7th Grade Functions- Cp Wk 15

The function table is asking for the value of y when x is 10. To find this, we can use the given equation y = 3x and substitute x = 10. Therefore, y = 3 * 10 = 30.

The given sequence is increasing by 5 each time. Starting from 5, the next number is 10, then 15, and then 20. Therefore, the next number in the sequence would be 25.

The function table follows a pattern where the value of y is obtained by adding 6 to the value of x. For example, when x is 2, y is 8 (2 + 6 = 8). Similarly, when x is 4, y is 10 (4 + 6 = 10). Applying the same pattern, when x is 10, y would be 16 (10 + 6 = 16).

The rule given is 2x + 2, which means that for any value of x, the corresponding value of y is obtained by multiplying x by 2 and adding 2. In the given table, the value of x is 5. Plugging this value into the rule, we get 2(5) + 2 = 10 + 2 = 12. Therefore, the missing value of y is 12.

The coordinates of Point T are (2, -6).

The coordinates of Point U are (6, -4). This is determined by the ordered pair (x, y), where x represents the horizontal position and y represents the vertical position. In this case, the x-coordinate is 6, indicating that Point U is 6 units to the right of the origin. The y-coordinate is -4, indicating that Point U is 4 units below the origin.

The coordinates of Point F are (4, 1) because the x-coordinate is 4 and the y-coordinate is 1. This means that Point F is located 4 units to the right and 1 unit up from the origin (0, 0) on a coordinate plane.

The rule in the table is given as 5x - 4. To find the value of y for the third row, we substitute x = 3 into the rule. Therefore, y = 5(3) - 4 = 15 - 4 = 11.

Point J lies in Quadrant III because in the Cartesian coordinate system, Quadrant III is the region where the x-coordinate is negative and the y-coordinate is also negative. Since no specific coordinates are given for Point J, we can assume that it falls in Quadrant III based on the given answer.

Point B is located in Quadrant II because it has negative x-coordinate and positive y-coordinate. In Quadrant II, the x-coordinate is negative and the y-coordinate is positive.