What acceleration will the mass fall on release? A mass ‘m’ is - ProProfs Discuss
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What acceleration will the mass fall on release? A mass ‘m’ is supported by a massless string wound around a uniform hollow cylinder of mass m and radius R. If the string does not slip on the cylinder.





A. 5g/6
B. 2g/3
C. G/2
D. G

This question is part of VRs JEE MOCK TEST -1
Asked by VREducation, Last updated: Jun 28, 2020

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2 Answers

L. Brett

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L. Brett, Sales Manager, MBA, Detroit

Answered May 29, 2019

In science, you may have to calculate the acceleration or mass of something based on the formula designated for acceleration. The method is known as being acceleration is equal to the final velocity minus the initial speed over time, which is the change in the velocity divided by the time.

Therefore, you must first know the velocity. The velocity can also be calculated based on its formula, which is velocity is equal to speed divided by time. In this situation, a massless string is wound around a uniform hollow cylinder of mass which is represented by M and radius which is represented by R. The string does not slip on the cylinder. Therefore, the acceleration that will let the mass fall on the release is G/2.

 

VREducation

VREducation

Answered Apr 15, 2018

G/2

MgT=ma T R= mR2 /2 a/R a= g /2 ####

 

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