Latihan Soal Cahaya Dan Lensa

1. Pemantulan cahaya pada bidang kasar sehingga tidak menghasilkan bayangan disebut ….

pantulan sempurna
pantulan sebagian
pantulan baur
pantulan teratur

Option 1

Option 2

Option 3

Option 4

Pemantulan cahaya pada bidang kasar sehingga tidak menghasilkan bayangan disebut pantulan baur.

Explanation

Pemantulan cahaya pada bidang kasar sehingga tidak menghasilkan bayangan disebut pantulan baur.

2.

Option 1

Option 2

Option 3

Option 4

not-available-via-ai

Explanation

not-available-via-ai

3. Jawab

Option 1

Option 2

Option 3

Option 4

not-available-via-ai

Explanation

not-available-via-ai

4. Sifat bayangan pada cermin datar adalah ….

tegak, maya, dan sama besar
tegak, maya, dan diperkecil
tegak, nyata, dan sama besar
tegak, nyata, dan diperkecil

Option 1

Option 2

Option 3

Option 4

Sifat bayangan pada cermin datar adalah tegak, maya, dan sama besar.

Explanation

Sifat bayangan pada cermin datar adalah tegak, maya, dan sama besar.

5. Seorang siswa melakukan percobaan dengan meletakkan sebuah benda berada 15 cm di depan cermin cekung. Bayangan nyata diperoleh pada jarak 30 cm. Jarak titik fokus cermin yang digunakan oleh siswa tersebut adalah …. a. 2 cm b. 10 cm c. 15 cm d. 30 cm

Option 1

Option 2

Option 3

Option 4

The correct answer is option 2 (10 cm). In this experiment, the student placed an object 15 cm in front of a concave mirror and obtained a real image at a distance of 30 cm. According to the mirror formula, 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance. By substituting the given values, we can calculate the focal length of the mirror to be 10 cm.

Explanation

The correct answer is option 2 (10 cm). In this experiment, the student placed an object 15 cm in front of a concave mirror and obtained a real image at a distance of 30 cm. According to the mirror formula, 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance. By substituting the given values, we can calculate the focal length of the mirror to be 10 cm.

6.

Option 1

Option 2

Option 3

Option 4

not-available-via-ai

Explanation

not-available-via-ai

7. Suatu benda dapat dilihat mata jika benda tersebut ….

menyerap cahaya
memantulkan cahaya
membiaskan cahaya
menguraikan cahaya

Option 1

Option 2

Option 3

Option 4

When light falls on an object, it can either be absorbed, reflected, or refracted. In this case, the correct answer is option 2, "memantulkan cahaya" which means "reflecting light". This means that the object is able to bounce off the light that falls on it, allowing it to be visible to the human eye.

Explanation

When light falls on an object, it can either be absorbed, reflected, or refracted. In this case, the correct answer is option 2, "memantulkan cahaya" which means "reflecting light". This means that the object is able to bounce off the light that falls on it, allowing it to be visible to the human eye.

8. Pada cermin cekung, agar didapat bayangan maya dan diperbesar benda harus diletakkan pada jarak ….

antara F dan M
di titik F
antara F dan O
di titik M

Option 1

Option 2

Option 3

Option 4

To obtain a virtual and magnified image in a concave mirror, the object should be placed between the focal point (F) and the center of curvature (O). This is because in this position, the rays of light from the object will converge and form a magnified image. Placing the object at the focal point or at the midpoint (M) will not result in a magnified image.

Explanation

To obtain a virtual and magnified image in a concave mirror, the object should be placed between the focal point (F) and the center of curvature (O). This is because in this position, the rays of light from the object will converge and form a magnified image. Placing the object at the focal point or at the midpoint (M) will not result in a magnified image.

9.

Option 1

Option 2

Option 3

Option 4

not-available-via-ai

Explanation

not-available-via-ai

10. Seberkas sinar datang pada sebuah cermin datar dengan sudut datang 10⁰. Kemudian, cermin datar tersebut diputar 30⁰ searah putaran jarum jam pada sumbunya. Sudut yang dibentuk oleh sinar datang dengan sinar pantul setelah cermin diputar adalah ….

40⁰
60⁰
80⁰
100⁰

Option 1

Option 2

Option 3

Option 4

When a ray of light hits a mirror, the angle of incidence is equal to the angle of reflection. In this case, the angle of incidence is 100 degrees. When the mirror is rotated 300 degrees clockwise, the angle of reflection will also change by the same amount. Therefore, the angle formed by the incident ray and the reflected ray after the mirror is rotated will be 400 degrees.

Explanation

When a ray of light hits a mirror, the angle of incidence is equal to the angle of reflection. In this case, the angle of incidence is 100 degrees. When the mirror is rotated 300 degrees clockwise, the angle of reflection will also change by the same amount. Therefore, the angle formed by the incident ray and the reflected ray after the mirror is rotated will be 400 degrees.

11.

Option 1

Option 2

Option 3

Option 4

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Explanation

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12. Sebuah benda berada 12 cm di depan cermin cembung berjari-jari 6 cm. Bayangan yang dihasilkan adalah …. a. nyata, terbalik pada jarak 12 cm b. nyata, tegag pada jarak 2,4 cm c. maya, tegak pada jarak 2,4 cm d. maya, terbalik pada jarak 6 cm

Option 1

Option 2

Option 3

Option 4

The correct answer is option c. The image formed by a convex mirror is always virtual and upright. The distance of the image from the mirror is equal to the distance of the object from the mirror divided by the magnification. In this case, the object is 12 cm in front of the mirror and the radius of curvature is 6 cm. Using the mirror formula, we can calculate the magnification as -1/2. Therefore, the distance of the image from the mirror is 12 cm divided by -1/2, which equals -24 cm. Since the distance is negative, it means the image is virtual.

Explanation

The correct answer is option c. The image formed by a convex mirror is always virtual and upright. The distance of the image from the mirror is equal to the distance of the object from the mirror divided by the magnification. In this case, the object is 12 cm in front of the mirror and the radius of curvature is 6 cm. Using the mirror formula, we can calculate the magnification as -1/2. Therefore, the distance of the image from the mirror is 12 cm divided by -1/2, which equals -24 cm. Since the distance is negative, it means the image is virtual.

13.

Option 1

Option 2

Option 3

Option 4

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Explanation

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14.

Option 1

Option 2

Option 3

Option 4

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Explanation

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15.

Option 1

Option 2

Option 3

Option 4

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Explanation

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16. Sebuah pensil dengan panjang 0,20 m diletakkan 1,5 m di depan sebuah cermin cekung yang jarak fokusnya 0,75 m. Bayangan pensil adalah .... a. tegak dan panjangnya 0,30 m b. tegak dan panjangnya 0,20 m c. terbalik dan panjangnya 0,30 m d. terbalik dan panjnagnya 0,20 m

Option 1

Option 2

Option 3

Option 4

The correct answer is option 4. When an object is placed in front of a concave mirror, the image formed is virtual, upright, and magnified. The magnification can be calculated using the mirror formula: 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance. In this case, the object distance is 1.5 m and the focal length is 0.75 m. Plugging these values into the formula, we can calculate the image distance as 0.5 m. Since the image is upright and magnified, the length of the image will be the same as the length of the object, which is 0.20 m. Therefore, the correct answer is option 4.

Explanation

The correct answer is option 4. When an object is placed in front of a concave mirror, the image formed is virtual, upright, and magnified. The magnification can be calculated using the mirror formula: 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance. In this case, the object distance is 1.5 m and the focal length is 0.75 m. Plugging these values into the formula, we can calculate the image distance as 0.5 m. Since the image is upright and magnified, the length of the image will be the same as the length of the object, which is 0.20 m. Therefore, the correct answer is option 4.

17.