Task Unit 2 Senior One

25 Questions | Total Attempts: 51

SettingsSettingsSettings
Task Unit  2   Senior One - Quiz

This Quiz is made by : Mr: Ayman Ali


Questions and Answers
  • 1. 
    ANSWER THE FOLLOWING QUESTIONS : 1-what is meant by : a- Chemical Equation  b-ionic Equation
  • 2. 
    Solve the following equation in form of ions : H2SO4 (Aq) + 2NaOH(Aq) ------ Na2SO4(aq) + 2H2O(l)
  • 3. 
    How much molecules , atoms , ions in water H2O
  • 4. 
    Calculate the mass of 0.2 mol of H2O. H=1 , O=16
  • 5. 
    1. the mass percentage of Fe and O in iron III oxide. [Fe = 56 , O = 16 ]
  • 6. 
    Symbol (S) represents the cpd in ..............................state
    • A. 

      Liquid 

    • B. 

      Solid 

    • C. 

      Vapour

  • 7. 
    Give reason : chemical equation must be balanced 
    • A. 

      To acheive law of force 

    • B. 

      To acheive law of mass conservation 

    • C. 

      To acheive law of nuclear energy

  • 8. 
    Dimensions of atoms , molecules or ions are measured in ……………………………
    • A. 

      Nanometer

    • B. 

      Meter 

    • C. 

      Milimeter

  • 9. 
    The arrow in chemical equation is indicates …….
    • A. 

      Reactants 

    • B. 

      Products 

    • C. 

      Conditions 

  • 10. 
    Mg + O2 ---- MgO choose the suitable balance for this equation
    • A. 

      2-1-2

    • B. 

      1-1-2

    • C. 

      2-3-2

  • 11. 
    The dissolution of  all elements compounds in form of ions is .............................
    • A. 

      Neutralization process

    • B. 

      Dissolving process

    • C. 

      Precipitation process

  • 12. 
    Its dissolving of all elements Except one of the products in precipitate is .....................
    • A. 

      Neutralization process

    • B. 

      Precpitate process

    • C. 

      Dissolution process

  • 13. 
    Atomic mass unit is equal ....................
    • A. 

      1.66 x 10

    • B. 

      1.66 x 10-25 g

    • C. 

      1.66 x 10-24 g

  • 14. 
    why We can't deal with limited atoms , molecules or ions
    • A. 

      Due to their small masses and volumes 

    • B. 

      As we haven't rule for them 

  • 15. 
    Building unit of ionic compound is ..................
    • A. 

      Formula unit 

    • B. 

      Atom

    • C. 

      Crystal lattice

  • 16. 
    Calculate the molar mass of NaHCO3 Na=23 , H=1 ,C=12 , O=16
    • A. 

      32

    • B. 

      84

    • C. 

      108

  • 17. 
    Phosphourous contains ...............atom in its vapour state 
    • A. 

      8

    • B. 

      1

    • C. 

      4

  • 18. 
    Molar mass of hydrogen gas is ……………………
    • A. 

      Mass of 6.02x1023molc

    • B. 

      Mass of 12.04x1023 atoms

    • C. 

      All

  • 19. 
    The number of moles of carbon dioxide which contain 8 g of oxygen is C=12  , O=16 
    • A. 

      0.5

    • B. 

      0.25

    • C. 

      0.4

  • 20. 
    The total no of ions present in 111 g of cacl2 is Ca=40 Cl=35.5
    • A. 

      3

    • B. 

      1

    • C. 

      2

  • 21. 
    Volume at N.T.P of 0.22 g of CO2 is same as that of- H=1 , S=32 , O=16
    • A. 

      (a) 0.01 g of hydrogen

    • B. 

      320 mg of gaseous So2

    • C. 

      All

  • 22. 
    Total number of atoms present 17 g of NH3 is N=14 , H=1
    • A. 

      4 × 10-24 g

    • B. 

      3 × 6. 02 ×1023

    • C. 

      None

  • 23. 
    In the following reaction : 2Mg + O2 ------ 2MgO What is the limiting reactant ? if 16 g of oxygen is added to 48 g Mg Mg=24 , O=16
    • A. 

      Limiting Reacatnt is oxygen 

    • B. 

      Limiting Reactant is Mg

    • C. 

      None

  • 24. 
    Chemical analysis has proven that acetic acid is formed from 40 % of C , 6.67 % of H , and 53.33 % of O and its molar mass is 60g/mol .        H=1 , O=16 , C=12What are the empirical ,d
    • A. 

      CH2O

    • B. 

      C2H2

  • 25. 
    The molecular formula of the pervious question is ..................
    • A. 

      C2H2

    • B. 

      CH4

    • C. 

      C2H4O2

Back to Top Back to top