How Much Do You Know About Triglyceride Trivia Quiz
Triglycerides are essential fats that give our body the necessary energy to function. How much do you know about Triglyceride? Take this trivia quiz will test your knowledge. Can you answer all the questions on our awesome fun quiz? Do you know it all? Let's see you try! Please make sure to attempt all the questions on our quiz to get accurate results. All the very best for the quiz! Hope you get them all right!
- 1.
Lipoprotein lipase acts in:
- A.
Hydrolysis of triacylglycerols of plasma lipoproteins to supply fatty acids to various tissues.
- B.
Intestinal uptake of dietary fat.
- C.
Intracellular lipid breakdown of lipoproteins.
- D.
Lipoprotein breakdown to supply needed amino acids.
- E.
None of the above.
Correct Answer
A. Hydrolysis of triacylglycerols of plasma lipoproteins to supply fatty acids to various tissues.Explanation
Lipoprotein lipase is an enzyme that plays a crucial role in the hydrolysis of triacylglycerols present in plasma lipoproteins. This process breaks down the triacylglycerols into fatty acids, which can then be utilized by various tissues in the body. It is responsible for supplying the necessary fatty acids for energy production and other metabolic processes. Therefore, the correct answer is that lipoprotein lipase acts in the hydrolysis of triacylglycerols of plasma lipoproteins to supply fatty acids to various tissues.Rate this question:
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- 2.
Free fatty acids in the bloodstream are:
- A.
Bound to hemoglobin.
- B.
Carried by the protein serum albumin.
- C.
Freely soluble in the aqueous phase of the blood.
- D.
Nonexistent; the blood does not contain free fatty acids.
- E.
Present at levels that are independent of epinephrine.
Correct Answer
B. Carried by the protein serum albumin.Explanation
Free fatty acids in the bloodstream are carried by the protein serum albumin. Serum albumin is the most abundant protein in the blood and it acts as a carrier for various substances, including fatty acids. Fatty acids are not freely soluble in the aqueous phase of the blood, so they require a carrier protein like serum albumin to be transported throughout the bloodstream. The statement that free fatty acids are nonexistent in the blood is incorrect, as they are indeed present and are carried by serum albumin. The statement about the levels of free fatty acids being independent of epinephrine is not mentioned in the question and therefore cannot be determined.Rate this question:
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- 3.
The role of hormone-sensitive triacylglycerol lipase is to:
- A.
Hydrolyze lipids stored in the liver.
- B.
Hydrolyze membrane phospholipids in hormone-producing cells.
- C.
Hydrolyze triacylglycerols stored in adipose tissue.
- D.
Synthesize lipids in adipose tissue.
- E.
Synthesize triacylglycerols in the liver.
Correct Answer
C. Hydrolyze triacylglycerols stored in adipose tissue.Explanation
Hormone-sensitive triacylglycerol lipase plays a role in hydrolyzing triacylglycerols stored in adipose tissue. Triacylglycerols are the main form of stored energy in adipose tissue, and when energy is needed, hormone-sensitive triacylglycerol lipase breaks down these triacylglycerols into fatty acids and glycerol, which can then be used as a fuel source by the body. This process is important for regulating energy balance and maintaining proper metabolic function.Rate this question:
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- 4.
The glycerol produced from the hydrolysis of triacylglycerides enters glycolysis as:
- A.
Glucose.
- B.
Glucose-6-phosphate.
- C.
Dihydroxyacetone phosphate.
- D.
Pyruvate.
- E.
Glyceryl CoA.
Correct Answer
C. Dihydroxyacetone phosphate.Explanation
The glycerol produced from the hydrolysis of triacylglycerides enters glycolysis as dihydroxyacetone phosphate. This is because glycerol is converted into dihydroxyacetone phosphate through a series of enzymatic reactions. Dihydroxyacetone phosphate is an intermediate molecule in glycolysis, where it can be further metabolized to produce ATP. Therefore, dihydroxyacetone phosphate is the correct answer as it is the form in which glycerol enters the glycolytic pathway.Rate this question:
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- 5.
Transport of fatty acids from the cytoplasm to the mitochondrial matrix requires:
- A.
ATP, carnitine, and coenzyme A.
- B.
ATP, carnitine, and pyruvate dehydrogenase.
- C.
ATP, coenzyme A, and hexokinase.
- D.
ATP, coenzyme A, and pyruvate dehydrogenase.
- E.
Carnitine, coenzyme A, and hexokinase.
Correct Answer
A. ATP, carnitine, and coenzyme A. -
- 6.
Fatty acids are activated to acyl-CoAs and the acyl group is further transferred to carnitine because:
- A.
Acyl-carnitines readily cross the mitochondrial inner membrane, but acyl-CoAs do not.
- B.
Acyl-CoAs easily cross the mitochondrial membrane, but the fatty acids themselves will not.
- C.
Carnitine is required to oxidize NAD+ to NADH.
- D.
Fatty acids cannot be oxidized by FAD unless they are in the acyl-carnitine form.
- E.
None of the above is true.
Correct Answer
A. Acyl-carnitines readily cross the mitochondrial inner membrane, but acyl-CoAs do not.Explanation
Fatty acids are activated to acyl-CoAs in the cytosol, but they need to be transported into the mitochondria for oxidation. Acyl-carnitines are formed by transferring the acyl group from acyl-CoA to carnitine, which allows them to cross the mitochondrial inner membrane through a specific transporter. Once inside the mitochondria, the acyl-carnitine is converted back to acyl-CoA, which can then undergo beta-oxidation. This process ensures that fatty acids can be efficiently transported into the mitochondria for oxidation.Rate this question:
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- 7.
Carnitine is:
- A.
A 15-carbon fatty acid.
- B.
An essential cofactor for the citric acid cycle.
- C.
Essential for intracellular transport of fatty acids.
- D.
One of the amino acids commonly found in protein.
- E.
Present only in carnivorous animals.
Correct Answer
C. Essential for intracellular transport of fatty acids.Explanation
Carnitine is essential for intracellular transport of fatty acids. It plays a crucial role in the movement of fatty acids into the mitochondria, where they can be oxidized to produce energy. Without carnitine, fatty acids would not be able to enter the mitochondria and would be unable to be used as a fuel source. Carnitine is not a fatty acid itself, nor is it an essential cofactor for the citric acid cycle. It is also not an amino acid commonly found in protein, and while it is more abundant in meat, it is not exclusively found in carnivorous animals.Rate this question:
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- 8.
Which of these is able to cross the inner mitochondrial membrane?
- A.
Acetyl–CoA
- B.
Fatty acyl–carnitine
- C.
Fatty acyl–CoA
- D.
Malonyl–CoA
- E.
None of the above can cross.
Correct Answer
B. Fatty acyl–carnitineExplanation
Fatty acyl-carnitine is able to cross the inner mitochondrial membrane. This is because fatty acids need to be transported into the mitochondria for beta-oxidation, and they do so by forming a complex with carnitine. This complex, called fatty acyl-carnitine, can then cross the inner mitochondrial membrane through a specific transport protein called the carnitine-acylcarnitine translocase. Once inside the mitochondria, the fatty acyl-carnitine is converted back to fatty acyl-CoA, which can then undergo beta-oxidation. Acetyl-CoA, fatty acyl-CoA, and malonyl-CoA are not able to cross the inner mitochondrial membrane directly.Rate this question:
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- 9.
What is the correct order of function of the following enzymes of (beta) oxidation? 1. Beta-Hydroxyacyl-CoA dehydrogenase 2. Thiolase 3. Enoyl-CoA hydratase 4. Acyl-CoA dehydrogenase
- A.
1, 2, 3, 4
- B.
3, 1, 4, 2
- C.
4, 3, 1, 2
- D.
1, 4, 3, 2
- E.
4, 2, 3, 1
Correct Answer
C. 4, 3, 1, 2Explanation
The correct order of function for the enzymes of β-oxidation is Acyl-CoA dehydrogenase, Enoyl-CoA hydratase, β-Hydroxyacyl-CoA dehydrogenase, and Thiolase. Acyl-CoA dehydrogenase is responsible for the first step, which is the dehydrogenation of acyl-CoA. Enoyl-CoA hydratase then adds water to the double bond, followed by β-Hydroxyacyl-CoA dehydrogenase, which oxidizes the hydroxyl group. Finally, Thiolase cleaves the β-ketoacyl-CoA into acetyl-CoA and a shorter acyl-CoA chain.Rate this question:
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- 10.
If the 16-carbon saturated fatty acid palmitate is oxidized completely to carbon dioxide and water (via the Beta-oxidation pathway and the citric acid cycle), and all of the energy-conserving products are used to drive ATP synthesis in the mitochondrion, the net yield of ATP per molecule of palmitate is:
- A.
3
- B.
10
- C.
25
- D.
108
- E.
1,000
Correct Answer
D. 108Explanation
The complete oxidation of palmitate through beta-oxidation and the citric acid cycle produces a total of 129 ATP molecules. However, since 2 ATP molecules are used in the activation of palmitate, the net yield of ATP per molecule of palmitate is 129 - 2 = 127 ATP molecules.Rate this question:
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- 11.
Saturated fatty acids are degraded by the stepwise reactions of beta oxidation, producing acetyl-CoA. Under aerobic conditions, how many ATP molecules would be produced as a consequence of removal of each acetyl-CoA?
- A.
2
- B.
3
- C.
4
- D.
6
- E.
5
Correct Answer
C. 4Explanation
During aerobic conditions, each acetyl-CoA produced from the degradation of saturated fatty acids goes through the citric acid cycle (also known as the Krebs cycle) to produce energy. In the citric acid cycle, one molecule of acetyl-CoA produces 3 molecules of NADH, 1 molecule of FADH2, and 1 molecule of GTP (which can be converted to ATP). The NADH and FADH2 molecules then go through the electron transport chain, which produces ATP. Each NADH molecule produces approximately 2.5 ATP, while each FADH2 molecule produces approximately 1.5 ATP. Therefore, the total ATP produced from the degradation of each acetyl-CoA is approximately 4 ATP molecules.Rate this question:
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- 12.
Which of the following is (are) true of the oxidation of 1 mol of palmitate (a 16-carbon saturated fatty acid; 16:0) by the beta-oxidation pathway, beginning with the free fatty acid in the cytoplasm? 1. Activation of the free fatty acid requires the equivalent of two ATPs. 2. Inorganic pyrophosphate (PPi) is produced. 3. Carnitine functions as an electron acceptor. 4. 8 mol of FADH2 are formed. 5. 8 mol of acetyl-CoA are formed. 6. There is no direct involvement of NAD+.
- A.
1 and 5 only
- B.
1, 2 and 5
- C.
1, 2 and 6
- D.
1, 3 and 5
- E.
5 only
Correct Answer
B. 1, 2 and 5Explanation
The oxidation of palmitate by the β-oxidation pathway requires the activation of the free fatty acid, which requires the equivalent of two ATPs (1). Inorganic pyrophosphate (PPi) is produced during the process (2). Through the β-oxidation pathway, 1 mol of palmitate produces 8 mol of acetyl-CoA (5). Therefore, the correct answer is 1, 2, and 5. There is no information provided regarding carnitine functioning as an electron acceptor (3) or the direct involvement of NAD+ (6).Rate this question:
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- 13.
Complete oxidation of 1 mole of which fatty acid would yield the most ATP?
- A.
16-carbon saturated fatty acid
- B.
18-carbon mono-unsaturated fatty acid
- C.
16-carbon mono-unsaturated fatty acid
- D.
16-carbon poly-unsaturated fatty acid
- E.
14-carbon saturated fatty acid
Correct Answer
B. 18-carbon mono-unsaturated fatty acidExplanation
The 18-carbon mono-unsaturated fatty acid would yield the most ATP because it has the longest carbon chain, which provides more opportunities for beta-oxidation. Beta-oxidation is the process by which fatty acids are broken down to produce ATP. The longer the carbon chain, the more acetyl-CoA molecules can be produced, leading to more ATP production through the citric acid cycle and oxidative phosphorylation. Additionally, the mono-unsaturation of the fatty acid does not significantly affect its ability to be oxidized, so it can still undergo beta-oxidation efficiently.Rate this question:
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- 14.
Which of the following statements apply (applies) to the betaWhich of the following statements apply (applies) to the beta oxidation of fatty acids? 1. The process takes place in the cytosol of mammalian cells. 2. Carbon atoms are removed from the acyl chain one at a time. 3. Before oxidation, fatty acids must be converted to their CoA derivatives. 4. NADP+ is the electron acceptor. 5. The products of beta oxidation can directly enter the citric acid cycle for further oxidation. oxidation of fatty acids?
- A.
1 and 3 only
- B.
1, 2 and 3
- C.
1, 2 and 5
- D.
3 and 5 only
- E.
4 only
Correct Answer
D. 3 and 5 onlyExplanation
The beta oxidation of fatty acids takes place in the cytosol of mammalian cells. Carbon atoms are removed from the acyl chain one at a time during the process. Before oxidation, fatty acids must be converted to their CoA derivatives. NADP+ is not the electron acceptor in beta oxidation. The products of beta oxidation can directly enter the citric acid cycle for further oxidation. Therefore, the correct statements are 3 and 5 only.Rate this question:
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- 15.
Which of the following statements concerning the beta oxidation of fatty acids is true?
- A.
About 1,200 ATP molecules are ultimately produced per 20-carbon fatty acid oxidized.
- B.
One FADH2 and two NADH are produced for each acetyl-CoA.
- C.
The free fatty acid must be carboxylated in the beta position by a biotin-dependent reaction before the process of beta oxidation commences
- D.
The free fatty acid must be converted to a thioester before the process of beta oxidation commences
- E.
Two NADH are produced for each acetyl-CoA.
Correct Answer
D. The free fatty acid must be converted to a thioester before the process of beta oxidation commencesExplanation
Before the process of β-oxidation can begin, the free fatty acid must be converted to a thioester. This is done by the enzyme fatty acyl-CoA synthetase, which activates the fatty acid by attaching it to CoA, forming a fatty acyl-CoA thioester. This thioester is then ready to undergo β-oxidation, where it is sequentially broken down into acetyl-CoA units. This process occurs in the mitochondria and ultimately results in the production of ATP.Rate this question:
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- 16.
The balanced equation for the degradation of CH3(CH2)10COOH via the beta-oxidation pathway is:
- A.
CH3(CH2)10COOH + 5FAD + 5NAD+ + 6CoA—SH + 5H2O + ATP 6 Acetyl-CoA + 5FADH2 + 5NADH + 5H+ + AMP + PPi
- B.
CH3(CH2)10COOH + 5FAD + 5NAD+ + 6CoA—SH + 5H2O 6 Acetyl-CoA + 5FADH2 + 5NADH + 5H+
- C.
CH3(CH2)10COOH + 6FAD + 6NAD+ + 6CoA—SH + 6H2O + ATP 6 Acetyl-CoA + 6FADH2 + 6NADH + 6H+ + AMP + PPi
- D.
CH3(CH2)10COOH + 6FAD + 6NAD+ + 6CoA—SH + 6H2O 6 Acetyl-CoA + 6FADH2 + 6NADH + 6H+
Correct Answer
A. CH3(CH2)10COOH + 5FAD + 5NAD+ + 6CoA—SH + 5H2O + ATP 6 Acetyl-CoA + 5FADH2 + 5NADH + 5H+ + AMP + PPiExplanation
The balanced equation for the degradation of CH3(CH2)10COOH via the β-oxidation pathway is provided in the given answer. It shows the reactants (CH3(CH2)10COOH, 5FAD, 5NAD+, 6CoA—SH, 5H2O, ATP) and the products (6 Acetyl-CoA, 5FADH2, 5NADH, 5H+, AMP, PPi) of the reaction. The coefficients in the equation represent the stoichiometric ratios between the reactants and products, ensuring that the equation is balanced.Rate this question:
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- 17.
Which compound is an intermediate of the beta oxidation of fatty acids?
- A.
CH3—(CH2)20—CO—COOH
- B.
CH3—CH2—CO—CH2—CO—OPO3 2–
- C.
CH3—CH2—CO—CH2—OH
- D.
CH3—CH2—CO—CO—S—CoA
- E.
CH3—CO—CH2—CO—S—CoA
Correct Answer
E. CH3—CO—CH2—CO—S—CoAExplanation
The compound CH3—CO—CH2—CO—S—CoA is an intermediate of the β-oxidation of fatty acids. β-oxidation is the process by which fatty acids are broken down in the mitochondria to produce energy. This compound, known as acetyl-CoA, is formed during the β-oxidation process and can then enter the citric acid cycle to generate ATP.Rate this question:
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- 18.
The conversion of palmitoyl-CoA (16:0) to myristoyl-CoA (14:0) and 1 mol of acetyl-CoA by the -oxidation pathway results in the net formation of:
- A.
1 FADH2 and 1 NADH.
- B.
1 FADH2 and 1 NADPH.
- C.
1 FADH2, 1 NADH, and 1 ATP.
- D.
2 FADH2 and 2 NADH.
- E.
2 FADH2, 2 NADH, and 1 ATP.
Correct Answer
A. 1 FADH2 and 1 NADH.Explanation
The conversion of palmitoyl-CoA to myristoyl-CoA through β-oxidation results in the removal of two carbons from the fatty acid chain. This process involves four steps: oxidation, hydration, oxidation, and thiolysis. In the first oxidation step, FAD is reduced to FADH2, generating 1 FADH2. In the second oxidation step, NAD+ is reduced to NADH, producing 1 NADH. Therefore, the net formation is 1 FADH2 and 1 NADH.Rate this question:
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- 19.
Which of the following is not true regarding the oxidation of 1 mol of palmitate (16:0) by the -oxidation pathway?
- A.
1 mol of ATP is needed.
- B.
8 mol of acetyl-CoA are formed.
- C.
8 mol of FADH2 are formed.
- D.
AMP and PPi are formed.
- E.
The reactions occur in the mitochondria.
Correct Answer
C. 8 mol of FADH2 are formed.Explanation
The oxidation of 1 mol of palmitate (16:0) by the β-oxidation pathway produces 7 mol of FADH2, not 8 mol. FADH2 is a reduced form of flavin adenine dinucleotide, which is an electron carrier in the electron transport chain.Rate this question:
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- 20.
If an aerobic organism (e.g., the bacterium E. coli) were fed each of the following four compounds as a source of energy, the energy yield per mole from these molecules would be in the order:
- A.
Alanine > glucose > palmitate (16:0)
- B.
Glucose > alanine > palmitate
- C.
Glucose > palmitate > alanine
- D.
Palmitate > alanine > glucose
- E.
Palmitate > glucose > alanine
Correct Answer
E. Palmitate > glucose > alanineExplanation
The correct answer is palmitate > glucose > alanine. This is because palmitate is a long-chain fatty acid which can yield a high amount of energy when oxidized. Glucose is a carbohydrate that can also be efficiently metabolized to produce energy. Alanine is an amino acid which can be converted to glucose through gluconeogenesis, but it yields less energy compared to palmitate and glucose. Therefore, the energy yield per mole from these molecules would be in the order palmitate > glucose > alanine.Rate this question:
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- 21.
Which of the following is (are) true of the oxidation of long-chain fatty acids? 1. The enzyme complex that catalyzes the reaction contains biotin. 2. FADH2 serves as an electron carrier. 3. NADH serves as an electron carrier. 4. Oxidation of an 18-carbon fatty acid produces six molecules of propionyl-CoA. 5. Oxidation of a 15-carbon fatty acid produces at least one propionyl-CoA.
- A.
1, 2 and 3
- B.
1, 2 and 5
- C.
2, 3 and 4
- D.
2, 3 and 5
- E.
3 and 5 only
Correct Answer
E. 3 and 5 onlyExplanation
The beta oxidation of long-chain fatty acids involves the breakdown of fatty acids into acetyl-CoA molecules. Biotin is not involved in this process, so statement 1 is false. FADH2 and NADH do serve as electron carriers in the beta oxidation process, so statement 2 and 3 are true. The oxidation of an 18-carbon fatty acid produces nine molecules of acetyl-CoA, not propionyl-CoA, so statement 4 is false. However, the oxidation of a 15-carbon fatty acid does produce one molecule of propionyl-CoA, so statement 5 is true. Therefore, the correct answer is 3 and 5 only.Rate this question:
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- 22.
The following fatty acid, in which the indicated carbon is labeled with 14C, is fed to an animal: 14CH3(CH2)9COOH After allowing 30 minutes for fatty acid oxidation, the label would most likely be recovered in:
- A.
Acetyl-CoA.
- B.
Beta-hydroxy butyryl-CoA.
- C.
Both acetyl-CoA and propionyl-CoA.
- D.
Palmitoyl-CoA.
- E.
Propionyl-CoA.
Correct Answer
E. Propionyl-CoA.Explanation
The given fatty acid has a 14C label on the indicated carbon. During β-oxidation, fatty acids are broken down into two-carbon units in the form of acetyl-CoA. However, if the fatty acid being oxidized has an odd number of carbons, the final product of β-oxidation will be a three-carbon compound called propionyl-CoA. Since the labeled carbon is in an odd-numbered position, it is most likely to be recovered in the form of propionyl-CoA.Rate this question:
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- 23.
The carbon atoms from a fatty acid with an odd number of carbons will enter the citric acid cycle as acetyl-CoA and:
- A.
Butyrate.
- B.
Citrate.
- C.
Malate
- D.
Succinyl-CoA.
- E.
-ketoglutarate.
Correct Answer
D. Succinyl-CoA.Explanation
Fatty acids with an odd number of carbons are broken down into acetyl-CoA molecules during beta-oxidation. However, since the citric acid cycle requires two carbons to enter, the acetyl-CoA from the odd-numbered fatty acid is further metabolized into succinyl-CoA. Therefore, the carbon atoms from a fatty acid with an odd number of carbons will enter the citric acid cycle as succinyl-CoA.Rate this question:
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- 24.
In the disease sprue, vitamin B12 (cobalamin) is poorly absorbed in the intestine, resulting in B12 deficiency. If each of the following fatty acids were in the diet, for which one would the process of fatty acid oxidation be most affected in a patient with sprue?
- A.
CH3(CH2)10COOH
- B.
CH3(CH2)11COOH
- C.
CH3(CH2)12COOH
- D.
CH3(CH2)14COOH
- E.
CH3(CH2)18COOH
Correct Answer
B. CH3(CH2)11COOHExplanation
In patients with sprue, the disease affects the absorption of vitamin B12 in the intestine, leading to a deficiency. Fatty acid oxidation is a process that requires vitamin B12 as a cofactor. Therefore, the process of fatty acid oxidation would be most affected by the presence of CH3(CH2)11COOH in the diet. This particular fatty acid would not be able to undergo proper oxidation due to the deficiency of vitamin B12 in patients with sprue.Rate this question:
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- 25.
Which enzyme is the major regulatory control point for -oxidation?
- A.
Pyruvate carboxylase
- B.
Carnitine acyl transferase I
- C.
Acetyl CoA dehydrogenase
- D.
Enoyl CoA isomerase
- E.
Methylmalonyl CoA mutase
Correct Answer
B. Carnitine acyl transferase IExplanation
Carnitine acyl transferase I is the major regulatory control point for β-oxidation. This enzyme is responsible for the transport of fatty acids into the mitochondria, where β-oxidation takes place. It catalyzes the conversion of acyl-CoA to acylcarnitine, allowing the fatty acids to enter the mitochondrial matrix for further breakdown and energy production. By regulating the activity of carnitine acyl transferase I, the cell can control the rate of fatty acid oxidation and adjust energy production according to its needs.Rate this question:
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- 26.
During oxidation of fatty acids, ___________ is produced in peroxisomes but not in mitochondria.
- A.
Acetyl-CoA
- B.
FADH2
- C.
H2O
- D.
H2O2
- E.
NADH
Correct Answer
D. H2O2Explanation
During β-oxidation of fatty acids, hydrogen peroxide (H2O2) is produced in peroxisomes but not in mitochondria. This is because peroxisomes contain the enzyme catalase, which can break down hydrogen peroxide into water (H2O) and oxygen (O2). Mitochondria do not have catalase, so they cannot break down hydrogen peroxide. This key difference allows peroxisomes to handle the potentially harmful byproduct of β-oxidation, while mitochondria do not have this capability.Rate this question:
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- 27.
When comparing the B-oxidation and W-oxidation pathways, which one of the following statements is correct?
- A.
B-oxidation and W-oxidation occur in the cytoplasm.
- B.
B oxidation occurs at the carboxyl end of the fatty acid whereas W oxidation occurs at the methyl end.
- C.
B oxidation occurs at the methyl end of the fatty acid whereas W oxidation occurs at the carboxyl end.
- D.
B oxidation occurs mainly in the cytoplasm whereas W oxidation occurs mainly in the mitochondria.
- E.
B oxidation occurs mainly in the mitochondria whereas W oxidation occurs mainly in the cytoplasm.
Correct Answer
B. B oxidation occurs at the carboxyl end of the fatty acid whereas W oxidation occurs at the methyl end.Explanation
In beta-oxidation, the fatty acid is broken down at the carboxyl end, while in omega-oxidation, it is broken down at the methyl end. This means that the correct statement is that beta-oxidation occurs at the carboxyl end of the fatty acid whereas omega-oxidation occurs at the methyl end.Rate this question:
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- 28.
Ketone bodies are formed in the liver and transported to the extrahepatic tissues mainly as:
- A.
Acetoacetyl-CoA.
- B.
Acetone.
- C.
Beta-hydroxybutyric acid.
- D.
Beta-hydroxybutyryl-CoA.
- E.
Lactic acid.
Correct Answer
C. Beta-hydroxybutyric acid.Explanation
Ketone bodies are formed in the liver as acetoacetyl-CoA, which is then converted to beta-hydroxybutyric acid. This is the main form in which ketone bodies are transported to extrahepatic tissues. Acetone is a minor ketone body that is produced in small amounts and exhaled through breath. Beta-hydroxybutyryl-CoA is not a ketone body but a precursor in the synthesis of ketone bodies. Lactic acid is not involved in the formation or transportation of ketone bodies.Rate this question:
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- 29.
The major site of formation of acetoacetate from fatty acids is the:
- A.
Adipose tissue.
- B.
Intestinal mucosa.
- C.
Kidney
- D.
Liver
- E.
Muscle
Correct Answer
D. LiverExplanation
The liver is the major site of formation of acetoacetate from fatty acids. This is because the liver plays a crucial role in fatty acid metabolism and is responsible for the breakdown of fatty acids into acetyl-CoA molecules. Acetyl-CoA can then be used to produce ketone bodies, including acetoacetate. Other tissues, such as muscle and adipose tissue, can also produce and utilize ketone bodies, but the liver is the primary organ involved in their formation.Rate this question:
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Aug 14, 2023Quiz Edited by
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Nov 20, 2011Quiz Created by
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