How Much Do You Know About Acceleration?
Quiz for Period 2 Computer based science class. Quiz is from the Holt Science Spectrum.
Questions and Answers
- 1.
Acceleration can mean
- A.
Speeding up.
- B.
Slowing down.
- C.
Changing direction.
- D.
All of the above
Correct Answer
D. All of the aboveExplanation
The term "acceleration" refers to any change in the velocity of an object, which can include speeding up, slowing down, or changing direction. Therefore, the correct answer is "All of the above" because all of these options are examples of acceleration.Rate this question:
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- 2.
Centripetal acceleration occurs because an object is
- A.
Speeding up.
- B.
Slowing down.
- C.
Changing direction.
- D.
None of the above
Correct Answer
C. Changing direction.Explanation
Centripetal acceleration occurs because an object is changing direction. When an object moves in a circular path, it constantly changes its direction, even if its speed remains constant. Centripetal acceleration is the acceleration directed towards the center of the circle, which keeps the object moving in a curved path. This acceleration is necessary to counteract the tendency of the object to move in a straight line and ensures that it stays on its circular path.Rate this question:
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- 3.
Which of the following is constant during uniform circular motion?
- A.
Velocity
- B.
Speed
- C.
Displacement
- D.
Direction
Correct Answer
B. SpeedExplanation
During uniform circular motion, the speed of the object remains constant. This is because the object is moving in a circle at a constant rate, meaning it covers the same distance in the same amount of time. However, the velocity of the object is not constant because velocity includes both speed and direction. In circular motion, the direction of the object is constantly changing as it moves around the circle, even though its speed remains the same. Displacement is also not constant as it depends on the starting and ending positions of the object.Rate this question:
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- 4.
The average acceleration of a car that goes from 0 m/s to 25 m/s in 8.0 s is.
- A.
0.32 m/s
- B.
0.32 m/s^2
- C.
3.1 m/s
- D.
3.1 m/s^2
Correct Answer
D. 3.1 m/s^2Explanation
The average acceleration of a car can be calculated by dividing the change in velocity by the time taken. In this case, the car goes from 0 m/s to 25 m/s in 8.0 s. The change in velocity is 25 m/s - 0 m/s = 25 m/s. Dividing this by the time taken, we get 25 m/s / 8.0 s = 3.1 m/s^2. Therefore, the correct answer is 3.1 m/s^2.Rate this question:
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- 5.
A cyclist is traveling at an initial speed of 10.0 m/s. She accelerates at a rate of 0.500 m/s^2. Find her final speed after 9.0 s.
- A.
14.5 m/s
- B.
14.5 m/s^2
- C.
5.5 m/s
- D.
5.5 m/s^2
Correct Answer
A. 14.5 m/sExplanation
The cyclist starts with an initial speed of 10.0 m/s and accelerates at a rate of 0.500 m/s^2. To find the final speed after 9.0 s, we can use the equation: final speed = initial speed + (acceleration * time). Plugging in the values, we get: final speed = 10.0 m/s + (0.500 m/s^2 * 9.0 s) = 10.0 m/s + 4.5 m/s = 14.5 m/s. Therefore, the correct answer is 14.5 m/s.Rate this question:
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- 6.
Peter runs in a constant direction on a straight road. The velocity-time graph of Peter's motion shows a straight line with a negative slope. What does the line tell you about Peter's speed?
- A.
It is increasing.
- B.
It is decreasing.
- C.
It is increasing, then decreasing.
- D.
It is constant.
Correct Answer
B. It is decreasing.Explanation
The velocity-time graph shows a straight line with a negative slope, indicating that Peter's velocity is decreasing over time. Since velocity is a measure of both speed and direction, this means that Peter's speed is decreasing as he runs in a constant direction on the straight road.Rate this question:
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- 7.
When velocity changes the same amount over each time interval, acceleration is
- A.
Zero.
- B.
Constant.
- C.
Positive.
- D.
Negative.
Correct Answer
B. Constant.Explanation
When velocity changes the same amount over each time interval, it means that the rate of change of velocity is constant. This indicates that the object is experiencing a constant acceleration. Therefore, the correct answer is constant.Rate this question:
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- 8.
On a velocity-time graph, what shows the value of acceleration?
- A.
The slope of the line
- B.
The x-axis
- C.
The y-axis
- D.
The final velocity
Correct Answer
A. The slope of the lineExplanation
The value of acceleration on a velocity-time graph is shown by the slope of the line. The slope represents the rate at which velocity is changing over time. A steeper slope indicates a greater change in velocity, indicating a higher acceleration. Conversely, a flatter slope indicates a smaller change in velocity, indicating a lower acceleration. Therefore, the slope of the line on a velocity-time graph directly represents the value of acceleration.Rate this question:
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- 9.
A cheetah can accelerate at up to 6.0 m/s^2. How long does it take for a cheeta to speed up from 10.5 m/s to 12.2 m/s?
- A.
0.28 s
- B.
1.7 s
- C.
3.5 s
- D.
10 s
Correct Answer
A. 0.28 sExplanation
The cheetah's acceleration is given as 6.0 m/s^2. To find the time it takes for the cheetah to speed up from 10.5 m/s to 12.2 m/s, we can use the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time. Rearranging the formula to solve for time, we have t = (v - u) / a. Plugging in the values, we get t = (12.2 - 10.5) / 6.0 = 1.7 / 6.0 = 0.28 s.Rate this question:
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- 10.
What does it mean when a change in velocity is negative?
- A.
The object is speeding up.
- B.
The object is changing direction.
- C.
The object is slowing down.
- D.
The object is falling down.
Correct Answer
C. The object is slowing down.Explanation
When a change in velocity is negative, it means that the object is slowing down. Negative velocity indicates that the object is moving in the opposite direction of its initial motion or is decelerating. This means that the object's speed is decreasing over time.Rate this question:
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Mar 21, 2023Quiz Edited by
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Feb 23, 2010Quiz Created by
Rmottershead
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