer properties, highest common factors, and number forms. It assesses key mathematical skills relevant for students, enhancing their problem-solving abilities in mathematics.
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- 2.
H. C. F. of 96 and 404 is
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8
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4696
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96
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4
Correct Answer
A. 4Explanation
The H.C.F. (Highest Common Factor) is the highest number that divides both 96 and 404 without leaving a remainder. In this case, the only number that satisfies this condition is 4. Therefore, 4 is the correct answer.Rate this question:
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- 3.
Write the HCF of the smallest composite number and the smallest even number
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4
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0
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1
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2
Correct Answer
A. 2Explanation
The HCF (Highest Common Factor) is the largest number that divides two or more numbers without leaving a remainder. In this case, the smallest composite number is 4, which can be divided by 1, 2, and 4. The smallest even number is 2, which can be divided by 1 and 2. The highest number that is common to both 4 and 2 is 2, as it is the largest number that divides both numbers without leaving a remainder. Therefore, the HCF of the smallest composite number and the smallest even number is 2.Rate this question:
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- 4.
HCF of the smallest composite number and the smallest prime number is
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0
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2
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4
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1
Correct Answer
A. 2Explanation
The HCF (Highest Common Factor) of any two numbers is the largest number that divides both of them without leaving a remainder. In this case, the smallest composite number is 4 (as it is the smallest number that is divisible by numbers other than 1 and itself) and the smallest prime number is 2. The only number that divides both 4 and 2 without leaving a remainder is 2, making it the HCF of the two numbers. Thus, the correct answer is 2.Rate this question:
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- 5.
If n is a positive integer , then n2 – n is always
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Multiple of 2 and 4
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Prime number
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Odd number
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Even number
Correct Answer
A. Even numberExplanation
When we expand the expression n^2 - n, we get n(n-1). Since n is a positive integer, both n and n-1 will be positive integers. Now, consider two consecutive positive integers. One of them will always be even and the other will always be odd. Thus, when we multiply an even number with an odd number, the result will always be an even number. Therefore, n^2 - n will always be an even number.Rate this question:
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- 6.
What is the HCF of 235 and 395?
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25
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5
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35
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15
Correct Answer
A. 5Explanation
The HCF (Highest Common Factor) is the largest number that can evenly divide both 235 and 395. In this case, the only number that can divide both 235 and 395 is 5. Therefore, the HCF of 235 and 395 is 5.Rate this question:
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- 7.
H.C.F. of two consecutive even numbers is
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2
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0
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4
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1
Correct Answer
A. 2Explanation
The H.C.F. (Highest Common Factor) of two consecutive even numbers is always 2. This is because every even number is divisible by 2. Since the two consecutive even numbers have no other common factors besides 2, the H.C.F. is 2.Rate this question:
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- 8.
4052 = 420 x q + 272 then value of q is
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12
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7
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8
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9
Correct Answer
A. 9Explanation
The given equation states that 4052 is equal to 420 times q plus 272. To find the value of q, we need to isolate it on one side of the equation. We can do this by subtracting 272 from both sides of the equation, which gives us 3780 = 420q. Next, we can divide both sides of the equation by 420, resulting in q = 9. Therefore, the value of q is 9.Rate this question:
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- 9.
For any two positive integers a and b, there exist unique integers q and r such that a = bq + r, 0 ≤ r < b, if b = 4 then which is not the value of r?
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2
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1
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3
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4
Correct Answer
A. 4Explanation
For any two positive integers a and b, there exist unique integers q and r such that a = bq + r, 0 ≤ r < b. In this case, b = 4. The possible values for r when b = 4 are 0, 1, 2, and 3. The only value that is not possible for r is 4.Rate this question:
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- 10.
For a=n and b=3, which of the following represents the correct mathematical form of Euclid’s division lemma?
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N = q+ 3
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N = 3q - r
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N = 3q +r
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N = 3q + n
Correct Answer
A. N = 3q +rExplanation
Euclid's division lemma states that for any two positive integers a and b, there exist unique integers q and r such that a = bq + r, where 0 ≤ r < b. In this case, the correct mathematical form of Euclid's division lemma is n = 3q + r. This equation represents the division of n by 3, where q is the quotient and r is the remainder.Rate this question:
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- 11.
Euclid’s division lemma states that if a and b are two positive integers, then there exist unique integers q and r such that:
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a = bq + r, 0 ≤ r ≤ b
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A = bq + r, 0 < r < b
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A = bq + r, 0 < b ≤ r
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A = bq + r, 0 ≤ r < b
Correct Answer
A. A = bq + r, 0 ≤ r < bExplanation
The correct answer is a = bq + r, 0 ≤ r < b. This is because Euclid's division lemma states that when dividing a positive integer a by a positive integer b, there exist unique integers q and r such that a = bq + r, where 0 ≤ r < b. This means that the remainder (r) when dividing a by b is always greater than or equal to 0 and less than b.Rate this question:
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- 12.
Complete the statement : Any positive odd integer is of the form 6q + 1, or 6q + 3, or ___________, where q is some positive interger.
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6q + 5
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6q + 4
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6q + 2
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6q
Correct Answer
A. 6q + 5Explanation
Any positive odd integer can be represented as 6q + 1, where q is a positive integer. The given statement suggests that the positive odd integer can also be expressed as 6q + 3 or 6q + 5. This is because when q is a positive integer, multiplying it by 6 and adding 3 or 5 will always result in an odd number. Therefore, the correct answer is 6q + 5.Rate this question:
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Dec 12, 2024Quiz Edited by
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Apr 08, 2020Quiz Created by
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