Multiplication And Division Tables: 2-4 Tables (Level 2)

216 Questions | By Benje Deacon | Updated: Mar 15, 2022 | Attempts: 14

Multiplication and Division tables – 2 to 4 Tables (Level 2). This quiz contains 216 questions. There is an ϰ involved in every question of which the correct value must be given in the answer. Examples:(1) 2 X ϰ = 6 ⇒ 2 must be added ϰ times to get 6⇒ ϰ = ___(2) ϰ ÷ 4 = 5⇒ 4 must be subtracted 5 times from ϰ to get 0⇒ There are 5 4’s in x⇒ ϰ = ___The general question for this quiz is: Give the correct value of ϰ. This quiz will improve your knowledge of the Read more2-4 Multiplication and Division Tables.

Questions and Answers

1.

1 X ϰ = 2 ⇒ 1 must be added ϰ times to get 2 ⇒ ϰ = ____ Type question here. Example: Practice makes you ________.

Explanation
1 X ϰ = 2
⇒ 1 must be added 2 times to get 2
⇒ ϰ = 2 →

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4
2.

1 X 2 = ϰ ⇒ 1 must be added 2 times to get ϰ ⇒ ϰ = ____

Explanation
1 X 2 = ϰ
⇒ 1 added 2 times = 2
⇒ ϰ = 2 →

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4
3.

ϰ ÷ 2 = 1 ⇒ 2 must be subtracted 1 time from ϰ to get 0 ⇒ There is ONE 2 in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 2 = 1
⇒ There is ONE 2 in ϰ
⇒ 2 X 1 = ϰ
⇒ ϰ = 2 →

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4
4.

ϰ X 2 = 2 ⇒ ϰ must be added 2 times to get 2 ⇒ ϰ = ____

Explanation
ϰ X 2 = 2
⇒ 1 must be added 2 times to get 2
⇒ ϰ = 1 →

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4
5.

2 ÷ 2 = ϰ ⇒ 2 must be subtracted ϰ times from 2 to get 0 ⇒ There are ϰ 2's in 2 ⇒ ϰ = ____

Explanation
2 ÷ 2 = ϰ
⇒ There are ϰ 2's in 2
⇒ 2 X ϰ = 2
⇒ ϰ = 1 →

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4
6.

2 ÷ ϰ = 1 ⇒ ϰ must be subtracted 1 time from 2 to get 0 ⇒ There is 1 ϰ in 2 ⇒ ϰ = ____

Explanation
2 ÷ ϰ = 1
⇒ There is 1 ϰ in 2
⇒ ϰ X 1 = 2
⇒ ϰ = 2 →

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4
7.

1 X ϰ = 4 ⇒ 1 must be added ϰ times to get 4 ⇒ ϰ = ____

Explanation
1 X ϰ = 4
⇒ 1 must be added 4 times to get 4
⇒ ϰ = 4 →

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4
8.

ϰ X 4 = 4 ⇒ ϰ must be added 4 times to get 4 ⇒ ϰ = ____

Explanation
ϰ X 4 = 4
⇒ 1 must be added 4 times to get 4
⇒ ϰ = 1 →

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4
9.

1 X 4 = ϰ ⇒ 1 must be added 4 times to get ϰ ⇒ ϰ = ____

Explanation
1 X 4 = ϰ
⇒ 1 added 4 times = 4
⇒ ϰ = 4 →

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4
10.

1 X ϰ = 3 ⇒ 1 must be added ϰ times to get 3 ⇒ ϰ = ____

Explanation
1 X ϰ = 3
⇒ 1 must be added 3 times to get 3
⇒ ϰ = 3 →

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4
11.

1 X 3 = ϰ ⇒ 1 must be added 3 times to get ϰ ⇒ ϰ = ____

Explanation
1 X 3 = ϰ
⇒ 1 added 3 times = 3
⇒ ϰ = 3 →

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4
12.

ϰ ÷ 3 = 1 ⇒ 3 must be subtracted 1 time from ϰ to get 0 ⇒ There is ONE 3 in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 3 = 1
⇒ There is ONE 3 in ϰ
⇒ 3 X 1 = ϰ
⇒ ϰ = 3 →

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4
13.

ϰ X 3 = 3 ⇒ ϰ must be added 3 times to get 3 ⇒ ϰ = ____

Explanation
ϰ X 3 = 3
⇒ 1 must be added 3 times to get 3
⇒ ϰ = 1 →

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4
14.

3 ÷ 3 = ϰ ⇒ 3 must be subtracted ϰ times from 3 to get 0 ⇒ There are ϰ 3's in 3 ⇒ ϰ = ____

Explanation
3 ÷ 3 = ϰ
⇒ There are ϰ 3's in 3
⇒ 3 X ϰ = 3
⇒ ϰ = 1 →

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4
15.

3 ÷ ϰ = 1 ⇒ ϰ must be subtracted 1 time from 3 to get 0 ⇒ There is 1 ϰ in 3 ⇒ ϰ = ____

Explanation
3 ÷ ϰ = 1
⇒ There is 1 ϰ in 3
⇒ ϰ X 1 = 3
⇒ ϰ = 3 →

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4
16.

4 ÷ 2 = ϰ ⇒ 2 must be subtracted ϰ times from 4 to get 0 ⇒ There are ϰ 2's in 4 ⇒ ϰ = ____

Explanation
4 ÷ 2 = ϰ
⇒ There are ϰ 2's in 4
⇒ 2 X ϰ = 4
⇒ ϰ = 2 →

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4
17.

ϰ ÷ 2 = 2 ⇒ 2 must be subtracted 2 times from ϰ to get 0 ⇒ There are 2 2's in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 2 = 2
⇒ There are 2 2's in ϰ
⇒ 2 X 2 = ϰ
⇒ ϰ = 4 →

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4
18.

4 ÷ ϰ = 2 ⇒ ϰ must be subtracted 2 times from 4 to get 0 ⇒ There are 2 ϰ's in 4 ⇒ ϰ = ____

Explanation
4 ÷ ϰ = 2
⇒ There are 2 ϰ's in 4
⇒ ϰ X 2 = 4
⇒ ϰ = 2 →

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4
19.

4 ÷ 4 = ϰ ⇒ 4 must be subtracted ϰ times from 4 to get 0 ⇒ There are ϰ 4's in 4 ⇒ ϰ = ____

Explanation
4 ÷ 4 = ϰ
⇒ There are ϰ 4's in 4
⇒ 4 X ϰ = 4
⇒ ϰ = 1 →

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4
20.

ϰ ÷ 4 = 1 ⇒ 4 must be subtracted 1 time from ϰ to get 0 ⇒ There is ONE 4 in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 4 = 1
⇒ There is ONE 4 in ϰ
⇒ 4 X 1 = ϰ
⇒ ϰ = 4 →

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4
21.

4 ÷ ϰ = 1 ⇒ ϰ must be subtracted 1 time from 4 to get 0 ⇒ There is 1 ϰ in 4 ⇒ ϰ = ____

Explanation
4 ÷ ϰ = 1
⇒ There is 1 ϰ in 4
⇒ ϰ X 1 = 4
⇒ ϰ = 4 →

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4
22.

2 X ϰ = 4 ⇒ 2 must be added ϰ times to get 4 ⇒ ϰ = ____

Explanation
2 X ϰ = 4
⇒ 2 must be added 2 times to get 4
⇒ ϰ = 2 →

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4
23.

ϰ X 2 = 4 ⇒ ϰ must be added 2 times to get 4 ⇒ ϰ = ____

Explanation
ϰ X 2 = 4
⇒ 2 must be added 2 times to get 4
⇒ ϰ = 2 →

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4
24.

2 X 2 = ϰ ⇒ 2 must be added 2 times to get ϰ ⇒ ϰ = ____

Explanation
2 X 2 = ϰ
⇒ 2 added 2 times = 4
⇒ ϰ = 4 →

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4
25.

2 X 4 = ϰ ⇒ 2 must be added 4 times to get ϰ ⇒ ϰ = ____

Explanation
2 X 4 = ϰ
⇒ 2 added 4 times = 8
⇒ ϰ = 8 →

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4
26.

8 ÷ 4 = ϰ ⇒ 4 must be subtracted ϰ times from 8 to get 0 ⇒ There are ϰ 4's in 8 ⇒ ϰ = ____

Explanation
8 ÷ 4 = ϰ
⇒ There are ϰ 4's in 8
⇒ 4 X ϰ = 8
⇒ ϰ = 2 →

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4
27.

ϰ ÷ 4 = 2 ⇒ 4 must be subtracted 2 times from ϰ to get 0 ⇒ There are 2 4's in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 4 = 2
⇒ There are 2 4's in ϰ
⇒ 4 X 2 = ϰ
⇒ ϰ = 8 →

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4
28.

2 X ϰ = 6 ⇒ 2 must be added ϰ times to get 6 ⇒ ϰ = ____

Explanation
2 X ϰ = 6
⇒ 2 must be added 3 times to get 6
⇒ ϰ = 3 →

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4
29.

ϰ X 3 = 6 ⇒ ϰ must be added 3 times to get 6 ⇒ ϰ = ____

Explanation
ϰ X 3 = 6
⇒ 2 must be added 3 times to get 6
⇒ ϰ = 2 →

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4
30.

2 X 3 = ϰ ⇒ 2 must be added 3 times to get ϰ ⇒ ϰ = ____

Explanation
2 X 3 = ϰ
⇒ 2 must be added 3 times to get ϰ
⇒ ϰ = ____

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4
31.

6 ÷ 3 = ϰ ⇒ 3 must be subtracted ϰ times from 6 to get 0 ⇒ There are ϰ 3's in 6 ⇒ ϰ = ____

Explanation
6 ÷ 3 = ϰ
⇒ There are ϰ 3's in 6
⇒ 3 X ϰ = 6
⇒ ϰ = 2 →

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4
32.

ϰ ÷ 3 = 2 ⇒ 3 must be subtracted 2 times from ϰ to get 0 ⇒ There are 2 3's in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 3 = 2
⇒ There are 2 3's in ϰ
⇒ 3 X 2 = ϰ
⇒ ϰ = 6 →

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4
33.

2 X ϰ = 8 ⇒ 2 must be added ϰ times to get 8 ⇒ ϰ = ____

Explanation
2 X ϰ = 8
⇒ 2 must be added 4 times to get 8
⇒ ϰ = 4 →

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4
34.

3 X 3 = ϰ ⇒ 3 must be added 3 times to get ϰ ⇒ ϰ = ____

Explanation
3 X 3 = ϰ
⇒ 3 added 3 times = 9
⇒ ϰ = 9 →

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4
35.

6 ÷ ϰ = 2 ⇒ ϰ must be subtracted 2 times from 6 to get 0 ⇒ There are 2 ϰ's in 6 ⇒ ϰ = ____

Explanation
6 ÷ ϰ = 2
⇒ There are 2 ϰ's in 6
⇒ ϰ X 2 = 6
⇒ ϰ = 3 →

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4
36.

ϰ X 4 = 8 ⇒ ϰ must be added 4 times to get 8 ⇒ ϰ = ____

Explanation
ϰ X 4 = 8
⇒ 2 must be added 4 times to get 8
⇒ ϰ = 2 →

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4
37.

8 ÷ ϰ = 2 ⇒ ϰ must be subtracted 2 times from 8 to get 0 ⇒ There are 2 ϰ's in 8 ⇒ ϰ = ____

Explanation
8 ÷ ϰ = 2
⇒ There are 2 ϰ's in 8
⇒ ϰ X 2 = 8
⇒ ϰ = 4 →

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4
38.

3 X ϰ = 6 ⇒ 3 must be added ϰ times to get 6 ⇒ ϰ = ____

Explanation
3 X ϰ = 6
⇒ 3 must be added 2 times to get 6
⇒ ϰ = 2 →

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4
39.

ϰ X 2 = 6 ⇒ ϰ must be added 2 times to get 6 ⇒ ϰ = ____

Explanation
ϰ X 2 = 6
⇒ 3 must be added 2 times to get 6
⇒ ϰ = 3 →

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4
40.

3 X 2 = ϰ ⇒ 3 must be added 2 times to get ϰ ⇒ ϰ = ____

Explanation
3 X 2 = ϰ
⇒ 3 added 2 times = 6
⇒ ϰ = 6 →

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4
41.

ϰ ÷ 2 = 3 ⇒ 2 must be subtracted 3 times from ϰ to get 0 ⇒ There are 3 2's in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 2 = 3
⇒ There are 3 2's in ϰ
⇒ 2 X 3 = ϰ
⇒ ϰ = 6 →

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4
42.

3 X ϰ = 9 ⇒ 3 must be added ϰ times to get 9 ⇒ ϰ = ____

Explanation
3 X ϰ = 9
⇒ 3 must be added 3 times to get 9
⇒ ϰ = 3 →

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4
43.

6 ÷ 2 = ϰ ⇒ 2 must be subtracted ϰ times from 6 to get 0 ⇒ There are ϰ 2's in 6 ⇒ ϰ = ____

Explanation
6 ÷ 2 = ϰ
⇒ There are ϰ 2's in 6
⇒ 2 X ϰ = 6
⇒ ϰ = 3 →

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4
44.

6 ÷ ϰ = 3 ⇒ ϰ must be subtracted 3 times from 6 to get 0 ⇒ There are 3 ϰ's in 6 ⇒ ϰ = ____

Explanation
6 ÷ ϰ = 3
⇒ There are 3 ϰ's in 6
⇒ ϰ X 3 = 6
⇒ ϰ = 2 →

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4
45.

ϰ X 3 = 9 ⇒ ϰ must be added 3 times to get 9 ⇒ ϰ = ____

Explanation
ϰ X 3 = 9
⇒ 3 must be added 3 times to get 9
⇒ ϰ = 3 →

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4
46.

9 ÷ 3 = ϰ ⇒ 3 must be subtracted ϰ times from 9 to get 0 ⇒ There are ϰ 3's in 9 ⇒ ϰ = ____

Explanation
9 ÷ 3 = ϰ
⇒ There are ϰ 3's in 9
⇒ 3 X ϰ = 9
⇒ ϰ = 3 →

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4
47.

ϰ ÷ 3 = 3 ⇒ 3 must be subtracted 3 times from ϰ to get 0 ⇒ There are 3 3's in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 3 = 3
⇒ There are 3 3's in ϰ
⇒ 3 X 3 = ϰ
⇒ ϰ = 9 →

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4
48.

9 ÷ ϰ = 3 ⇒ ϰ must be subtracted 3 times from 9 to get 0 ⇒ There are 3 ϰ's in 9 ⇒ ϰ = ____

Explanation
9 ÷ ϰ = 3
⇒ There are 3 ϰ's in 9
⇒ ϰ X 3 = 9
⇒ ϰ = 3 →

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4
49.

3 X ϰ = 12 ⇒ 3 must be added ϰ times to get 12 ⇒ ϰ = ____

Explanation
3 X ϰ = 12
⇒ 3 must be added 4 times to get 12
⇒ ϰ = 4 →

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4
50.

ϰ X 4 = 12 ⇒ ϰ must be added 4 times to get 12 ⇒ ϰ = ____

Explanation
ϰ X 4 = 12
⇒ 3 must be added 4 times to get 12
⇒ ϰ = 3 →

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4

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Mar 15, 2022

Quiz Edited by
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Apr 23, 2020

Quiz Created by
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Multiplication And Division Tables: 2-4 Tables (Level 2)

1 X ϰ = 2 ⇒ 1 must be added ϰ times to get 2 ⇒ ϰ = ____ Type question here. Example: Practice makes you ________.

1 X 2 = ϰ ⇒ 1 must be added 2 times to get ϰ ⇒ ϰ = ____

ϰ ÷ 2 = 1 ⇒ 2 must be subtracted 1 time from ϰ to get 0 ⇒ There is ONE 2 in ϰ ⇒ ϰ = ____

ϰ X 2 = 2 ⇒ ϰ must be added 2 times to get 2 ⇒ ϰ = ____

2 ÷ 2 = ϰ ⇒ 2 must be subtracted ϰ times from 2 to get 0 ⇒ There are ϰ 2's in 2 ⇒ ϰ = ____

2 ÷ ϰ = 1 ⇒ ϰ must be subtracted 1 time from 2 to get 0 ⇒ There is 1 ϰ in 2 ⇒ ϰ = ____

1 X ϰ = 4 ⇒ 1 must be added ϰ times to get 4 ⇒ ϰ = ____

ϰ X 4 = 4 ⇒ ϰ must be added 4 times to get 4 ⇒ ϰ = ____

1 X 4 = ϰ ⇒ 1 must be added 4 times to get ϰ ⇒ ϰ = ____

1 X ϰ = 3 ⇒ 1 must be added ϰ times to get 3 ⇒ ϰ = ____

1 X 3 = ϰ ⇒ 1 must be added 3 times to get ϰ ⇒ ϰ = ____

ϰ ÷ 3 = 1 ⇒ 3 must be subtracted 1 time from ϰ to get 0 ⇒ There is ONE 3 in ϰ ⇒ ϰ = ____

ϰ X 3 = 3 ⇒ ϰ must be added 3 times to get 3 ⇒ ϰ = ____

3 ÷ 3 = ϰ ⇒ 3 must be subtracted ϰ times from 3 to get 0 ⇒ There are ϰ 3's in 3 ⇒ ϰ = ____

3 ÷ ϰ = 1 ⇒ ϰ must be subtracted 1 time from 3 to get 0 ⇒ There is 1 ϰ in 3 ⇒ ϰ = ____

4 ÷ 2 = ϰ ⇒ 2 must be subtracted ϰ times from 4 to get 0 ⇒ There are ϰ 2's in 4 ⇒ ϰ = ____

ϰ ÷ 2 = 2 ⇒ 2 must be subtracted 2 times from ϰ to get 0 ⇒ There are 2 2's in ϰ ⇒ ϰ = ____

4 ÷ ϰ = 2 ⇒ ϰ must be subtracted 2 times from 4 to get 0 ⇒ There are 2 ϰ's in 4 ⇒ ϰ = ____

4 ÷ 4 = ϰ ⇒ 4 must be subtracted ϰ times from 4 to get 0 ⇒ There are ϰ 4's in 4 ⇒ ϰ = ____

ϰ ÷ 4 = 1 ⇒ 4 must be subtracted 1 time from ϰ to get 0 ⇒ There is ONE 4 in ϰ ⇒ ϰ = ____

4 ÷ ϰ = 1 ⇒ ϰ must be subtracted 1 time from 4 to get 0 ⇒ There is 1 ϰ in 4 ⇒ ϰ = ____

2 X ϰ = 4 ⇒ 2 must be added ϰ times to get 4 ⇒ ϰ = ____

ϰ X 2 = 4 ⇒ ϰ must be added 2 times to get 4 ⇒ ϰ = ____

2 X 2 = ϰ ⇒ 2 must be added 2 times to get ϰ ⇒ ϰ = ____

2 X 4 = ϰ ⇒ 2 must be added 4 times to get ϰ ⇒ ϰ = ____

8 ÷ 4 = ϰ ⇒ 4 must be subtracted ϰ times from 8 to get 0 ⇒ There are ϰ 4's in 8 ⇒ ϰ = ____

ϰ ÷ 4 = 2 ⇒ 4 must be subtracted 2 times from ϰ to get 0 ⇒ There are 2 4's in ϰ ⇒ ϰ = ____

2 X ϰ = 6 ⇒ 2 must be added ϰ times to get 6 ⇒ ϰ = ____

ϰ X 3 = 6 ⇒ ϰ must be added 3 times to get 6 ⇒ ϰ = ____

2 X 3 = ϰ ⇒ 2 must be added 3 times to get ϰ ⇒ ϰ = ____

6 ÷ 3 = ϰ ⇒ 3 must be subtracted ϰ times from 6 to get 0 ⇒ There are ϰ 3's in 6 ⇒ ϰ = ____

ϰ ÷ 3 = 2 ⇒ 3 must be subtracted 2 times from ϰ to get 0 ⇒ There are 2 3's in ϰ ⇒ ϰ = ____

2 X ϰ = 8 ⇒ 2 must be added ϰ times to get 8 ⇒ ϰ = ____

3 X 3 = ϰ ⇒ 3 must be added 3 times to get ϰ ⇒ ϰ = ____

6 ÷ ϰ = 2 ⇒ ϰ must be subtracted 2 times from 6 to get 0 ⇒ There are 2 ϰ's in 6 ⇒ ϰ = ____

ϰ X 4 = 8 ⇒ ϰ must be added 4 times to get 8 ⇒ ϰ = ____

8 ÷ ϰ = 2 ⇒ ϰ must be subtracted 2 times from 8 to get 0 ⇒ There are 2 ϰ's in 8 ⇒ ϰ = ____

3 X ϰ = 6 ⇒ 3 must be added ϰ times to get 6 ⇒ ϰ = ____

ϰ X 2 = 6 ⇒ ϰ must be added 2 times to get 6 ⇒ ϰ = ____

3 X 2 = ϰ ⇒ 3 must be added 2 times to get ϰ ⇒ ϰ = ____

ϰ ÷ 2 = 3 ⇒ 2 must be subtracted 3 times from ϰ to get 0 ⇒ There are 3 2's in ϰ ⇒ ϰ = ____

3 X ϰ = 9 ⇒ 3 must be added ϰ times to get 9 ⇒ ϰ = ____

6 ÷ 2 = ϰ ⇒ 2 must be subtracted ϰ times from 6 to get 0 ⇒ There are ϰ 2's in 6 ⇒ ϰ = ____

6 ÷ ϰ = 3 ⇒ ϰ must be subtracted 3 times from 6 to get 0 ⇒ There are 3 ϰ's in 6 ⇒ ϰ = ____

ϰ X 3 = 9 ⇒ ϰ must be added 3 times to get 9 ⇒ ϰ = ____

9 ÷ 3 = ϰ ⇒ 3 must be subtracted ϰ times from 9 to get 0 ⇒ There are ϰ 3's in 9 ⇒ ϰ = ____

ϰ ÷ 3 = 3 ⇒ 3 must be subtracted 3 times from ϰ to get 0 ⇒ There are 3 3's in ϰ ⇒ ϰ = ____

9 ÷ ϰ = 3 ⇒ ϰ must be subtracted 3 times from 9 to get 0 ⇒ There are 3 ϰ's in 9 ⇒ ϰ = ____

3 X ϰ = 12 ⇒ 3 must be added ϰ times to get 12 ⇒ ϰ = ____

ϰ X 4 = 12 ⇒ ϰ must be added 4 times to get 12 ⇒ ϰ = ____

1 X ϰ = 2 ⇒ 1 must be added ϰ times to get 2 ⇒ ϰ = Type question here. Example: Practice makes you ____.