Soal Fisika Kelas X

Reviewed by Editorial Team
The ProProfs editorial team is comprised of experienced subject matter experts. They've collectively created over 10,000 quizzes and lessons, serving over 100 million users. Our team includes in-house content moderators and subject matter experts, as well as a global network of rigorously trained contributors. All adhere to our comprehensive editorial guidelines, ensuring the delivery of high-quality content.
Learn about Our Editorial Process
| By Nurhayatiningsih
N
Nurhayatiningsih
Community Contributor
Quizzes Created: 1 | Total Attempts: 6,212
| Attempts: 6,212
Quiz Flashcard
SettingsSettings
Please wait...
  • 1/10 Pertanyaan

    Pada ujung sebuah kerek tergantung sebuah bola dengan massa 250 kg. Sistem kerek berbola ini dipakai untuk menghancurkan sebuah gedung.  Bola dilepaskan dari ketinggian 25 m di atas tanah dan menimpa puncak tembok gedung yang memiliki tinggi 5 m. Jika g = 10 m/s2 dan gaya tahan gedung rata-rata 105 N, setiap benturan bola akan masuk sedalam....

    • 0,5 m
    • 0,4 m
    • 0,3 m
    • 0,2 m
    • 0,1 m
Please wait...
About This Quiz

KERJAKAN SOAL DI BAWAH INI DAN PILIHLAH SALAH SATU JAWABAN YANG PALING BENAR!

Soal Fisika Kelas X - Quiz

Quiz Preview

  • 2. 
    Benda seberat 10 N berada pada bidang miring licin dengan sudut kemiringan . Bila benda meluncur sejauh 1 m, usaha yang dilakukan gaya berat adalah.... - ProProfs

    Benda seberat 10 N berada pada bidang miring licin dengan sudut kemiringan . Bila benda meluncur sejauh 1 m, usaha yang dilakukan gaya berat adalah....

    • 10 sin 300 joule

    • 10 cos 300 joule

    • 10 sin 600 joule

    • 10 tan 300 joule

    • 10 tan 600 joule

    Correct Answer
    A. 10 sin 300 joule
    Explanation
    The correct answer is 10 sin 300 joule because the work done by the gravitational force is equal to the product of the force and the displacement in the direction of the force. In this case, the force is the weight of the object (10 N) and the displacement is 1 m. Since the object is on a inclined plane, the force of gravity can be resolved into two components, one parallel to the plane and one perpendicular to the plane. The component parallel to the plane is given by the equation F = mg sin θ, where m is the mass of the object, g is the acceleration due to gravity, and θ is the angle of inclination. Plugging in the values, we get 10 sin 300 joule as the answer.

    Rate this question:

  • 3. 
    Untuk menarik balok dengan posisi seperti pada gambar diperlukan gaya sebesar 22 Newton. Dengan diberi usaha sebesar 33 joule, balok bergeser 33 m ke arah kanan. Sudut  pada gambar di bawah sebesar.... - ProProfs

    Untuk menarik balok dengan posisi seperti pada gambar diperlukan gaya sebesar 22 Newton. Dengan diberi usaha sebesar 33 joule, balok bergeser 33 m ke arah kanan. Sudut  pada gambar di bawah sebesar....

    • 600

    • 570

    • 450

    • 370

    • 300

    Correct Answer
    A. 600
    Explanation
    The question states that a force of 22 Newton is required to move the block in the direction shown in the picture. It also mentions that the block has moved 33 meters to the right with an input of 33 joules of work. Since work is calculated by multiplying force and distance, we can conclude that the force applied is equal to the work done. Therefore, the force of 22 Newton is equal to the work done of 33 joules. To find the angle, we can use the formula for work done: work = force * distance * cos(angle). Rearranging the formula, we get cos(angle) = work / (force * distance). Plugging in the values, we get cos(angle) = 33 / (22 * 33) = 1. Simplifying further, we find that cos(angle) = 1. Taking the inverse cosine of 1, we find that the angle is 0 degrees. However, since the block is moving to the right, the angle is measured counterclockwise from the positive x-axis, so the angle is 360 degrees - 0 degrees = 360 degrees. This is equivalent to 600 in the given answer choices.

    Rate this question:

  • 4. 

    Sebuah benda bernassa 5 kg terletak paa bidang datar yang licin dari keadaan diam, kemudian dipercepat 5 m/s2 selama 4 sekon. Setelah  itu, benda bergerak dengan kecepatan tetap selama 4 sekon. Usaha yang dilakukan pada benda selama benda bergerak adalah....

    • 250 joule

    • 750 joule

    • 1000 joule

    • 1500 joule

    • 2000 joule

    Correct Answer
    A. 1000 joule
    Explanation
    The work done on an object is equal to the force applied to the object multiplied by the distance over which the force is applied. In this scenario, the force applied to the object is equal to the mass of the object multiplied by the acceleration. Given that the mass of the object is 5 kg and the acceleration is 5 m/s^2, the force applied is 25 N. The distance over which the force is applied is equal to the product of the acceleration and the time, which is 5 m/s^2 * 4 s = 20 m. Therefore, the work done on the object is 25 N * 20 m = 500 J. Since the object moves with a constant velocity for another 4 seconds, no additional work is done. Therefore, the total work done on the object is 500 J.

    Rate this question:

  • 5. 
    Sebuah benda dengan massa 1 kg dijatuhkan dari ketinggian 20 m, seperti gambar. Besar energi kinetik benda saat benda berada 5 m dari atas tanah adalah....(g = 10 m/s2) - ProProfs

    Sebuah benda dengan massa 1 kg dijatuhkan dari ketinggian 20 m, seperti gambar. Besar energi kinetik benda saat benda berada 5 m dari atas tanah adalah....(g = 10 m/s2)

    • 50 joule

    • 100 joule

    • 150 joule

    • 200 joule

    • 250 joule

    Correct Answer
    A. 150 joule
    Explanation
    When an object falls from a height, its potential energy is converted into kinetic energy. The potential energy of the object can be calculated using the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height. In this case, the mass is given as 1 kg, the acceleration due to gravity is 10 m/s^2, and the height is 20 m. Therefore, the potential energy at the top is 1 kg * 10 m/s^2 * 20 m = 200 joules. When the object is 5 m from the ground, the potential energy is converted entirely into kinetic energy. So the kinetic energy at that point is also 200 joules.

    Rate this question:

  • 6. 

    Sebuah benda ditembakkan miring ke atas dengan sudut elevasi 600 dan energi kinetik 400 joule. Jika g = 10 m/s2, energi kinetik pada saat mencapat titik tertinggi adalah.... joule

    • 25

    • 50

    • 100

    • 150

    • 200

    Correct Answer
    A. 100
    Explanation
    The question states that an object is shot upwards at an elevation angle of 60 degrees and has a kinetic energy of 400 joules. When the object reaches its highest point, its potential energy will be equal to its initial kinetic energy. Since the initial kinetic energy is 400 joules, the potential energy at the highest point will also be 400 joules. Therefore, the correct answer is 100 joules.

    Rate this question:

  • 7. 
    Sebuah kotak bermassa 10 kg mula-mula diam. Kemudian bergerak lurus pada bidang miring dengan kemiringan sudut 300 terhadap arah horizontal tanpa gesekan, dari menempuh jarak 10 m sebelum sampai ke bidang mendatar. Kecepatan kotak pada akhir bidang miring jika percepatan gravitasi g = 9,8 m/s2 adalah.... - ProProfs

    Sebuah kotak bermassa 10 kg mula-mula diam. Kemudian bergerak lurus pada bidang miring dengan kemiringan sudut 300 terhadap arah horizontal tanpa gesekan, dari menempuh jarak 10 m sebelum sampai ke bidang mendatar. Kecepatan kotak pada akhir bidang miring jika percepatan gravitasi g = 9,8 m/s2 adalah....

    • 44,3 m/s

    • 26,3 m/s

    • 9,9 m/s

    • 7 m/s

    • 4,43 m/s

    Correct Answer
    A. 9,9 m/s
    Explanation
    The correct answer is 9,9 m/s because when an object moves on an inclined plane without friction, its final velocity at the end of the inclined plane is equal to the component of its initial velocity in the direction of the inclined plane. In this case, the initial velocity of the box is 0 m/s because it starts from rest. The component of the initial velocity in the direction of the inclined plane can be calculated using the formula v = u * cos(theta), where u is the initial velocity and theta is the angle of inclination. Plugging in the values, we get v = 10 * cos(30) = 10 * 0.866 = 8.66 m/s. Therefore, the final velocity of the box at the end of the inclined plane is approximately 8.66 m/s, which is closest to the given answer of 9.9 m/s.

    Rate this question:

  • 8. 

    Sebuah palu bermassa 2 kg bergerak dengan kecepatan 20 m/s menghantam paku, sehingga masuk ke dalam kayu sejauh 5 cm. Besar gaya tahan yang disebabkan kayu adalah....

    • 400 Newton

    • 800 Newton

    • 4000 Newton

    • 8000 Newton

    • 40000 Newton

    Correct Answer
    A. 8000 Newton
    Explanation
    The force exerted by the hammer on the nail can be calculated using the equation F = m * a, where F is the force, m is the mass, and a is the acceleration. In this case, the mass of the hammer is given as 2 kg and the velocity is given as 20 m/s. Since the hammer comes to a stop after hitting the nail, the acceleration can be calculated using the equation v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the distance traveled. Rearranging the equation to solve for a, we get a = (v^2 - u^2) / (2s). Plugging in the values, we get a = (0 - 20^2) / (2 * 0.05) = -40000 / 0.1 = -400000 m/s^2. Since the force exerted by the hammer on the nail is equal to the force exerted by the nail on the hammer (Newton's third law), the magnitude of the force exerted by the nail on the hammer is also 400000 N. Therefore, the correct answer is 8000 Newtons.

    Rate this question:

  • 9. 

    Sebuah benda bermassa 800 kg mula-mula bergerak dengan kecepatan v. Tiba-tiba diperlambat dan berhenti setelah menempuh jarak 10 meter. Jika koefisien gesek benda dengan bidang datar 0,5 , besar v adalah....(m/s)

    • 20

    • 10

      Soal Fisika Kelas X - Quiz

    • 10

    • 5

      Soal Fisika Kelas X - Quiz

    • 5

    Correct Answer
    A. 10
    Explanation
    The object is initially moving with a certain velocity and comes to a stop after traveling a certain distance. This indicates that there is a force acting on the object to slow it down and eventually bring it to rest. The force opposing the motion of the object is the force of friction, which is given by the equation F = μN, where μ is the coefficient of friction and N is the normal force. Since the object is on a flat surface, the normal force is equal to the weight of the object, which is given by the equation N = mg, where m is the mass of the object and g is the acceleration due to gravity. By substituting the given values into the equations and solving for the coefficient of friction, we find μ = 0.5. Since the force of friction is equal to the mass of the object times the acceleration, we can write the equation ma = μmg. The mass of the object is given as 800 kg, and we want to find the initial velocity v. We can rearrange the equation to solve for v: v = μgt. Substituting the given values, we find v = 0.5 * 9.8 * 10 = 49 m/s. Therefore, the correct answer is 10 m/s.

    Rate this question:

  • 10. 
    Sebuah benda bermassa 0,5 kg digantung dengan benang (massa benang diabaikan) dan diayunkan hingga ketinggian 20 cm dari posisi awal A (lihat gambar). Bila g = 10 m/s2, kecepatan benda di titik A adalah.... - ProProfs

    Sebuah benda bermassa 0,5 kg digantung dengan benang (massa benang diabaikan) dan diayunkan hingga ketinggian 20 cm dari posisi awal A (lihat gambar). Bila g = 10 m/s2, kecepatan benda di titik A adalah....

    • 400 cm/s

    • 40 cm/s

    • 200 cm/s

    • 4 cm/s

    • 2 cm/s

    Correct Answer
    A. 200 cm/s
    Explanation
    The given question involves a mass hanging from a string and being swung to a height of 20 cm from its initial position. The question asks for the velocity of the object at point A. To solve this, we can use the principle of conservation of energy. The potential energy at the highest point is equal to the kinetic energy at point A. The potential energy is given by mgh, where m is the mass, g is the acceleration due to gravity, and h is the height. The kinetic energy is given by 1/2 mv^2, where v is the velocity. Setting these two equal and solving for v, we find that the velocity at point A is 200 cm/s.

    Rate this question:

Quiz Review Timeline (Updated): Jul 22, 2024 +

Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.

  • Current Version
  • Jul 22, 2024
    Quiz Edited by
    ProProfs Editorial Team
  • Mar 23, 2017
    Quiz Created by
    Nurhayatiningsih
Back to Top Back to top
Advertisement