Soal Remidi Uas Instalasi Penerangan Listrik Semester 5 Tahun 2016
SMK Negeri 3 YogyakartaTeknik Pemanfaatan Tenaga Listrik
Questions and Answers
- 1.
Gambar dibawah ini yang ditunjukkan oleh huruf A dan C adalah …..
- A.
Kabel NYM dan Kontaktor Magnet
- B.
Busbar dan Kabel Duct
- C.
Rel Omega dan Terminal Kabel
- D.
ELCB dan MCB
- E.
Kontaktor Magnet dan Rel Omega
Correct Answer
B. Busbar dan Kabel DuctExplanation
The correct answer is Busbar dan Kabel Duct. The image below shows two different components, represented by letters A and C. The components in question are busbars and cable ducts. A busbar is a metal strip or bar that conducts electricity within a switchboard, distribution board, or any electrical equipment. A cable duct, on the other hand, is a protective enclosure for electrical cables. Therefore, the correct answer is that the image represents busbars and cable ducts.Rate this question:
-
- 2.
Penggunaan warna kabel untuk R/L1, S/L2, T/L3, Netral dan pentanahan, menurut PUIL 2000 adalah…
- A.
Merah, Kuning, Hitam, Biru dan Kuning strip Hijau
- B.
Kuning, Merah, Hitam, Biru dan Hijau Strip Kuning
- C.
Hitam, Kuning, Biru, Merah, dan Hijau Strip Kuning
- D.
Merah, Hitam, Biru, Hijau dan Kuning Strip Hijau
- E.
Merah, Hitam, Kuning, Coklat dan Kuning Strip Hijau
Correct Answer
A. Merah, Kuning, Hitam, Biru dan Kuning strip HijauExplanation
The correct answer is Merah, Kuning, Hitam, Biru dan Kuning strip Hijau. This is because the question is asking for the correct color coding for R/L1, S/L2, T/L3, Neutral, and grounding wires according to PUIL 2000. According to the given answer, the correct sequence is Red, Yellow, Black, Blue, and Yellow with Green stripe.Rate this question:
-
- 3.
Untuk membedakan antar fasa dalam pemasangan pengahantar instalasi Penerangan 3 fasa adalah....
- A.
Ukuran Penghantar
- B.
Menggunakan taspen
- C.
Taspen
- D.
Warna penghantar
- E.
Ukuran Pipa
Correct Answer
D. Warna penghantarExplanation
The correct answer is "Warna penghantar." In the installation of 3-phase lighting conductors, the differentiation between phases is done by using different colors for each conductor. This helps to identify and distinguish the different phases easily. The size of the conductor, the use of taspen, and the size of the pipe may also be important factors in the installation process, but they are not specifically mentioned in the question.Rate this question:
-
- 4.
Untuk mengindari gangguan instalasi penerangan, maka pemasangan instalasi tenaga harus dipisahkan. Pemisahan ini dimulai dari....
- A.
Panel Hubung Bagi
- B.
Kotak Cabang
- C.
Kotak Sambng
- D.
Sakelar
- E.
KWH meter
Correct Answer
A. Panel Hubung BagiExplanation
To avoid interference with lighting installations, the power installation must be separated. This separation starts from the Panel Hubung Bagi, which is a distribution panel that divides the power supply to different circuits. By separating the power installation, any issues or disruptions in the lighting installations can be isolated and addressed without affecting the rest of the power supply.Rate this question:
-
- 5.
Dalam pemasangan instalasi penerangan 3 fasa untuk Industri dengan gedung bertingkat, maka pembagian fasanya adalah...
- A.
Setiap lantai menggunakan fasa yang berbeda
- B.
Fasa R untuk penerangan, fasa S untuk Kotak kontak dan fasa T untuk instalasi Tenaga
- C.
Beban antar fasa dibuat seimbang
- D.
Fasa R untuk lantai 1, fasa S untuk lantai 2 dan fasa T untuk lantai 3
- E.
Yang digunakan 2 fasa saja, yang lainya untuk cadangan.
Correct Answer
C. Beban antar fasa dibuat seimbangExplanation
The correct answer states that "Beban antar fasa dibuat seimbang" which means that the load between phases is balanced. This is important in a 3-phase lighting installation for an industrial building with multiple floors. Balancing the load between phases ensures that the electrical system operates efficiently and prevents overloading of any single phase. It also helps to distribute the load evenly across the three phases, reducing the risk of voltage fluctuations and improving the overall stability of the electrical system.Rate this question:
-
- 6.
Jumlah kabel kabel yang ditunjukan pada huruf A, adalah ....
- A.
2 penghantar
- B.
3 penghantar
- C.
4 penghantar
- D.
5 penghantar
- E.
6 penghantar
Correct Answer
B. 3 penghantarExplanation
The correct answer is 3 penghantar. The question is asking for the number of cables shown in letter A. The answer indicates that there are three conductors in the cables shown in letter A.Rate this question:
-
- 7.
Gambar disamping ini adalah simbol…….
- A.
Pengawatan belok
- B.
Pengawatan
- C.
Pengawatan Kanan
- D.
Pengawatan Kiri
- E.
Pengawatan menuju keatas
Correct Answer
E. Pengawatan menuju keatasExplanation
The correct answer is "Pengawatan menuju keatas." This symbol represents a wiring or connection that goes upwards. It indicates that the wires or cables are being connected in a direction that goes vertically upwards.Rate this question:
-
- 8.
Bagan disamping ini sering disebut...
- A.
Bagan besarnya arus
- B.
Rekapitulasi jumlah kelompok
- C.
Rekapitulasi arus
- D.
Rekapitulasi daya
- E.
Penghitungan arus
Correct Answer
D. Rekapitulasi dayaExplanation
The given answer, "Rekapitulasi daya," is the most appropriate choice because it accurately describes the content of the given options. The other options, such as "Bagan besarnya arus" (graph of the magnitude of current) and "Penghitungan arus" (calculation of current), do not fit the context as they focus solely on current, while the options "Rekapitulasi jumlah kelompok" (recapitulation of group numbers) and "Rekapitulasi arus" (recapitulation of current) do not cover the concept of power, which is mentioned in the correct answer. Therefore, "Rekapitulasi daya" is the most suitable option.Rate this question:
-
- 9.
Apabila tegangan 220 volt, cos j 0,9, berapa besarnya daya dan arus fasa 1 pada bagan disamping ini...
- A.
250 watt dan 1,26 Ampere
- B.
340 watt dan 1,26 Ampere
- C.
540 watt dan 3,74 Ampere
- D.
640 watt dan 3,74 Ampere
- E.
740 watt dan 3,74 Ampere
Correct Answer
E. 740 watt dan 3,74 AmpereExplanation
The correct answer is 740 watt dan 3,74 Ampere. This is because power (P) is calculated by multiplying voltage (V) with current (I) and power factor (cos j). In this case, the given voltage is 220 volts, the power factor is 0.9, and the current is unknown. By rearranging the formula, we can calculate the current as I = P / (V * cos j). Plugging in the given values, we get I = 740 / (220 * 0.9) = 3.74 Ampere. Therefore, the power and current for phase 1 are 740 watt and 3.74 Ampere, respectively.Rate this question:
-
- 10.
Pemasangan instalasi listrik 3 fasa dengan dua sumber dengan Saklar jenis ......
- A.
SPDT
- B.
DPDT
- C.
DPST
- D.
TPDT
- E.
SPST
Correct Answer
D. TPDT -
- 11.
Ruang tamu mempunyai data sebagai berikut:
- Panjang : 3,5 meter
- Lebar : 3 meter
- Lampu PL-C 26 W : 1800 lumen
- Efisiensi 80 % : 0,8
- Intensitas penerangan ruang tamu menurut tabel (E) = 250 lux
- A.
1 buah
- B.
2 buah
- C.
3 buah
- D.
4 buah
- E.
5 buah
Correct Answer
B. 2 buahExplanation
Based on the given data, the room has a length of 3.5 meters and a width of 3 meters. The lamp used is a PL-C 26 W lamp with an efficiency of 80%. The intensity of the illumination in the living room according to the table is 250 lux. To calculate the number of lamps needed, we can use the formula:
Number of lamps = (Illuminance x Area) / (Lamp Lumen x Efficiency)
Plugging in the values, we get:
Number of lamps = (250 lux x 3.5 m x 3 m) / (1800 lumen x 0.8)
Simplifying this equation gives us approximately 2 lamps, which is the correct answer.Rate this question:
- 12.
Gambar disamping merukan Teknisi Listrik yang sedang merepasi Instalasi Listrik, Apakah sesuai dengan keselamatan kerja?
- A.
Betul
- B.
Salah
Correct Answer
B. SalahExplanation
The correct answer is "Salah" because the picture shows an electric technician repairing an electrical installation without wearing any personal protective equipment (PPE). This is not in accordance with safety regulations as PPE is essential to protect the technician from potential electrical hazards such as electric shock or burns.Rate this question:
-
- 13.
Jenis panel disamping merupakan Panel jenis …
- A.
Terbka
- B.
Semi Terbuka
- C.
Tertutup
- D.
Baja Taang
Correct Answer
B. Semi TerbukaExplanation
The given correct answer is "Semi Terbuka". This suggests that the panel being referred to is of a semi-open type.Rate this question:
-
- 14.
Rel dari tembaga untuk pencabangan arus pada panel disebut dengan istilah …
- A.
Busbar
- B.
Pusat sambungan
- C.
Rel Omega
- D.
Terminal netral
- E.
Kontaktor
Correct Answer
A. BusbarExplanation
A copper rail used for branching current in a panel is called a busbar.Rate this question:
-
- 15.
Penyambungan kabel ke terminal atau bussbar biasanya memkai Kabel Duct
- A.
Betul
- B.
Salah
Correct Answer
A. BetulExplanation
The given statement is true because when connecting cables to terminals or bussbars, it is common practice to use cable ducts. Cable ducts provide a protective housing for the cables, preventing damage and ensuring proper organization and management of the cables. This helps to maintain the integrity and efficiency of the electrical connections.Rate this question:
-
- 16.
Rel Omega merupakan salah satu komponen untuk memasang MCB, Kontaktor dll.
- A.
Betul
- B.
Salah
Correct Answer
A. BetulExplanation
The statement is explaining that Rel Omega is one of the components used for installing MCB, contactors, etc. The answer "Betul" confirms that the statement is correct.Rate this question:
-
- 17.
Dibawah ini, merupakan beberapa cara dalam pemasangan Panel, Kecuali...
- A.
Dipasang di lemari
- B.
Dilantai dekat dinding
- C.
Dipasang di rak
- D.
Digantung di langit-langit
- E.
Di lantai, berdiri bebas di ruangan
Correct Answer
A. Dipasang di lemariExplanation
The given options describe different ways of installing a panel. The options "Dipasang di lemari" (Installed in a cabinet) is the exception because the other options describe panel installation on the floor near the wall, on a shelf, hanging from the ceiling, or standing freely in the room. Installing a panel in a cabinet is not mentioned in the other options, making it the correct answer.Rate this question:
-
- 18.
Gambar dibawah ini yang merupakan simbol kontak tusuk adalah :
- A.
1
- B.
2
- C.
3
- D.
4
- E.
5
Correct Answer
E. 5 -
- 19.
Jenis Lampu led dengan seperti nampak pada gambar disamping sangat cocok di pasang pada:
- A.
Ruang Kantor
- B.
Ruang Kelas
- C.
Lapangan Sepak Bola
- D.
Jalan Raya
- E.
Industri
Correct Answer
E. IndustriExplanation
The given LED lamp, as shown in the picture, is suitable for installation in an industrial setting. This is because industrial areas typically require bright and durable lighting solutions, and LED lamps are known for their high brightness and long lifespan. Additionally, LED lamps are energy-efficient, which is beneficial for industrial settings where lighting is required for extended periods of time.Rate this question:
-
- 20.
Salah satu cara untuk memperbaiki faktor daya dalam pemasangan instalasi listrik adalah dengan memasang:
- A.
MCCB
- B.
Resistor
- C.
Kapasitor
- D.
ELCB
- E.
Lampu Led
Correct Answer
C. KapasitorExplanation
Kapasitor adalah salah satu cara untuk memperbaiki faktor daya dalam pemasangan instalasi listrik. Kapasitor bekerja dengan mengimbangi arus reaktif yang dihasilkan oleh beban induktif sehingga meningkatkan faktor daya. Dengan memasang kapasitor, daya yang terbuang akibat arus reaktif dapat dikurangi, sehingga efisiensi sistem listrik meningkat.Rate this question:
-
- 21.
Unutuk mencari intensites penerangan dalam suatu bidang dapat menggunakan rumus..
- A.
Perkalian Intensiats penerangan dengan flux lampu
- B.
Flux cayaha dibagi luas ruangan
- C.
Flux yang dibutuhkan dibagi flux yang dipancarkan dikalikan dengan efisiensi
- D.
Perkalian Intensitas penerangan dengan Luas Ruangan
- E.
Flux cayaha guna dibagi flux caya yang dipancarkan lampu
- F.
Flux cayaha guna dibagi flux caya yang dipancarkan lampu
Correct Answer
B. Flux cayaha dibagi luas ruanganExplanation
The correct answer is "Flux cayaha dibagi luas ruangan." This formula is used to calculate the intensity of illumination in a given area. It states that the flux of light emitted by a lamp should be divided by the area of the room to obtain the intensity of illumination.Rate this question:
-
- 22.
Berikut ini yang termasuk APP adalah.....
- A.
KWh meter dan MCB
- B.
MCB dan MCCB
- C.
KWh meter dan Ampere mater
- D.
Kontaktor dan Ampere meter
- E.
Sekering dan NFB
Correct Answer
A. KWh meter dan MCBExplanation
The correct answer is KWh meter dan MCB. KWh meter is used to measure the amount of electrical energy consumed by a device or system, while MCB (Miniature Circuit Breaker) is a device that automatically interrupts the flow of electric current in a circuit when it exceeds a certain level. Both KWh meter and MCB are commonly used in electrical systems to monitor and protect against excessive energy consumption and electrical faults.Rate this question:
-
- 23.
Supaya efisiensi dalam menghidupkan dan mematikan lampu pada tangga rumah bertingkat dapat berikut memerlukan bahan, diantaranya......
- A.
1 sakelar tunggal, 1 lumpu, kabel
- B.
2 sakelar tukar, 1 lampu, kabel
- C.
2 sakelar tunggal, 2 lampu, kabel
- D.
1 sakelar seri, 2 lampu, kabel
- E.
1 sakelar tukar. 2 lampu, kabel
Correct Answer
B. 2 sakelar tukar, 1 lampu, kabelExplanation
To achieve efficiency in turning on and off the lights on a multi-story staircase, two-way switches are needed. With two-way switches, the lights can be controlled from both the top and bottom of the staircase, eliminating the need to go up or down to turn the lights on or off. One lamp and cables are also required to complete the setup.Rate this question:
-
- 24.
Diketahui flux cahaya 5000, efisiensi 86% Panjang ruang 6 meter dan lebuar 4 meter. Berapa intensitas penerangan ruangan tersebut?
- A.
179 lux
- B.
208,33 lux
- C.
209,33 lux
- D.
242 lux
- E.
210,33 lux
Correct Answer
B. 208,33 luxExplanation
The intensity of illumination in a room is calculated by dividing the luminous flux (in lumens) by the product of the room's length and width (in meters squared). In this case, the luminous flux is given as 5000 and the efficiency is given as 86%. Therefore, the actual luminous flux is 5000 * 0.86 = 4300 lumens. The room's length is 6 meters and the width is 4 meters. So, the intensity of illumination is 4300 / (6 * 4) = 208.33 lux.Rate this question:
-
- 25.
Perkalian Intensitas penerangan dengan Luas Ruangan adalah rumus untk mencari jumlah kebutuhan fl
- A.
Betul
- B.
Salah
Correct Answer
A. BetulExplanation
The given statement is true. The formula for calculating the total amount of light required is by multiplying the intensity of illumination by the area of the room. This formula takes into account both the brightness of the light and the size of the space, providing a more accurate estimation of the lighting needs.Rate this question:
-
Quiz Review Timeline +
Our quizzes are rigorously reviewed, monitored and continuously updated by our expert board to maintain accuracy, relevance, and timeliness.
-
Current Version
-
Mar 22, 2023Quiz Edited by
ProProfs Editorial Team -
Dec 07, 2016Quiz Created by
Maryonoam
Sekolah Global Mandiri - Wilayah Negara Kesatuan Republik Indonesia
Sekolah Global Mandiri - Wilayah Negara Kesatuan Republik Indonesia
Seleksi Penerimaan Mahasiswa Baru Poltekkes Hermina Tahun 2020
Seleksi Penerimaan Mahasiswa Baru Poltekkes Hermina Tahun 2020
Back to top