2477 Linear Regression Gradient & Y-intercept Formulae

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AP Statistics

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| Attempts: 76 | Questions: 24

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1) We are trying to find the y-intercept for the linear regression line.The gradient is given as -2.The mean of the x values is -4 and the mean of the y values is 8The standard deviation of the x values is 7 and the standard deviation of the y values is 12.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

About This Quiz

2477 Linear Regression Gradient & Y-intercept Formulae - Quiz

. The three formulae used in this quiz are : General, y-intercept (a) and gradient (b)

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2) We are trying to find the y-intercept for the linear regression line.The gradient is given as 0.5.The mean of the x values is 6 and the mean of the y values is 2The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

3) We are trying to find the y-intercept for the linear regression line.The correlation coefficient is 0.8The mean of the x values is 6 and the mean of the y values is 8The standard deviation of the x values is 18 and the standard deviation of the y values is 4.What is the y intercept to one decimal place?

The App - rxsys2equ - When you don't have the gradient (b) and you are looking for the y intercept, you should find both a & b.

Explanation

The App - rxsys2equ - When you don't have the gradient (b) and you are looking for the y intercept, you should find both a & b.

Submit

4) We are trying to find the y-intercept for the linear regression line.The gradient is given as 2.The mean of the x values is 4 and the mean of the y values is 2The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

5) We are trying to find the y-intercept for the linear regression line.The gradient is given as -0.5.The mean of the x values is 10 and the mean of the y values is 2The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

6) We are trying to find the y-intercept for the linear regression line.The gradient is given as 0.5.The mean of the x values is 10 and the mean of the y values is 8The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

7) We are trying to find the y-intercept for the linear regression line.The gradient is given as 1.The mean of the x values is 6 and the mean of the y values is 8The standard deviation of the x values is 5 and the standard deviation of the y values is 3.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

8) We are trying to find the y-intercept for the linear regression line.The gradient is given as 0.5.The mean of the x values is 8 and the mean of the y values is 8The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

9) The explanatory variable is height in cm, and the response variable is weight in kg.Using the generic equation for the linear regression line, y = 150 +17x, match the answers below.

Blue

Red

Purple

Orange

Green

App - slopeint and page 1.7 help with this data.

Explanation

App - slopeint and page 1.7 help with this data.

Submit

10) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is 0.8.The mean of the x values is 12 and the mean of the y values is 30The standard deviation of the x values is 4 and the standard deviation of the y values is 8.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

11) We are trying to find the y-intercept for the linear regression line.The correlation coefficient is 0.8The mean of the x values is 5 and the mean of the y values is 8The standard deviation of the x values is 10 and the standard deviation of the y values is 15.What is the y intercept to one decimal place?

The App - rxsys2equ - When you don't have the gradient (b) and you are looking for the y intercept, you should find both a & b.

Explanation

The App - rxsys2equ - When you don't have the gradient (b) and you are looking for the y intercept, you should find both a & b.

Submit

12) The data collected from a faulty freezer shows the following linear regression line :freezer temperature in degrees C = -2 + 1.2 x hours from pump failureSlope Statement

Blue

Red

Purple

Orange

Green

Yellow

App - slopeint and page 1.7 help with this data.

Explanation

App - slopeint and page 1.7 help with this data.

Submit

13) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is 0.7.The mean of the x values is 15 and the mean of the y values is 30The standard deviation of the x values is 6 and the standard deviation of the y values is 18.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

14) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is 0.9.The mean of the x values is 18 and the mean of the y values is 34The standard deviation of the x values is 2 and the standard deviation of the y values is 6.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

15) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is -0.9.The mean of the x values is 18 and the mean of the y values is 34The standard deviation of the x values is 4 and the standard deviation of the y values is 8.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

16) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is -0.9.The mean of the x values is 6 and the mean of the y values is 27The standard deviation of the x values is 4 and the standard deviation of the y values is 2.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

17) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is -0.8.The mean of the x values is 6 and the mean of the y values is 27The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

18) We are trying to find the y-intercept for the linear regression line.The gradient is given as 2.The mean of the x values is 4 and the mean of the y values is 8The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Explanation

The App - rxsys2equ - the y intercept only requires the gradient (b) and the mean of the x and y values.

Submit

19) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is -0.6.The mean of the x values is 9 and the mean of the y values is 22The standard deviation of the x values is 7 and the standard deviation of the y values is 3.5.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

20) We are trying to find the y-intercept for the linear regression line.The correlation coefficient is 0.9The mean of the x values is 4 and the mean of the y values is 8The standard deviation of the x values is 9 and the standard deviation of the y values is 4.5.What is the y intercept?

The App - rxsys2equ - When you don't have the gradient (b) and you are looking for the y intercept, you should find both a & b.

Explanation

The App - rxsys2equ - When you don't have the gradient (b) and you are looking for the y intercept, you should find both a & b.

Submit

21) We are trying to find the gradient of the least squares regression line.The Correlation Coefficient is 0.9.The mean of the x values is 6 and the mean of the y values is 29The standard deviation of the x values is 2 and the standard deviation of the y values is 8.What is the gradient?

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Explanation

The App - rxsys2equ - the gradient only requires the correlation coefficient (r) and the SD for x and y.

Submit

23) The data collected from a weight lifter shows the following linear regression line :weight lifted in kg = 45 + 2.3 x weeks spent in training programmeSlope Statement

Blue

Red

Purple

Orange

Green

Yellow

App - slopeint and page 1.7 help with this data.

Explanation

App - slopeint and page 1.7 help with this data.

Submit

24) The data collected from a faulty freezer shows the following linear regression line :freezer temperature in degrees C = -2 + 1.2 x hours from pump failureY intercept Statement

Blue

Purple

Orange

Green