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Explanation To convert a binary number to decimal, we need to multiply each digit of the binary number by the corresponding power of 2 and then sum them up. In this case, the binary number 1001.0010 can be broken down as follows: 1 * 2^3 + 0 * 2^2 + 0 * 2^1 + 1 * 2^0 + 0 * 2^-1 + 0 * 2^-2 + 1 * 2^-3 + 0 * 2^-4. Simplifying this equation gives us 8 + 1 + 0.125 = 9.125. Therefore, the correct answer is 9.125.
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2.
Number of bytes required to represent (1234 )_{10 } in BCD is
A.
1
B.
2
C.
3
D.
4
Correct Answer B. 2
Explanation To represent the decimal number 1234 in BCD (Binary-Coded Decimal), each digit is represented by a 4-bit binary code. Therefore, the total number of bits required to represent the number is equal to the number of digits multiplied by 4. In this case, there are 4 digits in the number 1234, so the total number of bits required is 4 * 4 = 16 bits. Since there are 8 bits in a byte, the number of bytes required to represent 1234 in BCD is 16 / 8 = 2 bytes.
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3.
. Determine the values of A, B, C and D that can make the sum term A’+B+C’+D equal to zero.
A.
A = 1, B = 0, C = 0, D = 0
B.
A = 0, B = 1, C = 0, D = 0
C.
A = 1, B = 0, C = 1, D = 1
D.
A = 1, B = 0, C = 1, D = 0
Correct Answer A. A = 1, B = 0, C = 0, D = 0
Explanation The given sum term A' + B + C' + D can be simplified as A' + C' + D, since B = 0. In order for the sum to equal zero, A, C, and D must all be equal to zero. Therefore, the values A = 1, B = 0, C = 0, and D = 0 satisfy the condition and make the sum term equal to zero.
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4.
The number of half adders required to general full adder are
A.
4
B.
3
C.
2
D.
1
Correct Answer C. 2
Explanation To generate a full adder, we need to combine two half adders. A half adder can add two single bits and produce a sum and a carry. However, a full adder can add three single bits and produce a sum and a carry. Therefore, to create a full adder, we need to combine two half adders, one for adding the first two bits and another for adding the third bit along with the carry from the previous addition. So, the correct answer is 2.
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5.
An AND gate with schematic "bubbles" on its inputs performs the same function as ________ gate.
A.
NOT
B.
OR
C.
NOR
D.
NAND
Correct Answer C. NOR
Explanation An AND gate with "bubbles" on its inputs performs the same function as a NOR gate. The "bubbles" represent the inversion of the inputs, so when they are connected to an AND gate, it effectively becomes a NOR gate. In a NOR gate, the output is only high (1) when both inputs are low (0), whereas in an AND gate with "bubbles", the output is only high when both inputs are low as well. Therefore, the AND gate with "bubbles" on its inputs is equivalent to a NOR gate.
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6.
----------------------- bus indicates data handling capacity of the Microprocessor
A.
System Bus
B.
Address Bus
C.
Data Bus
D.
Control Bus
Correct Answer C. Data Bus
Explanation The data bus is responsible for transferring data between the microprocessor and other devices in the computer system. It determines the amount of data that can be transferred at a given time. Therefore, the data bus indicates the data handling capacity of the microprocessor. The system bus, address bus, and control bus are also important components of the microprocessor, but they do not directly determine the data handling capacity.
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7.
Select the statement that best describes Read-Only Memory (ROM).
A.
Non-volatile, used to store information that changes during system operation
B.
Non-volatile, used to store information that does not change during system operation
C.
Volatile, used to store information that changes during system operation
D.
Volatile, used to store information that does not change during system operation
Correct Answer B. Non-volatile, used to store information that does not change during system operation
Explanation ROM stands for Read-Only Memory, which is a type of computer memory that is non-volatile, meaning it retains its data even when the power is turned off. ROM is used to store information that does not change during system operation, such as firmware or permanent instructions that are essential for the computer to boot up. This information is pre-programmed and cannot be modified or erased by normal computer operations, hence the term "read-only."
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8.
The maximum number of minterms that can be formed from 2 variables are
A.
6 minterms
B.
8 minterms
C.
4 minterms
D.
2 minterms
Correct Answer C. 4 minterms
Explanation The maximum number of minterms that can be formed from 2 variables is 4. This is because each variable can take on two values (0 or 1), and there are two variables. Therefore, the total number of possible combinations is 2^2 = 4. Each combination represents a minterm, so there are 4 minterms in total.
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9.
The Boolean expression X=A'+ B' + C' is logically equivalent to what single gate?
A.
AND
B.
OR
C.
NAND
D.
NOR
Correct Answer A. AND
Explanation The Boolean expression X=A' + B' + C' is logically equivalent to the AND gate. This is because the expression represents the logical OR operation of three variables A', B', and C'. In an AND gate, the output is true only when all the inputs are true. So, the expression X=A' + B' + C' will be true only when A', B', and C' are all true, which is equivalent to the behavior of an AND gate.
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10.
A group of two 1s in a three variable k-map will simplify to _________ variable expression.
(Specify the number)
A.
1
B.
2
C.
3
D.
None of these
Correct Answer B. 2
Explanation A group of two 1s in a three variable k-map will simplify to a two-variable expression. This is because a group of two 1s in a k-map represents a product term in a Boolean expression, and each product term consists of variables that are common to all the 1s in the group. Since there are three variables in the k-map, the two-variable expression will only include the two variables that are common to the group of 1s.
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11.
The Boolean expression A'+CA reduces to
A.
A+C
B.
A Ì…+C
C.
ABC+ABC Ì…
D.
A Ì…
Correct Answer B. A Ì…+C
Explanation The given Boolean expression A' + CA can be simplified as A' + C since A' + A = 1 and 1C = C. Therefore, the correct answer is A' + C.
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12.
Which of the followings is not a memory?
A.
RAM
B.
SRAM
C.
EEPROM
D.
EPAM
Correct Answer D. EPAM
13.
Decimal 41 in Hexadecimal and BCD number system is respectively
A.
B2, 01000011
B.
29, 01000001
C.
2B, 01000010
D.
29, 00101001
Correct Answer B. 29, 01000001
Explanation The correct answer is 29, 01000001. In the hexadecimal number system, the decimal number 41 is represented as 29. In the BCD (Binary Coded Decimal) number system, the decimal number 41 is represented as 01000001.
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14.
A simple flip-flop
A.
Is a four state device
B.
Has nothing to do with memory
C.
Is 2 bit memory
D.
Is 1 bit memory
Correct Answer D. Is 1 bit memory
Explanation A simple flip-flop is considered to be a 1 bit memory because it can store and remember a single binary value, either 0 or 1. It has two stable states, typically labeled as "SET" and "RESET," and it can hold its current state until it receives a signal to change. It is commonly used in digital circuits to store and control the flow of data.
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15.
How many binary bits are necessary to represent 748 different numbers?
A.
9
B.
8
C.
7
D.
10
Correct Answer D. 10
Explanation To represent 748 different numbers, we need to find the minimum number of bits required to represent that range. We can calculate this by finding the smallest power of 2 that is greater than or equal to 748. In this case, 2^10 (1024) is the smallest power of 2 that is greater than 748. Therefore, 10 binary bits are necessary to represent 748 different numbers.
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16.
A half subtractor circuit requires
A.
Two inputs and two outputs
B.
Two inputs and three outputs
C.
Three inputs and one output
D.
Three inputs and two outputs
Correct Answer A. Two inputs and two outputs
Explanation A half subtractor circuit requires two inputs and two outputs because it is used to subtract two single-bit binary numbers. The two inputs represent the minuend and subtrahend, while the two outputs represent the difference and borrow. The circuit performs the subtraction operation and generates the difference output, which is the result of the subtraction, and the borrow output, which indicates if a borrow is required from the next higher-order bit.
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17.
_____________ register is used in all ALU operations, i.e., to store one of operands and also result.
A.
Status
B.
Stack Pointer
C.
Program Counter
D.
Accumulator
Correct Answer D. Accumulator
Explanation The accumulator register is used in all ALU operations to store one of the operands and also the result. This means that the accumulator is responsible for holding the data that is being operated on and the final result of the operation. It is a crucial register in the ALU as it helps in performing arithmetic and logical operations.
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18.
. In the decimal numbering system, what is MSD?
A.
The middle digit of a stream of numbers
B.
The last digit on the right
C.
The digit to the right of the decimal point
D.
The digit with the most weight
Correct Answer D. The digit with the most weight
Explanation MSD stands for Most Significant Digit. In the decimal numbering system, the digit with the most weight is the leftmost digit, also known as the most significant digit. This digit represents the largest value in the number and has the greatest influence on the overall value of the number. Therefore, the correct answer is "The digit with the most weight."
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19.
. Suppose Y is a Boolean variable, which of the following expressions will be equal to 1?
a. Y XOR Y b. Y AND 0 c. Y NOR 1 d. Y XNOR Y
A.
A
B.
B
C.
C
D.
D
Correct Answer D. D
Explanation The expression Y XNOR Y will be equal to 1 when Y is equal to 1. The XNOR operator returns 1 if both operands are equal, and in this case, if Y is equal to 1. Therefore, when Y is equal to 1, the expression Y XNOR Y will be equal to 1.
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20.
NAND gate is combination of
A.
AND & OR
B.
OR & NOT
C.
NOT & AND
D.
NOR and NOT
Correct Answer C. NOT & AND
Explanation A NAND gate is a combination of NOT and AND gates. The NOT gate inverts the output of the AND gate. In other words, it takes the output of the AND gate and produces the opposite value. This combination allows the NAND gate to perform logical negation and conjunction operations simultaneously.
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21.
A full subtractor circuit requires
A.
Two inputs and two outputs
B.
Two inputs and three outputs
C.
Three inputs and one output
D.
Three inputs and two outputs
Correct Answer D. Three inputs and two outputs
Explanation A full subtractor circuit requires three inputs and two outputs because it is used to subtract two binary numbers. The three inputs are the minuend, subtrahend, and borrow-in. The two outputs are the difference and borrow-out. The circuit performs the subtraction operation by considering the borrow-in and produces the difference and borrow-out as outputs.
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22.
Terminals of a transistor
A.
E,B,C
B.
B, D, E
C.
V ,C ,E
D.
V,B,C
Correct Answer A. E,B,C
Explanation The correct answer is E, B, C. In a transistor, the terminals are labeled as Emitter (E), Base (B), and Collector (C). The Emitter is responsible for emitting or releasing electrons, the Base controls the flow of electrons, and the Collector collects the electrons. Therefore, the correct terminals for a transistor are E, B, and C.
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23.
A half Adder circuit requires
A.
Two inputs and two outputs
B.
Three inputs and one output
C.
Two inputs and three outputs
D.
Three inputs and two outputs
Correct Answer A. Two inputs and two outputs
Explanation A half adder circuit requires two inputs and two outputs because it is used to add two single-digit binary numbers. The two inputs represent the two numbers to be added, and the two outputs represent the sum and carry. The sum output represents the result of adding the two numbers, while the carry output indicates whether there is a carry-over to the next digit.
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24.
In the decimal numbering system, what is LSB?
A.
Low sign bit
B.
Less Significant bit
C.
Least significant bit
D.
Lower significant bit
Correct Answer C. Least significant bit
Explanation LSB stands for "Least Significant Bit." In the decimal numbering system, it refers to the rightmost bit or the bit with the lowest value in a binary number. The LSB holds the least amount of significance or weight in determining the value of the number. It is often used in digital systems and computer programming to represent the smallest unit of information or to indicate the smallest possible change in a value.
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25.
Expansion of BJT
A.
Bi-Polar Junction Transistor
B.
Bypass junction Transistor
C.
Bold junction Transistor
D.
Bass junction Transistor
Correct Answer A. Bi-Polar Junction Transistor
Explanation The correct answer is Bi-Polar Junction Transistor. A BJT, or Bi-Polar Junction Transistor, is a type of transistor that consists of three layers of semiconductor material. It is called "bi-polar" because it can conduct both positive and negative charges. The junctions between the layers allow the transistor to amplify and switch electronic signals. BJT is a commonly used term in electronics and is an important component in many electronic devices.