Position Verses Time

Step one.     Reset all of the "moving mans" to zero.  Step Two.    Use the position slider to move the man near the tree (-10.0 m) Step Three. Give him a velocity of 1.2 m/s and an acceleration of 0 m/s/s  Step Four.    Start the man in motion until he hits the wall, then stop recording. Question.  What happened to the blue position slider as the man moved across the screen?

• A.

  It stayed in the same place

• B.

  It moves to the right

• C.

  It moves to the left

• D.

  It moved to right stopped then moved to the left

Question.  What happened to the red velocity slider as the man moved across the screen?

• A.

  It stayed in the same place

• B.

  It moves to the right

• C.

  It moves to the left

• D.

  It moved to right stopped then moved to the left

Predict what the Position verses Time graph would look like for this situation?

Predict what the Velocity verses Time graph would look like for this situation?

Step One.      Click on the the tab "chart" at the top of the window Step Two.      Reset all of the "moving mans" to zero.  Step Three.   Use the position slider to move the man near the tree (-10.0 m) Step Four.     Give him a velocity of 1.2 m/s and an acceleration of 0 m/s/s  Step Five.      Start the man in motion until he hits the wall, then stop recording. Which of the following statements best describes the position verses time graph

• A.

  The position stayed the same

• B.

  The position started out positive then over time it became negative

• C.

  The position started out negative then over time it became positive

• D.

  The position started out negative and became more negative

• E.

  The position started out positive and became more positive

Which of the following statements best describes the Velocity verses Time graph

• A.

  The velocity stayed the same

• B.

  The velocity started out positive then over time it became negative

• C.

  The velocity started out negative then over time it became positive

• D.

  The velocity started out negative and became more negative

• E.

  The velocity started out positive and became more positive

Step One.      Click on the the tab "chart" at the top of the window Step Two.      Reset all of the "moving mans" to zero.  Step Three.   Use the position slider to move the man near the house (10.0 m) Step Four.     Give him a velocity of -1.2 m/s and an acceleration of 0 m/s/s  Step Five.      Start the man in motion until he hits the wall, then stop recording. Which of the following statements best describes the position verses time graph

• A.

  The position stayed the same

• B.

  The position started out positive then over time it became negative

• C.

  The position started out negative then over time it became positive

• D.

  The position started out negative and became more negative

• E.

  The position started out positive and became more positive

Which of the following statements best describes the Velocity verses Time graph

• A.

  The velocity stayed the same

• B.

  The velocity started out positive then over time it became negative

• C.

  The velocity started out negative then over time it became positive

• D.

  The velocity started out negative and became more negative

• E.

  The velocity started out positive and became more positive

Looking at the value for the velocities in both "experiments" (1.2 m/s and -1.2 m/s) what effects did these values have on the behavior of the position verses time graph.

• A.

  The first experiment (1.2 m/s) had a positive slope, and the second experiment (-1.2 m/s) had a negative slope.

• B.

  The second experiment (1.2 m/s) had a positive slope and the first experiment (-1.2 m/s) had a negative slope.

• C.

  No changes in the shape of the graphs

Looking at the value for the velocities in both "experiments" (1.2 m/s and -1.2 m/s) what effects did these values have on the behavior of the velocity verses time graph.

• A.

  The first experiment (1.2 m/s) had a velocity verses time that was upper pointing / positive slope. The second experiment (-1.2 m/s) had a velocity verses time that was downward pointing / negative slope.

• B.

  The second experiment (1.2 m/s) had a velocity verses time that was upper pointing / positive slope. The first experiment (-1.2 m/s) had a velocity verses time that was downward pointing / negative slope.

• C.

  No changes in the shape of the graphs, but the first experiment had a constant value above zero and the second experiment was constant value below zero