Multiplication And Division Tables: 5-7 Tables (Level 2)

216 Questions | By Benje Deacon | Updated: Mar 18, 2022

Multiplication and Division tables – 5 to 7 Tables (Level 2). This quiz contains 216 questions. There is an ϰ involved in every question of which the correct value must be given in the answer. Examples:(1) 2 X ϰ = 10 ⇒ 2 must be added ϰ times to get 10⇒ ϰ = ___(2) ϰ ÷ 7 = 5⇒ 7 must be subtracted 5 times from ϰ to get 0⇒ There are 5 7’s in x⇒ ϰ = ___The general question for this quiz is: Give the correct value of ϰ. This quiz will improve your knowledge of the Read more5-7 Multiplication and Division Tables.

Questions and Answers

1.

1 X ϰ = 5 ⇒ 1 must be added ϰ times to get 5 ⇒ ϰ = ____

Explanation
1 X ϰ = 5
⇒ 1 must be added 5 times to get 5
⇒ ϰ = 5 →

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4
2.

ϰ X 5 = 5 ⇒ ϰ must be added 5 times to get 5 ⇒ ϰ = ____

Explanation
ϰ X 5 = 5
⇒ 1 must be added 5 times to get 5
⇒ ϰ = 1 →

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4
3.

1 X 5 = ϰ ⇒ 1 must be added 5 times to get ϰ ⇒ ϰ = ____

Explanation
1 X 5 = ϰ
⇒ 1 added 5 times = 5
⇒ ϰ = 5 →

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4
4.

5 ÷ 5 = ϰ ⇒ 5 must be subtracted ϰ times from 5 to get 0 ⇒ There are ϰ 5's in 5 ⇒ ϰ = ____

Explanation
5 ÷ 5 = ϰ
⇒ There are ϰ 5's in 5
⇒ 5 X ϰ = 5
⇒ ϰ = 1 →

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4
5.

ϰ ÷ 5 = 1 ⇒ 5 must be subtracted 1 time from ϰ to get 0 ⇒ There is ONE 5 in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 5 = 1
⇒ There is ONE 5 in ϰ
⇒ 5 X 1 = ϰ
⇒ ϰ = 5 →

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4
6.

5 ÷ ϰ = 1 ⇒ ϰ must be subtracted 1 time from 5 to get 0 ⇒ There is 1 ϰ in 5 ⇒ ϰ = ____

Explanation
5 ÷ ϰ = 1
⇒ There is 1 ϰ in 5
⇒ ϰ X 1 = 5
⇒ ϰ = 5 →

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4
7.

1 X ϰ = 6 ⇒ 1 must be added ϰ times to get 6 ⇒ ϰ = ____

Explanation
1 X ϰ = 6
⇒ 1 must be added 6 times to get 6
⇒ ϰ = 6 →

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4
8.

ϰ X 6 = 6 ⇒ ϰ must be added 6 times to get 6 ⇒ ϰ = ____

Explanation
ϰ X 6 = 6
⇒ 1 must be added 6 times to get 6
⇒ ϰ = 1 →

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4
9.

1 X 6 = ϰ ⇒ 1 must be added 6 times to get ϰ ⇒ ϰ = ____

Explanation
1 X 6 = ϰ
⇒ 1 added 6 times = 6
⇒ ϰ = 6 →

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4
10.

6 ÷ 6 = ϰ ⇒ 6 must be subtracted ϰ times from 6 to get 0 ⇒ There are ϰ 6's in 6 ⇒ ϰ = ____

Explanation
6 ÷ 6 = ϰ
⇒ There are ϰ 6's in 6
⇒ 6 X ϰ = 6
⇒ ϰ = 1 →

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4
11.

ϰ ÷ 6 = 1 ⇒ 6 must be subtracted 1 time from ϰ to get 0 ⇒ There is ONE 6 in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 6 = 1
⇒ There is ONE 6 in ϰ
⇒ 6 X 1 = ϰ
⇒ ϰ = 6 →

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4
12.

6 ÷ ϰ = 1 ⇒ ϰ must be subtracted 1 time from 6 to get 0 ⇒ There is 1 ϰ in 6 ⇒ ϰ = ____

Explanation
6 ÷ ϰ = 1

⇒ There is 1 ϰ in 6

⇒ ϰ X 1 = 6

⇒ ϰ = 6 →

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4
13.

1 X ϰ = 7 ⇒ 1 must be added ϰ times to get 7 ⇒ ϰ = ____

Explanation
1 X ϰ = 7
⇒ 1 must be added 7 times to get 7
⇒ ϰ = 7 →

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4
14.

ϰ X 7 = 7 ⇒ ϰ must be added 7 times to get 7 ⇒ ϰ = ____

Explanation
ϰ X 7 = 7
⇒ 1 must be added 7 times to get 7
⇒ ϰ = 1 →

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4
15.

1 X 7 = ϰ ⇒ 1 must be added 7 times to get ϰ ⇒ ϰ = ____

Explanation
1 X 7 = ϰ
⇒ 1 added 7 times = 7
⇒ ϰ = 7 →

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4
16.

7 ÷ 7 = ϰ ⇒ 7 must be subtracted ϰ times from 7 to get 0 ⇒ There are ϰ 7's in 7 ⇒ ϰ = ____

Explanation
7 ÷ 7 = ϰ
⇒ There are ϰ 7's in 7
⇒ 7 X ϰ = 7
⇒ ϰ = 1 →

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4
17.

ϰ ÷ 7 = 1 ⇒ 7 must be subtracted 1 time from ϰ to get 0 ⇒ There is ONE 7 in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 7 = 1
⇒ There is ONE 7 in ϰ
⇒ 7 X 1 = ϰ
⇒ ϰ = 7 →

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4
18.

7 ÷ ϰ = 1 ⇒ ϰ must be subtracted 1 time from 7 to get 0 ⇒ There is 1 ϰ in 7 ⇒ ϰ = ____

Explanation
7 ÷ ϰ = 1
⇒ There is 1 ϰ in 7
⇒ ϰ X 1 = 7
⇒ ϰ = 7 →

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4
19.

2 X ϰ = 10 ⇒ 2 must be added ϰ times to get 10 ⇒ ϰ = ____

Explanation
2 X ϰ = 10
⇒ 2 must be added 5 times to get 10
⇒ ϰ = 5 →

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4
20.

ϰ X 5 = 10 ⇒ ϰ must be added 5 times to get 10 ⇒ ϰ = ____

Explanation
ϰ X 5 = 10
⇒ 2 must be added 5 times to get 10
⇒ ϰ = 2 →

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4
21.

2 X 5 = ϰ ⇒ 2 must be added 5 times to get ϰ ⇒ ϰ = ____

Explanation
2 X 5 = ϰ
⇒ 2 added 5 times = 10
⇒ ϰ = 10 →

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4
22.

10 ÷ 5 = ϰ ⇒ 5 must be subtracted ϰ times from 10 to get 0 ⇒ There are ϰ 5's in 10 ⇒ ϰ = ____

Explanation
10 ÷ 5 = ϰ
⇒ There are ϰ 5's in 10
⇒ 5 X ϰ = 10
⇒ ϰ = 2 →

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4
23.

ϰ ÷ 5 = 2 ⇒ 5 must be subtracted 2 times from ϰ to get 0 ⇒ There are 2 5's in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 5 = 2
⇒ There are 2 5's in ϰ
⇒ 5 X 2 = ϰ
⇒ ϰ = 10 →

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4
24.

10 ÷ ϰ = 2 ⇒ ϰ must be subtracted 2 times from 10 to get 0 ⇒ There are 2 ϰ's in 10 ⇒ ϰ = ____

Explanation
10 ÷ ϰ = 2
⇒ There are 2 ϰ's in 10
⇒ ϰ X 2 = 10
⇒ ϰ = 5 →

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4
25.

2 X ϰ = 12 ⇒ 2 must be added ϰ times to get 12 ⇒ ϰ = ____

Explanation
2 X ϰ = 12
⇒ 2 must be added 6 times to get 12
⇒ ϰ = 6 →

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4
26.

ϰ X 6 = 12 ⇒ ϰ must be added 6 times to get 12 ⇒ ϰ = ____

Explanation
ϰ X 6 = 12
⇒ 2 must be added 6 times to get 12
⇒ ϰ = 2 →

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4
27.

2 X 6 = ϰ ⇒ 2 must be added 6 times to get ϰ ⇒ ϰ = ____

Explanation
2 X 6 = ϰ
⇒ 2 added 6 times = 12
⇒ ϰ = 12 →

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4
28.

12 ÷ 6 = ϰ ⇒ 6 must be subtracted ϰ times from 12 to get 0 ⇒ There are ϰ 6's in 12 ⇒ ϰ = ____

Explanation
12 ÷ 6 = ϰ
⇒ There are ϰ 6's in 12
⇒ 6 X ϰ = 12
⇒ ϰ = 2 →

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4
29.

ϰ ÷ 6 = 2 ⇒ 6 must be subtracted 2 times from ϰ to get 0 ⇒ There are 2 6's in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 6 = 2
⇒ There are 2 6's in ϰ
⇒ 6 X 2 = ϰ
⇒ ϰ = 12 →

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4
30.

12 ÷ ϰ = 2 ⇒ ϰ must be subtracted 2 times from 12 to get 0 ⇒ There are 2 ϰ's in 12 ⇒ ϰ = ____

Explanation
12 ÷ ϰ = 2
⇒ There are 2 ϰ's in 12
⇒ ϰ X 2 = 12
⇒ ϰ = 6 →

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4
31.

2 X ϰ = 14 ⇒ 2 must be added ϰ times to get 14 ⇒ ϰ = ____

Explanation
2 X ϰ = 14
⇒ 2 must be added 7 times to get 14
⇒ ϰ = 7 →

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4
32.

ϰ X 7 = 14 ⇒ ϰ must be added 7 times to get 14 ⇒ ϰ = ____

Explanation
ϰ X 7 = 14
⇒ 2 must be added 7 times to get 14
⇒ ϰ = 2 →

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4
33.

2 X 7 = ϰ ⇒ 2 must be added 7 times to get ϰ ⇒ ϰ = ____

Explanation
2 X 7 = ϰ
⇒ 2 added 7 times = 14
⇒ ϰ = 14 →

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4
34.

14 ÷ 7 = ϰ ⇒ 7 must be subtracted ϰ times from 14 to get 0 ⇒ There are ϰ 7's in 14 ⇒ ϰ = ____

Explanation
14 ÷ 7 = ϰ
⇒ There are ϰ 7's in 14
⇒ 7 X ϰ = 14
⇒ ϰ = 2 →

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4
35.

ϰ ÷ 7 = 2 ⇒ 7 must be subtracted 2 times from ϰ to get 0 ⇒ There are 2 7's in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 7 = 2
⇒ There are 2 7's in ϰ
⇒ 7 X 2 = ϰ
⇒ ϰ = 14 →

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4
36.

14 ÷ ϰ = 2 ⇒ ϰ must be subtracted 2 times from 14 to get 0 ⇒ There are 2 ϰ's in 14 ⇒ ϰ = ____

Explanation
14 ÷ ϰ = 2
⇒ There are 2 ϰ's in 14
⇒ ϰ X 2 = 14
⇒ ϰ = 7 →

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4
37.

3 X ϰ = 15 ⇒ 3 must be added ϰ times to get 15 ⇒ ϰ = ____

Explanation
3 X ϰ = 15
⇒ 3 must be added 5 times to get 15
⇒ ϰ = 5 →

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4
38.

ϰ X 5 = 15 ⇒ ϰ must be added 5 times to get 15 ⇒ ϰ = ____

Explanation
ϰ X 5 = 15
⇒ 3 must be added 5 times to get 15
⇒ ϰ = 3 →

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4
39.

3 X 5 = ϰ ⇒ 3 must be added 5 times to get ϰ ⇒ ϰ = ____

Explanation
3 X 5 = ϰ
⇒ 3 added 5 times = 15
⇒ ϰ = 15 →

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4
40.

15 ÷ 5 = ϰ ⇒ 5 must be subtracted ϰ times from 15 to get 0 ⇒ There are ϰ 5's in 15 ⇒ ϰ = ____

Explanation
15 ÷ 5 = ϰ
⇒ There are ϰ 5's in 15
⇒ 5 X ϰ = 15
⇒ ϰ = 3 →

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4
41.

ϰ ÷ 5 = 3 ⇒ 5 must be subtracted 3 times from ϰ to get 0 ⇒ There are 3 5's in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 5 = 3
⇒ There are 3 5's in ϰ
⇒ 5 X 3 = ϰ
⇒ ϰ = 15 →

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4
42.

15 ÷ ϰ = 3 ⇒ ϰ must be subtracted 3 times from 15 to get 0 ⇒ There are 3 ϰ's in 15 ⇒ ϰ = ____

Explanation
15 ÷ ϰ = 3
⇒ There are 3 ϰ's in 15
⇒ ϰ X 3 = 15
⇒ ϰ = 5 →

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4
43.

3 X ϰ = 18 ⇒ 3 must be added ϰ times to get 18 ⇒ ϰ = ____

Explanation
3 X ϰ = 18
⇒ 3 must be added 6 times to get 18
⇒ ϰ = 6 →

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4
44.

ϰ X 6 = 18 ⇒ ϰ must be added 6 times to get 18 ⇒ ϰ = ____

Explanation
ϰ X 6 = 18
⇒ 3 must be added 6 times to get 18
⇒ ϰ = 3 →

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4
45.

3 X 6 = ϰ ⇒ 3 must be added 6 times to get ϰ ⇒ ϰ = ____

Explanation
3 X 6 = ϰ
⇒ 3 added 6 times = 18
⇒ ϰ = 18 →

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4
46.

18 ÷ 6 = ϰ ⇒ 6 must be subtracted ϰ times from 18 to get 0 ⇒ There are ϰ 6's in 18 ⇒ ϰ = ____

Explanation
18 ÷ 6 = ϰ
⇒ There are ϰ 6's in 18
⇒ 6 X ϰ = 18
⇒ ϰ = 3 →

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4
47.

ϰ ÷ 6 = 3 ⇒ 6 must be subtracted 3 times from ϰ to get 0 ⇒ There are 3 6's in ϰ ⇒ ϰ = ____

Explanation
ϰ ÷ 6 = 3
⇒ There are 3 6's in ϰ
⇒ 6 X 3 = ϰ
⇒ ϰ = 18 →

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4
48.

18 ÷ ϰ = 3 ⇒ ϰ must be subtracted 3 times from 18 to get 0 ⇒ There are 3 ϰ's in 18 ⇒ ϰ = ____

Explanation
18 ÷ ϰ = 3
⇒ There are 3 ϰ's in 18
⇒ ϰ X 3 = 18
⇒ ϰ = 6 →

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4
49.

3 X ϰ = 21 ⇒ 3 must be added ϰ times to get 21 ⇒ ϰ = ____

Explanation
3 X ϰ = 21
⇒ 3 must be added 7 times to get 21
⇒ ϰ = 7 →

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4
50.

ϰ X 7 = 21 ⇒ ϰ must be added 7 times to get 21 ⇒ ϰ = ____

Explanation
ϰ X 7 = 21
⇒ 3 must be added 7 times to get 21
⇒ ϰ = 3 →

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4

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Mar 18, 2022

Quiz Edited by
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May 01, 2020

Quiz Created by
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Multiplication And Division Tables: 5-7 Tables (Level 2)

1 X ϰ = 5 ⇒ 1 must be added ϰ times to get 5 ⇒ ϰ = ____

ϰ X 5 = 5 ⇒ ϰ must be added 5 times to get 5 ⇒ ϰ = ____

1 X 5 = ϰ ⇒ 1 must be added 5 times to get ϰ ⇒ ϰ = ____

5 ÷ 5 = ϰ ⇒ 5 must be subtracted ϰ times from 5 to get 0 ⇒ There are ϰ 5's in 5 ⇒ ϰ = ____

ϰ ÷ 5 = 1 ⇒ 5 must be subtracted 1 time from ϰ to get 0 ⇒ There is ONE 5 in ϰ ⇒ ϰ = ____

5 ÷ ϰ = 1 ⇒ ϰ must be subtracted 1 time from 5 to get 0 ⇒ There is 1 ϰ in 5 ⇒ ϰ = ____

1 X ϰ = 6 ⇒ 1 must be added ϰ times to get 6 ⇒ ϰ = ____

ϰ X 6 = 6 ⇒ ϰ must be added 6 times to get 6 ⇒ ϰ = ____

1 X 6 = ϰ ⇒ 1 must be added 6 times to get ϰ ⇒ ϰ = ____

6 ÷ 6 = ϰ ⇒ 6 must be subtracted ϰ times from 6 to get 0 ⇒ There are ϰ 6's in 6 ⇒ ϰ = ____

ϰ ÷ 6 = 1 ⇒ 6 must be subtracted 1 time from ϰ to get 0 ⇒ There is ONE 6 in ϰ ⇒ ϰ = ____

6 ÷ ϰ = 1 ⇒ ϰ must be subtracted 1 time from 6 to get 0 ⇒ There is 1 ϰ in 6 ⇒ ϰ = ____

1 X ϰ = 7 ⇒ 1 must be added ϰ times to get 7 ⇒ ϰ = ____

ϰ X 7 = 7 ⇒ ϰ must be added 7 times to get 7 ⇒ ϰ = ____

1 X 7 = ϰ ⇒ 1 must be added 7 times to get ϰ ⇒ ϰ = ____

7 ÷ 7 = ϰ ⇒ 7 must be subtracted ϰ times from 7 to get 0 ⇒ There are ϰ 7's in 7 ⇒ ϰ = ____

ϰ ÷ 7 = 1 ⇒ 7 must be subtracted 1 time from ϰ to get 0 ⇒ There is ONE 7 in ϰ ⇒ ϰ = ____

7 ÷ ϰ = 1 ⇒ ϰ must be subtracted 1 time from 7 to get 0 ⇒ There is 1 ϰ in 7 ⇒ ϰ = ____

2 X ϰ = 10 ⇒ 2 must be added ϰ times to get 10 ⇒ ϰ = ____

ϰ X 5 = 10 ⇒ ϰ must be added 5 times to get 10 ⇒ ϰ = ____

2 X 5 = ϰ ⇒ 2 must be added 5 times to get ϰ ⇒ ϰ = ____

10 ÷ 5 = ϰ ⇒ 5 must be subtracted ϰ times from 10 to get 0 ⇒ There are ϰ 5's in 10 ⇒ ϰ = ____

ϰ ÷ 5 = 2 ⇒ 5 must be subtracted 2 times from ϰ to get 0 ⇒ There are 2 5's in ϰ ⇒ ϰ = ____

10 ÷ ϰ = 2 ⇒ ϰ must be subtracted 2 times from 10 to get 0 ⇒ There are 2 ϰ's in 10 ⇒ ϰ = ____

2 X ϰ = 12 ⇒ 2 must be added ϰ times to get 12 ⇒ ϰ = ____

ϰ X 6 = 12 ⇒ ϰ must be added 6 times to get 12 ⇒ ϰ = ____

2 X 6 = ϰ ⇒ 2 must be added 6 times to get ϰ ⇒ ϰ = ____

12 ÷ 6 = ϰ ⇒ 6 must be subtracted ϰ times from 12 to get 0 ⇒ There are ϰ 6's in 12 ⇒ ϰ = ____

ϰ ÷ 6 = 2 ⇒ 6 must be subtracted 2 times from ϰ to get 0 ⇒ There are 2 6's in ϰ ⇒ ϰ = ____

12 ÷ ϰ = 2 ⇒ ϰ must be subtracted 2 times from 12 to get 0 ⇒ There are 2 ϰ's in 12 ⇒ ϰ = ____

2 X ϰ = 14 ⇒ 2 must be added ϰ times to get 14 ⇒ ϰ = ____

ϰ X 7 = 14 ⇒ ϰ must be added 7 times to get 14 ⇒ ϰ = ____

2 X 7 = ϰ ⇒ 2 must be added 7 times to get ϰ ⇒ ϰ = ____

14 ÷ 7 = ϰ ⇒ 7 must be subtracted ϰ times from 14 to get 0 ⇒ There are ϰ 7's in 14 ⇒ ϰ = ____

ϰ ÷ 7 = 2 ⇒ 7 must be subtracted 2 times from ϰ to get 0 ⇒ There are 2 7's in ϰ ⇒ ϰ = ____

14 ÷ ϰ = 2 ⇒ ϰ must be subtracted 2 times from 14 to get 0 ⇒ There are 2 ϰ's in 14 ⇒ ϰ = ____

3 X ϰ = 15 ⇒ 3 must be added ϰ times to get 15 ⇒ ϰ = ____

ϰ X 5 = 15 ⇒ ϰ must be added 5 times to get 15 ⇒ ϰ = ____

3 X 5 = ϰ ⇒ 3 must be added 5 times to get ϰ ⇒ ϰ = ____

15 ÷ 5 = ϰ ⇒ 5 must be subtracted ϰ times from 15 to get 0 ⇒ There are ϰ 5's in 15 ⇒ ϰ = ____

ϰ ÷ 5 = 3 ⇒ 5 must be subtracted 3 times from ϰ to get 0 ⇒ There are 3 5's in ϰ ⇒ ϰ = ____

15 ÷ ϰ = 3 ⇒ ϰ must be subtracted 3 times from 15 to get 0 ⇒ There are 3 ϰ's in 15 ⇒ ϰ = ____

3 X ϰ = 18 ⇒ 3 must be added ϰ times to get 18 ⇒ ϰ = ____

ϰ X 6 = 18 ⇒ ϰ must be added 6 times to get 18 ⇒ ϰ = ____

3 X 6 = ϰ ⇒ 3 must be added 6 times to get ϰ ⇒ ϰ = ____

18 ÷ 6 = ϰ ⇒ 6 must be subtracted ϰ times from 18 to get 0 ⇒ There are ϰ 6's in 18 ⇒ ϰ = ____

ϰ ÷ 6 = 3 ⇒ 6 must be subtracted 3 times from ϰ to get 0 ⇒ There are 3 6's in ϰ ⇒ ϰ = ____

18 ÷ ϰ = 3 ⇒ ϰ must be subtracted 3 times from 18 to get 0 ⇒ There are 3 ϰ's in 18 ⇒ ϰ = ____

3 X ϰ = 21 ⇒ 3 must be added ϰ times to get 21 ⇒ ϰ = ____

ϰ X 7 = 21 ⇒ ϰ must be added 7 times to get 21 ⇒ ϰ = ____