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What is the tolerance of the process that exhibits the limits of normal variation? A process has a mean of 10 and a standard deviation of 2.

What is the tolerance of the process that exhibits the limits of normal variation? A process has a mean of 10 and a standard deviation of 2.

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A. 5 to 15
B. 4 to 16
C. 2 to 8
D. 6 to 14

This question is part of Six Sigma Green Belt Exam
Asked by PracticeExcellence, Last updated: Jan 10, 2018

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3 Answers

l.Steven

L.Steven

Answered on Jan 07, 2018

The standard deviation is actually a mathematical representation of how spread out the numbers is. If you need to calculate it, it is the square root of the variance. Now variance is basically the average of the squared differences that are calculated from the mean.

Therefore, if we want to calculate the variance, using these two values we simply subtract 6 from 10 and add 6 to ten. This will give us the range over which the actual tolerance lies around the mean. This results in an answer of 4 to 16. This means that the true answer is anywhere from four to 16, 6 units on either side of the mean.

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John Adney

John Adney

Answered on Jul 13, 2017

Can someone please explain how this is calculated?

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John Smith

John Smith

Answered on Nov 26, 2016

4 to 16
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