Titration Problems

8 Questions  I  By Kwchiro
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 Titration Problems
The concentration of NaOH is 0. 5 M, if 30 ml is needed to titrate 35 mL of acid, what is the concentration of the acid?

  
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  • 1. 
    The concentration of NaOH is 0.5 M, if 20 ml is needed to titrate 35 mL of acid, what is the concentration of the acid?
    • A. 

      0.875 M of acid

    • B. 

      0.0029 M of the acid

    • C. 

      0.29 M of the acid

    • D. 

      0.00875 M of acid


  • 2. 
    A 15.5 mL sample of 0.215 M KOH was titrated with a weak acid. It took 21.2 mL of the acid to reach the equivalence point. What is the molarity of the acid?
    • A. 

      0.157 M acid

    • B. 

      0.29 M acid

    • C. 

      0.0157 M acid

    • D. 

      0.029 M acid


  • 3. 
    If 20.0 mL of 0.100 M HCl are titrated with 19.5 mL of an NaOH solution. What is the molarity of the NaOH solution?
    • A. 

      0.0975 M NaOH

    • B. 

      0.0103 M NaOH

    • C. 

      0.103 M NaOH

    • D. 

      0.975 M NaOH


  • 4. 
    The concentration of HCl, a strong acid is 0.5 M. If 20 ml HCl is needed to titrate 40 mL of NaOH, what is the concentration of NaOH?
    • A. 

      0.25 M NaOH

    • B. 

      0.5 M NaOH

    • C. 

      1 M NaOH

    • D. 

      0.1 M NaOH


  • 5. 
    The concentration of LiOH is 0.50 M. If 25 mL of LiOH is needed to titrate 40 mL of HNO3 (nitric acid) what is the concentraiton of HNO3?
    • A. 

      0.03125 M HNO3

    • B. 

      0.8 M HNO3

    • C. 

      0.3125 M HNO3

    • D. 

      0.08 M HNO3


  • 6. 
    What is the purpose of an indicator in the solution with the unknown concentration?
    • A. 

      It tells when there is enough acid in the solution.

    • B. 

      It tells when the equivalence point is obtained.

    • C. 

      It tells when there is enough base in the solution


  • 7. 
    The equation for the neutralization reaction between solutions of potassium hydroxide and hydrochloric acid is:
    • A. 

      H+ (aq) + OH- (aq) --> H2O

    • B. 

      KOH (aq) + HCl (aq) -->H2O (l) + KCl

    • C. 

      POH (aq) + HClO (aq) --> H2O (l) + PClO (aq)

    • D. 

      KOH (aq) + HCl (aq) -->K2Cl (aq)+ H2O (l)

    • E. 

      KOH (aq) + HCl (aq) --> K2Cl (aq)+ H2O (l) + H+


  • 8. 
    Calculate the molarity of a HCl solution if 25.0 mL of the solution is  neutralized by 15.5 mL of 0.800 M NaOH:           
    • A. 

      0.248 M

    • B. 

      0.496 M

    • C. 

      1.29 M

    • D. 

      0.645 M


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