Solving Quadratic Expressions

1. (x + 6)(x + 7) = 0, x =

6, 7

-6, -7

-6, 7

2. X + 4 = 0; x =

4

0

-4

3. (x - 4)(X + 5) = 0, x =

4, -5

4, 5

-4, -5

4. Any value multiplied by zero will equal

Itself

Zero

One

5. (2x - 5)(x + 3) = 0, 0 =

-3, 5

-2.5, 3

2.5, -3

6. (x -3)(x - 2) = 0, x =

-3, -2

3, -2

3, 2

7. (5 + x)(2 - x) = 0, 0 =

-5, 2

5, 2

-5, -2

8. (4 - x)(3 + x) = 0, 0=

4, 3

4, -3

-4, -3

9. An expression contained in brackets (parentheses) can be treated as a single value.

True

False

10. (x - 4)(4 - x) = 0, 0 =

4, -4

-4, 0

4

11. (4 - 3x)(2 + x) = 0, 0 =

4/3, -2

3/4, -2

4, -2

Solving Quadratic Expressions

1. (x + 6)(x + 7) = 0, x =

2.

What first name or nickname would you like us to use?

2. X + 4 = 0; x =

3. (x - 4)(X + 5) = 0, x =

4. Any value multiplied by zero will equal

5. (2x - 5)(x + 3) = 0, 0 =

6. (x -3)(x - 2) = 0, x =

7. (5 + x)(2 - x) = 0, 0 =

8. (4 - x)(3 + x) = 0, 0=

9. An expression contained in brackets (parentheses) can be treated as a single value.

10. (x - 4)(4 - x) = 0, 0 =

11. (4 - 3x)(2 + x) = 0, 0 =