Cahaya
Quiz IPA dengan Judul " Cahaya " ini berjumlah 20 butir. Untuk menjawab Quiz ini silakan tulis nama , kelas dan nomor absen ( contoh : Munawaroh VIII A 20 ) pada kotak " Name " kemudian klik Start untuk memulai. Untuk melanjutkan dari soal satu ke soal berikutnya klik next question. Setelah selesai menjawab semua soal anda akan memperoleh " certificate " , kemudian print / cetak certificate tersebut. Selamat belajar semoga sukses.
Questions and Answers
- 1.
Berikut ini merupakan sifat-sifat cahaya, kecuali ... .
- A.
Merambat lurus
- B.
Dapat dibiaskan
- C.
Dapat dipantulkan
- D.
Memiliki cepat rambat yang sama di semua medium
Correct Answer
D. Memiliki cepat rambat yang sama di semua mediumExplanation
Cahaya memiliki sifat-sifat seperti merambat lurus, dapat dibiaskan, dan dapat dipantulkan. Namun, cahaya tidak memiliki cepat rambat yang sama di semua medium. Cahaya akan mengalami perubahan kecepatan saat melewati medium yang berbeda, seperti saat melewati udara dan air.Rate this question:
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- 2.
Nyala lilin tidak tampak jika dilihat dengan pipa bengkok, hal ini menunjukkan bahwa cahaya ….
- A.
Memiliki energi
- B.
Merambat lurus
- C.
Mampu berinterferensi
- D.
Memiliki panjang gelombang
Correct Answer
B. Merambat lurusExplanation
The correct answer is "merambat lurus". This is because when light passes through a bent pipe, the light rays continue to travel in a straight line. This demonstrates that light propagates in a straight path, indicating that it travels in a straight line or "merambat lurus".Rate this question:
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- 3.
Apabila sumber cahaya kecil, akan terbentuk bayang-bayang inti yang disebut ….
- A.
Bayang-bayang kabur
- B.
Umbra
- C.
Penumbra
- D.
Bayang-bayang sumber
Correct Answer
B. UmbraExplanation
When a small light source is present, a distinct shadow called "umbra" is formed. The term "umbra" refers to the darkest part of a shadow where all light is blocked by the object. This is in contrast to a "penumbra" which is a lighter shadow that occurs when only part of the light is blocked, creating a partial shadow. Therefore, the correct answer is "umbra".Rate this question:
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- 4.
Terjadinya bayang-bayang benda akibat ….
- A.
Cahaya mengenai benda yang tidak tembus cahaya
- B.
Cahaya dibiaskan oleh benda bening
- C.
Cahaya berinterferensi
- D.
Cahaya merambat lurus dalam medium yang sama
Correct Answer
A. Cahaya mengenai benda yang tidak tembus cahayaExplanation
When light hits an object that does not allow light to pass through, it creates a shadow. This is because the object blocks the path of the light, preventing it from reaching the surface behind the object. Therefore, the correct answer is "cahaya mengenai benda yang tidak tembus cahaya" which means "light hitting an object that does not allow light to pass through."Rate this question:
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- 5.
Bayang-bayang kabur disebut juga ….
- A.
Umbra
- B.
Penumbra
- C.
Inti
- D.
Bayangan
Correct Answer
B. PenumbraExplanation
A "penumbra" refers to the fuzzy or indistinct area of a shadow where only some light is blocked. In the context of the question, "bayang-bayang kabur" translates to "blurry shadow," which aligns with the concept of a penumbra. Therefore, "penumbra" is the correct answer.Rate this question:
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- 6.
Pemantulan baur terjadi karena permukaan bidang pemantul ...
- A.
Datar mengkilap
- B.
Cekung mengkilap
- C.
Halus
- D.
Datar kasar
Correct Answer
D. Datar kasarExplanation
Pemantulan baur terjadi karena permukaan bidang pemantul yang datar kasar. Permukaan yang kasar akan menyebabkan sinar yang datang dipantulkan ke berbagai arah, sehingga terjadi pemantulan baur. Permukaan yang halus atau mengkilap cenderung memantulkan sinar secara teratur dan terarah, sehingga tidak terjadi pemantulan baur.Rate this question:
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- 7.
Perhatikan gambar ! Berdasarkan gambar pemantulan sinar di atas, pernyataan yang benar adalah ….
- A.
Sudut α ≠ sudut β
- B.
Sudut β - sudut γ > 90o
- C.
Sudut α = sudut β
- D.
Sudut β + sudut γ > 90o
Correct Answer
C. Sudut α = sudut βExplanation
Based on the image, it can be observed that the angle of reflection, denoted as α, is equal to the angle of incidence, denoted as β.Rate this question:
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- 8.
Bila seberkas sinar cahaya jatuh pada permukaan bidang pemantul dengan sudut datang 30o, besar sudut yang diapit oleh sinar pantul dan sinar datang adalah ...
- A.
30o
- B.
45o
- C.
60o
- D.
90o
Correct Answer
C. 60oExplanation
When a beam of light falls on a reflective surface, the angle between the incident ray and the normal to the surface is known as the angle of incidence. According to the law of reflection, the angle of incidence is equal to the angle of reflection. In this question, the angle of incidence is given as 30 degrees. Since the angle of reflection is equal to the angle of incidence, the angle between the reflected ray and the incident ray is also 30 degrees. Therefore, the angle between the reflected ray and the incident ray is 60 degrees.Rate this question:
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- 9.
Sifat bayangan yang dibentuk oleh cermin datar adalah ….
- A.
Maya dan terbalik
- B.
Nyata dan sama besar
- C.
Nyata dan tegak
- D.
Maya dan tegak
Correct Answer
D. Maya dan tegakExplanation
The correct answer is "maya dan tegak". This means that the image formed by a flat mirror is virtual (maya) and upright (tegak). In a flat mirror, the reflected rays of light do not actually converge at a point to form a real image. Instead, they appear to diverge from a point behind the mirror, creating a virtual image that is the same size and orientation as the object being reflected.Rate this question:
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- 10.
Sebuah benda diletakkan pada jarak 10 cm di depan cermin datar. Jika cermin digeser 2 cm mendekati benda, maka jarak antara letak bayangan setelah cermin digeser dengan bayangan sebelum cermin digeser adalah ...
- A.
2 cm
- B.
4 cm
- C.
8 cm
- D.
12 cm
Correct Answer
A. 2 cmExplanation
When an object is placed in front of a flat mirror, the distance between the object and its image is twice the distance between the object and the mirror. In this case, the object is initially placed 10 cm in front of the mirror. When the mirror is shifted 2 cm closer to the object, the distance between the object and the mirror becomes 8 cm. Therefore, the distance between the new position of the image and the original position of the image is 2 cm.Rate this question:
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- 11.
Sebuah benda berada di depan dua buah cermin yang disusun membentuk sudut tertentu. Jika bayangan yang terbentuk ada 11 bayangan, sudut antara kedua cermin tersebut adalah ….
- A.
200
- B.
300
- C.
600
- D.
1200
Correct Answer
B. 300Explanation
When an object is placed in front of two mirrors arranged at a certain angle, multiple reflections occur. The number of images formed can be determined using the formula (360/angle) - 1. In this case, if there are 11 images formed, substituting the number of images in the formula, we get (360/angle) - 1 = 11. Solving this equation, we find that the angle between the two mirrors is 30 degrees. Therefore, the correct answer is 300.Rate this question:
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- 12.
Sifat berkas cahaya yang dipantulkan oleh cermin cekung adalah ….
- A.
Dikumpulkan
- B.
Disebarkan
- C.
Dibiaskan
- D.
Diteruskan
Correct Answer
A. DikumpulkanExplanation
Cermin cekung memiliki bentuk yang melengkung ke dalam, sehingga ketika cahaya dipantulkan oleh cermin cekung, sinar-sinar cahaya yang semula tersebar akan terkumpul menjadi satu titik fokus. Oleh karena itu, jawaban yang tepat adalah "dikumpulkan".Rate this question:
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- 13.
Perhatikan gambar di bawah ini! Jika benda diletakkan antara 2F1 dan F1 seperti gambar di atas, maka sifat-sifat bayangan yang akan terbentuk adalah ... .
- A.
Maya, tegak, dan sama besar
- B.
Maya, tegak, dan diperkecil
- C.
Nyata, terbalik, dan diperkecil
- D.
Nyata, terbalik, dan diperbesar
Correct Answer
D. Nyata, terbalik, dan diperbesarExplanation
Jika benda diletakkan antara 2F1 dan F1 pada lensa, maka bayangan yang terbentuk akan nyata, terbalik, dan diperbesar. Ini karena ketika benda diletakkan di antara 2F1 dan F1, bayangan yang terbentuk akan berada di sebelah yang sama dengan benda, terbalik dari benda tersebut, dan memiliki ukuran yang lebih besar dari benda tersebut.Rate this question:
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- 14.
Lukisan pembentukan bayangan pada cermin cekung yang benar adalah ….
- A.
![Cahaya - Quiz]()
- B.
![Cahaya - Quiz]()
- C.
![Cahaya - Quiz]()
- D.
![Cahaya - Quiz]()
Correct Answer
A. -
- 15.
Sebuah botol diletakkan pada jarak 30 cm di depan sebuah cermin cekung ( f = 20 cm ). Jarak bayangan adalah …
- A.
20 CM
- B.
30 CM
- C.
40 CM
- D.
60 CM
Correct Answer
D. 60 CMExplanation
The correct answer is 60 CM. When a bottle is placed 30 cm in front of a concave mirror with a focal length of 20 cm, the image formed will be virtual, upright, and magnified. The magnification of the mirror can be calculated using the formula: M = -d_i / d_o, where M is the magnification, d_i is the distance of the image from the mirror, and d_o is the distance of the object from the mirror. Given that the object distance is 30 cm and the focal length is 20 cm, the image distance can be calculated as 60 cm using the formula 1/f = 1/d_i - 1/d_o. Therefore, the distance of the image is 60 cm.Rate this question:
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- 16.
Perhatikan gambar pembiasan cahaya di bawah ini ! Pada gambar di atas, notasi X menunjukkan suatu medium berbentuk ...
- A.
Kaca
- B.
Udara
- C.
Gas Hidrogen
- D.
Gas CO2
Correct Answer
A. KacaExplanation
Based on the given image, the notation X represents a medium that is transparent and allows light to pass through it. Among the options provided, only glass (kaca) fits this description as it is a transparent material commonly used for windows and lenses. Therefore, the correct answer is glass (kaca).Rate this question:
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- 17.
Suatu benda ditempatkan pada jarak 10 cm di depan sebuah cermin sferik, ternyata terbentuk bayangan maya sejauh 30 cm diukur dari cermin itu. Cermin itu adalah ...
- A.
Cermin cekung dengan jari-jari kelengkungan 15 cm
- B.
Cermin cembung dengan jari-jari kelengkungan 15 cm
- C.
Cermin cekung dengan jari-jari kelengkungan 30 cm
- D.
Cermin cembung dengan jari-jari kelengkungan 30 cm
Correct Answer
A. Cermin cekung dengan jari-jari kelengkungan 15 cmExplanation
The correct answer is "cermin cekung dengan jari-jari kelengkungan 15 cm" because the object is placed in front of the mirror at a distance of 10 cm, and the virtual image is formed at a distance of 30 cm from the mirror. In a concave mirror, the virtual image is formed on the same side as the object and is magnified. The fact that the virtual image is formed at a greater distance than the object suggests that the mirror is concave, and the radius of curvature of 15 cm indicates the degree of curvature of the mirror.Rate this question:
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- 18.
Harga jarak fokus pada cermin cembung adalah ….
- A.
Selalu positif
- B.
Dapat positif dapat negatif
- C.
Selalu negatif
- D.
Tergantung jarak benda
Correct Answer
C. Selalu negatifExplanation
The correct answer is "selalu negatif" because in the context of concave mirrors, the focal length is always negative. This is because the focal point is located on the same side as the object, which means the light rays converge before they reach the mirror.Rate this question:
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- 19.
Sebuah cangkir tingginya 8 cm terletak 10 cm di depan cermin cembung. Jika jari-jari kelengkungan cermin 30 cm, letak bayangan cangkir adalah …
- A.
2 cm dibelakang cermin
- B.
4 cm dibelakang cermin
- C.
6 cm dibelakang cermin
- D.
30 cm dibelakang cermin
Correct Answer
C. 6 cm dibelakang cerminExplanation
The correct answer is 6 cm dibelakang cermin. When an object is placed in front of a convex mirror, the image formed is virtual, upright, and diminished. The distance of the image from the mirror is equal to the focal length of the mirror, which is half the radius of curvature. In this case, the radius of curvature is 30 cm, so the focal length is 15 cm. Since the cup is placed 10 cm in front of the mirror, the image will be formed 10 cm behind the mirror. Therefore, the location of the cup's image is 6 cm behind the mirror.Rate this question:
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- 20.
Sifat bayangan yang dibentuk oleh cermin cembung selalu...
- A.
Maya, tegak, diperkecil
- B.
Maya, tegak, diperbesar
- C.
Nyata, terbalik, diperkecil
- D.
Nyata, terbalik, diperbesar
Correct Answer
A. Maya, tegak, diperkecilExplanation
The correct answer is "Maya, tegak, diperkecil". When an object is placed in front of a convex mirror, the image formed is virtual (maya), upright (tegak), and smaller (diperkecil) than the actual object. Convex mirrors diverge the light rays, causing the image to appear smaller and closer to the mirror. The image is virtual because the light rays do not actually converge at a point to form the image.Rate this question:
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Mar 21, 2023Quiz Edited by
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