# Test 1- Edupinnacle-rims

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| By Donedupinnacle
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Donedupinnacle
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Quizzes Created: 1 | Total Attempts: 262
Questions: 30 | Attempts: 262  Settings  • 1.

### The average of 9 integers arranged in a certain order is 32. If the average of the first four integers is 26 and that of the last four integers is 28, then the fifth integer is

• A.

72

• B.

76

• C.

68

• D.

58

A. 72
Explanation
Solution :
Fifth integer
= 9 x 32 – 4 x 26 – 4 x 28
= 288 – 104 – 112 = 72

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• 2.

### In an examination, the average of marks was found to be 50. For deducting marks for computational errors, the marks of 100 candidates had to be changed from 90 to 60 each and so the average of marks came down to 45. The total number of candidates, who appeared at the examination, was ?

• A.

600

• B.

300

• C.

200

• D.

150

A. 600
Explanation
Solution:

Let total number of candidates be x.50 x – 30 x 100 = 45x
5x = 3000X = 3000/5 = 600

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• 3.

### In a History examination, the average for the entire class was 80 marks. If 10 % of the students scored 95 marks and 20% scored 90 marks, what was the average mark of the remaining students of the class?

• A.

65.5

• B.

85

• C.

75

• D.

72.5

C. 75
Explanation
Solution:

Let there be 100 students in the class
Sum of marks for 100 students = 80 x 100 = 8000
Sum of marks for 30 students = 10 x 95 + 20 x 90 = 950 + 1800 = 2750
Sum of marks for remaining 70 students = 8000 – 2750 = 5250
Average marks = 5250 / 70 = 75

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• 4.

### An article is sold at a loss of 29%. Had it been sold for Rs. 84 more, the profit would have been 11%. The cost price of the article must be ?

• A.

210

• B.

200

• C.

180

• D.

170

A. 210
Explanation
Solution:

Suppose C.P. = Rs. K

k – 29% of k + 84 = k + 11% of k

40% of k = 84 => k = 210

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• 5.

### The difference between the selling price and cost price of an article is Rs. 210. If the profit percent is 25, then the selling price of the article is ?

• A.

Rs 950

• B.

Rs 1,050

• C.

Rs 1,150

• D.

Rs 1,250

B. Rs 1,050
Explanation
Solution:
S.P. – C.P. / C.P x 100 = 25
=> 210/C.P. x 100 = 25
=> CP = 100 x 210 / 25 = 840
S.P. = 125/100 of 840
=840 x 125/100 = Rs. 1050

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• 6.

### Oranges are bought at 7 for Rs. 3. At what rate per hundred must they be sold to gain 33% ?

• A.

Rs 56

• B.

Rs 60

• C.

Rs 58

• D.

Rs 57

D. Rs 57
Explanation
Solution:

Cost price of 7 oranges = Rs. 3/7
Cost price of 100 oranges
= 3/7 x 100 = Rs. 300/7
133% = 300/7 x 133/100 = Rs. 57

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• 7.

### 75 litres of a mixture of wine and water contain 15 litres more wine than water. 12 litres of water is added to it. The ratio of the wine to the water in the mixture is?

• A.

3:2

• B.

4:5

• C.

15:14

• D.

1:5

C. 15:14
Explanation
Solution:

Let water in the mixture be x lit. => x + (x+15) = 75 => x = 30, wine = 45 lit.
Wine: water = 45: 42 => 15:14

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• 8.

### 2/5th of a poles is in mud, 1/3rd of the remainder is in water and 10 m is above water. The length of the pole is

• A.

20m

• B.

25m

• C.

15m

• D.

10m

B. 25m
Explanation
Solution:
Mud = 2/5 Remainder= 3/5.Water = 3/5 X 1/3 = 1/5. Above water = 1- (2/5 + 1/5) = 2/5
2/5 = 10 met Total length = 25 m

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• 9.

### A sum of money is divided into 2 parts such that 6 times of one part added to 15 times the other gives 8 times the whole. The ratio of one part to another is ?

• A.

3:5

• B.

5:8

• C.

7:2

• D.

8:13

C. 7:2
Explanation
Solution:

Let the two parts be x and y
6x + 15y = 8(x + y)
2x = 7y => x/7 = y/2=> ratio = 7:2

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• 10.

### The interest on a sum of money at the end of 8 years is 2/5th of the sum itself. Rate percent of interest charged was ?

• A.

5%

• B.

5¼%

• C.

5¾%

• D.

5 ½%

A. 5%
Explanation
SOLUTION:
Let the sum be Rs x
S.I. = 2/5 x
Rate % = 2/5 x * 100 / x * 8 = 5 R = (SI X 100/P X Time)

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• 11.

### A man received Rs. 8000 as Pooja bonus. He invests a part of it at 8 percent per annum and the remaining at 4 percent per annum simple interest. The interest earned by him in 5 years was Rs. 2200. The sum invested at 8 percent per annum must be ?

• A.

Rs. 3000

• B.

Rs. 5000

• C.

Rs. 4500

• D.

Rs. 2000

A. Rs. 3000
Explanation
SOLUTION:

Let ‘x’ be invested at 8% for 5 years. So, 8000-x invested at 4% for 5 years

Interest = 2200= 40x/100 + {(8000-x) X 20}/100

Solving, x = 3000

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• 12.

### If a sum of money placed at compound interest doubles itself in 5 years, then the same amount of money will be 8 times of itself in ?

• A.

25 years

• B.

20 years

• C.

15 years

• D.

10 years

C. 15 years
Explanation
SOLUTION:

If a sum of money becomes ‘x’ times in ‘n’ years, it will become xa times in ‘an’ years, at compound interest

We have, 23 = 8. Hence, no of years= an = 3 X 5 = 15 years.

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• 13.

### The sum of two numbers is 4000. 10% of one number is 6 2/3% of the other. The difference of the numbers is ?

• A.

600

• B.

800

• C.

1025

• D.

1175

B. 800
Explanation
SOLUTION:
Let the nos be x and y.x + y = 4000.x/10 = y/15 => 3x = 2y . Solving, x = 1600And y= 2400 difference = 800

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• 14.

### A man spent 10% of his money and then Rs. 500 and then 10% of the remaining. If he had Rs.360  left, then he initially had how much ?

• A.

Rs 750

• B.

Rs 800

• C.

Rs 900

• D.

Rs 1000

D. Rs 1000
Explanation
Solution:

Working back wards: The man is left with 360 after 10% , hence the amount is Rs 400. ( 90% = 360, so 100% = 400) Adding 500 to that we have 900 which is 90%. Hence100% = 1000

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• 15.

### Rs. 1500 were divided into two parts and one part was put out at 6% interest and the other at 5%. If the whole annual interest from both the investments was Rs. 85, then the investment at 6% was?

• A.

Rs 1200

• B.

Rs 1000

• C.

Rs 1300

• D.

Rs 1150

B. Rs 1000
Explanation
Solution:

Suppose Rs. K were put at 6% and Rs. (1500 – K) were put at 5% S.I.
K x 6 x 1 / 100 + (1500 – K) x 5 x 1 / 100 = 85
=>6K + 7500 – 5K = 8500K = 1000Rs. 1000 were invested at 6%.

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• 16.

### A train takes 12 seconds to pass completely through a station 108 metres long and 16 seconds to pass completely through another station 164 metres long. The length of the train is ?

• A.

64 metres

• B.

60 metres

• C.

80 metres

• D.

84 metres

B. 60 metres
Explanation
Solution:

Let the length of the train be x metres
(x + 108) /12 = (x + 164) /16

4x + 432 = 3x + 492
x = 60

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• 17.

### A train takes 18 seconds in crossing a platform  162 metres long and 15 seconds in crossing another platform 120 metres long. The length of the train is ?

• A.

60 metres

• B.

81 metres

• C.

120 metres

• D.

90 metres

D. 90 metres
Explanation
Solution:

Let length of the train be k metres
162 + k / 18 = 120 + k / 15

=> 162 + k / 6 = 120 + k / 5
=> k = 90

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• 18.

### Raju runs 1250 metre on Monday and Friday. Other days he runs 1500 metre except for Sunday (He does not run on Sunday).How many kilometer will he run in 3 weeks (first day starting from Monday).?

• A.

12.5 km

• B.

20.5 km

• C.

8.5 km

• D.

25.5 km

D. 25.5 km
Explanation
Solution:

Total distance covered
= 3 (2 x 1250 + 4 x 1500) metre
= 3 (2500 + 6000) metre
= 25500 metre = 25.5 km

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• 19.

### If 5 men earn Rs. 540 in 4 days, then earning of 7 men in 6 days is ?

• A.

Rs 1,440

• B.

Rs 1,134

• C.

Rs 1,270

• D.

Rs 1,468

B. Rs 1,134
Explanation
Solution:
5 men in 4 days earn Rs. 540
5 men in 1 day earn Rs. 135
1 man in 1 day earn Rs. 27
7 men in 1 day earn Rs. 189
7 men in 6 days earn Rs. 1134

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• 20.

### A contractor engages 36 men on a job. They do 2/3 of the job in 16 days. He engages 12 more men to finish the job. The number of days now required to complete the remaining portion of the job is ?

• A.

8

• B.

6

• C.

5

• D.

4

B. 6
Explanation
Solution:

Men Work Days
36 2/3 16
48 1/3 X

=> X = 36/48 X 1/3 X 3/2 X 16 = 6

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• 21.

### A group of workers accepted to do a piece of work in 25 days. If 6 of them did not turn up for the work and the remaining workers did the work in 40 days, then the original number of workers was ?

• A.

22

• B.

20

• C.

18

• D.

16

D. 16
Explanation
Solution:

Suppose original number of workers = K
25K = 40(K – 6) => K = 16

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• 22.

### Directions for the following :Examine carefully the following statements and answer the three items that follow:Out of four friends A, B, C and D,A and B play football and cricket,Band C play cricket and hockey,A and D play basketball and football,C and D play hockey and basketball.Question:Who does not play hockey?

• A.

D

• B.

C

• C.

B

• D.

A

D. A
Explanation
Solution:

A Plays football, basketball, football and cricket

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• 23.

### Directions for the following :Examine carefully the following statements and answer the three items that follow:Out of four friends A, B, C and D,A and B play football and cricket,Band C play cricket and hockey,A and D play basketball and football,C and D play hockey and basketball.Question:Who plays football, basketball and hockey?

• A.

D

• B.

C

• C.

B

• D.

A

A. D
Explanation
Solution :

D Plays football, basketball and hockey

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• 24.

### Directions for the following :Examine carefully the following statements and answer the three items that follow:Out of four friends A, B, C and D,A and B play football and cricket,Band C play cricket and hockey,A and D play basketball and football,C and D play hockey and basketball.Question:Which game do B, C and D play?

• A.

• B.

Hockey

• C.

Cricket

• D.

Football

B. Hockey
Explanation
Solution :
The Common game among them is Hockey.

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• 25.

### The music director of a film wants to select four persons to work on different aspects of the composition of a piece of music. Seven persons are available for this work; they are Rohit,Tanya,Shobha,Kaushal,Kunal,Mukesh and Jaswant. Rohit and Tanya will not work together. Kunal and Shobha will not work together. Mukesh and Kunal want to work together.Which of the following is the most acceptable group of the people that can be selected by the music director?

• A.

Rohit,Shobha,Kunal and Kaushal

• B.

Tanya, Kaushal,Shobha and Rohit

• C.

Tanya,Mukesh,Kunal and Jaswant

• D.

Shobha,Tanya,Rohit and Mukesh

C. Tanya,Mukesh,Kunal and Jaswant
Explanation
Solution:
Let us check the answer options one by one.
Option (a) is not possible as Shobha and Kunal shall not work together
Option (b) is not possible as Rohit and Tanya shall not work together
Option (d) is not possible as Rohit and Tanya shall not work together
Hence we shall go with option ( Tanya,Mukesh,Kunal and Jaswant )

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• 26.

### Geeta is older than her cousin Meena. Meena's brother Bipin is older than Geeta. When Meena and Bipin visit Geeta they want to play chess. Meena wins the game more than Geeta. Based on the above information, four conclusions as given below, have been made. Which one of these logically follows from the information given above?

• A.

While playing chess with Geeta and Meena, Bipin often loses

• B.

Geeta is the oldest among the three

• C.

Geeta hates to lose the game

• D.

Meena is the youngest of the three

D. Meena is the youngest of the three
Explanation
Solution:
Let us try to write the given conditions in the form of equations:
Geeta is older than her cousin Meena => G > M
Meena's brother Bipin is older than Geeta => B > G
From these two we can easily say that B > G > M => Bipin is eldest and Meena is youngest among the three. So we can take option (Meena is the youngest of the three
) as right option.

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• 27.

### Seven men A,B,C,D,E,F and G are standing in a queue in that order. Each one is wearing a cap of different colour like violet,indigo,blue,green,yellow,orange and red. D is able to see in front of him green and blue, but not violet. E can see violet and yellow but not red. G can see caps of all colours other than orange. If E is wearing an indigo coloured cap, then the colour of cap worn by F is ?

• A.

Blue

• B.

Violet

• C.

Red

• D.

Orange

C. Red
Explanation
Solution:

Order: A,B,C,D,E,F, G
The point is – A person can see caps of all persons standing in front of him but can’t see his own cap and caps of persons standing behind him.
D is able to see in front of him green and blue, but not violet => The people in front of D ie., A or B or C worn green or blue and people after D and including himself ie., D or E or F or G worn violet
E can see violet and yellow but not red => From this and above statements, we can fix violet cap for D. and A/B/C worn green/blue/yellow not necessarily in that order
G can see caps of all colours other than orange => As he is the last person in the row, he can see all caps except his. So we can fix Orange cap for G
Given that E wears indigo cap.
The summary is:
A/B/C - green/blue/yellow
D - violet
E - indigo
G - orange
Finally, we are left with red cap and so we can fix this to F
Ans: (RED)

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• 28.

### There are some balls of red,green and yellow colour lying on a table. There are as many red balls as there are yellow balls. There are twice as many yellow balls as there are green ones. The number of red balls?

• A.

Is equal to the sum of yellow and green balls

• B.

Is double the number of green balls

• C.

Is equal to yellow balls minus green balls

• D.

Cannot be ascertained

B. Is double the number of green balls
Explanation
Solution:

Let us write as equations:
R=Y and Y=2G => R=2G
=> The number of red balls is equal to double the number of green balls
Ans: (is double the number of green balls)

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• 29.

### In a rare coin collection, there is one gold coin for every three non-gold coins. 10 more gold coins are added to the collection and the ratio of gold coins to non-gold coins would be 1:2. Based on the information, the total number of coins in the collection now becomes?

• A.

90

• B.

80

• C.

60

• D.

50

A. 90
Explanation
Solution:
Initial ratio = G:N = 1:3 ---(1)
After adding 10 gold coins, the ratio becomes (10+G):N = 1:2 ---(2)
On solving (1) & (2), we get, G=20 and N=60.
Presently, the total number of coins in the collection = (10+G)+N= 10+20+60=90
Ans: (90)

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• 30.

### A gardener has 1000 plants. He wants to plant them in such a way that the number of rows and the number of columns remains the same. What is the minimum number of plants that he needs more for this purpose ?

• A.

90

• B.

24

• C.

32

• D.

34

B. 24
Explanation
Solution:

If the number of rows and number of columns are to be equal, then the total number of trees will be in the form of x2, which is nothing but a perfect square. As 1000 is not a perfect square, we need to check for a perfect square above and nearest to 1000.

It’s 1024, which is square of 32. So he needs to add 24 more trees to get 1024.

Ans: (24)

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