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What is its maximum height? A basketball was launched 12 m/s at an angle of 40 degrees above the horizontal. Neglect air resistance and the height of the player who launched it.



A. 4.22 m
B. 3.03 m
C. 5.09 m
D. 8.30 m
E. 9.67 m

This question is part of NSC07 lab fa2
Asked by Thechadwictan, Last updated: Jul 03, 2020

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3 Answers

N. Jarah

N. Jarah

Answered Nov 14, 2019

B is the answer to this question. To solve this, you need to do the following processes: The first thing is you need to find VOY. Then, you need to look for T. Look for YMAX, and you will get the answer. You just need to place all of the needed figures to get the best answer available.

The movement that the basketball went through can be considered as projectile motion. This usually occurs when an object is thrown in the air. This happens when the object is thrown near the earth’s surface. There are various factors that may affect the rate of the motion of the object. For example, the object’s weight will matter.

 

kenster.jksb

Kenster.jksb

Answered Jul 09, 2017

My answer is 3.06 m
Find Voy
40 sin 12 = 7.71 m/s
Find t
7.71 / 9.8 = 0.79 s
Then find Ymax
9.8(0.79)Raise to 2 / 2= 3.06 s

 

John Smith

John Smith

Answered Oct 28, 2016

3.03 m
 

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