Chpt. 4 - Section A: Gases In The Atmosphere

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  • 1/16 Questions

    This gas is the most abundant in the atmosphere.

    • Nitrogen
    • Hydrogen
    • Oxygen
    • Argon
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About This Quiz

This quiz covers key concepts about gases in the atmosphere, including their properties and behaviors under different conditions, as outlined in Chapter 4, Section A.

Gases Quizzes & Trivia

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  • 2. 
    Which of the following terms best describes the relationship between temperature and volume? - ProProfs

    Which of the following terms best describes the relationship between temperature and volume?

    • Inversely related

    • Directly related

    • Complimentary

    • Indirectly related

    Correct Answer
    A. Directly related
    Explanation
    The term "directly related" best describes the relationship between temperature and volume. This means that as temperature increases, the volume also increases, and as temperature decreases, the volume decreases. The two variables change in the same direction, indicating a positive correlation between them.

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  • 3. 
    A temperature of 373 K is equal to what temperature on the Celsius scale? - ProProfs

    A temperature of 373 K is equal to what temperature on the Celsius scale?

    • 0 degrees Celsius

    • 100 degrees Celsius

    • 373 degrees Celsius

    • 646 degrees Celsius

    Correct Answer
    A. 100 degrees Celsius
    Explanation
    A: 0 degrees is the freezing point of water
    C & D: is Celsius plus 273 = kelvin

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  • 4. 
    Which of the following terms best describes the relationship between pressure and volume? (Boyle's Law) - ProProfs

    Which of the following terms best describes the relationship between pressure and volume? (Boyle's Law)

    • Inversely related

    • Directly related

    • Complimentary

    • Indirectly related

    Correct Answer
    A. Inversely related
    Explanation
    Boyle's Law states that the pressure and volume of a gas are inversely related when temperature is held constant. This means that as the volume of a gas increases, the pressure decreases, and vice versa. This relationship can be explained by the behavior of gas molecules. When the volume of a gas is decreased, the molecules are forced closer together, resulting in more frequent collisions with the container walls and an increase in pressure. Conversely, when the volume is increased, the molecules have more space to move around, leading to fewer collisions and a decrease in pressure. Therefore, "inversely related" is the best term to describe the relationship between pressure and volume in Boyle's Law.

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  • 5. 
    In the relationship described by Boyle's law, which property must remain constant? - ProProfs

    In the relationship described by Boyle's law, which property must remain constant?

    • Pressure

    • Temperature

    • Volume

    Correct Answer
    A. Temperature
    Explanation
    Boyle's law states that the pressure of a gas is inversely proportional to its volume, as long as the temperature remains constant. This means that if the volume of a gas decreases, its pressure will increase, and vice versa. Therefore, in the relationship described by Boyle's law, the property that must remain constant is temperature. Any changes in temperature would affect the relationship between pressure and volume, violating Boyle's law.

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  • 6. 
    If temperature is held constant, decreasing the volume of a sample of gas will cause its pressure to.. - ProProfs

    If temperature is held constant, decreasing the volume of a sample of gas will cause its pressure to..

    • Decrease

    • Increase

    • Remain the same

    Correct Answer
    A. Increase
    Explanation
    according to Boyle's Law, volume is inverse to pressure. Decreasing the volume will increase the pressure.

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  • 7. 
    When air is removed from a bell jar with a vacuum pump reducing the pressure in the bell jar (at constant temperature), a sealed inflated balloon inside the bell jar - ProProfs

    When air is removed from a bell jar with a vacuum pump reducing the pressure in the bell jar (at constant temperature), a sealed inflated balloon inside the bell jar

    • Gets smaller

    • Gets larger

    • Stays the same size

    Correct Answer
    A. Gets larger
    Explanation
    When air is removed from a bell jar with a vacuum pump, the pressure inside the bell jar decreases. As a result, the pressure inside the inflated balloon becomes higher than the pressure outside. This pressure difference causes the balloon to expand and get larger in size.

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  • 8. 
    What causes pressure inside a tire? - ProProfs

    What causes pressure inside a tire?

    • Gas molecules colliding with each other

    • Gas molecules colliding with the wall of the tire

    • The diffusion of the gases

    • Constant changing of temperature

    Correct Answer
    A. Gas molecules colliding with the wall of the tire
    Explanation
    The pressure inside a tire is caused by gas molecules colliding with the wall of the tire. As the gas molecules move around inside the tire, they collide with the walls, exerting a force. This force creates pressure, which is measured in pounds per square inch (psi). The more collisions that occur, the higher the pressure inside the tire.

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  • 9. 
    A sample of oxygen occupies 400mL when the pressure is 800mm Hg. If the temperature is held constant, what is the volume that the gas will occupy if the pressure decreases to 400mm Hg? (Boyle's Law: P1V1 = P2V2) - ProProfs

    A sample of oxygen occupies 400mL when the pressure is 800mm Hg. If the temperature is held constant, what is the volume that the gas will occupy if the pressure decreases to 400mm Hg? (Boyle's Law: P1V1 = P2V2)

    • 200mL

    • 800mL

    • 1600mL

    • 2400mL

    Correct Answer
    A. 800mL
    Explanation
    According to Boyle's Law, the product of pressure and volume is constant when temperature is held constant. In this case, the initial pressure is 800mm Hg and the initial volume is 400mL. The final pressure is 400mm Hg. To find the final volume, we can rearrange Boyle's Law equation as P1V1 = P2V2 and solve for V2. Plugging in the given values, we get (800mm Hg)(400mL) = (400mm Hg)(V2). Solving for V2, we find that the final volume is 800mL.

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  • 10. 
    A gas has a pressure of 801 mm Hg at 349 K. If the pressure is reduced to 701 mm Hg, what is the new temperature? (Gay Lussac's Law: P1/T1 = P2/T2) - ProProfs

    A gas has a pressure of 801 mm Hg at 349 K. If the pressure is reduced to 701 mm Hg, what is the new temperature? (Gay Lussac's Law: P1/T1 = P2/T2)

    • 250 K

    • 305 K

    • 399 K

    • 802 K

    Correct Answer
    A. 305 K
    Explanation
    According to Gay Lussac's Law, the pressure and temperature of a gas are directly proportional. Therefore, if the pressure is reduced from 801 mm Hg to 701 mm Hg, the temperature should also decrease. The correct answer is 305 K, which is lower than the initial temperature of 349 K.

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  • 11. 
    You have 1.42 L of a gas exerting a pressure of 125 kPA. Assuming constant temperature what pressure will the gas exert if its volume is reduced to 0.853L? (Boyle's Law: P1V1 = P2V2) - ProProfs

    You have 1.42 L of a gas exerting a pressure of 125 kPA. Assuming constant temperature what pressure will the gas exert if its volume is reduced to 0.853L? (Boyle's Law: P1V1 = P2V2)

    • 75.1 kPA

    • 208 kPA

    • 151 kPA

    • More information is needed

    Correct Answer
    A. 208 kPA
    Explanation
    A: do you think the volume increasing or decreasing?
    C: try using the 'reason and ration' method.
    D: check your math.

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  • 12. 
    Air is best described as... - ProProfs

    Air is best described as...

    • Pure substance

    • Compound

    • Element

    • Solution

    Correct Answer
    A. Solution
    Explanation
    Air is a homogeneous mixture, also called a solution

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  • 13. 
    In the relationship described by Charles' Law, which property must remain constant? - ProProfs

    In the relationship described by Charles' Law, which property must remain constant?

    • Pressure

    • Temperature

    • Volume

    Correct Answer
    A. Pressure
    Explanation
    In Charles' Law, the relationship between temperature and volume of a gas at constant pressure is described. According to this law, when the temperature of a gas increases, its volume also increases, and vice versa, as long as the pressure remains constant. Therefore, in order to maintain the relationship described by Charles' Law, the property that must remain constant is pressure.

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  • 14. 
    To pop popcorn, you need to increase the temperature, which causes an increase in - ProProfs

    To pop popcorn, you need to increase the temperature, which causes an increase in

    • The pressure of the water vapor inside the popcorn kernels

    • The volume of the liquid water inside the popcorn kernels

    • The mass of the water vapor inside the popcorn kernels

    • The solubility of the water vapor inside the popcorn kernels

    Correct Answer
    A. The pressure of the water vapor inside the popcorn kernels
    Explanation
    When popcorn is heated, the water inside the kernels turns into steam. This steam builds up pressure within the kernel, causing it to eventually explode and turn into popcorn. Therefore, increasing the temperature increases the pressure of the water vapor inside the popcorn kernels.

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  • 15. 
    A gas is collected at 600. mm Hg and 300. K. What would the pressure be at 350 K (at constant volume)? (Gay Lussac's Law: P1/T1 = P2/T2) - ProProfs

    A gas is collected at 600. mm Hg and 300. K. What would the pressure be at 350 K (at constant volume)? (Gay Lussac's Law: P1/T1 = P2/T2)

    • 175 mm Hg

    • 300. mm Hg

    • 514 mm Hg

    • 700. mm Hg

    Correct Answer
    A. 700. mm Hg
    Explanation
    According to Gay Lussac's Law, the pressure of a gas is directly proportional to its temperature when the volume is constant. In this case, the initial pressure is 600 mm Hg at a temperature of 300 K. To find the pressure at 350 K, we can use the formula P1/T1 = P2/T2. Plugging in the values, we get P2 = (P1 * T2) / T1 = (600 * 350) / 300 = 700 mm Hg. Therefore, the correct answer is 700 mm Hg.

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  • 16. 
    Calculate the pressure in kilopascals exerted by a textbook on the desk. The dimensions of the textbook are 24.0 cm by 18.0 cm and the force it exerts is 3.00 Newtons. (Pressure = Force/Area) - ProProfs

    Calculate the pressure in kilopascals exerted by a textbook on the desk. The dimensions of the textbook are 24.0 cm by 18.0 cm and the force it exerts is 3.00 Newtons. (Pressure = Force/Area)

    • 69.4 kPa

    • 0.0694 kPa

    • 0.0144 kPa

    • 14.4 kPa

    Correct Answer
    A. 0.0694 kPa
    Explanation
    The pressure exerted by the textbook on the desk can be calculated by dividing the force exerted by the area over which it is distributed. The area can be found by multiplying the length and width of the textbook. In this case, the area is (24.0 cm)(18.0 cm) = 432.0 cm². Converting the force to Newtons, the pressure is then calculated as 3.00 N / 432.0 cm² = 0.00694 N/cm². To convert this to kilopascals, we divide by 1000, resulting in 0.00694 kPa. Rounding to four decimal places, the answer is 0.0694 kPa.

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  • Current Version
  • Mar 20, 2022
    Quiz Edited by
    ProProfs Editorial Team
  • Feb 03, 2008
    Quiz Created by
    Sgreenblatt
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