Process Of Oxidation Numbers Quiz

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Quizzes Created: 21 | Total Attempts: 36,259

Questions: 8 | Attempts: 659 | Updated: Jan 7, 2024

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Process Of Oxidation Numbers Quiz - Quiz

Oxidation states simplify the whole process of working out what is being oxidized and what is being reduced in redox reactions. See if you can guess the following oxidation numbers.

Questions and Answers

1.

What is the oxidation state of sulfur in S2O3?
- A.
  
  +2
- B.
  
  -2
- C.
  
  +3
- D.
  
  -3
Correct Answer
C. +3

Explanation
The oxidation state of sulfur in S2O3 is +3. This is because each oxygen atom in the compound has an oxidation state of -2, and the overall charge of the compound is -2. Since there are three oxygen atoms, the total oxidation state contributed by oxygen is -6. In order to balance the overall charge of -2, the oxidation state of sulfur must be +3.

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2.

What is the oxidation state of oxygen in S2O3?
- A.
  
  +2
- B.
  
  -2
- C.
  
  +3
- D.
  
  -3
Correct Answer
B. -2

Explanation
The oxidation state of oxygen in S2O3 is -2. This is because oxygen is more electronegative than sulfur, and in most compounds, oxygen has an oxidation state of -2. Since there are three oxygen atoms in S2O3, the total oxidation state contribution from oxygen is -6. The overall oxidation state of the compound is 0, so the oxidation state of sulfur must be +6 to balance out the -6 contribution from oxygen. Therefore, each oxygen atom in S2O3 has an oxidation state of -2.

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3.

What is the oxidation state of phosphorus in P2O5?
- A.
  
  +5
- B.
  
  -5
- C.
  
  +2
- D.
  
  -2
Correct Answer
A. +5

Explanation
The oxidation state of phosphorus in P2O5 is -2. This is because oxygen is typically assigned an oxidation state of 5.

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4.

What is the oxidation state of oxygen in P2O5?
- A.
  
  +2
- B.
  
  -2
- C.
  
  +5
- D.
  
  -5
Correct Answer
A. +2

Explanation
The oxidation state of oxygen in P2O5 is +2. In this compound, phosphorus has an oxidation state of +5, and since there are two oxygen atoms for every phosphorus atom, the total oxidation state contributed by oxygen is -10. Since the overall charge of P2O5 is 0, the oxidation state of oxygen must be +2 to balance out the -10 contributed by phosphorus.

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5.

What is the oxidation state of chromium in Na2Cr2O7?
- A.
  
  +2
- B.
  
  -2
- C.
  
  +6
- D.
  
  +7
Correct Answer
C. +6

Explanation
The oxidation state of an element refers to the charge it would have if all its bonds were ionic. In Na2Cr2O7, sodium (Na) has an oxidation state of +1 since it belongs to Group 1 of the periodic table. Oxygen (O) usually has an oxidation state of -2. By assigning x to the oxidation state of chromium (Cr), we can set up the equation: 2(+1) + 2x + 7(-2) = 0. Solving this equation gives us x = +6, indicating that the oxidation state of chromium in Na2Cr2O7 is +6.

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6.

What is the oxidation state of oxygen in Na2Cr2O7?
- A.
  
  +2
- B.
  
  -2
- C.
  
  +7
- D.
  
  -7
Correct Answer
B. -2

Explanation
The oxidation state of oxygen in Na2Cr2O7 is -2. This is because the overall charge of the compound is 0, and since there are two oxygen atoms, the total charge contributed by them is -4. Therefore, each oxygen atom must have an oxidation state of -2 in order to balance out the positive charges of sodium and chromium.

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7.

What is the oxidation state of aluminum in Al2(SO4)3?
- A.
  
  +2
- B.
  
  -2
- C.
  
  +3
- D.
  
  -3
Correct Answer
C. +3

Explanation
In the compound Al2(SO4)3, the sulfate ion (SO4) has a charge of -2. Since there are three sulfate ions, the total charge contributed by them is -6. The overall charge of the compound must be neutral, so the two aluminum ions (Al) must contribute a total charge of +6 to balance out the negative charge. Since there are two aluminum ions, each aluminum ion must have an oxidation state of +3 to give a total charge of +6. Therefore, the oxidation state of aluminum in Al2(SO4)3 is +3.

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8.

What is the oxidation state of sodium in Na2O2?
- A.
  
  +1
- B.
  
  -1
- C.
  
  +2
- D.
  
  -2
Correct Answer
A. +1

Explanation
In Na2O2, the oxidation state of oxygen is -1. Since the overall charge of the compound is 0, the oxidation state of sodium can be calculated as follows: 2(+1) + 2(-1) = 0. Therefore, the oxidation state of sodium in Na2O2 is +1.

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