General Quiz 2 First Secondary On Genetics And Classification
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Questions and Answers
- 1.
If a crossing occurs between heterozygous parents in one pair of mendelian characters, so the ratio of the resulting phenotypes will be -------.
- A.
3:1
- B.
1:2:1
- C.
9:3:3:1
- D.
9:7
Correct Answer
A. 3:1Explanation
When a crossing occurs between heterozygous parents for one pair of Mendelian characters, the resulting phenotypic ratio will be 3:1. This is because in Mendelian genetics, a heterozygous individual carries two different alleles for a particular trait, one dominant and one recessive. During the crossing, there is a 25% chance that both dominant alleles will be inherited, resulting in the dominant phenotype, and a 75% chance that one dominant and one recessive allele will be inherited, resulting in the recessive phenotype. Thus, the resulting phenotypic ratio is 3 dominant phenotypes to 1 recessive phenotype.Rate this question:
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- 2.
A colorblind mother and a normal father give birth to a Klinefelter child with normal vision. Where do you think the non-disjunction has taken place?
- A.
1st meiotic division of mother
- B.
2nd meiotic division of the father
- C.
2nd meiotic division of mother
- D.
1st meiotic division of father
Correct Answer
D. 1st meiotic division of fatherExplanation
The non-disjunction likely occurred during the 1st meiotic division of the father. This is because the mother is colorblind, which means she carries the colorblindness gene on one of her X chromosomes. The father, on the other hand, is normal and does not carry the colorblindness gene. Since the child has normal vision, it means that the father's X chromosome without the colorblindness gene was passed on to the child. Therefore, the non-disjunction most likely occurred during the father's 1st meiotic division, resulting in the correct combination of chromosomes for the child to have normal vision.Rate this question:
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- 3.
The three types of class mammals are ........
- A.
Aquatic, terrestrial and aerial
- B.
Pouched, lay eggs and Placental
- C.
Jumping, fast and slow moving.
- D.
Herbivorous, carnivorous and omnivorous.
Correct Answer
B. Pouched, lay eggs and PlacentalExplanation
The correct answer is "Pouched, lay eggs and Placental". This answer correctly identifies three types of class mammals based on their reproductive methods. Pouched mammals, like kangaroos, carry their young in a pouch. Mammals that lay eggs, like monotremes (e.g., platypus), are unique as they are the only group of mammals that reproduce this way. Placental mammals, which include humans and most other mammals, give birth to live young after a gestation period during which the fetus is nourished by a placenta.Rate this question:
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- 4.
From the antigen-antibody reaction shown below. What is the type of the blood group?
- A.
A+ve
- B.
A-ve
- C.
B+ve
- D.
B-ve
Correct Answer
A. A+veExplanation
The blood group is determined by the presence or absence of certain antigens on the surface of red blood cells. In this case, the antigen-antibody reaction suggests the presence of the A antigen and the absence of the B antigen. Therefore, the blood group is A. The positive sign indicates the presence of the Rh antigen, making it A+ve.Rate this question:
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- 5.
The decrease in red blood cells, results in .......
- A.
The increase in antigen A and antigen B
- B.
The decrease in anti-A and anti-B
- C.
The decrease in antigen A and antigen B
- D.
The increase in anti-A and anti-B
Correct Answer
C. The decrease in antigen A and antigen BExplanation
A decrease in red blood cells can lead to a decrease in antigen A and antigen B. Antigens are substances that stimulate an immune response, and they are present on the surface of red blood cells. When red blood cells decrease, the levels of antigen A and antigen B also decrease.Rate this question:
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- 6.
Individuals with sex-chromosome trisomy can have ……….
- A.
XXY
- B.
XXX
- C.
XYY
- D.
Any of these
Correct Answer
D. Any of theseExplanation
Individuals with sex-chromosome trisomy can have any of the mentioned conditions, including XXY, XXX, and XYY. Sex-chromosome trisomy refers to the presence of an extra sex chromosome in an individual's genetic makeup. In the case of XXY, the individual has two X chromosomes and one Y chromosome. In the case of XXX, the individual has three X chromosomes. In the case of XYY, the individual has one X chromosome and two Y chromosomes. Therefore, any of these conditions can occur in individuals with sex-chromosome trisomy.Rate this question:
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- 7.
It is known fact that a person with blood group O will have anti A, anti B antibodies, then how is it eligible for transfusing blood to other persons as antiserum could cause blood coagulation?
- A.
The recipient’s blood produces antibodies for anti A and anti B.
- B.
The small amount of antibody present in the donated plasma, is further diluted on transfusion into the recipient's circulation.
- C.
Anti-A and anti-B are destroyed by the enzymes found in the recipient's blood plasma
- D.
The absence of A-B antigens on the donor's red blood cells, which cannot, therefore, be hemolyzed by the recipient's antibodies.
Correct Answer
B. The small amount of antibody present in the donated plasma, is further diluted on transfusion into the recipient's circulation.Explanation
When a person with blood group O donates blood to another person, the small amount of anti-A and anti-B antibodies present in the donated plasma gets diluted as it is transfused into the recipient's circulation. This dilution reduces the concentration of antibodies, minimizing the risk of blood coagulation caused by the antiserum. Therefore, despite having antibodies, blood group O can still be eligible for transfusing blood to other individuals.Rate this question:
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- 8.
If nigricans is the species, so it belongs to …… phylum.
- A.
Phaeophyta
- B.
Pyrrophyta
- C.
Zygomycota
- D.
Cnidaria
Correct Answer
C. ZygomycotaExplanation
The correct answer is Zygomycota because nigricans is a species that belongs to the phylum Zygomycota. This phylum includes fungi that reproduce sexually by forming zygospores, and they are commonly found in soil and decaying organic matter.Rate this question:
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- 9.
The phenotype expresses the genotype in males in case of the --------- trait
- A.
Normal person in cystic fibrosis disease (a recessive lethal)
- B.
Sex-linked
- C.
Sex-influenced
- D.
Mendelian traits
Correct Answer
B. Sex-linkedExplanation
In the case of the trait mentioned, the phenotype expresses the genotype in males. This suggests that the trait is sex-linked, meaning it is determined by genes located on the sex chromosomes. In this case, the trait is likely to be located on the X chromosome, as males only have one X chromosome and therefore only one copy of the gene.Rate this question:
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- 10.
In the pedigree below, if the gene of brown eyes dominates the gene of blue eyes, so the colour of father's eyes should be ---------.
- A.
Blue
- B.
Pure brown
- C.
Black
- D.
Hybrid brown
Correct Answer
D. Hybrid brownExplanation
In the given pedigree, if the gene for brown eyes dominates the gene for blue eyes, it means that the brown eye gene is dominant over the blue eye gene. This means that if an individual has even one copy of the brown eye gene, they will have brown eyes. Since the color of the father's eyes is not specified in the pedigree, it can be inferred that his eye color is not pure brown (as that would be specified), but rather a hybrid brown color.Rate this question:
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- 11.
A colour blind man marries a woman with normal sight who has no history of color blindness in her family. What is the probability of their grandson through daughter being color blind?
- A.
25%
- B.
50%
- C.
100%
- D.
Zero %
Correct Answer
B. 50%Explanation
The probability of their grandson through their daughter being color blind is 50% because color blindness is a sex-linked trait that is passed down through the X chromosome. Since the man is color blind, he only has one X chromosome to pass on to his daughter. If the daughter inherits the color blindness gene from her father, she will be a carrier of the trait. If she then has a son, there is a 50% chance that she will pass on the color blindness gene to him.Rate this question:
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- 12.
Long radishes crossed with round radishes result in all oval radishes. This type of inheritance is ------
- A.
Incomplete dominance
- B.
Multiple alleles.
- C.
Complete dominance.
- D.
Sex- influenced trait
Correct Answer
A. Incomplete dominanceExplanation
When long radishes are crossed with round radishes and the resulting radishes are all oval, it suggests that neither the long nor round trait is completely dominant over the other. In incomplete dominance, the heterozygous offspring show a blending of the two parental traits, resulting in an intermediate phenotype. Therefore, the oval shape of the radishes indicates incomplete dominance as the type of inheritance in this case.Rate this question:
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- 13.
Patterned baldness is a sex influenced trait more expressed in a male. If B is normal allele making non-bald phenotype and B+ is mutant leading to bald phenotype, for a cross between a bald mother and normal father, what is the probability of a bald son?
- A.
0%
- B.
25%
- C.
50%
- D.
100%
Correct Answer
D. 100%Explanation
Patterned baldness is a sex-influenced trait, meaning it is influenced by the sex of the individual. It is more commonly expressed in males. In this scenario, the mother is bald, which means she must have the mutant allele (B+), as the trait is more expressed in males. The father, being normal, must have the normal allele (B). Since the mother is bald and the trait is dominant, all of her sons will inherit the mutant allele and therefore have a bald phenotype. Therefore, the probability of a bald son in this cross is 100%.Rate this question:
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- 14.
From the figure below, which of the following statements is not correct?
- A.
Plants in figure (1) have tap roots
- B.
Vascular bundles of plants in figure (2) are scattered inside the stem
- C.
Maize plant belongs to figure (1)
- D.
Flowers of plants in figure (2) have trimerous floral whorls
Correct Answer
C. Maize plant belongs to figure (1)Explanation
The given figure shows two different types of plants. The first statement states that the plants in figure (1) have tap roots, which is correct as the plants in figure (1) have long, thick, and tapering roots. The second statement states that the vascular bundles of plants in figure (2) are scattered inside the stem, which is also correct as the vascular bundles are scattered throughout the stem in a random manner. The third statement states that maize plant belongs to figure (1), which is incorrect as maize plant belongs to figure (2) as shown in the figure. The fourth statement states that the flowers of plants in figure (2) have trimerous floral whorls, which is not mentioned in the figure.Rate this question:
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- 15.
The figure represents the limbs of two different mammals, which statement of the following is not correct?
- A.
Both belong to order Artiodactyla
- B.
Both are herbivorous animals
- C.
Both are Eutherian mammals
- D.
Their mating produces a Mule
Correct Answer
D. Their mating produces a MuleExplanation
The correct answer is "Their mating produces a Mule" because mules are the offspring of a male donkey and a female horse, not two different mammals. Mules are sterile and cannot reproduce, making this statement incorrect.Rate this question:
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- 16.
The likelihood of a child being born with a major genetic defect, such as mental retardation, can often be detected by sampling ......
- A.
The mother's uterus cells.
- B.
Cells from the embryo.
- C.
The father's blood cells.
- D.
Spermatozoa of the father.
Correct Answer
B. Cells from the embryo.Explanation
Cells from the embryo can be sampled to detect the likelihood of a child being born with a major genetic defect. This is because the embryo's cells contain the genetic material that will determine the development and characteristics of the child. By analyzing the embryo's cells, geneticists can identify any abnormalities or mutations that may lead to genetic defects such as mental retardation. Sampling the mother's uterus cells, the father's blood cells, or the spermatozoa of the father would not provide the same level of information about the genetic makeup of the developing child.Rate this question:
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- 17.
All of the following, their fertilization is externally except ............
- A.
Ray fish
- B.
Bolti fish
- C.
Bouri fish
- D.
Salamander
Correct Answer
A. Ray fishExplanation
Ray fish is the correct answer because it is the only option that undergoes internal fertilization. Internal fertilization occurs when the sperm and egg meet inside the body of the female organism. In contrast, external fertilization occurs when the sperm and egg meet outside the body, typically in water. Bolti fish, Bouri fish, and Salamander all reproduce through external fertilization, releasing their eggs and sperm into the water where fertilization takes place.Rate this question:
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- 18.
If X' is a sex chromosome carries the gene of hemophilia disease and X is a sex chromosome doesn’t carry the gene of hemophilia disease, then a normal mother and a hemophiliac father can produce a hemophiliac girl if ------.
- A.
A sperm with X’ chromosome fertilizes an ovum with X chromosome
- B.
A sperm with Y chromosome fertilizes an ovum with no sex chromosomes
- C.
A sperm with X chromosome fertilizes an ovum with X chromosome
- D.
A sperm with X’ chromosome fertilizes an ovum with no sex chromosomes
Correct Answer
D. A sperm with X’ chromosome fertilizes an ovum with no sex chromosomesExplanation
If a normal mother and a hemophiliac father produce a hemophiliac girl, it means that the girl inherited the hemophilia gene from her father. Since the father is hemophiliac, he must have a sex chromosome that carries the gene for hemophilia (X'). The mother, being normal, does not carry the gene for hemophilia on her sex chromosome (X). In order for the girl to be hemophiliac, she must receive the X' chromosome from her father and an ovum with no sex chromosomes from her mother.Rate this question:
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- 19.
The following two animals share a common character ..........
- A.
Their tail is long
- B.
They are rodents
- C.
Their forelimbs are modified into wings
- D.
They suckle their youngs
Correct Answer
D. They suckle their youngsExplanation
The correct answer is "They suckle their youngs." This is because all the other options listed are characteristics that are shared by different animals. Having a long tail is not exclusive to any specific group of animals, as many different species can have long tails. Being rodents also does not narrow down the options, as there are many different types of rodents. The modification of forelimbs into wings is a characteristic of birds, not rodents. However, the ability to suckle their youngs is a unique characteristic of mammals, which narrows down the options and makes it the correct answer.Rate this question:
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- 20.
A dihybrid cross, is a genetic cross yielding a ----- ratio of offspring.
- A.
9:3:3:1
- B.
1:2:1
- C.
3:1
- D.
2:1
Correct Answer
A. 9:3:3:1Explanation
A dihybrid cross involves the crossing of two individuals that differ in two traits. The resulting offspring show a phenotypic ratio of 9:3:3:1, which means that for every 9 individuals displaying both dominant traits, there are 3 individuals displaying the first dominant trait and the second recessive trait, 3 individuals displaying the first recessive trait and the second dominant trait, and 1 individual displaying both recessive traits. This ratio is a result of the independent assortment of alleles during meiosis and the combination of different genotypes.Rate this question:
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- 21.
In all the following genetic cases, the phenotype indicates the genotype except in the ---------.
- A.
Green colour of corn seedlings
- B.
Mice with yellow fur
- C.
Mice with grey fur
- D.
Colour blindness in males
Correct Answer
A. Green colour of corn seedlingsExplanation
The phenotype of an organism refers to its physical characteristics, while the genotype refers to the genetic makeup or combination of alleles that determine those characteristics. In all the given cases, the phenotype is directly indicative of the genotype, except in the case of green color of corn seedlings. This suggests that there may be other factors, such as environmental conditions, influencing the expression of the green color in corn seedlings, rather than just the genotype alone.Rate this question:
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- 22.
Rhinoceros shares with Deer all of the following, EXCEPT -------.
- A.
Eating herbs
- B.
Number of toes
- C.
Presence of hooves
- D.
Suckling their young
Correct Answer
B. Number of toesExplanation
Both rhinoceros and deer are herbivores, meaning they eat herbs. They both have hooves and suckle their young. However, the number of toes is where they differ. Deer typically have cloven hooves, which means they have two toes, while rhinoceros have three toes. Therefore, the correct answer is "Number of toes."Rate this question:
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- 23.
All the following statements are correct except ------.
- A.
The sperm is similar to the ovum in the number of autosomes
- B.
The sperm is similar to the ovum in the number of sex chromosomes
- C.
Each of the sperm and the ovum contains half the number of chromosomes in somatic cell
- D.
The ovum is responsible for sex determination
Correct Answer
D. The ovum is responsible for sex determinationExplanation
The statement "The ovum is responsible for sex determination" is incorrect. In humans, it is the sperm that determines the sex of the offspring because it can carry either an X or a Y chromosome, while the ovum always carries an X chromosome.Rate this question:
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- 24.
Marine weeds that consist of filaments adhering together by a gelatinous membrane .......
- A.
Spirogyra
- B.
Fucus
- C.
Polysiphonia
- D.
All the previous
Correct Answer
C. PolysiphoniaExplanation
Polysiphonia is the correct answer because it is a type of marine weed that consists of filaments adhering together by a gelatinous membrane. Spirogyra and Fucus are also types of marine weeds, but they do not adhere together in the same way as Polysiphonia. Therefore, the correct answer is Polysiphonia.Rate this question:
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- 25.
A Klinefelter person can pass his X- chromosome to --------.
- A.
His son
- B.
His daughter
- C.
Grandson
- D.
None of them
Correct Answer
D. None of themExplanation
A Klinefelter person has an extra X chromosome, resulting in a genotype of XXY. Therefore, they can only pass on one of their X chromosomes to their offspring. Since none of the options listed include receiving an X chromosome from the Klinefelter person, the correct answer is "None of them".Rate this question:
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- 26.
A hemophiliac father and a pure normal mother have a hemophiliac daughter. This daughter may result from the fusion of the following two gametes -------.
- A.
A sperm with X-chromosome and an ovum lacking sex chromosomes.
- B.
A sperm with X-chromosome and an ovum with XX-chromosomes.
- C.
A sperm lacking sex chromosomes and an ovum with XX-chromosomes.
- D.
A sperm with X-chromosome and an ovum with X-chromosome.
Correct Answer
A. A sperm with X-chromosome and an ovum lacking sex chromosomes.Explanation
Hemophilia is a sex-linked recessive disorder that is carried on the X chromosome. Since the father is a hemophiliac, he can only pass on the affected X chromosome to his children. The mother, being pure normal, does not carry the hemophilia gene. In order for the daughter to be hemophiliac, she must receive the affected X chromosome from her father and an X chromosome lacking the hemophilia gene from her mother. Therefore, the fusion of a sperm with an X-chromosome (carrying the hemophilia gene) and an ovum lacking sex chromosomes (not carrying the hemophilia gene) would result in a hemophiliac daughter.Rate this question:
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- 27.
A heterotrophic organism that contains a cell wall is ---------.
- A.
Trypanosoma
- B.
Yeast
- C.
Sponge
- D.
Nostoc
Correct Answer
B. YeastExplanation
Yeast is a heterotrophic organism that contains a cell wall. Yeast is a type of fungus that obtains its nutrients by consuming organic matter. It is also known for its ability to ferment sugars in anaerobic conditions, which is why it is commonly used in baking and brewing. The cell wall of yeast provides structural support and protection to the cell, similar to other fungi. Therefore, yeast is the correct answer to the question.Rate this question:
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- 28.
The following figure represents two types of living organisms, where they share a common character in --------.
- A.
Can walk upside down
- B.
The type of eyes
- C.
The number of body regions
- D.
The number walking legs
Correct Answer
A. Can walk upside downExplanation
The correct answer is "Can walk upside down" because the figure represents two types of living organisms that share a common character, and that character is the ability to walk upside down.Rate this question:
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- 29.
An example of a simple animal is ------------.
- A.
Fern.
- B.
Sponge.
- C.
Mold.
- D.
Insect.
Correct Answer
B. Sponge.Explanation
A sponge is an example of a simple animal because it is a multicellular organism that lacks specialized tissues and organs. Sponges are considered simple because they have a relatively simple body structure and lack complex systems found in more advanced animals. They are filter feeders that live in aquatic environments and are characterized by their ability to absorb water and filter out food particles. Sponges play an important ecological role in marine ecosystems and are often used in household cleaning products.Rate this question:
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- 30.
What is sub-class (A) in the following dichotomous key?
- A.
Filicatae
- B.
Monocotyledonae
- C.
Dicotyledonae
- D.
Mosses
Correct Answer
B. MonocotyledonaeExplanation
In this dichotomous key, sub-class (A) is identified as Monocotyledonae. This means that the organism being classified belongs to the sub-class Monocotyledonae, which is a group of plants that have a single seed leaf or cotyledon. This classification is based on the presence of certain characteristics or traits that are unique to plants in the Monocotyledonae sub-class.Rate this question:
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- 31.
The number of chromosomes in a female with Down's syndrome is equal to their number in ---------.
- A.
A male with Down's syndrome
- B.
A male with Klinefelter syndrome
- C.
A female with a triple-X
- D.
All the previous
Correct Answer
D. All the previousExplanation
Individuals with Down's syndrome have an extra copy of chromosome 21, resulting in a total of 47 chromosomes instead of the usual 46. Similarly, individuals with Klinefelter syndrome have an extra X chromosome, resulting in a total of 47 chromosomes as well. Females with a triple-X condition have three X chromosomes instead of the usual two, also resulting in a total of 47 chromosomes. Therefore, the number of chromosomes in a female with Down's syndrome is equal to the number of chromosomes in a male with Down's syndrome, a male with Klinefelter syndrome, and a female with a triple-X condition.Rate this question:
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- 32.
Bilateral symmetry is seen in the body organization of …….
- A.
Only chordates
- B.
Only vertebrates
- C.
Vertebrates, annelids, arthropods and cnidarians
- D.
Annelids, arthropods and vertebrates
Correct Answer
D. Annelids, arthropods and vertebratesExplanation
Bilateral symmetry is a type of symmetry where the body can be divided into two equal halves along a plane. This type of symmetry is seen in the body organization of annelids, arthropods, and vertebrates. These organisms have a distinct left and right side, with similar body parts on each side. Chordates, which include vertebrates, also exhibit bilateral symmetry. However, cnidarians, such as jellyfish, have radial symmetry rather than bilateral symmetry. Therefore, the correct answer is annelids, arthropods, and vertebrates.Rate this question:
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- 33.
Corn plant is unable to synthesize chlorophyll pigments in case of -------.
- A.
The presence of chlorophyll gene and unexposure to light
- B.
The absence of chlorophyll gene and exposure to light
- C.
The absence of chlorophyll gene and unexposure to light
- D.
Al the previous
Correct Answer
D. Al the previousExplanation
Corn plants are unable to synthesize chlorophyll pigments in case of the absence of the chlorophyll gene, regardless of whether they are exposed to light or not. This means that if the corn plant does not have the gene responsible for producing chlorophyll, it will not be able to synthesize the pigment, regardless of whether it is exposed to light or not.Rate this question:
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- 34.
If there are multiple alleles for a gene which of the following is true?
- A.
All the alleles are present at the same time.
- B.
Among the multiple copies, only the dominant ones are expressed.
- C.
Only two alleles are present at a time.
- D.
Only one allele of them is dominant while the rest are all recessive.
Correct Answer
C. Only two alleles are present at a time.Explanation
When there are multiple alleles for a gene, only two alleles are present at a time in an individual. This is because an individual can only inherit two alleles (one from each parent) for a particular gene. Therefore, among the multiple alleles available in a population, only two of them will be present in an individual at any given time.Rate this question:
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- 35.
Mitotic cell division results in two cells that have ____.
- A.
N chromosomes and are genetically identical.
- B.
N chromosomes and are genetically different.
- C.
2N chromosomes and are genetically identical.
- D.
2N chromosomes and are genetically different.
Correct Answer
C. 2N chromosomes and are genetically identical.Explanation
During mitotic cell division, the cell's DNA is replicated, resulting in two cells that each contain the same number of chromosomes as the original cell (2N). Additionally, since the DNA is replicated faithfully, the two resulting cells are genetically identical to each other and to the original cell.Rate this question:
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- 36.
If a bald father has all his sons with normal hair, which of the following can’t exist?
- A.
Father is heterozygous
- B.
Mother carries the gene of hair falling
- C.
Mother suffers from hair falling
- D.
Mother does not carry the gene of baldness
Correct Answer
C. Mother suffers from hair fallingExplanation
If a bald father has all his sons with normal hair, it means that the father is heterozygous for the gene responsible for baldness. This means that he carries both the dominant and recessive alleles for the gene. In order for the sons to have normal hair, they must inherit the dominant allele from the father. The mother carrying the gene of hair falling or not carrying the gene of baldness does not affect the sons' hair as long as the father passes on the dominant allele. However, if the mother suffers from hair falling, it means she has the recessive allele for the gene, which would result in the sons inheriting the recessive allele and having baldness. Therefore, the mother suffering from hair falling can't exist in this scenario.Rate this question:
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- 37.
An example of alleles is --------.
- A.
AB and Tt.
- B.
TT and Tt.
- C.
T and t.
- D.
Chromosome X and chromosome Y.
Correct Answer
C. T and t.Explanation
Alleles are alternative forms of a gene that occupy the same position on a chromosome and determine the same trait. In this case, the example of alleles is given as "T and t". This means that there are two different forms of the gene for a particular trait, with one form represented by the capital letter T and the other form represented by the lowercase letter t. These alleles can be inherited from parents and can result in different variations of the trait being expressed in individuals.Rate this question:
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- 38.
The body of ……. can be divided into head, thorax and abdomen.
- A.
Insecta only
- B.
Insecta and Arachnida
- C.
Insecta and Crustacea
- D.
Insecta and Myriapoda
Correct Answer
C. Insecta and CrustaceaExplanation
The body of insects can be divided into head, thorax, and abdomen. This is also true for crustaceans, which are a group of arthropods that includes crabs, lobsters, and shrimp. Therefore, the correct answer is "Insecta and Crustacea".Rate this question:
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- 39.
Which antibodies are found in the plasma of a person with a blood type A-ve previously received a wrong blood group B+ve by a mistake?
- A.
Neither anti-A nor anti-B
- B.
Both anti-A and anti-D
- C.
Both anti-B and anti-D
- D.
Anti-B, but not anti-D
Correct Answer
C. Both anti-B and anti-DExplanation
When a person with blood type A- receives the wrong blood type B+, their immune system will produce antibodies against the foreign antigens present in the B+ blood. In this case, the person will produce both anti-B antibodies to fight against the B antigen and anti-D antibodies to fight against the D antigen (which is present in the Rh factor of the B+ blood). Therefore, the correct answer is that both anti-B and anti-D antibodies will be found in the plasma of a person with blood type A-ve who previously received the wrong blood type B+ve.Rate this question:
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- 40.
A chromosomal abnormality that causes a man to have feminine body contours with large breasts, height greater than average, small testes, and infertility is ---------.
- A.
Down syndrome
- B.
XYY syndrome
- C.
Turner syndrome
- D.
Klinefelter syndrome
Correct Answer
D. Klinefelter syndromeExplanation
Klinefelter syndrome is a chromosomal abnormality that occurs in males. It is characterized by the presence of an extra X chromosome, resulting in a karyotype of 47, XXY. This condition leads to various physical and reproductive abnormalities, such as feminine body contours with large breasts, above-average height, small testes, and infertility. This explanation fits the given symptoms and accurately identifies Klinefelter syndrome as the correct answer.Rate this question:
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- 41.
A man of blood group A marries women of blood group AB. Which type of progeny would indicate that the man is heterozygous?
- A.
AB
- B.
A
- C.
O
- D.
B
Correct Answer
D. BExplanation
If the man is heterozygous for blood group A, it means he has one allele for blood group A and one allele for blood group O. When a man with blood group A marries a woman with blood group AB, there is a possibility of their progeny having blood groups A, B, or AB. However, if the progeny has blood group B, it indicates that the man is heterozygous because the only way for the child to have blood group B is if the man passed on his allele for blood group O to the child.Rate this question:
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- 42.
The phenotype indicates the genotype in the following genetic pattern -------.
- A.
Blood group A
- B.
A tall Pea plant
- C.
A red Antirrhinum flower
- D.
A white sweet pea flower
Correct Answer
C. A red Antirrhinum flowerExplanation
The phenotype indicates the genotype in the case of a red Antirrhinum flower. This means that the physical appearance of the flower (red color) can be used to determine the genetic makeup or genes responsible for that trait. In this case, the red color is a result of a specific genotype or combination of genes that code for the production of red pigments in the flower.Rate this question:
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- 43.
In a dominant sex-linked character where the gene XR dominates the gene Xr. If you know that in the pedigree below, the shaded individuals are having the dominant character. Also to know that the members in a square shape are males while those in a circle shape are females. What is the genotype of each of the two members (A) and (B)?
- A.
A is XRY and B is XRXR
- B.
A is XrY and B is XRXr
- C.
A is XRY and B is XRXr
- D.
A is XRY and B is XrXr
Correct Answer
C. A is XRY and B is XRXrExplanation
Based on the given information that the gene XR dominates the gene Xr, and the shaded individuals in the pedigree have the dominant character, we can determine the genotypes of members A and B. Since A is shaded and in a square shape, it is a male. Therefore, A must have one dominant allele (XR) and one recessive allele (Y), resulting in the genotype XRY. On the other hand, B is shaded and in a circle shape, indicating that it is a female. Since B also has the dominant character, she must have two dominant alleles (XRXR) in her genotype. Therefore, the correct answer is A is XRY and B is XRXr.Rate this question:
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- 44.
An extra finger in humans is rare but is due to a dominant gene. When one parent is normal and the other parent has an extra finger but is heterozygous for the trait, what is the probability that the first child will be normal?
- A.
0%
- B.
25%
- C.
50%
- D.
100%
Correct Answer
C. 50%Explanation
When one parent is normal and the other parent has an extra finger but is heterozygous for the trait, it means that the parent with the extra finger has one dominant gene for the trait and one recessive gene. The normal parent has two recessive genes for the trait. In this scenario, there is a 50% chance that the first child will inherit the dominant gene from the parent with the extra finger and therefore have an extra finger, and a 50% chance that the child will inherit the recessive gene from the normal parent and be normal.Rate this question:
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- 45.
The graph below represents --------.
- A.
Animal 1
- B.
Animal 2
- C.
Animal 3
- D.
Animal 4
Correct Answer
A. Animal 1 -
- 46.
All of the following plants form seeds except ---------.
- A.
Pea
- B.
Polypodium
- C.
Pinus
- D.
Cotton
Correct Answer
B. PolypodiumExplanation
Polypodium is a type of fern that reproduces through spores, not seeds. Spores are single-celled reproductive structures that are released into the environment and develop into new individuals. In contrast, plants like pea, Pinus (pine), and cotton produce seeds as their reproductive structures. Seeds contain an embryo and are surrounded by a protective coat, allowing for dispersal and germination. Therefore, Polypodium is the only option in the given list that does not form seeds.Rate this question:
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- 47.
The term “head” in vertebrate morphology includes ……..
- A.
Brain and its protective coverings
- B.
Brain, its protective coverings and some sense organs
- C.
Brain, skull, sense organs and jaws
- D.
Brain, skull, sense organs, jaws and pharyngeal skeleton
Correct Answer
C. Brain, skull, sense organs and jawsExplanation
The term "head" in vertebrate morphology refers to the anatomical structures including the brain, skull, sense organs, and jaws. These structures are all located in the uppermost part of the body and are essential for various functions such as sensory perception, feeding, and protection of the brain. Therefore, the correct answer is brain, skull, sense organs, and jaws.Rate this question:
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- 48.
Animals must eat other organisms for food, so they are classified as .......
- A.
Heterotrophs
- B.
Autotrophs
- C.
Eukaryotic
- D.
Prokaryotic
Correct Answer
A. HeterotrophsExplanation
Animals must eat other organisms for food, indicating that they cannot produce their own food through photosynthesis or other means. This means they rely on obtaining nutrients from other sources, making them heterotrophs.Rate this question:
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- 49.
Plants having vascular tissue without seeds ……..
- A.
Angiosperm
- B.
Pteridophytes
- C.
Bryophytes
- D.
Gymnosperms
Correct Answer
B. PteridophytesExplanation
Pteridophytes are plants that have vascular tissue but do not produce seeds. They reproduce through spores instead. Angiosperms, on the other hand, are flowering plants that have vascular tissue and produce seeds enclosed in fruits. Bryophytes are non-vascular plants that also do not produce seeds, while gymnosperms are vascular plants that do produce seeds, but not enclosed in fruits. Therefore, the correct answer is Pteridophytes.Rate this question:
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