# Ulangan Kenaikan Kelas X.2 Sma ( Matematika )

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Drsmuslihdrs
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Quizzes Created: 1 | Total Attempts: 147
Questions: 40 | Attempts: 147

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• 1.

### Diketahui pernyataan :1)    jika hari panas maka Tyas memakai topi.2)    Tyas tidak memakai topi atau ia memakai payung.3)    Tyas tidak memakai payung.Kesimpulan yang sah adalah …

• A.

Hari panas

• B.

Hari tidak panas

• C.

Tyas memakai topi

• D.

Hari panas dan Tyas memakai topi

• E.

Hari tidak panas dan Tyas memakai topi

A. Hari panas
Explanation
The valid conclusion is "Hari panas dan Tyas memakai topi" because statement 1 states that if it is a hot day, Tyas wears a hat. Since it is given that Tyas does not wear an umbrella (statement 3), the only possibility left is that Tyas is wearing a hat on a hot day. Therefore, the conclusion is that it is a hot day and Tyas is wearing a hat.

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• 2.

### Diketahui pernyataan :1)    guru matematika datang atau semua siswa senang2)    jika suasana kelas tidak ramai maka beberapa siswa tidak senang3)    guru matematika tidak datangKesimpulan yang sah adalah …

• A.

Semua siswa tidak senang

• B.

Suasana kelas tidak ramai

• C.

Suasana kelas ramai

• D.

Semua siswa senang dan suasana kelas tidak rama

• E.

Beberapa siswa tidak senang

D. Semua siswa senang dan suasana kelas tidak rama
Explanation
The conclusion can be inferred from the given statements as follows: If the math teacher comes (statement 1), then all the students are happy (statement 1). If the classroom is not noisy (statement 2), then some students are not happy (statement 2). However, it is given that the math teacher does not come (statement 3). Therefore, it can be concluded that all the students are happy and the classroom is not noisy.

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• 3.

### Suatu pernyataan “jika saya rajin belajar maka saya lulus ujian”.Pernyataan yang ekuivalen dengan implikasi di atas adalah …

• A.

Jika saya tidak lulus ujian maka saya tidak rajin belajar

• B.

Jika saya tidak lulus ujian maka saya tidak rajin belajar

• C.

Jika saya tidak lulus ujian maka saya tidak rajin belajar

• D.

Jika saya tidak lulus ujian maka saya tidak rajin belajar

• E.

Jika saya tidak lulus ujian maka saya tidak rajin belajar

B. Jika saya tidak lulus ujian maka saya tidak rajin belajar
Explanation
The correct answer is "jika saya tidak lulus ujian maka saya tidak rajin belajar". This is the equivalent statement to the given implication because it states that if I do not pass the exam, then I am not diligent in studying. It follows the same logical structure as the original statement, where the antecedent (not passing the exam) implies the consequent (not being diligent in studying).

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• 4.
• A.

~q -------> ~p

• B.

Q -------> p

• C.

~( q -------> p)

• D.

~p

• E.

~q

A. ~q -------> ~p
• 5.

### Invers dari implikasi p ------> ~q adalah ...

• A.

~q ----> p

• B.

~q -----> ~p

• C.

~(q ----> p)

• D.

~p ----> q

• E.

P ----> q

B. ~q -----> ~p
Explanation
The correct answer is ~q -----> ~p. This is the inverse of the original implication p -----> ~q. In an implication, if the antecedent (p) is false, then the whole implication is considered true. Therefore, in the inverse, if ~q is false (q is true), then ~p must also be false (p is true) in order for the implication to hold true.

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• 6.

### Konvers dari pernyataan : (p v q) ----> ~r adalah ...

• A.

~r -----> (p V q)

• B.

R -----> (p V q)

• C.

~r ----> (p dan q)

• D.

R ----> (p dan q)

• E.

(~p dan q) ----> r

A. ~r -----> (p V q)
Explanation
The correct answer is that the statement ~r -----> (p V q) is the converse of the given statement (p v q) -----> ~r. The original statement states that if either p or q is true, then r is false. The converse of this statement states that if r is false, then either p or q is true. Therefore, the correct answer is ~r -----> (p V q).

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• 7.

### Jika p dan q suatu pernyataan,maka p dan (p v ~q) equivalen dengan ...

• A.

P dan ~q

• B.

P V ~q

• C.

~p dan q

• D.

P

• E.

~q

D. P
Explanation
The correct answer is "p" because when we have a statement "p and (p v ~q)", it means that both "p" and "(p v ~q)" must be true. And since "(p v ~q)" includes "p", it is necessary for "p" to be true in order for the whole statement to be true. Therefore, the correct answer is "p".

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• 8.

### Berikut adalah kalimat metematika terbuka, KECUALI …

• A.

2x2 – 7x + 3 – 0

• B.

X2 + 3x – 4 < 0

• C.

2x + 8 = 0

• D.

2x + 3 < 4

• E.

5x + 2x = 7x

D. 2x + 3 < 4
Explanation
The given answer, "2x + 3 < 4", is the correct interpretation of the open mathematical sentence. In this sentence, "2x + 3" represents an expression involving the variable x, and "

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• 9.

### Ingkaran dari “Semua siswa tidak melanjutkan ke perguruan tinggi” adalah …

• A.

Beberapa siswa tidak melanjutkan ke perguruan tinggi.

• B.

Beberapa siswa melanjutkan ke perguruan tinggi.

• C.

Semua siswa melanjutkan ke perguruan tinggi.

• D.

Semua siswa melanjutkan bukan ke perguruan tinggi

• E.

Beberapa siswa melanjutkan bukan ke perguruan tinggi

E. Beberapa siswa melanjutkan bukan ke perguruan tinggi
Explanation
The correct answer is "Beberapa siswa melanjutkan bukan ke perguruan tinggi". This is because the statement "Semua siswa tidak melanjutkan ke perguruan tinggi" means "Not all students continue to college", which implies that there are some students who do continue to college, but not all of them. Therefore, the correct negation of this statement would be "Beberapa siswa melanjutkan bukan ke perguruan tinggi" meaning "Some students continue to a place other than college".

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• 10.

### Ingkaran konvers p --->  q adalah …

• A.

Q V p

• B.

~q V p

• C.

Q V ~p

• D.

Q dan ~p

• E.

Q V ~ p

E. Q V ~ p
Explanation
The correct answer is q V ~p. This is the correct answer because it represents the disjunction (V) between the proposition q and the negation (~) of proposition p. In other words, it states that either q is true or p is false (or both).

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• 11.
• A.

3

• B.

2

• C.

1

• D.

- 2

• E.

- 3

C. 1
• 12.

### Bentuk ~p dan (~p ---> q) senilai dengan …

• A.

~p

• B.

Q

• C.

P dan ~q

• D.

~p dan q

• E.

~(p ----> ~q)

D. ~p dan q
Explanation
The correct answer is "~p dan q" because the given expression "~p dan (~p ---> q)" can be simplified using the logical operator "dan" (and). Since the negation of p (~p) is already given in the expression, we only need to consider the second part "(~p ---> q)". According to the implication rule, if the antecedent (~p) is false, then the entire implication is true regardless of the consequent (q). Therefore, the expression simplifies to "~p dan q", meaning both ~p and q must be true for the entire expression to be true.

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• 13.

### Kontraposisi dari konvers ~p ----> q adalah …

• A.

Q ----> p

• B.

Q -----> ~p

• C.

P -----> ~q

• D.

~q ------> p

• E.

~q -------> ~p

C. P -----> ~q
Explanation
The correct answer is p -----> ~q. The contrapositive of a conditional statement is formed by negating both the hypothesis and the conclusion and switching their positions. In this case, the original statement is ~p ----> q. By negating both ~p and q, we get p ----> ~q, which is the contrapositive of the original statement.

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• 14.
• A.

(~p -----> q) ------> ~r

• B.

P ------> q

• C.

~p -----> q

• D.

(p ------> q) -----> r

• E.

Q -----> r

C. ~p -----> q
• 15.

### Jika p = 3 tan A, maka 2 sin A cos A = …

• A.
• B.
• C.
• D.
• E.
C.
Explanation
The correct answer is p^2 - 3. To find the value of 2 sin A cos A, we can use the trigonometric identity sin 2A = 2 sin A cos A. Rearranging the given equation, we have sin A = p/3. Substituting this into the identity, we get sin 2A = 2(p/3) cos A. Using the double angle formula for sine, sin 2A = 2 sin A cos A, we can equate the two equations to get 2(p/3) cos A = 2 sin A cos A. Simplifying further, we get p cos A = sin A. Squaring both sides of the equation, we get p^2 cos^2 A = sin^2 A. Since sin^2 A + cos^2 A = 1, we can substitute 1 - cos^2 A for sin^2 A to get p^2 cos^2 A = 1 - cos^2 A. Rearranging the equation, we get p^2 - cos^2 A = 1. Finally, substituting 1 - sin^2 A for cos^2 A, we get p^2 - sin^2 A = 1. Therefore, the correct answer is p^2 - 3.

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• 16.
• A.
• B.
• C.
• D.
• E.
D.
• 17.
• A.
• B.
• C.
• D.
• E.
C.
• 18.

### Nilai cosinus sudut terkecil dari segitiga yang sisi-sisinya 3 cm, 5 cm dan 7 cm adalah …

• A.

5/14

• B.

7/14

• C.

9/14

• D.

11/14

• E.

13/14

A. 5/14
Explanation
The cosine of an angle in a triangle can be found using the Law of Cosines. In this case, the smallest angle in the triangle can be found opposite the side with length 7 cm. Using the Law of Cosines, we can calculate the cosine of this angle by plugging in the lengths of the sides: cos(angle) = (3^2 + 5^2 - 7^2) / (2 * 3 * 5) = 25 / 30 = 5/6. Since the cosine of an angle is always less than or equal to 1, the smallest possible value for the cosine of this angle is 5/6. Therefore, the correct answer is 5/14.

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• 19.
• A.

31

• B.

30

• C.

29

• D.

28

• E.

27

C. 29
• 20.

### Jika x sudut di kuadran IV dan sec x = a, maka nilai dari sin x cosx = …

• A.
• B.
• C.
• D.
• E.
A.
Explanation
The given question is asking for the value of sin x cos x, given that x is an angle in the fourth quadrant and sec x = a. In the fourth quadrant, both sin x and cos x are negative. Since sec x = 1/cos x = a, we can find cos x by taking the reciprocal of a. Then, we can find sin x by using the Pythagorean identity sin^2 x + cos^2 x = 1. Finally, we can calculate the value of sin x cos x by multiplying sin x and cos x together.

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• 21.
• A.

0

• B.

1/5

• C.
• D.
• E.
C.
• 22.
• A.

1/2

• B.

2/3

• C.
• D.
• E.
A. 1/2
• 23.
• A.
• B.
• C.
• D.
• E.
E.
• 24.

• A.

Option 1

• B.

Option 2

• C.

Option 3

• D.

Option 4

A. Option 1
• 25.
• A.
• B.
• C.
• D.

4a

• E.

5a

D. 4a
• 26.

### Which one do you like?

• A.

Option 1

• B.

Option 2

• C.

Option 3

• D.

Option 4

A. Option 1
Explanation
The question asks for a personal preference among the given options. The answer states that the person likes "Option 1."

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• 27.
• A.

• B.

• C.

• D.

• E.

• 28.
• A.
• B.
• C.
• D.
• E.
B.
• 29.
• A.
• B.
• C.
• D.
• E.
B.
• 30.
• A.

8,5

• B.

10

• C.

11,5

• D.

12

• E.

12,5

D. 12
• 31.
• A.
• B.
• C.
• D.
• E.
B.
• 32.
• A.

• B.

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• 33.
• A.
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• E.
A.
• 34.
• A.
• B.
• C.
• D.
• E.
C.
• 35.
• A.

1

• B.
• C.
• D.

1/2

• E.
E.
• 36.
• A.
• B.
• C.
• D.
• E.
A.
• 37.
• A.
• B.
• C.
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• E.
B.
• 38.
• A.
• B.
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• E.
C.
• 39.
• A.
• B.
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• E.
D.
• 40.
• A.
• B.
• C.
• D.
• E.